A different group is worried that the motion detector will not
effectively track the falling object, so they decide to roll a round
object down a ramp instead of dropping it. They measure the initial
height to calculate gravitational potential energy, use the motion
detector to track the final velocity, and calculate the kinetic energy of
the object at the end.
Despite all their careful measurements, it appears that energy is not
conserved! The object is not moving as fast at the bottom as the
initial gravitational potential would have led them to predict. Which
of the following suggestions is possible? Select all that apply.

Answers

Answer 1

The energy is not  conserved because:

1. Energy may still be leaving the system through friction.

2. There could be measurement error that account for the missing energy

Given that a different group roll a round  object down a ramp instead of dropping it. They measure the initial  height to calculate gravitational potential energy, use the motion  detector to track the final velocity, and calculate the kinetic energy of  the object at the end.

Despite all their careful measurements, it appears that energy is not

conserved because

1. Energy may still be leaving the system through friction. In which the energy lost will be converted to thermal energy

2. There could be measurement error that account for the missing energy. The may occur due to systematic error or parallax error

The object is not moving as fast at the bottom as the initial gravitational potential would have led them to predict. This is not as a result of rotational energy. There is nothing like rotational energy.

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Related Questions

Why are theories excepted as true

Answers

Answer:

A theory not only explains known facts; it also allows scientists to make predictions of what they should observe if a theory is true. Scientific theories are testable. New evidence should be compatible with a theory. If it isn't, the theory is refined or rejected.

Explanation:

Please mark as brainliest! Thanks!

i need help guys please how to do it

Answers

Answering your question but a bit confusing lovesur

The drag force due to air resistance on a soccer ball traveling through the air at 20 m/s is 2.3 N. What is the drag force on that same soccer ball when it is moving through the air at 35.4 m/s

Answers

The drag force on that same soccer ball when it is moving through the air at [tex]35.4 m/s[/tex] is 7.2 Newton.

Given the data in the question;

Initial speed; [tex]v_1 = 20m/s[/tex]Initial drag force; [tex]F_1 = 2.3N[/tex]Final speed; [tex]v_2 = 35.4m/s[/tex]

Final drag force; [tex]F_2 =\ ?[/tex]

From Newton's laws, Drag force is directly proportional to velocity squared:

[tex]F\ \alpha \ v^2 \\\\F = Kv^2[/tex]

Where k is the constant of proportionality.

Hence;

[tex]\frac{F_1}{F_2} = \frac{V_1^2}{V_2^2}[/tex]

We make "[tex]F_2[/tex]" the subject of the formula

[tex]F_2 = \frac{F_1 * v_2^2}{v_1^2}[/tex]

We substitute our values into the equation;

[tex]F_2 = \frac{2.3N * (35.4m/s)^2}{(20m/s)^2}\\\\F_2 = \frac{2.3N * 1253.16}{400} \\\\F_2 = \frac{2882.268N}{400}\\\\F_2 = 7.2N[/tex]

Therefore, the drag force on that same soccer ball when it is moving through the air at [tex]35.4 m/s[/tex] is 7.2 Newton.

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How long does Sun remain in one zodiac?

(A) 1 year (B) 1 month (C) 1 week (D) 1 day​

Answers

A. The sun takes a year to complete a zodiac cycle

Answer:  (B) 1 month

Brainliest if correct pls!

100 POINTS PLEASE HELP You push on a box with 50N to the right, your friend decides to be difficult and pushes against you with 15N. There is also friction between the box and ground that is making your job harder. The friction is 6N in total and the box has a mass of 8kg 1. Draw a free body diagram and put in the essay box using the insert media button 2. Find acceleration of the box 3. bonus - what is the coefficient of friction between the box and the ground

Answers

Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:

1. See attachment to this answer

2. a = 3.63 m/[tex]s^{2}[/tex]

3. μ = 0.36

Friction is an oppositional force between the surfaces of two bodies in contact, and tries to limit the motion of one body over the other. It is dependent on the nature of the surfaces in contact.

From the given question;

1. The free body diagram for this question is herewith attached to this answer.

Given that: [tex]F_{1}[/tex] = 50 N, [tex]F_{2}[/tex] = 15 N, [tex]F_{3}[/tex] = 6 N, and m = 8 kg.

2. The acceleration of the body can be determined by:

F = ma

where F is the total force acting on the body, m is the mass of the body and a is its acceleration.

So that;

a = [tex]\frac{F}{m}[/tex]

The total force on the body is;

F = [tex]F_{1}[/tex] - ([tex]F_{2}[/tex] + [tex]F_{3}[/tex])

  = 50 - (15 + 6)

  = 50 - 21

F = 29 N

Then;

a = [tex]\frac{29}{8}[/tex]

  = 3.625

a = 3.63 m/[tex]s^{2}[/tex]

The acceleration of the body is 3.63 m/[tex]s^{2}[/tex].

3. The coefficient of limiting friction (μ) between the surfaces is:

μ = [tex]\frac{Force}{Reaction}[/tex]

Force = 29 N

Reaction = mg

               = 8 x 10

               = 80 N

μ = [tex]\frac{29}{80}[/tex]

   = 0.3625

μ = 0.36

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Answer:

Friction is a force that opposes the relative motion of two surfaces in contact. It exists when the surfaces of two bodies are in contact.The answers to the given questions are:

1. See attachment to this answer

2. a = 3.63 m/

3. μ = 0.36

Explanation:

only question 7. I keep getting it wrong and i’m not sure

Answers

Answer:

I think you just have to input the horizontal velocity component.

Explanation:

Assuming no air resistance

The horizontal velocity is constant at

vx = 17.5cos71 = 5.6974... = 5.70 i m/s

The vertical velocity varies with gravity

vy = 17.5sin71 + -9.81(22) = -199.273... = -199 j m/s

v = 5.70i - 199j m/s

arguably one should round to only two significant digits

A 770-kg two-stage rocket is traveling at a speed of 6.90×103 m/s away from Earth when a predesigned explosion separates the rocket into two sections of equal mass that then move with a speed of 2.60×103 m/s relative to each other along the original line of motion.What is the speed of each section (relative to Earth) after the explosion?How much energy was supplied by the explosion?

Answers

Answer:

Explanation:

Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.

Each half will have a mass of 770/2 = 385 kg

Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s

Now add back the reference frame velocity to get velocity relative to earth.

Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s

Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s

In the moving reference frame, each half will have kinetic energy which could only come from the explosion

KE = ½(385)(1.3 x 10³)² = 325,325,000 J

2(325,325,000) = 650,650,000 J released in the explosion.

Rounding to the three significant figures of the problem numerals

E = 6.50 x 10⁸ J or 650 MJ released

For each of the following measurements give an example of one thing that you might measure with it and why:
Example: square centimeter – the lid of a small box to find its area
A. kilogram
B. meter
C. milliliter
D. square meter

Answers

Answer:

i think its d or b but mostly i prefer d

Explanation:

50 points help

Column I Column II

______ 1. acceleration a. change in distance over time

______ 2. speed b. time interval

______ 3. velocity c. scalar

______ 4. Δt. d. change in position

______ 5. Magnitude only e. change in velocity over time

______ 6. Δx f. change in displacement over time

Answers

[tex]\\ \sf\longmapsto Acceleration\longrightarrow Change\:in\: Velocity\:over\:time[/tex]

[tex]\\ \sf\longmapsto Speed\longrightarrow Change\:in\: Distance\:over\:Time[/tex]

[tex]\\ \sf\longmapsto Velocity\longrightarrow Change\:in\: Displacement\: over\:time[/tex]

[tex]\\ \sf\longmapsto ∆t\longrightarrow Time\: interval [/tex]

[tex]\\ \sf\longmapsto Magnitude\:only\longrightarrow Scaler[/tex]

[tex]\\ \sf\longmapsto ∆x=Change\:in\: position [/tex]

How can gravity's role in tectonic plate motion be described?

Answers

Answer: In ridge push, the mantle wells upward because of the convection and elevates the edges of spreading oceanic plates. Because these plates are higher at the spreading center, they are forced downhill due to gravity and eventually flatten out to the ocean floor.

the answer I need points for my math test

The refractive index of water with respect to air is 5/3 and that of glass is 3/2.What is the refractive index glass with respect to water?

Answers

Answer:

9/8

Explanation:

PLEASE PLEASE HELP!!

An arrow is shot straight up in the air from the ground with an initial velocity of 54.0 m/s. If on striking the ground it
embeds itself 15.0 cm into the ground, what is the acceleration required to stop the arrow when it hits the ground?

Answers

Answer:

you have patience the distance.

Explanation:

the train leaves at 6.30.

HELP PLS! :/

A ball thrown straight up takes 1.89s to reach a height of 41.6m.
Taking g =9.81 m/s2 the balls initial speed was:

Help plsss

Answers

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 A 0.25 kg block oscillates on the end of a spring with a spring constant of 100 N/m. If the oscillation is started by elongating the spring 0.1m and giving the block a speed of 3 mis then the amplitude of the oscillation is:​

Answers

(K+U)
i

=(K+U)
f



0+
2
1

kA
2
=
2
1

mv
2
+
2
1

kx
2



2
1

(6.50 N/m)(0.100 m)
2
=
2
1

m(0.300 m/s)
2
+
2
1

(6.50 N/m)(5.00×10
−2
m)
2


3.25×10
−2
J=
2
1

m(0.300 m/s)
2
+8.12×10
−3
J

giving m=
9.0×10
−2
m
2
/s
2

2(2.44×10
−2
J)

=
0.542 kg



(b) ω=
m
k



=
0.542 kg
6.50 N/m



=3.46 rad/s

Then, T=
ω


=
3.46 rad/s
2π rad

=
1.81 s



(c) a
max

=Aω
2
=(0.100 m)(3.46 rad/s)
2
=
1.20 m/s
2

Please write a paragraph explaining the bible verse below in your own words.


Exodus 16:1-3

Answers

Answer: Moses

Explanation: The Israelites are angry at Aaron and Moses, because they lead them into this desert where there is no food, or water. It was told that after the Israelites left Egypt they would wander the desert for forty years. The Israelites complain that they would have had plenty of food if they had just stayed enslaved in Egypt. They are not grateful that God has liberated them from slavery.

What advantage is there in measuring your distance from I1 to I1' and dividing by 2 rather than measuring the distance OI1 directly

Answers

Measuring the distance from  [tex]I_1 \ to \ I_1'[/tex] and dividing by 2 has advantage of achieving a more accurate result compared to measurement taking directly.

Measuring the distance from [tex]I_1 \ to \ I_1'[/tex] is equivalent to the double of the distance.

This method of measurement gives a more accurate result because it minimizes error that may result from taking readings form the intervals. It ensures more accurate result compared to the measurement obtained when [tex]OI_1[/tex] is measured directly.

[tex]OI_1 = \frac{I_1 + I_1'}{2}[/tex]

Thus, we can conclude that measuring the distance from  [tex]I_1 \ to \ I_1'[/tex] and dividing by 2 has advantage of achieving a more accurate result compared to measurement taking directly.

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A bear slides down an incline which is oriented at 17 degrees above horizontal. What is the coefficient of friction between the bear and the incline if the bear moves with a constant velocity?

Answers

[tex]\mu = 0.306[/tex]

Explanation:

Assume that the direction down the incline is the +x-direction. We can apply Newton's 2nd law along the x-axis as

[tex]x:\:\:\:\:\:mg\sin17° - f_s = ma[/tex]

[tex]\Rightarrow mg\sin17° - \mu N = 0[/tex]

where m is the mass of the bear and g is the acceleration due to gravity and acceleration a is zero since the bear is moving with a constant velocity. Along the y-axis, we can write Newton's 2nd law as

[tex]y:\:\:\:\:\:N - mg\cos17° = 0 \Rightarrow N = mg\cos17°[/tex]

Combining these two equations together, we get

[tex]mg\sin17° = \mu(mg\cos17°)[/tex]

Solving for [tex]\mu, [/tex]

[tex]\mu = \dfrac{\sin17°}{\cos17°} = \tan17° = 0.306[/tex]

An astronaut travels to a star system 6.5 ly away at a speed of 0.80c . Assume that the time needed to accelerate and decelerate is negligible.How much time elapses in earth between the launch and the arrival of the first radio message from the astronaut saying that she has arrived? please 911

Answers

Answer:

14.625 years

Explanation:

Because acceleration/deceleration are negligent we can simplify this problem into 2 basic parts:

First: how long before the astronaut arrives? Since the speed of the craft is 0.8 times the speed of light and the distance to travel is 6.5 light-years, the equation to answer this part is:

0.8t=6.5

solve for t by dividing by 0.8

t=6.5/0.8 or 8.125

so, she will arrive in 8.125 years.

Then, once she sends her message, it will travel towards earth at 1 times the speed of light or:

1.0t=6.5 which is just t=6.5

so, her message will arrive back to Earth (8.125+6.5) 14.625 years after takeoff.

The time elapsed in earth will be 14.625 years.

To understand this we need to find how much time she took to travel 6.5 light years and then how much time the signal took to reach the earth.

How much time she took to travel 6.5 light year?

 0.8t = 6.5 ( because 1 light year = distance travelled by light in a year)

      t = 6.5/0.8

      t = 8.125 years

So, she travelled for 8.125 year.

How much time it took for the signal?

1.0 t = 6.5 ( because radio signal travells with the same speed of light)

     t  = 6.5/1.0

     t  = 6.5 years

Sum of these two gives us how much time elapsed on earth between two mentioned events.

So, 8.125 + 6.5 = 14.625 years

So, the time elapsed on earth between the launch and the arrivel of the first radio signal is 14.625 years.

#SPJ2

What hero means to me is when a person will do good things for others, no matter how bad it is for them. Also to me a hero is someone who doesn’t follow his pride or show himself good while sabotaging others.





I do not think Cesar Chavez is a hero because he did stand up for gay pride. I did like how he stood up for farmers, but a big no on gay pride. God gave us the gender we are supposed to be. People who turn gay turn against God. Men are supposed to stay Men and Women are supposed to stay Women. That is why I don’t think Chavez is a hero, because he stood up for the gay pride. I know it is what they want to be but not everything is meant to be changed.






I do not think Roberto Clemente is a hero, according to WTAE-TV Pittsburgh he did more to the fans than to the other people. I have realized that he died in a plane crash going to South Africa to help people, but he did not help the other people before his death than he did to his fans.





I do not think Jackie Robinson is a hero because he did not do much to help the citizens. He did help the Dodgers by a lot and went through a tough childhood but I do not think that he is a hero. He is encouraging though because he went through a lot of hate but he didn’t help out other people than the Dodgers.





I do think Hellen Keller is a hero because she did help people a lot. She fought for the rights of women and the rights for people with disabilities which sounds pretty awesome to me. She has also been inspirational for a very long time. Even now!

Answers

Answer:

good job my boy this is the right answer

Explanation:

I would recommend quizlet for this one because I actully have been getting As from it so yea

Change 1m2 in to cm2, mm2 and km2​

Answers

Answer:

1m² = 10000cm²

1m² = 1000000mm²

1m² = 1 × 10^-6

Explanation:

When coverting from square meter to square centimetre, multiply the area value by 10.

When coverting from square meter to millimetre, multiply the area value by 10⁶ ( 1 million )

When converting from meter square to kilometre square, divide the area value by 10^-6 ( 0.000001)

What does it mean that " memory is organized in semantic
networks

Answers

Answer:

Semantic memory is a category of long-term memory that involves the recollection of ideas, concepts and facts commonly regarded as general knowledge. Examples of semantic memory include factual information such as grammar and algebra.

What is metamarket ?

Answers

Answer:

metamarket (plural metamarkets) A group of businesses that offer products that are related from a consumer's perspective but which have no institutional connections. quotations . A market that trades in the medium of exchange of a lower-level market, such as money, derivatives, or credit. quotations.

Explanation:

The best examples of Meta Marketing can be selling family planning ideas or the idea of prohibition. ... Let's say a car selling in a Meta market would be a website, that sells cars but you will also find car parts there, add-ons for cars, colours for cars, mechanic's reviews, etc.

A group of businesses that offer products that are related from a consumer's perspective but which have no institutional connections.

The figure shows the light intensity on a screen behind a double slit. The slit spacing is 0.22 mm and the screen is 2.0 m behind the slits (Figure 1). What is the wavelength of the light?

Answers

The wavelength of the light is 550 nm

For a double slit interference pattern with slit spacing, d we have

dsinθ = mλ where d = slit spacing = 0.22 mm = 0.22 × 10⁻³ m, m = number of maximum fringe = 2(from the picture) and λ = wavelength of light.

Thus sinθ = mλ/d

Also, tanθ = L/D where L = distance between central maximum and fringe = 2.0 cm/2 = 1.0 cm = 1 × 10⁻² m and D = distance between slit and screen = 2.0 m

Since θ is small, sinθ ≅ tanθ

So, mλ/d = L/D

Making λ subject of the formula, we have

λ = dL/mD

Substituting the values of the variables into the equation, we have

λ = dL/mD

λ = 0.22 × 10⁻³ m × 1 × 10⁻² m/(2 × 2.0 m)

λ = 0.22 × 10⁻⁵ m²/4.0 m

λ = 0.055 × 10⁻⁵ m

λ = 0.55 × 10⁻⁶ m

λ = 550 × 10⁻⁹ m

λ = 550 nm

So, the wavelength of the light is 550 nm

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If a car travels 10 min 2 seconds, what is its speed?
A. 5 m/s
B. 0.2 m/s
C. 20 m/s
D. 2 m/s

Answers

If you meant the car travels 10 meters or miles then the answer would be 5m/s because v=d/t (v=10/2)

Does the stone remain at a constant speed? Or does it speed up?

Answers

Answer:

it would remain the same speed

Explanation: the rock isnt going down a hill or anything so therefore if gravity isnt pulling it down a slope then it would remain the same pace

The use of non-renewable energy resources in the UK has changed in the last 30 years.
Explain how the use of energy resources has changed in the last 30 years.

Answers

Answer: Varies

Explanation: It became more relied upon, technology is responsible for this.

The acceleration produced by a net force on an object is and why?
A.)inversely proportional to the mass of the object.
B.)directly proportional to the magnitude of the net force
C)in the same direction as the net force
D)all of the above

Answers

Answer:

A i think

Explanation:

Please help if u can thanksss

Answers

Answer:

yes its okay i think so it is the correct answer

A car drives at a constant speed of 45km in 20mn. The speed of the car is..?​

Answers

Answer:

83.8851 mi/h              


A) What parts of the EM spectrum are being used? Compare them in terms of
wavelength, frequency, and energy.

Answers

Answer:

All?

Explanation:

As wavelengths get shorter, energy increases, and frequency increases. As wavelenghts get longer, energy decreases, and frequency decreases. We can see the visible spectrum where the side UV has the shortest and strongest waves, but the IR side has the longest and weakest wavelengths.

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