A home gardener estimates that 24 apple trees will have an average yield of 104 apples per tree. But because of the size of the garden, for each additional tree planted the yield will decrease by two apples per tree. (a) How many additional trees should be planted to maximize the total yield of apples

Answer:

The angle between them is 60 degrees

Step-by-step explanation:

Given

[tex]a = 2i + j -3k[/tex]

[tex]b = 3i - 2j -k[/tex]

Required

The angle between them

The cosine of the angle between them is:

[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]

First, calculate a.b

[tex]a \cdot b =(2i + j -3k) \cdot (3i - 2j -k)[/tex]

Multiply the coefficients of like terms

[tex]a \cdot b =2 * 3 - 1 * 2 - 3 * -1[/tex]

[tex]a \cdot b =7[/tex]

Next, calculate |a| and |b|

[tex]|a| = \sqrt{2^2 + 1^2 + (-3)^2[/tex]

[tex]|a| = \sqrt{14[/tex]

[tex]|b| = \sqrt{3^2 + (-2)^2 + (-1)^2}[/tex]

[tex]|b| = \sqrt{14}[/tex]

Recall that:

[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]

This gives:

[tex]\cos(\theta) = \frac{7}{\sqrt{14} * \sqrt{14}}[/tex]

[tex]\cos(\theta) = \frac{7}{14}[/tex]

[tex]\cos(\theta) = 0.5[/tex]

Take arccos of both sides

[tex]\theta =\cos^{-1}(0.5)[/tex]

[tex]\theta =60^o[/tex]

Answer:

0,00567×10¹

Step-by-step explanation:

Para convertir a notación decimal:

0.00567×10¹

Answer:

x > 2, x < -8

Interval notation:

( -infinity, -8) U (2, infinity)

Step-by-step explanation:

x(x+6) > 16

distribute x into x+6, multiply

x^2 + 6x > 16

bring 16 to left side, subtract

x^2 + 6x - 16 > 0

factors of -16 that add to +6 is -2 and +8

(x - 2)(x + 8) > 0

solve for x:

x < -8,  x > 2

Interval notation:

( -infinity, -8) U (2, infinity)

Answer:

You make me feel like I can do anything and I am so happy to be with you. Thank you for being the wonderful, amazing person that you are. You surprise me every day and you warm my heart every night. I am the person I am today because you've loved me and helped me, love.

Answer:

Ok so on a clock there is 12 numbers where 12 is on top so at 12 am and 12 pm noon and midnight you will be at the top of the clock

Hope This Helps!!!

During the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.

To determine the time(s) during the ride on the London Eye when you are at the same height as the top of the Elizabeth Tower (commonly known as Big Ben), we need to consider the height of the London Eye and its rotational motion.

Given that the Elizabeth Tower is 320 feet tall, we need to find the position of the London Eye when its height aligns with the top of the tower.

The London Eye has a height of 443 feet, and it completes one full rotation in approximately 30 minutes (or 1800 seconds). This means that it moves at a constant angular velocity of 360 degrees per 1800 seconds.

To find the time(s) when the heights align, we can set up a proportion:

(Height of the Elizabeth Tower) / (Height of the London Eye) = (Angle covered by the London Eye) / 360 degrees

Substituting the given values:

320 / 443 = (Time to align) / 1800

Simplifying the equation:

(Time to align) = (320 / 443) * 1800

Calculating the value:

(Time to align) ≈ 1303.16 seconds

Converting the time to minutes and seconds:

(Time to align) ≈ 21 minutes and 43.16 seconds

Therefore, during the ride on the London Eye, you will be at the same height as the top of the Elizabeth Tower at approximately 21 minutes and 43.16 seconds after the start of the ride.

To know more about  London Eye. here

https://brainly.com/question/16401602

#SPJ2

Answer:

A

Step-by-step explanation:

small dog eats 3/4 cup each day

large dog eats 1 cup each day

~after 1 week (x7)~

small dog = 5.25 cups

large dog = 7 cups

(7-5.25=1.75)

= therefore 1 and 3/4 cups

Answer:

The variance of total loss is 8000000

Step-by-step explanation:

Let

[tex]X \to[/tex] Number of hurricane

Poisson [tex]E(X) = 4[/tex]

[tex]Y \to[/tex] Loss in each hurricane

Exponential [tex]E(Y) = 1000[/tex]

[tex]T \to[/tex] Total Loss

Required

The variance of the total loss

This is calculated as:

[tex]Var(T) = Var(E(T|X)) + E(Var(T|X))[/tex]

Where:

[tex]E(T|X) \to[/tex] Expected total loss given X hurricanes

And it is calculated as:

[tex]E(T|X) = E(Y) *N[/tex] --- Expected Loss in each hurricane * number of loss

[tex]Var(T|X) \to[/tex] Variance of total loss given X hurricanes

And it is calculated as:

[tex]Var(T|X) = Var(Y) * N[/tex] ---- --- Variance of loss in each hurricane * number of loss

So, we have:

[tex]Var(T) = Var(E(T|X)) + E(Var(T|X))[/tex]

[tex]Var(T) = Var(E(Y) * N) + E(Var(Y) * N)[/tex]

For exponential distribution;

[tex]Var(Y) = E(Y)^2[/tex]

So, we have:

[tex]Var(T) = Var(E(Y) * X) + E(E(Y)^2 * X)[/tex]

Substitute values

[tex]Var(T) = Var(1000 * X) + E(1000^2 * X)[/tex]

Simplify:

[tex]Var(T) = Var(1000 * X) + 1000^2E(X)[/tex]

Using variance formula, we have:

[tex]Var(T) = 1000^2Var(X) + 1000^2E(X)[/tex]

For poission distribution:

[tex]Var(X) = E(X)[/tex]

So, we have:

[tex]Var(X) = E(X) = 4[/tex]

The expression becomes:

[tex]Var(T) = 1000^2*4 + 1000^2*4[/tex]

[tex]Var(T) = 1000000*4 + 1000000*4[/tex]

[tex]Var(T) = 4000000 + 4000000[/tex]

[tex]Var(T) = 8000000[/tex]

Answer:

0.25

Step-by-step explanation:

Given that :

Charity raffle price = $1000

Amount of ticket sold = 4000

Only one winner is to be selected ;

Point ticket buyer is expected to break even :

Probability of winning = 1 / number of ticket sold = 1 / 4000 = 0.00025

P(winning) * raffle price = 0.00025 * 1000 = 0.25

Answer:

45°

Step-by-step explanation:

<lmk=90°

angles in a triangle add up to 180

45+90+<o=180

<o=180-135

<o=45

Answer:

∠ O = 45°

Step-by-step explanation:

The angle between the tangent and the radius at the point of contact is 90°

The sum of the 3 angles in Δ OML is 180° , then

∠ O = 180° - (90 + 45)° = 180° - 135° = 45°

Answer:

plese mark me brainlist

Step-by-step explanation:

thankyou and have nice day

Answer:

7 miles

Step-by-step explanation:

* means multiply

7/10 * 10 = 7

Answer:

71

Step-by-step explanation:

The measure of angle WXY will be thee ame as the measure of the intercepted arc, 109°.

W and Y are both tangent to the circle; this means angle XWZ and angle XYZ are both 90°.

Every quadrilateral has a total measure of 360°; to find the measure of WZY, we subtract:

360-90-90-109 = 71°

The measure of angle WZY (∠WZY) is; 71°

From the attached image, we can say that the measure of ∠WXY will be the same as the measure of the intercepted arc, 109°.

Now, W and Y are both tangent to the circle and this means that ∠XWZ and ∠XYZ are both equal to 90°.

Now, every quadrilateral has a total internal sum of angles as 360°.

Thus,  ∠WZY is gotten from;

∠WZY = 360 - (90 + 90 + 109)

∠WZY = 71°

Read more about angles in cyclic quadrilaterals at; https://brainly.com/question/24368895

Answer:

so first we start from the left

425*167=70975

but instead of adding this to 233 we use pemdas so instead we do

233*425=99025

now we add them together

70975+99025=170000

Hope This Helps!!!

Answer:

170,000

Step-by-step explanation:

425 × 167 + 233 × 425

= (425 × 167) + (233 × 425)

= 70,975 + 99,025

= 170,000

Answer:

6546 students would need to be sampled.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.

This means that [tex]n = 200, \pi = \frac{118}{200} = 0.59[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?

n students would need to be sampled, and n is found when M = 0.01. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.01 = 1.645\sqrt{\frac{0.59*0.41}{n}}[/tex]

[tex]0.01\sqrt{n} = 1.645\sqrt{0.59*0.41}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.59*0.41}}{0.01}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645\sqrt{0.59*0.41}}{0.01})^2[/tex]

[tex]n = 6545.9[/tex]

Rounding up:

6546 students would need to be sampled.

Answer:

1) C

2) D

3) A

4) B

hope it helps

Answer:

SAS=side angle side

there is two side and one angle

Answer:

SAS theorem

explanation:

These are indeed equivalent, and this identity is one of DeMorgan's laws.

The 6th column is the negation of the 5th column. For example, the first row says

not p or q

is true (T), so the negation would be false (F). The 5th column reads {T, F, T, T}, so the next column should be {F, T, F, F}.

Then in the 7th/last column, you are checking the truth value of the statement

p and not q

For example, in the first row, both p and q are true (T). This means (not q) is false, so (p and not q) is false (F). The last column should end up reading {F, T, F, F}, same as the previous column.

Answer:

[tex](a)\ P(White) = \frac{1}{2}[/tex]

(b) 10 additional white balls

(c) 10 additional black balls

Step-by-step explanation:

Given

[tex]White = 5[/tex]

[tex]Black =3[/tex]

[tex]Red = 2[/tex]

Solving (a): P(White)

This is calculated as:

[tex]P(White) = \frac{White}{Total}[/tex]

[tex]P(White) = \frac{5}{5+3+2}[/tex]

[tex]P(White) = \frac{5}{10}[/tex]

[tex]P(White) = \frac{1}{2}[/tex]

Solving (b): Additional white balls, if [tex]P(White) = \frac{3}{4}[/tex]

Let the additional white balls be x

So:

[tex]P(White) = \frac{White+x}{Total+x}[/tex]

This gives:

[tex]\frac{3}{4} = \frac{5+x}{10+x}[/tex]

Cross multiply

[tex]30+3x = 20 + 4x[/tex]

Collect like terms

[tex]4x - 3x = 30 - 20[/tex]

[tex]x = 10[/tex]

Hence, 10 additional white balls must be added

Solving (c): Additional black balls, if [tex]P(White) = \frac{1}{4}[/tex]

Let the additional black balls be x

So:

[tex]P(White) = \frac{White}{Total+x}[/tex]

So, we have:

[tex]\frac{1}{4} = \frac{5}{10+x}[/tex]

Cross multiply

[tex]10+x = 5 * 4[/tex]

[tex]10+x = 20[/tex]

Collect like terms

[tex]x = 20 -10[/tex]

[tex]x = 10[/tex]

Hence, 10 additional black balls must be added

Answer:

26.59 minutes

Step-by-step explanation:

Let's say the time needed to do the driveway combined is x. Sue does y parts of the driveway, and Tom does z parts of the driveway. Combined, y + z = 100% = 1, as they finish the whole driveway.

Next, Tom will take 45 * z minutes to do his part of the driveway. For example, if he did 50% = 0.5 of the driveway, he would take 45 * 0.5 = 22.5 minutes to do it. Similarly, Sue will take 65 *y minutes to do her part of the driveway. Since they will finish at the same time, we can say

45 * z = 65 * y

y + z = 1

Therefore, if we subtract y from both sides of the second equation, we have

z = 1-y

We can then plug 1-y in for z in the first equation to get

45 * (1-y) = 65 * y

45 - 45*y = 65*y

add both sides by 45 * y to separate the y values and their coefficients

45 = 110 * y

divide both sides by 110 to find y

y = 45/110 = 0.409

Use 1-y=z to get z = 1-0.409 = 0.59

Therefore, 45*z = 26.59 = 65*y

Answer:

11 + 10i

Step-by-step explanation:

Just treat i like any other variable, and combine like terms. Hope that helps!

Answer:

Answer is 6.

Step-by-step explanation:

The product is

[tex]15\times \frac{2}{5}[/tex]

Now, it does not means that the product of two quantities is always more than the individual quantities.

here, 2/5 is a part of whole.

So,

The product is

[tex]15\times \frac{2}{5}\\\\=3\times 2\\\\= 6[/tex]

The answer is 6 which is less than 15.

Here, it is the 2/5 part of whole 15.

Answer:

100

Step-by-step explanation:

f(1) = 1

f(2) = -10×f(1) = -10 × 1 = -10

f(3) = -10×f(2) = -10 × -10 × f(1) = -10 × -10 × 1 = 100

f(n) = -10 to the power of n-1

Answer:

c - 100

Step-by-step explanation:

Answer:

A 1/2

Step-by-step explanation:

Ratio of short length to hypotenuse

= cos60

= 1/2

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

[tex]\%\text{ decrease}=\dfrac{\text{Initial value - New value}}{\text{Initial value}}\times 100[/tex]

The percentage decrease in between 1950 and 1960 is:

[tex]\%\text{ decrease}=\dfrac{4-3.5}{4}\times 100[/tex]

[tex]\%\text{ decrease}=\dfrac{0.5}{4}\times 100[/tex]

[tex]\%\text{ decrease}=\dfrac{50}{4}[/tex]

[tex]\%\text{ decrease}=12.5[/tex]

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

[tex]\text{Expected enrollment}=7+\dfrac{12.5}{100}\times 7[/tex]

[tex]\text{Expected enrollment}=7+0.875[/tex]

[tex]\text{Expected enrollment}=7.875[/tex]

Therefore, the expected enrollment in 2010 is 7.875 thousands.

Pentagon has sum of 540°

9514 1404 393

Answer:

  56 miles

Step-by-step explanation:

Let d represent the distance in miles. Then the drive time in hours is ...

  d/42 = d/48 +10/60

  8d = 7d +56 . . . . . . . . multiply by 336

  d = 56

The distance from Jeremy's home to work is 56 miles.

_____

At 42 mph, his commute time is 1 hour 20 minutes.

Answer:

a) A

b) C and E

c) C, D and F

d) two

e) Equal

Answer:

[tex]Var = 1.9[/tex]

Step-by-step explanation:

Given

[tex]p = \frac{1}{20}[/tex]  i.e. 1 per 20cc of water

[tex]n = 40[/tex] -- sample size

Required

The variance

This is calculated using:

[tex]Var = np(1 - p)[/tex]

So, we have:

[tex]Var = 40 * \frac{1}{20} * (1 - \frac{1}{20})[/tex]

[tex]Var = 40 * \frac{1}{20} * \frac{19}{20}[/tex]

[tex]Var = 2 * \frac{19}{20}[/tex]

[tex]Var = \frac{38}{20}[/tex]

[tex]Var = 1.9[/tex]