A farmer has 6 buckets of blueberries and wants to sell them at a market stall. The farmer will charge $1.50 per pint. If each bucket can hold half a bushel of blueberries, how much will the farmer make in selling all of the blueberries?

Complete Question

The complete question is shown on the first uploaded image

Answer:

Option C is the correct option

Step-by-step explanation:

From the question we are told that

   The equation is  [tex]f (x, y , z ) = x^2 +y^2 + z^2[/tex]

    The constraint is  [tex]P(x, y , z) = x + y + z - 24 = 0[/tex]

Now using Lagrange multipliers  we have that  

   [tex]\lambda = \frac{ \delta f }{ \delta x } = 2 x[/tex]  

   [tex]\lambda = \frac{ \delta f }{ \delta y } = y[/tex]  

   [tex]\lambda = \frac{ \delta f }{ \delta z } = 2 z[/tex]

=>       [tex]x = \frac{ \lambda }{2}[/tex]

          [tex]y = \frac{ \lambda }{2}[/tex]

         [tex]z = \frac{ \lambda }{2}[/tex]

From the constraint  we have

      [tex]\frac{\lambda }{2} + \frac{\lambda }{2} + \frac{\lambda }{2} = 24[/tex]

=>   [tex]\frac{3 \lambda }{2} = 24[/tex]

=>   [tex]\lambda = 16[/tex]

substituting for x, y, z

=>   x =  8

=>  y =  8

=>   z =  8        

Hence

    [tex]f (8, 8 , 8 ) = 8^2 +8^2 + 8^2[/tex]

    [tex]f (8, 8 , 8 ) = 192[/tex]

Answer:

a.  the control limits should be set at (10.72, 11.28)

b. [tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c. [tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

Step-by-step explanation:

Given that:

population mean μ = 11

standard deviation [tex]\sigma[/tex] = 1.0

sample size n = 35

5% of the sample means will be greater than the upper control limit, and 5% of the sample means will be less than the lower control limit.

Therefore, level of significance ∝ = 0.05+0.05 = 0.10

Critical value for [tex]z_{1-\alpha/2} =z_{1-0.10 /2}[/tex]

[tex]\implies z_{1-0.05} = z_{0.95}[/tex]

Using the EXCEL FORMULA: = NORMSINV (0.95)

z = 1.64

The lower control limit and the upper control limit can be determined by using the respective formulas:

Lower control limit = [tex]\mathtt{\mu - z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

Upper control limit = [tex]\mathtt{\mu + z_{1-\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}}[/tex]

For the lower control limit = [tex]11-1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the lower control limit = [tex]11-0.27721[/tex]

For the lower control limit = 10.72279

For the lower control limit [tex]\simeq[/tex] 10.72

For the upper control limit = [tex]11+1.64 \times \dfrac{1.0}{\sqrt{35}}[/tex]

For the upper control limit = 11 + 0.27721

For the upper control limit = 11.27721

For the upper control limit  [tex]\simeq[/tex]  11.28

Therefore , the control limits should be set at (10.72, 11.28)

b. If the population mean shifts to 10.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 10.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 10.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{0.02}{\dfrac{1.0}{5.916}}<z < \dfrac{0.58}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(0.1183<z < 3.4313})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< 3.4313) - P(z< 0.1183) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (3.4313) - NORMSDIST (0.118 ); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.4526}[/tex]

c If the population mean shifts to 11.7, what is the probability that the change will be detected?

i.e

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}<z < \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{10.72- 11.7}{\dfrac{1.0}{\sqrt{35}}}<z < \dfrac{11.28- 11.7}{\dfrac{1.0}{\sqrt{35}}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P( \dfrac{-0.98}{\dfrac{1.0}{5.916}}<z < \dfrac{-0.42}{\dfrac{1.0}{5.916}}})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(-5.7978<z < -2.48472})[/tex]

[tex]\mathtt{P(10.72<x<11.28) = P(z< -2.48472) - P(z< -5.7978) }[/tex]

Using the EXCEL FORMULA: = NORMSDIST (-2.48472) - NORMSDIST (-5.7978); we have:

[tex]\mathbf{P(10.72<x<11.28) = 0.0065}[/tex]

Answer:

Solution : - 2.017 + 0.656i

Step-by-step explanation:

The quotient of the two expressions would be the following,

[tex]6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right][/tex] ÷ [tex]2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right][/tex]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) [tex]\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}[/tex]

( 2 ) [tex]\sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}[/tex]

These two identities makes sin(π / 10) = [tex]\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}[/tex], and cos(π / 10) = [tex]\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}[/tex].

Therefore cos(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}[/tex], and sin(2π / 5) = [tex]\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}[/tex]. Substitute,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right][/tex]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[0-i\right][/tex]

And now simplify this expression to receive our answer,

[tex]6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right][/tex] ÷ [tex]2\sqrt{2}\left[0-i\right][/tex] = [tex]-\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i[/tex],

[tex]-\frac{3\sqrt{5+\sqrt{5}}}{4}[/tex] = [tex]-2.01749\dots[/tex] and [tex]\:\frac{3\sqrt{3-\sqrt{5}}}{4}[/tex] = [tex]0.65552\dots[/tex]

= [tex]-2.01749+0.65552i[/tex]

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

Answer:

it's electromagnetic radiatum

Answer:

P(1 |F) = 10/17

Step-by-step explanation:

Let events

1 = restaurant 1

2 = restaurant 2

F = full-time worker chosen

P = part-time worken chosen

P(1 and F) = 1/2 * 10/16 = 5/16

P(2 and F) = 1/2 * 7/16 = 7/32

P( (1 or 2) and F ) = P(F) = 5/16+7/32 = 17/32

P(1 | F)          Probability of choosing restaurant 1 given a full-time was chosen

= P(1 and F) / P(F)

= 5/16  / (17/32)

= 5/16 * 32/17

= 10 / 17

Answer:

a) f(6)=(6)^2+4(6)+1=65

b)f (x+9)=(x+9)^2+4 (x+9)+1=(x^2+18x+81)+(4x+36)+1=x^2+22x+117

f (-x)=(-x)^2-4x+1

Answer:

(0.102, -0.062)

Step-by-step explanation:

sample size in 2018 = n1 = 216

sample size in 2017 = n2 = 200

number of people who went for another degree in 2018 = x1 = 54

number of people who went for another degree in 2017 = x2 = 46

p1 = x1/n1 = 0.25

p2 = x2/n2 = 0.23

At 95% confidence level, z critical = 1.96

now we have to solve for the confidence interval =

[tex]0.25 -0.23 ± 1.96*\sqrt{((1 - 0.25) * 0.25)/216 + ((1 - 0.23) *0.23/200}[/tex]

= 0.02 ± 1.96 * 0.042

= 0.02 + 0.082 = 0.102

= 0.02 - 0.082 = -0.062

There is 95% confidence that there is a difference that lies between  - 0.062 and 0.102 on the proportion of students who continued their education in the years, 2017 and 2018.

There is no significant difference between the two.

Answer:

im pretty sure its the -3 one

Step-by-step explanation:

Answer:

The answer is A, Square root of -3 is not a real number.

Step-by-step explanation: You can take the square root of positive numbers, so we can eliminate choices C and D. We can take the square root of 0, which would equal 0, so B is incorrect. However, We cannot take the square root of negative numbers, so choice A is the answer for this question.

Answer:

yes for each input there is exactly one output.

Step-by-step explanation:

phone pictures is given by y equals 0.25 x where X is the number of 32 y equals 3x + 2y

Answer:

d)  t = -10.12

Step-by-step explanation:

Explanation:-

Given sample size 'n'=10

Given the differences of mean x⁻ -μ = -3.36

Standard deviation of the sample 'S' =1.05 inches

We will use t-statistic

                      [tex]t = \frac{x^{-}-Mean }{\frac{S}{\sqrt{n} } }[/tex]

                     [tex]t= \frac{-3.36}{\frac{1.05}{\sqrt{10} } }[/tex]

                    t = -10.12

Answer: D

Step-by-step explanation:

Answer:is the first answer 15.875 and the second answer 17 x 28 ÷5

Step-by-step explanation:

Answer:

c. both A and B

Step-by-step explanation:

Given that there are two events A and B.

To find:

Intersection of the two sets represents which of the following events:

a. either A or B occurs but not both

b. neither A nor B occur

c. both A and B occur

d. All of these choices are true. a. b. c. d

Solution:

First of all, let us learn about the concept of intersection.

Intersection of two events means the common part in the two events.

Explanation using set theory:

Let set P contains the outcomes of roll of a dice.

P = {1, 2, 3, 4, 5, 6}

And set Q contains the set of even numbers less than 10.

Q = {2, 4, 6, 8}

Common elements are {2, 4, 6}

So, intersection of P and Q:

[tex]P \cap Q[/tex] = {2, 4, 6}

Explanation using Venn diagram:

Please refer to the image attached in the answer area.

The shaded region is the intersection of the two sets P and Q.

When we apply the above concept in events, we can clearly say from the above explanation that the intersection of two events A and B is the event that occurs when both A and B occur.

So, correct answer is:

c. both A and B

Answer:

C.

Step-by-step explanation:

Answer:

● The pythagorian theorem

The pythagorian theorem is used to find a missing side of a right triangle.

It states that the square of the hypotenus of a right triangle is equal to the sum of the squares of the two other sides.

Let a be the hypotenus, b and c are the othet sides:

☆☆☆☆☆ a^2 = b^2 + c^2☆☆☆☆☆

There are more than 350 way to prove this theorem.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● Hippasus of Croton was a member of the highly-secretive school og Pythagoras in Croton. He is credited in history as the first person to prove the existence of irrational numbers.

Answer:

17

Step-by-step explanation:

[tex]h(x) =x^2 +1\\k(x)=x-2\\\\3h(2)+2k(3)\\\\h(2)= ?\\k(3)=?\\\\h(2) = (2)^2 +1\\= 4+1\\h(2)=5\\\\\\k(3)= 3-2\\k(3) = 1\\\\3h(2) +2k(3)\\\\= 3(5)+2(1)\\=15+2\\3h(2)+2k(3) = 17[/tex]

5, 9, and 17

Step-by-step explanation:

Answer:

https://brainly.com/question/17155330

Step-by-step explanation:

Question:

Marcelina uses a blend of white corn and yellow corn to make tortilla chips at her restaurant. She needs to buy 50kg of corn in total for her next order. White corn costs $0.30 per kilogram, yellow corn costs $0.15 per kilogram, and she wants to spend $12 total.

What does point F represent in this context?

Answer:

Marcelina spends less that the intended amount of money and buy less than enough corn

Answer:

42 cm

Step-by-step explanation:

A square has 4 equal sides. To find the perimeter, add all side lengths together.

1. Set up the equation and solve

10.5 + 10.5 + 10.5 + 10.5 = 42

Answer:

21

Step-by-step explanation:

√1500 ≈ 38.7

round that up to 39 and square it:

39² = 1521

Answer:

s-6

Step-by-step explanation:

difference means subtract

s-6

Answer:

A

Step-by-step explanation:

40/20=2

80/40=2

Therefore the common ration is 2

The correct sequence which has a common ratio of 2 is,

⇒ {20, 40, 80, 160, 320, 640, …}

An sequence has the ratio of every two successive terms is a constant, is called a Geometric sequence.

Given that;

The common ratio of sequence is,

⇒ 2

Now, By option 1;

The sequence is,

⇒  {20, 40, 80, 160, 320, 640, …}

Hence, Common ratio = 40 / 20

                                   = 2

And, 80 / 40 = 2

Thus, The correct sequence which has a common ratio of 2 is,

⇒ {20, 40, 80, 160, 320, 640, …}

Learn more about the geometric sequence visit:

https://brainly.com/question/25461416

#SPJ2

Answer:

c. It does not appear to be within statistical control because there is an upward trend.

Step-by-step explanation:

Statistical process control is a method for quality control which employs statistical method to monitor and control process. It ensures operation efficiency and ensuring required specification to reduce wastes in production lines. Here the process variation is out of control because the statistical control has an upward trend.

Answer:

Step-by-step explanation:

Area of a triangle = 1/2 * base * height

A = 1/2bh

Rate of change of area is expresssed as dA/dt = dA/db * db/bt

db/dt is the rate at which the base is increasing.

Given db/dt = 18mm/min

A = 1/2*7b

A = 7b/2

dA/db = 7/2

The rate at which the area is changing dA/dt = dA/db * db/bt

dA/dt = 7/2 * 18

dA/dt = 7*9

dA/dt = 63mm/min

Hence the rate at which the area of the triangle is changing is  63mm/min

Answer:

[tex]2\sqrt{5v}[/tex]

Step-by-step explanation:

We can treat 20v as a regular number and not a term.

To simplify this square root, we need to break it down into parts which can be squared.

[tex]\sqrt{20v} = \sqrt{4\cdot5v}[/tex]

Square root of 4 is 2, so that goes outside the radical.

[tex]2\sqrt{5v}[/tex].

Hope this helped!

Answer:

2 sqrt(5)

Step-by-step explanation:

sqrt(20)

sqrt(4*5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(4) sqrt(5)

2 sqrt(5)

The yellow bar is the total cost of 2 pineapples. The black line in the middle of the yellow splits it equally in half and is located at the 3.

The constant bod proportionality would be 3, which means each pineapple cost $3

Answer:

first of all, brainly better not delete my answer again. (the answer is 3)

Step-by-step explanation:

you have to multiply to find the number of pineapples. but unlike me i did skip count and write down my number's and I tried to find "what number skips until it ends to 6?'' i found 3 as my answer! 3,6,9,12,15,18,21 etc..

can u go to my page real quick and answer my question pls

from the well known theorem that, primes are multiple of 6 ±1 ( eg 5,7,11,13,17,19...)

and one of them has [tex]-1[/tex] and other has $+1$ from the multiple of 6

let , $p=6n-1$, so $p+2=6n+1$

$\implies p+1=6n$

$\therefore 6|(p+1)$

QED

Answer:

10:35-3:15

[tex]\dfrac{5bc}{10b^2}=\dfrac{\not 5\cdot \not b\cdot c}{2\cdot \not 5\cdot \not b\cdot b}=\dfrac{c}{2b}[/tex]

Answer:

c / ( 2b)

Step-by-step explanation:

5bc/10b^2

Lets look at the numbers first

5/10 = 1/2

Then the variable b

b / b^2 = 1/b

Then the variable c

c/1 = c

Putting them back together

1/2 * 1/b * c/1

c/ 2b

Answer:

-7.

Step-by-step explanation:

g(x) = x^2 - 6x - 7

g(2) = 2^2 - 6(2) - 7

= 4 - 12 - 7

= -8 - 7

= -15

f(x) = x + 8

f(-15) = (-15) + 8

= 8 - 15

= -7

Hope this helps!

[tex]|\Omega|=5\cdot4=20[/tex]

a)

[tex]|A|=3\cdot2+2\cdot1=8\\\\P(A)=\dfrac{8}{20}=\dfrac{2}{5}[/tex]

b)

[tex]|A|=3\cdot2+2\cdot3=12\\\\P(A)=\dfrac{12}{20}=\dfrac{3}{5}[/tex]

c)

[tex]|A|=3\cdot2=6\\\\P(A)=\dfrac{6}{20}=\dfrac{3}{10}[/tex]

d)

[tex]|A|=2\cdot1=2\\\\P(A)=\dfrac{2}{20}=\dfrac{1}{10}[/tex]

Answer:

22

Step-by-step explanation:

We can write an equation:

(7+13+10+x)/4=13

x represents the number that needs to be added to get an average of

(7+13+10+x)/4=13

(30+x)/4=13

30+x=52

x=22

The number is 22

Hope this helps! Have a wonderful day :)