Answer:
35x^2 - 28x - 7
Step-by-step explanation:
The length of a shoe is 25 centimeters. How long is the shoe in meters? (Note: 1 meter = 100 centimeters). pls help
Answer:
0.25meters
As 100cm=1metre
so, 25cm=25/100meter
=0.25metre
Step-by-step explanation:
If you like my answer than please mark me brainliest
The answer is 0.25 meters
I need you guy’s help answer thanks so much
Answer:
(c) (f-g ) (x) = 6x*3 -2x*2 +4x -8
anyone know the answers for the final exam for part one of algebra 2 on edg?
Answer:
just show the questions i will help
Step-by-step explanation:
9.03 divided by 899.8 is closest to? a.0.01 b.0.001 c.1 d.100
9.03 divided by 899.8 is closest to a.0.01
Answer: a) 0.01
Step-by-step explanation:
What is the approximate value of log b to the nearest hundredth? 0.93 1.23 9.16 65.53
Answer:
1.23
Step-by-step explanation:
2.5 cm in the ratio of 1:500000
Answer:
1250000cm
Step-by-step explanation:
1:500000
1x2.5 : 500000x2.5
2.5:1250000
Which condition must exist in order for conduction to occur between two substances? The molecules of the substances must be touching. Both substances must be the same temperature. At least one substance must be a liquid. Most of the molecules must be slow moving.
Answer:
The molecules of the substances must be touching
FOR EXAMPLE, a metal spoon placed in a hot coffee mug shows the flow of heat from coffee to the spoon. and now we can conclude that a condition that must exist in order for conduction to occur between two substances is that the objects must be touching each other.
Answer:
The molecules of the substances must be touching.
A
Step-by-step explanation:
1) Seven less than twice a number, n, is 32.
A. 7 - 2n = 32
B. 2n - 7 = 32
C. 7-n=2.32
D. (n - 7). 2 = 32
1) Seven less than twice a number, n, is 32.
ANS) B. 2n - 7 = 32
Answer:
1.
B. 2n - 7 = 32 is the right answer
Graph the function g(x) = 3^x + 3 and give its domain and range using interval notation
The question is an illustration of a function using graphs. When a function is plotted on a graph, the x-axis represents the domain, while the y-axis represents the range of the function.
The domain and the range of the given function are:
Domain: [tex](-\infty,\infty)[/tex]
Range: [tex](3,\infty)[/tex]
From the question, we have the function to be:
[tex]g(x) = 3^x + 3[/tex]
First, we plot the graph of g(x)
To do this, we first generate values for x and g(x). The table is generated as follows:
[tex]x = 0 \to g(0) = 3^0 + 3 = 4[/tex]
[tex]x = 1 \to g(1) = 3^1 + 3 = 6[/tex]
[tex]x = 2 \to g(2) = 3^2 + 3 = 12[/tex]
[tex]x = 3 \to g(3) = 3^3 + 3 = 30[/tex]
[tex]x = 4 \to g(4) = 3^4 + 3 = 84[/tex]
In a tabular form, we have the following pair of values
[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ g(x) & {4} & {6} & {12} & {30} & {84} \ \end{array}[/tex]
See attachment for graph
From the attached graph of g(x), we can observe that the curve stretches through the x-axis and there are no visible endpoints.
This means that the curve starts from - infinity to +infinity
Hence, the domain is: [tex](-\infty,\infty)[/tex]
Also, from the same graph, we can observe that the curve of g(x) starts at y = 3 on the y-axis and the curve faces upward direction.
This means that the curve of g(x) is greater than 3 on the y-axis.
Hence, the range is: [tex](3,\infty)[/tex]
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1. Find the 4th term for the sequence with formula tn= n² + 1
Answer:
17
Step-by-step explanation:
T4 = 4² + 1
T4 = 4² + 1 = 17
Yip yip that's all
The object of a popular carnival game is to roll a ball up an incline into regions with different
values. The probability that Angus will get 100 points in a roll is 40%, 200 points is 35%, and
300 points is 25%. Find the expected value, E(X), of a roll.
O 185
O 200
O 400
O 150
The expected value, E(x) of the given observation is 185
The expected value is the mean of the overall observed value or random value. In other words, it is the average of the observed values.
The given parameters can be represented as:
[tex]\begin{array}{cccc}x & {100} & {200} & {300} \ \\ P(x) & {40\%} & {35\%} & {25\%} \ \end{array}[/tex]
The following formula calculates the expected value:
[tex]E(x) =\sum x * P(x)[/tex]
So, we have:
[tex]E(x) = 100 * 40\% + 200 * 35\% + 300 * 25\%[/tex]
[tex]E(x) = 40 + 70 + 75[/tex]
[tex]E(x) = 185[/tex]
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Which graph represents the function f(x) = x-2?
Answer:
click in photo
nejdjjd
nxndjdbbdjf
lấy x=0 ta có y= -2 => A(0;-2)
lấy y=0 ta có x=2 => B(2;0)
nối 2 điểm A và B ta có đồ thị:
Help please this is due today
9514 1404 393
Answer:
the correct choice is marked
Step-by-step explanation:
The end behavior matches that of an odd-degree polynomial. The only function shown that has that behavior is the one marked:
[tex]f(x)=\dfrac{x^2-36}{x-6}=\dfrac{(x+6)(x-6)}{(x-6)}=x+6\qquad x\ne6[/tex]
__
Additional comment
The other functions have horizontal (not slant) asymptotes, so do not have the described end behavior.
B: y=0
C, D: y=1
Please help im new and i need help!
Please help me if you onlw the answers please!!
9514 1404 393
Answer:
a) 2.038 seconds
b) 5.918 meters
c) 1.076 seconds
Step-by-step explanation:
For the purpose of answering these questions, it is convenient to put the given equation into vertex form.
h = -4.9t² +9.2t +1.6
= -4.9(t² -(9.2/4.9)t) +1.6
= -4.9(t² -(9.2/4.9)t +(4.6/4.9)²) +1.6 +4.9(4.6/4.9)²
= -4.9(t -46/49)² +290/49
__
a) To find h = 0, we solve ...
0 = -4.9(t -46/49)² +290/49
290/240.1 = (t -46/49)² . . . . subtract 290/49 and divide by -4.9
√(2900/2401) +46/49 = t ≈ 2.0378 . . . . seconds
The ball takes about 2.038 seconds to fall to the ground.
__
b) The maximum height is the h value at the vertex of the function. It is the value of h when the squared term is zero:
290/49 m ≈ 5.918 m
The maximum height of the ball is about 5.918 m.
__
c) We want to find t for h ≥ 4.5.
h ≥ 4.5
-4.9(t -46/49)² +290/49 ≥ 4.5
Subtracting 290/49 and dividing by -4.9, we have ...
(t -46/49)² ≥ 695/2401
Taking the square root, and adding 46/49, we find the time interval to be ...
-√(695/2401) +46/49 ≤ t ≤ √(695/2401) +46/49
The difference between the interval end points is the time above 4.5 meters. That difference is ...
2√(695/2401) ≈ 1.076 . . . . seconds
The ball is at or above 4.5 meters for about 1.076 seconds.
__
I like a graphing calculator for its ability to answer these questions quickly and easily. The essentials for answering this question involve typing a couple of equations and highlighting a few points on the graph.
_____
Additional comment
I have a preference for "exact" answers where possible, so have used fractions, rather than their rounded decimal equivalents. The calculator I use deals with these fairly nicely. Unfortunately, the mess of numbers can tend to obscure the working.
"Vertex form" for a quadratic is ...
y = a(x -h)² +k . . . . where the vertex is (h, k) and 'a' is a vertical scale factor.
In the above, we have 'a' = -4.9, and (h, k) = (46/49, 290/49) ≈ (0.939, 5.918)
Write an expression for the baseball team’s Purchase.
When multiplying by 10 how many spaces do you move the decimal point
Answer:
If you multiply a decimal by 10, the decimal point will move one place to the right. If you divide a decimal by 10, the decimal point will move one place to the left.
Step-by-step explanation:
Multiplying a decimal by 10 increases the value of each digit by 10. Multiplying a decimal by a power of 10 increases the value of each digit by a number of times that is equivalent to that power of 10. When a digit's value is changed, that digit is moved to the appropriate place.
First make a substitution and then use integration by parts to evaluate the integral. integral t^11 e^-t^6 dt + C
It looks like you want to find
[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt[/tex]
Substitute u = -t ⁶ and du = -6t ⁵ dt. Then
[tex]\displaystyle \int t^{11} e^{-t^6}\,\mathrm dt = \frac16 \int (-6t^5) \times (-t^6) e^{-t^6}\,\mathrm dt = \frac16 \int ue^u \,\mathrm du[/tex]
Integrate by parts, taking
f = u ==> df = du
dg = eᵘ du ==> g = eᵘ
Then
[tex]\displaystyle \frac16 \int ue^u \,\mathrm du = \frac16\left(fg-\int g\,\mathrm df\right) \\\\ =\frac16 ue^u - \frac16\int e^u\,\mathrm du \\\\ =\frac16 ue^u - \frac16 e^u + C \\\\ =-\frac16 t^6 e^{-t^6} - \frac16 e^{-t^6} + C \\\\ =\boxed{-\frac16 e^{-t^6} \left(t^6+1\right) + C}[/tex]
WILL GIVE BRAINIEST PLEASE WRITE IN ''f(x) = a(b)^x'' ORDERAn industrial copy machine has the ability to reduce image dimensions by a certain percentage each time it copies. A design began with a length of 16 inches, represented by the point (0,16). After going through the copy machine once, the length is 12, represented by the point (1,12).
Answer:
f(x) = 16*0.75^x
Step-by-step explanation:
first off let's use this coordinate (the one given) :
(0,16)
let's substitute this into the equation with x being 0 and f(x) being 16
16 = a*b^0
*anything to the power of 0 is 1*
so:
a = 16
now use the second coordinate :
(1,12)
and do the same by substituting 1 for x and 12 for f(x), we also know what 'a' is:
12 = 16*b^1
12 = 16 * b
b = 3/4
so :
f(x) = 16*0.75^x
Answer:
f(x) = 16(.75)^x
Step-by-step explanation:
90units needed 8 units per case what's the #of cases & # of additional units
Answer:
# of cases: 11
Additional units: 2
Step-by-step explanation:
If each case can hold 8 units, and we want to find the total # number of cases, we have to divide the # of units (8) for one case by the total # units (90).
As you can see, after dividing by 8, we have a total of 11 cases and a remainder of 2 units. The remainder will be the # of additional units because we cannot have another case filled with 8 units.
Solve for x^2=-25
Please help me
Answer:
Step-by-step explanation:
This is not possible over the real numbers system. You cannot take the square root of a negative number without ending up with imaginary solutions.
[tex]x^2=-25[/tex] and
[tex]x=\sqrt{-25}[/tex] In the world of imaginary numbers, the 2 solutions would be
x = 5i and x = -5i
Answer:
It should be x=5i-5i
Step-by-step explanation:
Two solutions of the equation Ax+By = 1 are (2, -1) and (-3,-2). Find A and B.
Answer:
Substitute in the values of both given coordinates & form 2 equations:
[tex]\left \{ {{A(2)+B(-1)=1} \atop {A(-3)+B(-2)=1}} \right. \\\\=\left \{ {{2A-B=1} \atop {-3A-2B=1}} \right.[/tex]
Find the value of B from the equation 2A - B = 1:
[tex]2A-B=1\\-B=1-2A\\B=2A-1[/tex]
Substitute in the B-value to the other equation:
[tex]-3A-2B=1\\-3A-2(2A-1)=1\\-3A-4A+2=1\\-7A=1-2\\-7A=-1\\A=\frac{-1}{-7} =\frac{1}{7}[/tex]
Find the B-value using the equation from before:
[tex]B=2A-1=2(\frac{1}{7})-1=\frac{2}{7} -\frac{7}{7} =-\frac{5}{7}[/tex]
Therefore the equation Ax + By = 1 would equal:
[tex]\frac{1}{7} x-\frac{5}{7} y=1[/tex]
A=7x^2-3x+10 B=-4x^2+6x-4
A-B=
Step-by-step explanation:
A-B
=7x-6x/2 +10) - (-2x +6x-4)
=x/2+10- 4x+4
= x-8x /2 +14
=-7x/2+14
Please help with step by step.
what is the area of the parallelogram?
Which point should be removed for the graph to represent a table of equivalent ratios?
A. (2, 10)
B. (3, 15)
C. (4, 20)
D. (5, 15)
===========================================================
Explanation:
As the graph shows, three of the four points are on the same line. That line being y = 5x. This line has slope 5 and y intercept 0.
The point not fitting this pattern is the point (5,15), so that is the final answer.
For the other three points, note that the jump from x to y coordinate is "times 5". For example, y = 5x = 5*2 = 10 for point A. In contrast, point D has a jump of "times 3" when going from x to y.
--------------
Alternatively, you can divide each y coordinate by its corresponding x coordinate.
For choice A, we have y/x = 10/2 = 5Choice B has y/x = 15/3 = 5Choice C has y/x = 20/4 = 5All results are 5 so far. Choice D doesn't follow the trend and instead has y/x = 15/5 = 3. This is another way to show that choice D is the answer.
Answer:
D
Step-by-step explanation:
i need help on 8-9 plss :))
Answer:
8. SU = 24
9. TU = 16√3
Step-by-step explanation:
Recall: SOH CAH TOA
8. Reference angle (θ) = 30°
Opposite = 8√3
Adjacent = SU
Apply TOA,
Tan θ = Opp/Adj
Substitute
Tan 30° = 8√3/SU
Tan 30° × SU = 8√3
SU = 8√3/Tan 30°
SU = 8√3/(1/√3) (tan 30° = 1/√3)
SU = 8√3*√3/1
SU = 8*3
SU = 24
9. Reference angle (θ) = 30°
Opposite = 8√3
Hypotenuse = TU
Apply SOH,
Sin θ = Opp/Hyp
Substitute
Sin 30° = 8√3/TU
Sin 30° × TU = 8√3
TU = 8√3/sin 30°
TU = 8√3/(½) (sin 30° = ½)
TU = 8√3 × 2/1
TU = 16√3
90./04/ (C) 98.7877 TD) (D) 98.7777 12. If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter is: (A) 13 cm (B) 17 cm (C) 27 cm (D) 30 cm 3. An article is purchased for 7,500 and sold for 8,400. The profit percent is : (A) 8% (B) 10%
Answer:
1) D - 30 cm 2) 12 percents
Step-by-step explanation:
The first question was If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter is: (A) 13 cm (B) 17 cm (C) 27 cm (D) 30 cm
two perpendicular sides are legs, find the hipotenuse of the triangle
It is equal to sqrt(5^2+12^2)= sqrt169=13
5+12+13=30 - D - the perimeter
The second question
7500 -100 percents
8400- x
7500/8400=100/x
75/84=100/x
(25/28)*x=100
(1/28)*x=4
x=4/(1/28)= 4*28= 112 percents
The profit is 12 percents
2) Option D is correct. If two perpendicular sides of a right-angled triangle are 5 cm and 12 cm, its perimeter will be 30cm.
3) None of the given options are correct. If an article is purchased for 7,500 and sold for 8,400, the profit percentage will be 12%
2) A right-angled triangle is a triangle with three sides and one of its angles is 90degrees. Find the image of a right-angled triangle attached below.
The triangle consists of 3 sides which are:
The opposite sideThe adjacent sideThe hypotenuse sideBefore we can get the perimeter of the right triangle, we need to get the third side first (the hypotenuse side) using the Pythagoras theorem. According to the theorem:
[tex]c^2=a^2+b^2[/tex]
Given
a = 5 cm
b =12 cm
[tex]c^2=5^2+12^2\\c^2=25+144\\c^2=169\\c=\sqrt{169}\\c=13 cm[/tex]
Perimeter of the right triangle = a + b + c
Perimeter of the right triangle = 5 cm + 12 cm + 13 cm
Perimeter of the right triangle = 30 cm
Hence the perimeter of the right triangle is 30 cm.
3) If an article is purchased for 7,500, then;
Cost price (C.P) = 7,500If the same article is sold for 8,400, then:
Selling price (S.P) = 8,400[tex]\% profit=\frac{SP-CP}{CP} \times 100[/tex]
Substitute the given parameters
[tex]\% profit=\frac{8400-7500}{7500} \times 100\\\%profit=\frac{900}{7500} \times 100 \\\%profit=\frac{900}{75}\\\% profit = 12 \%[/tex]
This shows that the profit percent is 12%
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the ordered pairs belonging to the relation
S = {(x, y): 2x = 3y}
Answer:
{(0, 0), (1, ⅔), (2, 4/3), (3, 2)…}
Start with the number 2380.
Divide by 10,
The 8 will end up in the _____ place.
The 8 will end up in the "ones place".
How can we interpret the division?When 'a' is divided by 'b', then the result we get from the division is the part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.
We need to find the 8 will end up in which place
A negative divided by a negative is positive, then;
2380/ 10 = 238
Therefore, The 8 will end up in the _ ones_ place.
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#SPJ2
Calculate the minimum number of subjects needed for a research study regarding the proportion of respondents who reported a history of diabetes using the following criteria:
95% confidence, within 5 percentage points, and a previous estimate is not known.
Answer:
The minimum number of subjects needed is 385.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
95% confidence, within 5 percentage points, and a previous estimate is not known.
The sample size is n for which M = 0.05. We don't know the true proportion, so we use [tex]\pi = 0.5[/tex]
Then
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}[/tex]
[tex]0.05\sqrt{n} = 1.96*0.5[/tex]
[tex]\sqrt{n} = \frac{1.96*0.5}{0.05}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*0.5}{0.05})^2[/tex]
[tex]n = 384.16[/tex]
Rounding up:
The minimum number of subjects needed is 385.
