A cube whose edge is 20 cm 1 point
long, has circles on each of its
faces painted black. What is the
total area of the unpainted
surface of the cube if the
circles are of the largest
possible areas?(a) 90.72 cm2 (b)
256.72 cm² (c) 330.3 cm² (d)
514.28 cm?

​

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

Answer:

The sum of the arithmetic progression is 2520

Step-by-step explanation:

The sum, Sₙ, of an arithmetic progression, AP, is given as follows;

[tex]S_{n}=\dfrac{n}{2}\cdot \left (2\cdot a+\left (n-1 \right )\cdot d \right )[/tex]

Where;

n = The nth term of the progression

a = The first term = 100

d = The common difference = -2

Given that the last term = -10, we have;

-10 = 100 + (n - 1) ×(-2)

n = (-10 - 100)/(-2) + 1 = 56

Therefore, the sum of the 56 terms of the arithmetic progression is [tex]S_{56}=\dfrac{56}{2}\cdot \left (2\cdot 100+\left (56-1 \right )\cdot (-2) \right )[/tex]

Which gives;

[tex]S_{56}={28}\cdot \left (200-\left 110 \right ) = 2520[/tex]

Answer:

330.00cm²

Step-by-step explanation:

find the area of both circles and subtract the smaller one from the bigger one.

area of a circle= πr²

π wasn't given so I will use 22/7

so area of the bigger circle = 22/7 × 11²

=22/7 × 121

=380.28cm²

area of the small circle=22/7 × 4²

= 22/7 × 16

= 50.28cm²

Area of the shaded portion = 380.28 - 50.28

= 330.00cm²

Answer:

4 cm

Step-by-step explanation:

Volume is given by area of cross section * height

_______________________________

For condition 1

height = 12 cm

base for area of cross section is 5*8

that is length 8 cm and width 5 cm

thus area of cross section = 5*8 = 40 cm square

volume of milk =  area of cross section* height of milk = 40*12 = 480 cm cube.

_______________________________________________

now milk is turned such that base of area of cross section will

15 by 8

that is length: 15 cm and width : 8 cm

thus area of cross section = 15*8 = 120 cm square

let the depth of milk be x

thus, volume of milk =  area of cross section* height of milk = 120*x

= 120x cm cube

Since milk is in the same container , its volume before and after the change of alignment of container will remain same

thus

120x cm cube = 480 cm

=> x = 480/120 = 4

Thus, depth under given situation will be 4 cm.

Answer:

Clarissa will take 10 hours by herself

Step-by-step explanation:

Let s = time for shawna

s-5 = time for clarissa

The formula for determining the time is

1/a + 1/b = 1/c  where a and b are the times alone and c is the time together

1/s + 1/(s-5) = 1/6

Multiply each side by 6s(s-5) to clear the fractions

6s(s-5) ( 1/s + 1/(s-5)) = 1/6 *6s(s-5)

Distribute

6(s-5) + 6s = s(s-5)

Distribute

6s -30 +6s = s^2 -5s

Combine like terms

12s -30 = s^2 -5s

Move everything to the right

0 = s^2 -5s -12s +30

0 = s^2 -17s +30

Factor

0 = ( s-15) (s-2)

Using the zero product property

s-15 =0   s-2 =0

s =15     s=2 ( This is not a reasonable answer since it is less than the time together)

s=15

s-5 = 10

Clarissa will take 10 hours by herself

Answer:

The systems of equation for the amount spent are as follows

[tex]Y= 0.99x+5[/tex]

[tex]Y= 0.79x+10[/tex]

Step-by-step explanation:

In this problem we are expect to give a model or an equation that represents the amount of money spent per month given a fix subscription amount and a variable fee which is based on extra minutes spent.

let Y represent the amount of money spent in total for the month

The first case:

Subscription =$5

charges per minutes = $0.99

therefore the amount spent can be modeled as

[tex]Y= 0.99x+5[/tex]

The second case:

Subscription =$10

charges per minutes = $0.79

therefore the amount spent can be modeled as

[tex]Y= 0.79x+10[/tex]

the two lines are parallel, the angle they make should be equal and one angle is common so the triangles are similar by AAA.

Now the ratio of sides are [tex] \frac{20+8}{20}=\frac{x+18}{x}[/tex]

use divideno, [tex]\frac8{20}=\frac{18}x[/tex]

and then inverse the whole equation to get [tex]x=20\times\frac{18}{8} \implies x= 45[/tex]

Answer:

[tex]\Large \boxed{\mathrm{B) \ 45}}[/tex]

Step-by-step explanation:

We can solve the problem using ratios.

[tex]\displaystyle \frac{x}{20} =\frac{x+18}{20+8}[/tex]

Cross multiply.

[tex]20(x+18)=x(20+8)[/tex]

Expand brackets.

[tex]20x+360=28x[/tex]

Subtract 20x from both sides.

[tex]360=8x[/tex]

Divide both sides by 8.

[tex]45=x[/tex]

Answer:

3x^2

Step-by-step explanation:

Given:

(3x) * {(1/x)^-4 }* (x^-3)

=(3x) * {1 ÷ (1/x)^4} * {1/x^3}

=(3x) * {1(x/1)^4} * (1/x^3)

=(3x) * (x^4) * (1/x^3)

=(3x) (x^4) (1) / x^3

Multiply the denominators

=3x^5 / x^3

Can also be written as

=3*x*x*x*x*x / x*x*x

Divide the x

= 3*x*x / 1

=3x^2

Answer:

i. a = 7

ii. b = 7

iii. c = 14

Step-by-step explanation:

1. In a parallelogram, the pair of opposite sides are equal, thus;

6a + 10 = 8a -4

4 + 10 = 8a - 6a

14 = 2a

Divide both sides by 2,

a = 7

2. <SPQ + <PSR = [tex]180^{0}[/tex]

(18b - 11) + (9b + 2) =  [tex]180^{0}[/tex]

18b + 9b + 2 -11 =  [tex]180^{0}[/tex]

27b -9 =  [tex]180^{0}[/tex]

27b =  [tex]180^{0}[/tex] + [tex]9^{0}[/tex]

27b = [tex]189^{0}[/tex]

Divide both sides by 27,

b = 7

Therefore,

c = a + b

  = 7 + 7

  = 14

c = 14

Answer:

y=3

Step-by-step explanation:

Answer:

[tex] \boxed{12 \sqrt{2} }[/tex]

Step-by-step explanation:

Isosceles triangle are those triangle which have two equal sides.

Perpendicular ( p ) = 12 inches

Base ( b ) = 12 inches

Hypotenuse ( h ) = ?

Now,Using Pythagoras theorem,

[tex] \mathsf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

Plug the values

[tex] \mathsf{ {h}^{2} = {12}^{2} + {12}^{2} }[/tex]

Evaluate the power

[tex] \mathsf{ {h}^{2} = 144 + 144}[/tex]

Calculate the sum

[tex] \mathsf{ {h}^{2} = 288}[/tex]

Squaring on both sides

[tex] \mathsf{h = 12 \sqrt{2} }[/tex]

Hope I helped!

Best regards!

Answer:

0.86, 8.14

Step-by-step explanation:

Answer:

32

Step-by-step explanation:

If y is 2 times as much as x, then 1 = 2

5 x 3 = 15 + 1 = 16

10 x 3 = 30 + 2 = 32, or 16 x 2 = 32

Please tell me if I'm wrong.

Answer:  see graph

Step-by-step explanation:

Look at the Unit Circle to see the coordinates of the quadrangles.

Build a sine table for one period (0° - 360°).

    x        y = sin(x)          y² = (sin(x))²      (x, y²)    

    0°       sin(0°) = 0          (0)² = 0              (0°, 0)

   90°     sin(90°) = 1          (1)² = 1               (90°, 1)

  180°     sin(180°) = 0        (0)² = 0            (180°, 0)

  270°     sin(270°) = -1       (-1)² = 1             (270°, 1)

  360°     sin(360°) = 0       (0)² = 0            (360°, 0)

Now plot the (x, y²) coordinates on your graph.

Answer:

y = 2x + 1

Step-by-step explanation:

Given a point and the slope, we can plug in these values into the equation to find the value of b:

y = mx + b

3 = 2(1) + b

3 = 2 + b

1 = b

Plug b into the equation:

y = 2x + 1

Answer:

y = 2x + 1

Step-by-step explanation:

Answer:

1- 5xy³√5y

2- 2xy²∛3y²

Step-by-step explanation:

√125x²y^7=

√25*5x²y^6y

5xy³√5y

2) ∛24x³y^8=

∛2³*3x³y^8=

2xy²∛3y²

Answer:

Option (3)

Step-by-step explanation:

This question is not complete; here is the complete question.

Triangle A″B″C″ is formed by a reflection over y = −3 and dilation by a scale factor of 2 from the origin. Which equation shows the correct relationship between ΔABC and ΔA″B″C″?

Coordinates of the vertices of the triangle ABC are,

A(-3, 3), B(1, -3) and C(-3, -3)

When triangle ABC is reflected over y = -3

Coordinates of the image triangle A'B'C' will be.

A(-3, 3) → A'(-3, -9)

B(1, -3) → B'(1, -3)

C(-3, -3) → C'(-3, -3)

Further ΔA'B'C' is dilated by a scale factor of 2 about the origin then the new vertices of image triangle A"B"C" will be,

Rule for the dilation will be,

(x, y) → (kx, ky) [where 'k' is the scale factor]

A'(-3, -9) → A"(-6, -18)

B'(1, -3) → B"(2, -6)

C'(-3, -3) → C"(-6, -6)

Length of AB = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                      = [tex]\sqrt{(-3-1)^2+(3+3)^2}[/tex]

                      = [tex]\sqrt{52}[/tex]

                      = [tex]2\sqrt{13}[/tex]

Length of A"B" = [tex]\sqrt{(-6-2)^2+(-18+6)^2}[/tex]

                         = [tex]\sqrt{64+144}[/tex]

                         = [tex]\sqrt{208}[/tex]

                         = [tex]4\sqrt{13}[/tex]

Therefore, [tex]\frac{\text{AB}}{\text{A"B"}}=\frac{2\sqrt{13}}{4\sqrt{13}}[/tex]

[tex]\frac{\text{AB}}{\text{A"B"}}=\frac{\sqrt{13}}{2\sqrt{13}}[/tex]

[tex]AB(2\sqrt{13})=A"B"(\sqrt{13})[/tex]

Option (3) is the answer.

Answer:

x-6/2=2x/7

7x-42=4x

7x-4x=42

3x= 42

X = 42/3

Answer:

Value of F(2) = 12

Step-by-step explanation:

Given:

F(x) = 7x - 2

Find:

Value of F(2)

Computation:

F(x) = 7x - 2

putting x = 2

f(2) = 7(2) -2

f(2) = 14 - 2

f(2) = 12

So, Value of F(2) = 12

Answer:

c(1) = -15

c(n) = c(n - 1) + 4

Step-by-step explanation:

Given arithmetic sequence is,

-15, -11, -7, -3...........

Common difference between each successive and previous term is,

d = -11 - (-15)

  = -11 + 15

  = 4

Since recursive formula of the arithmetic sequence is represented by,

a₁ = First term of the sequence

a(n) = a(n - 1) + d

where a(n) is the nth term and a(n-1) is the previous term of the nth term.

Form the given sequence,

c₁ = -15

c(n) = c(n - 1) + 4

Answer:

9, 13, 17, 21

Step-by-step explanation:

If x=2,

y=1+4(2)

y=9

This goes on, like a pattern. If x increases by 1, y inreases by 4. So, if y=3, x=13. If x=4, y=17, and so on.

Answer:

215483 cm³

Step-by-step explanation:

Formula for volume of a cylinder = πr² · h

radius = 1/2diameter

1. Set up the equation

(3.14)(15²)(305)

2. Solve

215482.5

rounded to the nearest cubic centimeter = 215483 cm³

Answer:

215483 cm³

Step-by-step explanation:

credit goes to person up top

Answer:

x = 6/4, or x = 3/2, OR x = 1 1/2

Step-by-step explanation:

5x - [7 - (2x-1)] = 3(x-5) + 4(x+3)

Pick one side to work on first, I will chose the right side,

Distribute on the right side.

5x - [7 - (2x-1)] = 3x - 15 + 4x + 3

Now, add like terms on the right side.

5x - [7 - (2x-1)] = 7x - 12

Now, to isolate 7 - (2x -1), subtract 5x from both sides.

so now,

-7 - (2x-1) = 2x - 12

Now, we can add 7 to both sides of the equation to isolate -(2x-1)

we add instead of subtract because the seven is a negative.

-(2x-1) = 2x - 5

Now, there is still a negative sign in front of the (2x-1), so we distribute the - to the equation.

-2x + 1 = 2x - 5

Now, we can isolate the variable and numbers bu adding five to both sides, and adding 2 to both sides. This is to make the equation easier by removing any negative terms.

6 = 4x

Divide both sides by 4

x = 6/4, or x = 3/2, OR x = 1 1/2

Answer:

The correct option is;

Formal

Step-by-step explanation:

The common levels of diction are formal, informal, and popular, with formal diction being the most selective of the word choices

Formal diction is used when when communicating in a situation that is formal

Formal diction uses languages that is devoid of slang and grammatically correct

Formal language is precise, grammatically correct language that does not use slang used in communication for legal, professional, business and academic purposes.

Answer: "B. [tex]12p^6q^5[/tex]

Step-by-step explanation:

The given monomial : [tex]6a^2b^8c[/tex]

Degree of this monomial = Sum of powers of variables=2+8+1= 11

Let's check all the options

A   [tex]18t^8[/tex]

Degree = 8

B [tex]12p^6q^5[/tex]

Degree = 6+5 =11

C [tex]9a^5b^3c^2[/tex]

Degree = 5+3+2=10

D [tex]6w^4x^2y^3z^3[/tex]

Degree =4+2+3+3=12

We can see that only option B has degree 11.

So, the monomial has the same degree as [tex]6a^2b^8c[/tex] is "B. [tex]12p^6q^5[/tex] "

Answer:

9 small boxes and 15 large boxes

Step-by-step explanation:

x = small box

y = large box

x + y = 24

9x + 24y = 441

-9x - 9y = -216

15y = 225

y = 15

x + 15 = 24

x = 9

Answer:

Let x be the small boxes

Let y be the large boxes

x+y=24

9x+24y=441

Step-by-step explanation:

Answer:

[tex]\displaystyle \boxed{y = -1\frac{1}{3}x + 22}[/tex]

Step-by-step explanation:

Parallel Equations have SIMILAR RATE OF CHANGES [SLOPES], so keep [tex]\displaystyle -\frac{4}{3}[/tex]as is and do this:

14 = −4⁄3[6] + b

14 = −8 + b

+ 8 + 8

_________

[tex]\displaystyle 22 = b \\ \\ y = -1\frac{1}{3}x + 22[/tex]

I am joyous to assist you at any time.

Answer:

number ten: x=5

number two: x=5³/5

Step-by-step explanation:

number ten:

4x + 3x - 9 = 26

4x + 3x = 26+9

7x = 35

x = 5

number two:

3x + 2x - 8 = 20

3x + 2x = 20+8

5x = 28

x = 5³/5

The question is not complete, so i have attached it.

Answer:

Option A - The data may not be reliable because there is an outlier.

Step-by-step explanation:

Looking at the question attached and the number of the gorrila vis - a - vis the time to interact, we can see that majority of the time to interact falls between 2.5 and 3.4.

However, we have a time of 8.3 days which is for gorrila 3.

This 8.3 is far higher than the range of the other values. Thus, we have an outlier because an outlier is a value is much more smaller or larger than most of the other values in a set of given data.

Thus, the data may not be reliable because there is an outlier.

Answer:

17 quarters

Step-by-step explanation:

Let q = quarters

n = nickels

.25q + .05n = 5.90

we have 16 more nickels than quarters so add 16 quarters to make them equal

n = q+16

Substitute

.25q + .05( q+16) = 5.90

Distribute

.25q+.5q+.80=5.90

Combine like terms

.30q +.8 = 5.90

Subtract .8 from each side

.30q = 5.10

Divide each side by .3

.3q/.3 = 5.1/.3

q = 17

Answer:

Gisel have:

17

quarters

Step-by-step explanation:

1 nickel = 5 cents

1 quarter = 25 cents

1 dollar = 100 cents

5,90 dollars = 5,9*100 = 590 cents

then:

n = t + 16

5n + 25t = 590

n = quantity of nickels

t = quantity of quarters

5(t+16) + 25t = 590

5*t + 5*16 + 25t = 590

5t + 80 + 25t = 590

30 t = 590 - 80

30 t = 510

t = 510 / 30

t = 17

n = t + 16

n = 17 + 16

n = 33

Check:

5n + 25t = 590

5*33 + 25*17 = 590

165 + 425 = 590