A construction company needs 2 weeks to construct a family room and
3 days to add a porch. Find the ratio of the time it takes for constructing the porch to the time constructing the family room, with all units in days.


Answers

Answer 1

Answer:

3/14

Step-by-step explanation:

it takes 3 days to construct a porch and 14 days to construct a family room

so porch/family room = 3/14

Brainliest if this was correct


Related Questions

Question 2
A force F=5i+3j-2k is applied to move a block of cement from A(0,1,1) to B(4.-1,3).
Determine the work done by the force.

Answers

The work is simply the dot product of the force and displacement (which I assume are given in Newtons and meters, respectively):

W = F • d

W = (5i + 3j - 2k) N • ((4i - j + 3k) m - (j + k) m)

W = (5i + 3j - 2k) • (4i - 2j + 2k) Nm

W = (20 - 6 - 4) Nm

W = 10 J

A radio transmission tower is 180 feet high. How long should a guy wire be if it is to be attached to the tower 11 feet from the top and is to make an angle of 45° with the ground?​

Answers

Answer:

Step-by-step explanation:

One urn contains 6 blue balls and 14 white balls, and a second urn contains 12 blue balls and 7 white balls. An urn is selected at random, and a ball is chosen from the urn. a. What is the probability that the chosen ball is blue? b. If the chosen ball is blue, what is the probability that it came from the first urn?

Answers

Answer:

a) 0.4658 = 46.58% probability that the chosen ball is blue

b) 0.322 = 32.2% probability that it came from the first urn

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

a. What is the probability that the chosen ball is blue?

6/20 = 0.3 of 0.5(first urn)

12/19 = 0.6316 out of 0.5(second urn).

So

[tex]P(A) = 0.3*0.5 + 0.6316*0.5 = 0.4658[/tex]

0.4658 = 46.58% probability that the chosen ball is blue.

b. If the chosen ball is blue, what is the probability that it came from the first urn?

Event A: Blue Ball

Event B: From first urn

From item a., [tex]P(A) = 0.4658[/tex]

Probability of blue ball from first urn:

0.3 of 0.5. So

[tex]P(A \cap B) = 0.3*0.5 = 0.15[/tex]

Probability:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.4658} = 0.322[/tex]

0.322 = 32.2% probability that it came from the first urn

What is the product (4.42 x 103)(5 x 10^) written in
scientific notation?

Answers

Answer:

2.2763 x 10 to the power of 4

for some reason it doesn't let me put in the explanation

Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement S (to take at least one science course). A poll of 150 sophomore students shows that: 60 completed M, 45 completed S, and 25 completed both M and S
Find the number of students who have completed
(a) At least one of the two requirements
(b) Exactly one of the two requirements
(c) Neither requirement.

Answers

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(c) Neither requirement:

(all students) - (M or S) = 150 - 80 = 70

Solve the system, or show that it has no solution. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, enter the general solution in terms of x, where x is any real number.)
20x − 80y = 100
−14x + 56y = −70
(x, y) =

Answers

Answer:

The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]

Step-by-step explanation:

From the first equation:

[tex]20x - 80y = 100[/tex]

[tex]20x = 100 + 80y[/tex]

[tex]x = \frac{100 + 80y}{20}[/tex]

[tex]x = 5 + 4y[/tex]

Replacing on the second equation:

[tex]-14x + 56y = -70[/tex]

[tex]-14(5 + 4y) + 56y = -70[/tex]

[tex]-70 - 56y + 56y = -70[/tex]

[tex]0 = 0[/tex]

This means that the system has an infinite number of solutions, considering:

[tex]x = 5 + 4y[/tex]

[tex]4y = x - 5[/tex]

[tex]y = \frac{x - 5}{4}[/tex]

The system has an infinite set of solutions [tex](x,y) = (x, \frac{x-5}{4})[/tex]

Allen is looking through his weekly local grocery store newspaper ads he notices that Costco is advertising a pack of 60 eggs for $9.35 Safeway is advertising a dozen eggs for $4.79 and Trader Joe's is advertising a pack of 18 eggs for $6.18 which store is offering the better deal?​

Answers

Answer:

Costco

Step-by-step explanation:

We find the cost per egg for each of the three stores.

Costco:

$9.35/(60 eggs) = $0.15583/egg

Safeway:

$4.79/(12 eggs) = $0.39917/egg

Trader Joe's:

$6.18/(18 eggs) = $0.34333/egg

The best deal is Costco.

Answer:

Costco

Step-by-step explanation:

[tex]\frac{60}{9.35}: \frac{1}{y}[/tex]

60 × y = 1 × 9.35

60y = 9.35

60y ÷ 60 = 9.35 ÷ 60

[tex]y=\frac{187}{1200}[/tex]

[tex]\frac{12}{4.79}: \frac{1}{y}[/tex]

12 × y = 1 × 4.79

12y = 4.79

12y ÷ 12 = 4.79 ÷ 12

[tex]y=\frac{479}{1200}[/tex]

[tex]\frac{18}{6.18}: \frac{1}{y}[/tex]

18 × y = 1 × 6.18

18y = 6.18

18y ÷ 18 = 6.18 ÷ 18

[tex]y=\frac{103}{300}=\frac{412}{1200}[/tex]

Need the answers from a - e

Answers

Answer:

10

Step-by-step explanation:

Sorry. I needed to answer this question to get access.

Consider the following game: You reach into a jar of money, and select a single bill at random to keep. There are 9 five-dollar bills, 5 ten-dollar bills, and 3 twenty-dollar bills in the jar. What should the cost of this game be in order for the game to be fair

Answers

Answer:

[tex]E(x)=\$9.118[/tex]

Step-by-step explanation:

From the question we are told that:

Available bills

 [tex]\$5=N0 9\\\\\$10=N0 5[/tex]

 [tex]\$20=N0 3[/tex]

Therefore

Total Bills

 [tex]n=5+9+3[/tex]

 [tex]n=17[/tex]

Probability of selecting each bill

 [tex]For\$5[/tex]

 [tex]P(\$5)=\frac{9}{17}[/tex]

 [tex]For\$10[/tex]

 [tex]P(\$10)=\frac{5}{17}[/tex]

 [tex]For\$20[/tex]

 [tex]P(\$20)=\frac{3}{17}[/tex]

Generally the equation for Expected winning is mathematically given by

 [tex]E(x)=\sum(X)*P(X)[/tex]

 [tex]E(x)=5*\frac{9}{17}+10*\frac{5}{17}+20*\frac{3}{17}[/tex]

 [tex]E(x)=\$9.118[/tex]

Suppose f(x,y,z) = x2 + y2 + z2 and W is the solid cylinder with height 7 and base radius 2 that is centered about the z-axis with its base at z = −2. Enter θ as theta.

A) As an iterated integral, ∭WfdV = ∫BA∫DC∫FE dzdrdθ with limits of integration.

B) Evaluate the integral.

Answers

In cylindrical coordinates, W is the set of points

W = {(r, θ, z) : 0 ≤ r ≤ 2 and 0 ≤ θ ≤ 2π and -2 ≤ z ≤ 5}

(A) Then the integral of f(x, y, z) over W is

[tex]\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

(B)

[tex]\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}[/tex]

From the table below, determine whether the data shows an exponential function. Explain why or why not.
x
3
2
1
–1
y
8
2
0.5
0.125
a. No; the domain values are at regular intervals and the range values have a common factor 0.25. b. No; the domain values are not at regular intervals although the range values have a common factor. c. Yes; the domain values are at regular intervals and the range values have a common factor 4. d. Yes; the domain values are at regular intervals and the range values have a common factor 0.25.

Answers

9514 1404 393

Answer:

  b. No; the domain values are not at regular intervals although the range values have a common factor.

Step-by-step explanation:

The differences between x-values are ...

  -1, -1, -1, -2 . . . . not a constant difference

The ratios of y-values are ...

  2/8 = 0.5/2 = 0.125/0.5 = 0.25 . . . . a constant difference

The fact that the domain values do not have a common difference renders the common factor of the range values irrelevant. The relation is not exponential.

I NEED HELP ILL MARK!!!

Answers

Answer:

c) tan

Step-by-step explanation:

For the 63-deg angle, YZ is the opposite leg. The unknown side, AY, is the adjacent leg. The trigonometric ratio that relates the opposite and adjacent legs is the tangent.

Answer: c) tan

You need
1
1
4
feet of string to make 20 holiday ornaments.

To make 14 holiday ornaments, you will need
feet of string.

Answers

Answer:

79.8

Step-by-step explanation:

math

2(-x-4)+3=-7x+5+5x

Pls help!!!!!!!!

Answers

4 I hope this helps you

1 Simplify

7
x
+
5
+
5
x
−7x+5+5x to

2
x
+
5
−2x+5.
2
(

x

4
)
+
3
=

2
x
+
5
2(−x−4)+3=−2x+5

2 Expand.

2
x

8
+
3
=

2
x
+
5
−2x−8+3=−2x+5

3 Simplify

2
x

8
+
3
−2x−8+3 to

2
x

5
−2x−5.

2
x

5
=

2
x
+
5
−2x−5=−2x+5

4 Cancel

2
x
−2x on both sides.

5
=
5
−5=5

5 Since

5
=
5
−5=5 is false, there is no solution.
No Solution

Here are the test scores for 8 students in Mr. M's class. 87, 55, 96, 38, 83, 64, 44, 81. What is the percentage of these test scores that are less than 84?

Answers

Answer:

75%

Step-by-step explanation:

Given that the score of 8 students in Mr. M's class are 87, 55, 96, 38, 83, 64, 44, 81, the scores less than 84 are 55, 38, 83, 64, 44, 81.

These means that 6 student had scores less that 84 of the 8 students hence the percentage of these test scores that are less than 84

= 6/8 * 100%

= 75%

This means that 75% of the students had scores less than 84

Is this a function? Yes or no?

Answers

Answer:

NO

Step-by-step explanation:

NO

what is the value of -2(7-15)/4

Answers

the value is 4 hope it helps
the value is 4 hope this helps

A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the speed of the dog to catch with the cat in 1 minute?

Answers

Answer:

[tex]3.8\:\mathrm{m/s}[/tex]

Step-by-step explanation:

Use the formula [tex]d=rt[/tex] (distance is equal to rate/speed multiplied by time) to solve this problem.

We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to [tex]d=3\cdot 60=180\text{ meters}[/tex].

To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover [tex]180+48=228[/tex] meters in one minute.

Therefore, we have:

[tex]228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}[/tex]

Answer:

[tex] \boxed{3.8 \: m/s} [/tex]

Explanation

The first step is to set the speed and the distance equal to the unknown rate of the dog.

3 m/s + 48 m = x m/60s.

Then substitute 60s in for both rates to get distance.

180m + 48m = x m/60

228m = 60x m

÷60 ÷60

3.8m = x m/s.

x = 3.8m/s

Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour. What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ? (Hint: Think exponential.)
a) e e-2 = 0.1353
b) e-13/15 = 0.4204
c) e-1 = 0.3679
d) 1-2-1 = 0.6321

Answers

Answer:

0.4204 probability, option b.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour

13 arrivals during an hour, which means that the mean time between arrivals, in minutes is of [tex]\mu = \frac{13}{60} = 0.2167[/tex]

What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ?

This is P(X > 4). So

[tex]P(X > 4) = e^{-0.2167*4} = 0.4204[/tex]

So the correct answer is given by option b.

Which rectangle has an area of 18 square units? On a coordinate plane, a rectangle is 2 units high and 7 units wide. On a coordinate plane, a rectangle is 2 units high and 6 units wide. On a coordinate plane, a rectangle is 3 units high and 5 units wide. On a coordinate plane, a rectangle is 3 units high and 6 units wide.

Answers

Answer:

On a coordinate plane, a rectangle is 3 units high and 6 units wide.

Answer:

option "B"

You Welcome

Step-by-step explanation:





Which expression has a value of 15 when it equals
2
49-57
3--5
61-28
28
19

Answers

Answer:

it is 61-28 but I not sure u can scan for any application to make sure u get it ur answer thx for

8th Grade Which expression is equivalent to 1/27​

Answers

Answer:

[tex]( \frac{1}{3})^{3} [/tex]

Step-by-step explanation:

There are many expressions that can be equivalent to 1/27.

For example, 2/54, 3/81 etc

But I think the expression you are looking for is

[tex] \frac{1}{27} = \frac{1 \times 1 \times 1}{3 \times 3 \times 3} = \frac{ {1}^{3} }{ {3}^{3} } = ( \frac{1}{3} )^{3} [/tex]

Hope this is helpful

You are designing an experiment using human subjects. The study will include 30 participants. Of these, 16 will be placed in the experimental group and the remaining 14 will be placed in the control group. In how many ways can you assign participants to the two groups?

Answers

Answer:

The participants can be assigned in 224 different ways.

Step-by-step explanation:

Given that you are designing an experiment using human subjects, and the study will include 30 participants, of which 16 will be placed in the experimental group and the remaining 14 will be placed in the control group, to determine in how many ways can you assign participants to the two groups the following calculation must be performed:

16 x 14 = X

224 = X

Therefore, the participants can be assigned in 224 different ways.

In 2013, the Public Religion Research Institute conducted a survey of 1,033 adults, 18 years of age or older, in the continental United States. One of the questions on their survey was as follows:

Answers

Answer:

Probability[Number of people from church] = 0.26 (Approx.)

Step-by-step explanation:

Given:

Total number of adult in survey = 1,033

Missing information:

Number of people from church = 269

Find:

Probability[Number of people from church]

Computation:

Probability of an event = Number of favourable outcomes / Number of total outcomes

Probability[Number of people from church] = Number of people from church / Total number of adult in survey

Probability[Number of people from church] = 269 / 1,033

Probability[Number of people from church] = 0.2604

Probability[Number of people from church] = 0.26 (Approx.)

How many orders are possible to view 6 videos from a stack of 8 videos?

Answers

Answer:

28

Step-by-step explanation:

We know that ,

n C r = n! / ( n - r)! r!

8! / ( 8 - 6)! 6!

8! / 2! × 6!

7 × 8 / 2 × 1

28

what is the slope of a line parallel to the line whose equation is 2x+5y=10

Answers

Answer:

1. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -11. The slope of a line  that is perpendicular to a line whose equation

is 5y = 10 + 2x is

2.

The line y = 2x - 1 is neither parallel nor perpendicular to the line

y = -2x + 3

The line y = -2x + 5 is parallel to the line y = -2x + 3

The line y =  x + 7 is perpendicular to the line

y = -2x + 3

3. The equation of the line that passes through the point (5 , -4) and

is parallel to the line whose equation is 2x + 5y = 10 is

y =  x - 2

Step-by-step explanation:

Let us revise some rules

The slope-intercept form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

The slopes of the parallel lines are equal

The product of the slopes of the perpendicular lines is -1

6. Aerial photography is to be taken of a tract of land that is 8 x 8 mi2. Flying height will be 4000 ft above average terrain, and the camera has focal length of 6 inches. If the focal plane opening is 9 x 9 in., and minimum side overlap is 30%, how many flight lines will be needed to cover the tract for the given data

Answers

Answer:

the number of flight lines needed is approximately 72

Step-by-step explanation:

Given the data in the question;

Aerial photography is to be taken of a tract of land that is 8 x 8 mi²

L × B = 8 x 8 mi²

Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in

focal length f = 6 in

[tex]l[/tex] × b = 9 × 9 in²

side overlap = 30% = 0.3

meaning remaining side overlap = 100% - 30% = 70% = 0.7

{ not end to end overlap }

we take 100% { remaining overlap }

[tex]l[/tex]' = 9 × 100% = 9 in

b' = 9 × 70% = 6.3 in

Now the scale will be;

Scale = f/H

we substitute

Scale = 6 in /  48000 in = 1 / 8000

so our scale is; 1 : 8000

⇒ 1 in = 8000 in

⇒ 1 in = (8000 / 63360)mi

⇒ 1 in = 0.126 mi

so since

L × B = 8 x 8 mi²

[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi

b' = ( 6.3 × 0.126 mi ) = 0.7938 mi

Now we get the flight lines;

N = ( L × B ) / ( [tex]l[/tex]' × b' )

we substitute

N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )

N = 64 / 0.9001692

N = 71.0977 ≈ 72

Therefore, the number of flight lines needed is approximately 72

PLEASE HELP I WILL MARK YOUR ANSWER AS BRAINLIEST PLEASE BE CORRECT BEFORE ANSWERING

LOOK AT THE BOTTOM

Answers

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

The figure must be flipped top-to-bottom, so the line of reflection must be a horizontal line. Point B must be reflected to itself, so it is on the line of reflection. That means the line of reflection is y = 2.

__

You can draw the line of reflection using any two points that have y-coordinates of 2, for example, (0, 2) and (2, 2).

Using the digits 2 through 8, find the number of different 5-digit numbers such that, digits can be used more than once.

Answers

Answer:

7 digits can be used for each position

There are a total of 5 positions

N = 7^5 = 16,807 numbers

You have 7 choices for the first position, second position, etc.

For any real number √a²
a
- |al
lal.
-a

Answers

Answer:

|a|

Step-by-step explanation:

For any positive or negative a, when you square it, the answer is positive.

The square root symbol means the principal square root. For a positive number, the principal square root is positive. To make sure the square root is always non-negative, use absolute value.

Answer: |a|

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