The name given to it is "terminal velocity".
In reality, it isn't a velocity, and it doesn't happen in free-fall.
Go figure.
five scientist who travelled to space
Answer:
The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...
Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...
Nicolaus Copernicus. Public Domain. ...
Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...
Galileo Galilei. NASA
there is no gain in mechanical advantage in a single fixed pulley but they are used
Answer:
A single fixed pulley is used to lift load by changing the direction of the lifting force. Even though a single fixed pulley has no mechanical gain in that, the effort applied is greater than the load, it is preferred in use since you do not have to pull or push the pulley up and down.
Explanation:
The answer itself speaks
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path.
A. 0.60 N, along the line tangent to the circle
B. 0.015 N, along the line tangent to the circle
C. 0.60 N, toward the center of the circle
D. 0.015 N, toward the center of the circle
Answer:
Option C
Explanation:
From the question we are told that:
Mass [tex]m=0.015kg[/tex]
Radius [tex]r=0.5m[/tex]
Time [tex]t=0.70[/tex]
Generally the equation for Tension is mathematically given by
[tex]T=\frac{4mr}{t^2} \pi[/tex]
[tex]T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)[/tex]
[tex]T=0.60N[/tex]
Therefore
[tex]T=0.60 N[/tex], toward the center of the circle
Option C
Answer:
0.60 N, toward the center of the circle
Explanation:
Got it right on the test.
which force is responsible for the moon revolving around the sun?
Amigos necesito que me ayuden a resolver esta gráfica :').
Answer:
ANO BA TO?(;-;)
Explanation:
miss the rage??
15. You are watching a baseball game on television that 15
being broadcast from 4500 km away. The batter hits
the ball with a loud "crack" of the bat. A microphone
is located 22 m from the batter, and you are 2.0 m from
the television set. On a day when sound travels 343 m/s
in air, what is the minimum time it takes for you to hear
the crack of the bat after the batter hits the ball?
Answer:
t_total = 6.99 s
Explanation:
It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is
t_total = t₁ + t₂ + t₂
we look for t1, it indicates that the distance x = 22m
v = x / t
t = x / v
t₁ = 22/343
t₁ = 6.41 10-2 s
time t₂
t₂ = 4500 103/3 108
t₂ = 1.5 10-5 s
time t₃
t₃ = 2/343
t₃ = 5.83 10⁻³
Total time is
t_total = t₁ + t₂ + t₃
t_total = 6.41 10⁻² + 1.5 10⁻⁵ + 0.583 10⁻²
t_total = 6.99 s
Solve this question please sqdancefan
Answer:
(D) 4×10⁻³
Explanation:
The difference is ...
0.2050 -0.2014 = 0.0036 = 3.6×10⁻³
The number 0.205 is expressed to a precision of 1×10⁻³, so the result of the subtraction operation cannot be considered to be more precise. It must be expressed as ...
4×10⁻³ . . . . matches choice D
_____
Additional comment
This is physics, not math. In the physical sciences, most numbers must be considered to be measurements. (A few are definitions.) Hence, the rules of significant figures and precision apply to the results of arithmetic operations. This problem is a good illustration of what happens when computing small differences of large numbers. We start with 3 significant figures in 0.205, and end up with 1 significant figure in 0.004.
HELP
What is the momentum of a 50-kg ice skater gliding across the ice at a speed of 5 m/s?
Answer:
250 kgm/s
Explanation:
To calculate momentum, simply take the product of the mass and velocity.
The isotope used to remove cancer malignancy cell the given options are a. Strontium 89 b. Uranium 238 c. Carbon 14 d. Chlorine 37.......... can anyone tell me the ans plzz
Answer:
B. Uranium 238.
Explanation:
It is radioactive and can be used to treat cancer in the form of radiotherapy
a body of mass 5kg moving on a horizontal ground has a coefficient of friction 0.36.find the normal reaction acting on the body?
Answer:
50 N.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 Kg
Coefficient of friction (μ) = 0.36
Normal reaction (N) =?
Next, we shall determine the weight of the body. This can be obtained as follow:
Mass (m) = 5 Kg
Acceleration due to gravity (g) = 10 m/s²
Weight (W) =?
W = mg
W = 5 × 10
W = 50 N
Finally, we shall determine the normal reaction. This can be obtained as follow:
Weight (W) = 50 N
Normal reaction (N) =?
Normal reaction = weight of the body
N = W = 50 N
Thus, the normal reaction acting on the body is 50 N
The pressure difference, , across a partial blockage in an artery (called a stenosis) is approximated by the equation where is the blood velocity, the blood viscosity , the blood density , the artery diameter, the area of the unobstructed artery, and the area of the stenosis. Determine the dimensions of the constants and . Would this equation be valid in any system of units
The question is incomplete. The complete question is :
The pressure difference, Δp, ac[tex]K_u[/tex]ross a partial blockage in an artery (called a stenosis) is approximated by the equation :
[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]
Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the artery diameter, [tex]A_0[/tex] the area of the unobstructed artery, and A1 the area of the stenosis. Determine the dimensions of the constants [tex]K_v[/tex] and [tex]K_u[/tex]. Would this equation be valid in any system of units?
Solution :
From the dimension homogeneity, we require :
[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]
Here, x means dimension of x. i.e.
[tex]$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$[/tex]
[tex]$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$[/tex]
So, [tex]$[K_u]=[K_v]=[1 ]=$[/tex] dimensionless
So, [tex]K_u[/tex] and [tex]K_v[/tex] are dimensionless constants.
This equation will be working in any system of units. The constants [tex]K_u[/tex] and [tex]K_v[/tex] will be different for different system of units.
Two cups having different liquids at a temperature of 20°c and 68°c lose heat energy to the environment. To measure the temperature difference between the two cups of liquid, you would use a ____
Answer:
youd use a thermometer. this can be used to measure the temperature of a solid such as food, a LIQUID such as water, or a gas such as air.
Explanation:
If a driver makes contact with a steering wheel during a 35 mph crash, she comes to rest in about Δ=15 ms. If, during an identical crash, the driver makes contact with an air bag, she comes to rest in about Δ=110 ms. What is the ratio of the force exerted by the steering wheel to the force exerted by the air bag on the driver?
Answer:
The ratio of forces is 22 : 3.
Explanation:
Case I:
initial velocity, u = 35 mph
final velocity, v = 0
time, t = 15 ms
Case II:
initial velocity, u = 35 mph
final velocity, v = 0
time, t' = 110 ms
let the mass is m.
According to the Newton's second law, the force is given by the rate of change of momentum.
So
[tex]F =\frac{m(v-u)}{t}\\\\F'= \frac{m(v-u)}{t'}\\\\So, \frac{F}{F'} =\frac{t'}{t}\\\\\frac{F}{F'}=\frac{110}{15}=22:3[/tex]
True or false please help I’ll give brainliest
Answer:
All of them are false
Explanation:
4. electrons flow from earth to the object
5. electrons move freely
6. protons can't move
Answer:
They all false
Activity 1 MATCH IT
Directions: Match Column A to Column B. Write your answer on the space provided before the number.
COLUMN A
__1. Hiking
__2. Orienteering
__3. Zumba
__4. Volleyball
__5.badminton
COLUMN B
A. It is an outdoor navigational recreational activity using specially drawn and detailed maps.
B. Created through on-the –spot aerobics class using the non- traditional music.
C.Going on an extended walk for the purpose of pleasure and exercise.
D. Can be traced from the ingenuity of William J. Morgan in 1895 at Holyoke Massachusetts.
E. Games are held inside the gym to avoid the effect of air in the flight of the shuttle.
Answer:
1. A hiking
2. C
3. B
4. D
5. E
20 POINTS!!! The photograph shows a the result of waves made by an earthquake.
What was transported to this location by the earthquake waves?
A. Gravity
O B. Energy
C. Rock
D. Matter
Answer:
It's B = Energy ....
i hope its right
On which planet would your weight be the most and the least?
a) Jupiter and Mercury
b. Jupiter and neptune
c. Saturn and Neptune
d. Saturn and uranus
Answer:
Jupiter and neptune
Explanation:
lubricants reduce friction by replacing sliding friction with fluid friction
HELPPP ILL GIVE BRAINLIST
Answer:
2. Letter C all those in the list are non living
3. Letter A a skunk is a living organism that shapes its environment
5. Letter A when talking about population it usually refers to a single type of species in that area
6. Letter B Niche (just recently heard of the word in ecology)
dimension of radius of sphere
Answer:
The dimension is L
Explanation:
Dimension analysis is a method of representing quantities majorly with respect to some fundamental quantities of mass (M), length (L), time (T).
A sphere has a definite volume which relates to its radius by:
V = [tex]\frac{4}{3}[/tex][tex]\pi[/tex][tex]r^{3}[/tex]
In this equation [tex]\pi[/tex] is a dimensionless quantity, and the unit of v is [tex]m^{3}[/tex].
But, metre is a measure of length, thus it has a dimension of L.
So that,
[tex]m^{3}[/tex] ≅ [tex]L^{3}[/tex]
Then,
[tex]L^{3}[/tex] = [tex]r^{3}[/tex]
Find the cube root of both sides to have,
r = L
Therefore, the dimension of the radius of a sphere is L.
Gold at 100.0°C is placed in 2.00×10^2 g of water at 20.0°C. The mixture reaches equilibrium at 21.2°C. the specific heat of gold is 0.129 (J/g°C) What is the mass of the gold? Specific heat of water is 4.18 (J/g°C) .
Answer:
there it is fella atleast i tried
Aiden is writing a report about the structure of the atom. In her report, she says that the atom has three main parts and two subatomic particles. Do you agree with her? Why or why not?
Answer:
I don't agree
Explanation:
Atoms have 3 subatomic particles protons, electrons and neutrons,
how does a dragline excavator work
what is the Young's modulus of a perfect rigid body
Answer:
Infinite
Explanation:
Young's modulus is infinite and bulk modulus is zero.
Answer:
Young's modulus is the ratio of tensile stress ( force of elasticity ) to tensile strain ( extension ).
Explanation:
[tex]E = \frac{stress}{strain} [/tex]
Suggest one reason why the experiment might not have given a correct value for
the specific heat capacity of the metal.
Answer:
It is because some of the heat is lost in the surroundings.
Explanation:
To calculate the specific heat of the metal, the following steps are performed.
Take a piece of metal whose mass and the initial temperature is known.
Now take a beaker filled with some measured amount of water and the temperature of water is known.
Drop the heated metal piece in the water so that the equilibrium is reached.
According to the principle of calorimetery,
Heat lost by the metal = heat gained by the water
here, some of the heat is lost in the surroundings so we don't get the correct value of the specific heta of the metal.
describe 2 ways you could increase the efficiency of a household central heating system
Answer:
Arrange an annual service. Treat your boiler like your car. ...
Keep your boiler clean. ...
Bleed your radiators. ...
Top up the pressure. ...
Use a Powerflush. ...
Insulate your pipes. ...
Turn the heating on. ...
If all else fails…
Explanation:
Define second class lever
Answer:
Please find detailed explanation of second class levers below
Explanation:
Levers are one of the classes of machine that possesses three levels namely: first class, second class and third claas. A second class lever is the level of levers in which the load (L) is in between the pivot (F) and the effort (E).
Examples of second class levers include; wheelbarrow, a bottle opener etc. In the bottle opener for example, the bottle lid (load) is in between the pivot of the opener and the hand opening it (effort).
Use the equation d = st, where d = distance, s = speed, and t = time. If you jog
at a speed of 1.5 m/s for 20 seconds, how far do you travel?
A. 13.3 m
B. 30 m
C. 5 m
D. 21.5 m
Answer:
Distance = 30 meters
Explanation:
Given the following data;
Speed = 1.5 m/s
Time = 20 seconds
To find the distance travelled;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the formula;
[tex]Speed = \frac{distance}{time}[/tex]
Making distance the subject of formula, we have;
[tex] Distance = speed * time [/tex]
Substituting into the above formula, we have;
[tex] Distance = 1.5 * 20 [/tex]
Distance = 30 meters
Which of the following statements is incorrect?
1) A ray of light travels from a point A to point B in a path that takes the shortest time
2) In reflection angle of incidence equal to angle of reflection
3) Magnification for a plane mirror is always unity
4) A plane mirror can form only virtual images
Answer:
2
Explanation:
in reflection the incident ray and reflected rays are equal an angle
1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia recorrida los últimos 5 segundos de su trayectoria.
Answer:
Initial velocity (u) = 40 m/s
Distance travel in last 5 seconds = 100 m
Explanation:
Given:
Acceleration (a) = 8 m/s²
Final velocity (v) = 0 m/s
Find;
1] Initial velocity before 5 sec
2] Distance travel in last 5 seconds
Computation:
1] Initial velocity before 5 sec
v = u + at
0 = u + (-8)(5)
u - 40 = 0
Initial velocity (u) = 40 m/s
2] Distance travel in last 5 seconds
s = ut + (1/2)(a)(t²)
s = (40)(5) + (1/2)(-8)(5²)
s = 200 - 100
Distance travel in last 5 seconds = 100 m
