Answer:7cm
Step-by-step explanation:
m^3=343
Take the cube root of both sides
m=7
If the mean of a symmetric distribution is 60, which of these values could be
the median of the distribution?
A. 100
B. 60
C. 80 As
D. 30
SUBMIT
Answer:
i think ...
Step-by-step explanation:
symmetric distribution usually be a bell shape distribution .
most likely the median = mean = 60
The required value of 60 could be the median of the distribution. Option B is correct.
What is mean?The mean of the values is the ratio of the total sum of values to the number of values.
What is the median?When a dataset is ordered, the median is the value that is exactly in the middle. It is a measure of central tendency that distinguishes between the lowest and top 50% of data.
Here,
The mean of a symmetric distribution is 60.
Since for the symmetric data and rational data, the mean is equal to the median,
So Mean = Median
Median = 60
Thus, the required value of 60 could be the median of the distribution.
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Talia is going to put a new carpet in her house. She measure's one side of her living room and finds it measures 17 meters which measurement does 17 meters represent
The answer in length
The length is used to measure the distance between to end points or edges. so 17 meters measurement represent the length.
What is perimeter?Its the sum of length of the sides used to made the given figure.
Talia is going to put a new carpet in her house. She measure's one side of her living room and finds it measures 17 meters.
Area is what is on the inside.
The perimeter is the outside of the hole thing.
Hence, the length is used to measure the distance between to end points or edges.
so 17 meters measurement represent the length.
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There are k students in the class. m of them are girls. How many boys are in the class? How many more boys than girls are there? HELP
Answer:
[tex]k-m=b[/tex]
[tex]b-m=diff[/tex]
Step-by-step explanation:
If there are total of k students in a class, and m of those students are girls, the total amount of boys would be:
[tex]k-m=b[/tex]
(Where k, m, b are variables that represent the total number of students, the amount of girls and the amount of boys respectively)
As the amount of girls subtracted from the total amount would leave you with the amount of boys.
There would be:
[tex]b-m[/tex] more boys than girls.
If there were 10 total students in the class and 3 of those students were girls, lets use our above equations to see if they are correct - and if we get the expected amounts of:
7 boys in the class, and 4 more boys than there are girls.
[tex]k-m=b\\10-3=7\\7=7[/tex]
This is correct, as we expected this amount.
[tex]b-m=diff\\7-3=4[/tex]
The difference between them is 4, so this is correct.
Three friends want to meet at a place that is the same distance from each of their houses. They draw a map and measure the approximate distances and angles, as shown. A triangle is labeled with Jo apostrophe s House, Boris apostrophe s House, and Carrie apostrophe s house on the points. The length from Jo to Boris is 0.5 miles, the length from Boris to Carrie is 0.4 miles, and the length from Carrie to Jo is 0.6 miles. The angle at Jo is 38 degrees. The angle at Boris is 88 degrees. The angle at Carrie is 54 degrees. Which step should they take next to find a meeting place that is the same distance from each person’s house?
Answer:
Draw perpendicular bisectors of two the sides
Step-by-step explanation:
The point that is the same distance from each of their houses is the point called the "circumcenter." It is the center of the circle that passes through the vertices of the triangle. Then each of the vertices is the same distance from the center.
The circumcenter is the intersection point of the perpendicular bisectors of the sides of the triangle. To find it, the group needs to draw perpendicular bisectors of two of the sides.
Answer:
The answer is C
Step-by-step explanation:
EDGE2020
profit 75% retail $350. what is cost at wholesale
Answer:
Step-by-step explanation:
350-75%=87.5\\so 350-87.5\\=262.5\\$262.5 dolla profit\\
Who’s good on algebra 1 ? Need help
Answer:
Which expression is equivalent to 3 over 175
I would say try - C or D
if 8% is deducted from the bill,$384 bill remains to be paid. How much is the original bill?
Answer:
$353.28
Step-by-step explanation:
Show steps how to solve for y!!!!!
2y+2=3y/2
Please help me
[tex]\text{Solve for y:}\\\\2y+2=\frac{3y}{2}\\\\\text{Multiply both sides by 2 to cancel the denominator}\\\\4y+4=3y\\\\\text{Subtract 3y from both sides}\\\\y+4=0\\\\\text{Subtract 4 from both sides}\\\\\boxed{y=-4}[/tex]
Answer:-4
Step-by-step explanation:
2y+2=3y/2
Cross multiply
2(2y+2)=3y
Open bracket
4y+4=3y
Collect like terms
4y-3y=-4
y=-4
Which of the following values of n will result in a true statement when substituted into the given equation? 4n + 9 = 1 A. n = -2 B. n = 2 C. n = 3 D. n = 4
Answer:
A. n = -2
Step-by-step explanation:
A. n = -2
4(-2) + 9 = 1
-8 + 9 = 1
1 = 1
The value of n for which the statement of equation 4n + 9 = 1 holds true is n = -2.
Given an equation:
4n + 9 = 1
There are some given options for the value of n.
It is required to find the value of n, where the statement is true.
A) When n = -2:
4n + 9 = 4(-2) + 9
= 1
B) When n = 2:
4n + 9 = 4(2) + 9
= 17
C) When n = 3:
4n + 9 = 4(3) + 9
= 21
D) When n = 4:
4n + 9 = 4(4) + 9
= 25
Hence the true statement is when n = -2.
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Ming throws a stone off a bridge into a river below.
The stone's height (in meters above the water), xxx seconds after Ming threw it, is modeled by:
h(x)=-5(x-1)^2+45h(x)=−5(x−1)
2
+45h, left parenthesis, x, right parenthesis, equals, minus, 5, left parenthesis, x, minus, 1, right parenthesis, squared, plus, 45
How many seconds after being thrown will the stone reach its maximum height?
Answer:
1 seconds after being thrown, the stone reaches its max height
Step-by-step explanation:
Answer:1 Seconds Is wrong the correct answer is 2
Step-by-step explanation:
Khan said so
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F=440(2)h/12 where h is 6
Answer:440
Step-by-step explanation:
F=440(2)h/12 h=6
F=440 x 2 x 6/12
F=(440 x 2 x 6) ➗ 12
F=5280 ➗ 12
F=440
Two tanks are interconnected. Tank A contains 60 grams of salt in 50 liters of water, and Tank B contains 80 grams of salt in 40 liters of water.
A solution of 2 gram/L flows into Tank A at a rate of 5 L/min, while a solution of 3 grams/L flows into Tank B at a rate of 7 L/min. The tanks are well mixed.
The tanks are connected, so 8 L/min flows from Tank A to Tank B, while 3 L/min flows from Tank B to Tank A. An additional 12 L/min drains from Tank B.
Letting x represent the grams of salt in Tank A, and y represent the grams of salt in Tank B, set up the system of differential equations for these two tanks.
Let a(t) and b(t) denote the amounts of salt in tanks A and B, respectively.
The volume of liquid in tanks A and B after t minutes are
A: 50 L + (5 L/min + 3 L/min - 8 L/min)t = 50 L
B: 40 L + (7 L/min + 8 L/min - 3 L/min - 12 L/min)t = 40 L
so the amount of solution in the tanks stays constant.
Salt flows into tank A at a rate of
(2 g/L)*(5 L/min) + (b(t)/40 g/L)*(3 L/min) = (10 + 3/40 b(t)) g/min
and out at a rate of
(a(t)/50 g/L)*(8 L/min) = 4/25 a(t) g/min
so the net flow rate is given by the differential equation
[tex]\dfrac{\mathrm da(t)}{\mathrm dt}=10+\dfrac{3b(t)}{40}-\dfrac{4a(t)}{25}[/tex]
We do the same for tank B: salt flows in at a rate of
(3 g/L)*(7 L/min) + (a(t)/50 g/L)*(8 L/min) = (21 + 4/25 a(t)) g/min
and out at a rate of
(b(t)/40 g/L)*(3 L/min + 12 L/min) = 3/8 b(t) g/min
and hence with a net rate of
[tex]\dfrac{\mathrm db(t)}{\mathrm dt}=21+\dfrac{4a(t)}{25}-\dfrac{3b(t)}8[/tex]
Replace a(t) and b(t) with x and y. Then the system is (in matrix form)
[tex]\dfrac{\mathrm d}{\mathrm dt}\begin{bmatrix}x\\y\end{bmatrix}=\dfrac1{200}\begin{bmatrix}-32&15\\32&-75\end{bmatrix}\begin{bmatrix}x\\y\end{bmatrix}+\begin{bmatrix}10\\21\end{bmatrix}[/tex]
with initial conditions x(0) = 60 g and y(0) = 80 g.
Determine the value of x for the triangle. show work.
Answer:
x=5
Step-by-step explanation:
x, x+7, x+8 must be a Pythagorean triple for it to make a right triangle. The only Pythagorean triple fitting these numbers is 5, 12, 13 so x must be 5.
Answer:
5
Step-by-step explanation:
Because this is a right triangle, you know that by the Pythagorean theorem:[tex]\sqrt{(x+7)^2+x^2}=x+8[/tex]
Squaring both sides to get rid of the square root:
[tex](x+7)^2+x^2=(x+8)^2[/tex]
Expanding all of the parentheses:
[tex]x^2+14x+49+x^2=x^2+16x+64[/tex]
Combine like terms:
[tex]x^2-2x-15=0[/tex]
Factor:
[tex](x-5)(x+3)=0[/tex]
Since x cannot be negative, it is equal to 5. Hope this helps!
Hi guys, Can anyone help me with this tripple integral? Thank you:)
I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.
We have to turn K into the limits of integration on our integrals.
Clearly 0 is the lower limit for all three of x, y and z.
Now we have to incorporate
x+y+z ≤ 1
Let's do the outer integral over x. It can go the full range from 0 to 1 without violating the constraint. So the upper limit on the outer integral is 1.
Next integral is over y. y ≤ 1-x-z. We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y. So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.
Similarly the inner integral goes from z=0 to z=1-x-y
We've transformed our integral into the more tractable
[tex]\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx[/tex]
For the inner integral we get to treat x like a constant.
[tex]\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3[/tex]
Let's expand that as a polynomial in y for the next integration,
[tex]= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3[/tex]
The middle integration is
[tex]\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy[/tex]
[tex]= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x} [/tex]
[tex]= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3[/tex]
Expanding, that's
[tex]=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)[/tex]
so our outer integral is
[tex]\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx[/tex]
That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).
[tex]= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12[/tex]
[tex]=0[/tex]
That's a surprise. You might want to check it.
Answer: 0
jared buts 2.4 pounds of broccoli for $3.24 which equation could jared use to find c, the cost of each pound of broccoli
Answer:
2.4c = 3.24
Step-by-step explanation:
Answer:
it is 4 ounces + 18 ounces
If the fish tanks dimension are 60 by 15 by 34 and its is completely empty, what volume of water is needed to fill three fourths of the aquarium? Please help
Answer:
22,950 units³
Step-by-step explanation:
All you have to do is:
[tex]\frac{3}{4} *60*15*34=\\45*15*34=\\675*34=\\\\22,950[/tex]
−7×8=?????????????????????????
Answer
the answer is -56
Step-by-step explanation:
Sean tossed a coin off a bridge into the stream below. The path of the coin can be represented by the equation h = -16t2 + 72t + 100. How long will it take the coin to reach the stream?
Answer:
about 5.613 seconds
Step-by-step explanation:
Using the quadratic formula to find the value of t when h = 0, we have ...
at² +bt +c = 0
t = (-b±√(b²-4ac))/(2a)
t = (-72±√(72² -4(-16)(100)))/(2(-16))
t = (-72±√11584)/-32 = (9±√181)/4
Only the positive value of t is of interest.
The coin will hit the stream after (9+√181)/4 seconds ≈ 5.613 seconds.
In ΔPQR, the measure of ∠R=90°, RP = 9.9 feet, and QR = 3.2 feet. Find the measure of ∠P to the nearest tenth of a degree.
Answer:
17.9
Step-by-step explanation:
The senior classes at Snellville High and General High planned separate trips to the water park. The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students. General High rented and filled 14 vans and 12 buses with 738 students. How many students would fill 2 buses and 3 vans?
Answer:
133 Students
Step-by-step explanation:
Let the number of student in a van=v
Let the number of student in a bus=b
The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students.
Therefore: 12v+14b=796
General High rented and filled 14 vans and 12 buses with 738 students.
Therefore: 14v+12b=738
We solve the two resulting equations simultaneously
12v+14b=796
14v+12b=738
Multiply equation 1 by 12 and equation 2 by 14 to eliminate b
144v+168b=9552
196v+168b=10332
Subtract
-52v=-780
Divide both sides by -52
v=15
We substitute v=15 to obtain b in any of the equations
12v+14b=796
12(15)+14b=796
14b=796-180
14b=616
Divide both sides by 14
b=44
Therefore a bus contains 44 Students and a Van contains 15 students.
Number of Students who would fill 2 buses and 3 vans
=2b+3v
=2(44)+3(15)
=133 Students
Matt says 3/3 is equivalent to 1 is he correct?
Answer: Yes
Step-by-step explanation:
It isn't an
1 an improper fraction
Less than the denominator
Therefore, three thirds or 3/3 is one whole fraction
Rly hope I helped!
☆꧁Ashlin꧂☆
Answer:yes he his correct
Step-by-step explanation:
3/3=1
What type of lines are shown?
Answer:
the angle is acute angle
Answer:
The type of angle shown is an acute angle
Step-by-step explanation:
there are 4 main types of angles. this is an acute angle as it is less than 90°.
Types of angles:
The 4 main types of angles are: acute, obtuse, right angles, reflex angles.
Acute angles- Acute angles are angles less than 90°.
Obtuse Angles-Obtuse angles are angles greater than 90° but less than 180°.
Right Angles- Right angles are angles of 90°.
Reflex Angles- Reflex angles are angles greater than 180° but less than 360°.
Write the fraction from least to greatest: 1/8, 1/3, 1/8
Answer:
Start with making them equal.
1/8 --> 3/24
1/8 --> 3/24
1/3 --> 8/24
Now order them.
1/8, 1/8, 1/3.
Hope this helps ;)
Choose the property of addition. ( 5 + 3 ) + 8 = 5 + ( 3 + ? )
A. associate property of addition
B. Commutative property of addition
C. Distributive property
D. Identity property of addition
Answer:
A. associative property of addition
Step-by-step explanation:
Associative because you can add or multiply those regardless of how the numbers are grouped.
I hope this helped and have a good rest of your day!
Answer:
Associative Property of Addition
Step-by-step explanation:
This property states that the sum of 3 or more numbers stays the same, no matter how they are grouped.
Hope this helped. Have an awesome day!
A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of
adults. There are half as many adults as there are children. If the total ticket sales was $ 2808, How many children,
students, and adults attended?
Answer:
The attendance was 198 children, 90 students and 99 adults.
Step-by-step explanation:
We define:
c: children attendance
s: students attendance
a: adult attendance
The equation that describes the total ticket sales is:
[tex]5c+7s+12a=2808[/tex]
We also know that the children attendance doubles the adult attendance:
[tex]c=2a[/tex]
The third equation is the seating capacity, which we assume is full:
[tex]c+s+a=387[/tex]
We start by replacing variables in two of the equations:
[tex]c=2a\\\\s=387-c-a=387-2a-a=387-3a[/tex]
Then, we solve the remaining equation for a:
[tex]5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99[/tex]
Then, we solve for the other two equations:
[tex]c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90[/tex]
The attendance was 198 children, 90 students and 99 adults.
Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead. Exceptions are allowed, but they want the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages. (a-1) Find the test statistic. (Round your answer to 4 decimal places.) The test statistic (a-2) At the .01 level of significance, is the true mean greater than 10
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ ≤ 10
For the alternative hypothesis,
µ > 10
The inequality sign indicates that It is a right tailed.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 35,
Degrees of freedom, df = n - 1 = 35 - 1 = 34
t = (x - µ)/(s/√n)
Where
x = sample mean = 14.44
µ = population mean = 10
s = samples standard deviation = 4.45
t = (14.44 - 10)/(4.45/√35) = 5.9
We would determine the p value using the t test calculator. It becomes
p < 0.00001
Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, At a 1% level of significance, we can conclude that the true mean is greater than 10.
If three points of a parallelogram are A (-5, -2), B (1,5), C (7.1). Which of the
following is the fourth point D of parallelogram ABCD?
(13,8)
(13.-6)
(1. -2)
(1,-6)
Choose the equation that best fits the following graph.
Answer:
c. y = 3.25^x
Step-by-step explanation:
At x=1, the value of y is slightly more than 3, so the base must be more than 3. The appropriate choice is ...
y = 3.25^x
Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular threat to shrubs in dry climates, as it can injure the roots as well as destroy the aboveground material. One study of resprouting took place in a dry area of Mexico. The investigation clipped the tops of samples of several species of shrubs. In some cases, they also applied a propane torch to the stumps to simulate a fire. Of 19 specimens of a particular species, 6 resprouted after fire. Estimate with 96% confidence the proportion of all shrubs of this species that will resprout after fire. Interval: .1884 to
The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.
Here, we have,
To estimate the proportion of all shrubs of this species that will resprout after fire with 96% confidence, we will use the formula for a confidence interval for a proportion.
The formula for the confidence interval for a proportion (p) is given by:
CI = p ± Z * √(p * (1 - p) / n)
where:
CI is the confidence interval
p is the sample proportion (resprouted specimens / total specimens)
Z is the critical Z-score corresponding to the desired confidence level (96% confidence level corresponds to a Z-score of approximately 1.750)
n is the sample size (total number of specimens)
Given information:
Total number of specimens (n) = 19
Number of specimens that resprouted after fire = 6
Now, calculate the sample proportion (p):
p = (number of specimens that resprouted) / (total number of specimens)
p = 6 / 19 ≈ 0.3158 (rounded to four decimal places)
Now, calculate the critical Z-score for a 96% confidence level (use a Z-table or calculator):
Z ≈ 1.750
Now, calculate the margin of error (E):
E = Z * √(p * (1 - p) / n)
E = 1.750 * √(0.3158 * (1 - 0.3158) / 19)
E ≈ 0.1884 (rounded to four decimal places)
Finally, calculate the confidence interval:
CI = p ± E
CI = 0.3158 ± 0.1884
The 96% confidence interval for the proportion of all shrubs of this species that will resprout after fire is approximately 0.1274 to 0.5042.
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The MIT soccer team has 2 games scheduled for one weekend. It has a 0.4 probability of not losing the first game. and a 0.7 probability of not losing the second game, independent of the first. If it does not lose a particular game, the team is equally likely to win or tie. independent of what happens in the other game. The MIT team will receive 2 points for a win, 1 for a tie. and 0 for a loss. Find the PMF of the number of points that the team earns over the weekend.
Answer:
Step-by-step explanation:
To determine the PMF of the points that the team receive, we must determine the probabilities of winning each of the games.
Consider the firt game. We know that the probability of not losing is 0.4. Since the team can either lose the game or not, we have that the probability of losing it is 0.6. We are told that given that the team does not lose, the probability of winning or having a tie is the same. Recall that, given events A, B, the conditional probability P(A|B) (which means probability of A given B) is given as
[tex]P(A|B) = \frac{P(A\cap B)}{P(B)}[/tex]
in our case, we have that B:= not losing the game. Consider A:= To win the game, C:= To tie the game. We know that P(A|B)=P(C|B). When the team doesn't lose, then the team either ties or wins, this means that
[tex]P(A|B)+P(C|B) = 1[/tex]
So we get that P(A|B) = P(C|B) = 1/2. Let us find P(A)
[tex]P(A|B) = \frac{P(A\cap B)}{P(B)} = \frac{P(A)}{P(B)}=\frac{1}{2}[/tex]
Then [tex]P(A) = \frac{P(B)}{2} = 0.2[/tex]. By an analogous calculation we have that P(A) = P(C) = 0.2.
We will define the following events: [tex]W_i[/tex] is the event that the team wins the game i, [tex]T_i[/tex] is the event that the team ties the game i and [tex]L_i[/tex] is the event that the team loses the game i. In this notation, we have that
[tex]P(W_1) = P(T_1) = 0.2, P(L_1) = 0.6[/tex]
By reasoning the same way for the second game, we can calculate that
[tex]P(W_2)=P(T_2)=0.35, P(L_2) = 0.3[/tex]
To calculate the PMF we must check all the possible outcomes of the results of both games. Since we can either win (W), tie(T) or lose(L) a game, we will express the outcome as follows TW(3) means that the team ties the first game and wins the second one, for a total of points. In this way, the possible outcomes are
WW(4), WT(3), WL(2), TW(3), TT(2), TL(1), LW(2), LT(1), LL(0)
We see that the number of possible points are 0,1,2,3,4. Let X be the number of points, to get the pmf of X is to give the probability P(X=k) for k=0,1,2,3,4 explicitly. Note that since each game is independent of each other, to get the probability of one of the outcomes it suffices to multiply the probability of each event. For example we have that [tex]P(WW) = P(W_1)\cdotP(W_2) = 0.07[/tex]
Then, the pmf is given by
[tex]P(X=0) = P(LL) = 0.18[/tex]
[tex]P(X=1)=P(LT)+P(TL) = 0.27[/tex]
[tex]P(X=2)=P(LW)+P(TT)+P(WL) = 0.34[/tex]
[tex]P(X=3)=P(WT)+P(TW) = 0.14[/tex]
[tex]P(X=4)=P(WW)= 0.07[/tex]
