A gas occupies 12.3 L at a temperature of 40.0 K. What is the volume when the temperature is increased to 60.0 K?

Answer:

C

Explanation:

Answer:

A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.

Answer:

Explanation:

false

Answer:

The first one is balanced. The second one is not.

Explanation:

The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced

More Detailed: first example

Reactant side (left of arrow)

H: 2

C: 1

O: 3

Product side (right of arrow)

H: 2

C: 1

O: 3

More detailed: second example

Reactant side:

Na: 1

O: 1

H: 1

C: 1

Product side:

Na: 2

O: 4

H: 2

C: 1

the variables needed to balance this equation is 2,1, 1, 1.

Answer:

[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]

Answer:

its the lunar and solar eclipse

Explanation:

the solar eclipse happens when the moon is in between the sun and earth

Answer: There is 0.8 liters (L) of water required to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.5 M        

[tex]V_{1}[/tex] = 4800 mL

Convert mL into L as follows.

[tex]1 mL = 0.001 L\\4800 mL = 4800 mL \times \frac{0.001 L}{1 mL}\\= 4.8 L[/tex]

[tex]M_{2}[/tex] = 3 M

Formula used to calculate the volume of water required as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 4.8 L = 3 M \times V_{2}\\V_{2} = \frac{0.5 M \times 4.8 L}{3 M}\\= 0.8 L[/tex]

Thus, we can conclude that 0.8 liters (L) of water need to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Answer:

13.25 M

Explanation:

Molarity is moles over liters so simply plug your values in as such:

5.30 mol ÷ 0.400 L = 13.25 M

Answer: B. Hydrogen Bonding

Explanation: I got it right on castle learning lol

There are different kinds of forces. The term that identifies a type of intermolecular force is hydrogen bonding.

The three known to be types of intermolecular interactions. They  are

Hydrogen bonding is known to be an intermolecular force that takes place between two molecules. That molecule is known to have a hydrogen atom be bonded to a nitrogen, oxygen, or fluorine atom.

Learn more about Bond from

https://brainly.com/question/1420470

Answer:

Option A:

Dig into the zone of aeration

Explanation:

Within the lithosphere of the earth's surface, the zone of aeration is the zone directly above the water table, with a lot of pore spaces within the rocks. These pore spaces contain air and water, which can be used to water the cows.

Once the zone of aeration has been dug into, the farmer can tap into the underground reserve of water, which is stored within the pores of rocks. This water can now sip into the hole that was dug up by the farmer, forming a pond for the cows.

Answer:

gO₂ = 32.32 g

Explanation:

In this case, let's write the general equation:

2H₂ + O₂ -------> 2H₂O

In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.

According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:

gO₂ = 36.36 - 4.04

Hope this helps

The Answer Is Sample A

Density -

[tex]density = \frac{mass}{volume} [/tex]

Input The Formula For Both Equations To Find Density.

Sample A -

[tex]d = \frac{40}{10} [/tex]

[tex]d = 4[/tex]

Sample B -

[tex]d = \frac{45}{15} [/tex]

[tex]d = 3[/tex]

Answer:

Molality = 9.498 mol  k g − 1

Explanation:

A final way to express the concentration of a solution is by its molality. The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride.

molality = number of moles of solute/ mass of solvent in kg

number of moles of KI = mass of KI / molar mass of KI  

number of moles of KI = 9.49.8 g / 1.00 g  m o l − 1

number of moles of KI = 9.498 moles  

molality = 9.498 moles / 1kg  

molality = 9.498 mol  k g − 1

Answer: A buffer solution is a solution made to prevent the pH level of something from changing when you add a base or an acid to it. For example, if you put a buffer solution in a pool, and then you put chlorine in it, the chlorine's effect on the PH level will be suppressed.

Answer:

15 km/hour

Explanation:

You need to find how fast he was going per hour.

Answer: 15

Divide. 60 ÷ 4

This gives us 15. So, Alex was going 15 mph

Answer:

Explanation:

what do u need to know

Answer:

164.088 g/mol

Explanation: hope this helps

Answer:

Calcium nitrate

Explanation:

164.088 g/mol

give me the brainliest plss

Answer:

Decrease occur in the amount and flow of water bodies.

Explanation:

There is decrease in the amount and flow of water from water bodies such as rivers and lakes etc occur when the river is diverted from large water bodies because the water flows to the diverted sides and decrease occurs in the amount of water in the rivers and lakes. Those regions from where this river passes can also be negatively affected due to low amount of water they receives for their daily needs or for cultivation of crops so we can say that this diversion has adverse effect on other populations.

Answer:133.4

c

m

3

Explanation: Explanation:

Molarity is number of moles of solute divided by number of litres of solution.

M

=

n

V

Rearrange for V to give

V

=

n

M

Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.

Now plug in the numbers:

V

=

n

m

=

0.0667

0.5

=

0.1334

litres

So you need to add 0.1334 litres of 133.4

c

m

3

of water.

(NB: symbol for molarity is upper case M. m is metres).

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

Answer:

Explanation:

Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).

Answer:

B, C

Explanation:

Hope it helps i read it all

Answer:

A, D, E

Explanation:

Answer:

the nucleus

Explanation:

He proposed that the mass of an atom is concentrated in the nucleus which occupies a small volume in the center .He added that the nucleus comprises the protons and neutrons.where the neutron had no charge while the protons had charge of +1

Answer:

the nucleus

Explanation:

Answer:

98 g/mol

Explanation:

La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:

masa molar = masa/número moles

Tenemos los siguientes datos del compuesto Y:

masa Y = 196 g

número de moles de Y = 2 mol

Entonces, podemos calcular la masa molar de Y de la siguiente manera:

masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol