A gun is sounded and an echo received from a wall 6 seconds later. If the speed of sound is 330m/s, how far away is
the wall?

Answer:

Both are electromagnetic waves

Explanation:

Hope this helped!!

Answer:

0.5

Explanation:

In this picture,

Answer:

13.1

Explanation:

thats what i put in for acellus and its right

When charged objects touch, you can assume that the charges move between the objects, so that the total amount of charge doesn't change but it splits equally between the two objects.

-- like two water tanks standing next to each other, with a different amount of water in each one.  When you connect a pipe between their bottoms, some water flows across until the LEVEL of water is the same in both tanks.

-- like one hard full balloon and one soft mooshy balloon.  When you connect them together, some air flows from the hard balloon into the soft balloon, until the pressure of air is the same in both balloons.  

The total amount of charge on your two objects is (+6.0 μC  -  2.0 μC).  That's +4.0 μC  .

When they touch, charges move around until the charge is the same on both objects . . . +2 μC.

Answer:

R =V/ I =12.6 ÷ 0.53= 27.77 ohm

Answer:

Relative Dating

Explanation:

Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages. Absolute dating is used to determine a precise age of a fossil by using radiometric dating to measure the decay of isotopes, either within the fossil or more often the rocks associated with it.

Answer:

7

Explanation:

The light travels a total of 4 cm to the screen, of that, 3 cm is in air and 1 cm is in the glass plate.

The total number of wavelengths of light between the source and screen is just the number of wavelengths in air plus the number in the glass.

To determine the number of wavelengths in air, divide the thickness of air (3 cm) by the wavelength of the light (6000 Angstroms), converting units as needed.

The refractive index of the glass is 1.5. That means that the velocity of propagation of the light in the glass is 2/3 of what it is in air, and so the wavelength of the light in glass is 2/3 of what it is in air. So, divide the thickness of glass (1 cm) by the wavelength of the light in glass (6000 * 2/3).

Add the two values for the final answer

Answer:

The correct response will be "13.755 kN".

Explanation:

According to the question,

The given values are:

a = 300 mm

i.e.,

  = 0.3 cm

b = 200 mm

i.e.,

  = 0.2 dm

Internal pressure,

[tex]P_{in}=100[/tex]

Now,

The area of the elliptical shape window will be:

⇒  [tex]A = \pi ab[/tex]

On substituting the values, we get

⇒      [tex]=3.14\times 0.300\times 0.200[/tex]

⇒      [tex]=0.1885 \ m^2[/tex]

By using the table,

At 10 km, the atmospheric pressure will be

⇒  [tex]p_o=27.03 \ kPa[/tex]

Now,

The outward force will be:

⇒  [tex]F_{net}=p_{in}A-p_{0}A[/tex]

⇒          [tex]=(p_{in}-p_{0})A[/tex]

⇒          [tex]=(100-27.03)\times (0.1885)[/tex]

⇒          [tex]=13.755 \ kN[/tex]

There is no observed spectrum above, and I didn't see any curves in the last section.  So I guess they're similar in that respect.

Otherwise, your question is quite intriguing.

Answer:

C. Solids,Liquids, Gases

Answer:

[tex]\underline{\textsf{\textbf{Answer -}}}[/tex]

No & Yes - the case depends actually.

You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).

Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.

its the earths forward motion that prevents it falling into the sun

Answer:

No & Yes - the case depends actually.

You can't make the velocity zero and expect to stay in space. you will need to constantly fire the engine to hold youself in position (this is possible, until you run out of fuel).

Yes, it is possible to fire the engine and lift off earth into space, and then fire in the opposite direction to earths movement until you are still, relative to the sun. But if you now turn the engine off, the suns gravity will pull you down and directly into the sun.

its the earths forward motion that prevents it falling into the sun

Answer:

[tex]\boxed {\boxed {\sf 100,000 \ Joules}}[/tex]

Explanation:

Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.

[tex]E_k= \frac{1}{2} mv^2[/tex]

The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.

Substitute these values into the formula.

[tex]E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2[/tex]

Solve the exponent.

[tex]E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)[/tex]

Multiply the first two numbers together.

[tex]E_k= 1000 \ kg \times (100 \ m^2/s^2)[/tex]

Multiply again.

[tex]E_k= 100,000 \ kg*m^2/s^2[/tex]

[tex]E_k= 100,000 \ J[/tex]

The roller coaster car has 100,000 Joules of kinetic energy.

Answer: C. 20J

Explanation:  im pretty sure sorry if im wrong :(

Answer:

Explanation:

At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points [tex]\theta _1 , \theta _2 , \theta _3[/tex] the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.

[tex]I = I_o \ cos \theta _1 \ cos \theta _2 \ cos \theta _ 3[/tex]

The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.

∴

a)

When sheet A is removed, the transmitted light goes through B, at 30°.

[tex]I = I_o \ cos ^2 \theta _1 \ cos ^2 \theta _2 \ cos^2 \theta _3[/tex]

[tex]I = 20 \ cos ^2 30 \ cos ^2 60 \ cos ^2 30[/tex]

[tex]I = 2.81 \ W/m^2[/tex]

b)

When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.

c)

When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.

[tex]\mathbf{d) \ I - I_o cos^2 (0) cos^2 (30) \ cos^2 (60)}[/tex]

[tex]\mathbf{d = 3.75 \ W/m^2}[/tex]

Answer:

roasting,

broiling,

pan-broiling,

pan-frying,

grilling.

Explanation:

good luck

Answer:

Explanation:

1. Stir frying

2. Pan frying

3. Grilling /BBQ

4. Baking/roasting

Answer:

226.8 kN/m

Explanation:

The work done by the spring, W equals the kinetic energy of the satellite, K

W = K

work done by the spring, W = 1/2kx² where k = force constant and x = extension of spring

kinetic energy of the satellite, K = 1/2mv² where m = mass of satellite = 1060 kg and v = speed of satellite = 3.35 m/s

1/2kx² = 1/2mv²

k = mv²/x²

Also, the spring force F = kx where k = force constant and x = extension of spring.

k = F/x

equation both expressions for k, we have

mv²/x² = F/x

x = mv²/F since F = ma where m = mass of satellite and a = maximum acceleration of satellite = 5.00g and g = 9.8 m/s²

x = mv²/ma = mv²/5.00mg = v²/5.00g

Substituting the values of the variables into the equation, we have

x = v²/5.00g

= (3.35 m/s)²/(5.00 × 9.8 m/s²)

= 11.2225 m²/s²/49 m/s²

=0.229 m

Now k = F/x = 5.00mg/x

Substituting the values of the variables into the equation, we have

k = 5.00mg/x

k = 5.00 × 1060 kg × 9.8 m/s²/0.229 m

k = 51940 kgm/s²/0.229 m

k = 51940 N/0.229 m

k = 226812.23 N/m

k = 226.81223 kN/m

k ≅ 226.8 kN/m

Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together

Explanation:

Answer:

The other 30% is lost from friction.

Explanation:

       friction 30% ---> |O| <------ 70% work

A machine has an efficiency of 70%, and the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

In any machine, the total work input is equal to the total work output plus any work that is lost or dissipated due to various factors such as friction, heat transfer, etc., so, for example, if a machine receives 100 units of energy as input, only 70 units of energy are converted into useful output work, and the remaining 30 units of energy are lost as waste energy.

Hence, the remaining 30% of the input work is lost as waste energy or dissipated in the form of heat, noise, or vibration, which cannot be harnessed to do any useful work.

Learn more about the work by machine here.

https://brainly.com/question/15365822

#SPJ6

Answer:

The positive impact in the cycle is that CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.

Explanation:

Carbon cycle is the process by which carbon dioxide travels from the atmosphere to the earth and returns back to the atmosphere.

The negative impact of carbon dioxide in the carbon cycle is that it will cause green house effect. However, when it comes to the positive impact in the cycle, CO2 will make plants to use water more efficiently and also thereby make them to become drought resistant and thereby grow faster.

Answer:

hydrogen and helium

Explanation:

i got it 100 percent. Hope this Helps!

Answer:

a.  0.00189 kg

b. 18.552 mN

c. 1.363 kN

d. Since the molecular density is high, the force exerted by the sample is thus high.

Explanation:

(a) Find the mass of the gas. kg

Using PV = mRT/M where P = pressure on gas = atmospheric pressure = 1.013 × 10⁵ Pa, V = volume of gas = L³ where L = length of cube = 11.6 cm = 0.116 cm,m = mas of gas, R = molar gas constant = 8.314 J/mol-K, T = temperature of gas = 291 K and M = molar mass of gas = 28.9 g/mol

So, m = PVM/RT = PL³M/RT

Substituting the values of the variables into the equation, we have

m = PL³M/RT

= 1.013 × 10⁵ Pa × (0.116)³ × 28.9 g/mol/ 8.314 J/mol-K × 291 K

= 0.0457 × 10⁵ Pa g/mol/2419.374J/mol

= 1.89 × 10⁻⁵ × 10⁵ g

= 1.89 g

= 1.89 × 10⁻³kg

= 0.00189 kg

(b) Find the gravitational force exerted on it. mN

The gravitational force, F exerted on it is its weight W

So, F = W = mg where m = mass of gas = 1.89 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²

F = mg

= 1.89 × 10⁻³ kg × 9.8 m/s²

= 18.522 × 10⁻³ kgm/s²

= 18.552 × 10⁻³ N

= 18.552 mN

(c) Find the force it exerts on each face of the cube. kN

Since pressure, P = F/A where F = force exerted on each face and A = area of each face = L² where L = length of side of cube = 11.6 cm = 0.116 m

So, F = PA since P = atmospheric pressure = 1.013 × 10⁵ Pa,

F = PL²

= 1.013 × 10⁵ Pa (0.116 m)²

= 0.01363 × 10⁵ N

= 1.363 × 10³ N

= 1.363 kN

(d) Why does such a small sample exert such a great force

To answer this question, we need to find the density of the gas in the cube.

So density of gas,ρ = m/V where m = mass of gas = 1.89 g and V = volume of gas = L³ and L = length of side of cube = 11.6 cm

ρ = m/V = m/L³ = 1.89 g/(11.6 cm)³ = 1.89 g/1560.896 cm³ = 0.00121 g/cm³

We now find the number of moles of gas in a cm³ by dividing its density by its molar mass.

So n = ρ/M = 0.00121 g/cm³ ÷ 28.9 g/mol = 23687.67 mol/cm³

Since there are 6.022 × 10²³/mol, we find the number of molecules in a cm³ which is n × 6.022 × 10²³/mol = 23687.67 mol/cm³ × 6.022 × 10²³/mol

= 143731.1 × 10²³ molecules/cm³

= 1.437311 × 10²⁸ molecules/cm³

≅ 1.44 × 10²⁸ molecules/cm³

Since the molecular density is high, the force exerted by the sample is thus high.

Answer:

0.238 m/min

Explanation:

The volume of water in the trough V =Ah' where A = area of cross-section = area of isosceles trapezoid = 1/2(a + b)h where a = length of bottom of isosceles trapezoid = 40 cm = 0.4 m, b =  length of top of isosceles trapezoid = 100 cm = 1 m and h = height of isosceles trapezoid = 60 cm = 0.6 m. So,

A = 1/2(a + b)h = 1/2(0.4 m + 1 m)0.6 m = (1.4 m)0.3 m = 0.42 m² and h' = height of water level in trough = H - h" where H = length of trough = 10 m and h" = depth of water level in trough = 10 cm = 0.1 m

So, V = Ah'

V = A(H - h") = A(10 - h")

Now, the rate of change of volume of the trough with respect to time dV/dt = d[A(10 - h")]/dt

dV/dt = -Adh"/dt

dh"/dt = -dV/dt/A

Since dV/dt = 0.1 m³/min, substituting the other variables into the equation, we have

dh"/dt = -dV/dt/A

dh"/dt = -0.1 m³/min/0.42 m²

dh"/dt = -0.238 m/min

This is the rate at which the depth is decreasing

Since the height h' = 10 - h"

dh'/dt = d(10 - h")/dt

= -dh"/dt

= -(-0.238 m/min)

= 0.238 m/min

So the water level is increasing at a rate of 0.238 m/min

Answer:

B. The same on the moon.

Explanation:

The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.

[tex]Density = \frac{Mass}{Volume}[/tex]

When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.

Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.

So, the correct option is:

B. The same on the moon.

Answer:

All the elements except for the ones on the last column (at the left of the periodic table)

Explanation: