A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
over the next few minutes?
Molecules in both the metal and the surrounding air will start moving at lower speeds.
Molecules in both the metal and the surrounding air will start moving at higher speeds.
The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.
The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Answers

Answer 1

Answer:

molecules will speed up

Explanation:


Related Questions

POINTSSS AND BRAINLIEST IF YOU ANSWER CORRECTLY!!! Write about the law of conservation of energy and where light energy goes. thank you :)

Answers

Answer:

The law of conservation of energy states that the total energy is constant in any process. Energy may change in form or be transferred from one system to another, but the total remains the same.

Could you please help me with the two most recent questions of mine on my page? I will give u brainliest and 20 points! :))) X

How many moles of hydrogen are needed to react with 0.234 mol oxygen according to this equation? 2H2 + O2 -> 2H2O

Answers

The number of moles of hydrogen to be 0.468.

The balanced chemical equation :

2H₂ + O₂ → 2H₂O

This implies that 2 moles of hydrogen and one mole of oxygen are required to produce 2 moles of water.

or

Thus molar ratio of ( H₂ : O₂)= 2 : 1.  

So, it requires double the moles of oxygen to get the required moles of water.

Number of moles of oxygen= 0.234 mol

So following the molar ratio concept:

We will get:

The number of moles of hydrogen to be 0.468.

Learn more:

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What is the smallest ph possible

Answers

Answer: -3.6

Explanation:

The lowest pH of -3.6 is the lowest known for any water in the environment

Balance the single replacement chemical reaction.

Answers

Explanation:

B) 3CuCl2+2AL..….2AlCl3+3Cu

hope it helps.

Balanced Equation:

3CuCl₂ + 2Al = 2AlCl₃ + 3Cu

What needs to be taken into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution?​

Answers

Hi how are you doing today

The more concentrated the buffer solution, the greater its buffer capacity.

What is an acid?

An acid is any substance that in water solution tastes sour, changes blue litmus paper to red, reacts with some metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions.

The more concentrated the buffer solution, the greater its buffer capacity.

If the buffer capacity is 10 times larger, then the buffer solution can absorb 10 times more strong acid or base before undergoing a significant change in pH.

Hence, we need to take this into consideration when increasing either the acid or base concentration in order to increase the buffering capacity of a solution.

Learn more about acid here:

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What is the reducing agent in the following reaction?

2 Br−(aq) + H2O2(aq) + 2 H+(aq) → Br2(aq) + 2 H2O(l)

Answers

Answer:

the reducing agent is Bromine

The oxidation state of an element is calculated by subtracting and the total sum of oxidation states of all the individual atom (excluding the one that has to be calculated) from total charge on the molecule. Bromine is the reducing agent in the following reaction.

What is oxidation state?

Oxidation state of an element is a number that is assigned to an element in a molecule that represents the number of electron gained or lost during the formation of that molecule or compound.

The ionic equation is given as

2 Br⁻(aq) + H[tex]_2[/tex]O[tex]_2[/tex](aq) + 2 H⁺(aq) → Br[tex]_2[/tex](aq) + 2 H[tex]_2[/tex]O(l)

The oxidation state of bromine on reactant side is -1 while on product side it is 0 so, oxidation state of bromine has increased by 1 so,  bromine is oxidized. If it is oxidized that means it must have reduced someone. So, bromine is acting as a reducing agent.

Therefore, bromine is the reducing agent in the given reaction.

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3 attempts left
Check my work
Enter your answer in the provided box.
The pressure inside a 1.0 L balloon at 25°C was 750 mm Hg. What is the pressure (in mmHg) inside the
balloon when it is cooled to -65°C and expands to 3.3 L in volume?
mm Hg

Answers

Answer:

shhsss×<×>×××<××××

Explanation:

4×738×8<#329×

Can someone please help with this !!!!

Answers

i think it's less, more, more. correct me if i'm wrong

Five identical test tubes are each filled from the following five copper (11) sulfate stock solutions. Which of the following test tubes would appear the lightest blue?

a) Stock solution made form 0.200 moles of CuSO4 dissolved to a total volume of 400 ml
b) Stock solution made form 0.150 moles of CuSO4 dissolved to a total volume of 300 mL
C)Stock solution made form 0.250 moles of CuSO4 dissolved to a total volume of 500 ml
d) Stock solution made form 0.175 moles of CuSO4 dissolved to a total volume of 400 ml
e) Stock solution made form 0.125 moles of CuSO4 dissolved to a total volume of 300 ml​

Answers

Answer:

deez cutz

Explanation:

did i get it right

Calculate how many grams of sodium acetate you expected to make from your starting amount of sodium bicarbonate (0.5g). This is your theoretical yield.

Equation: NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2

Answers

I think the answer is D

Joan performed a shadow puppet play for her younger brother by shining a flashlight on paper cutouts behind a curtain. What happens to the light from the flashlight?

Answers

Answer:

The light is transmitted through the curtain.

Explanation:

I believe this might be the answer, please comment if it’s incorrect

_FeCI3 + _ NaOH = _ NaCI + _Fe(OH)3 balance and strength the coefficients for each substance

Answers

Answer:

FeCl₃ + 3 NaOH ⇒ 3 NaCl + Fe(OH)₃

Explanation:

Let's consider the following unbalanced equation. This is a double displacement reaction.

FeCl₃ + NaOH ⇒ NaCl + Fe(OH)₃

We will start balancing Cl atoms by multiplying NaCl by 3.

FeCl₃ + NaOH ⇒ 3 NaCl + Fe(OH)₃

Then, we will get the balanced equation by multiplying NaOH by 3.

FeCl₃ + 3 NaOH ⇒ 3 NaCl + Fe(OH)₃

What is the pressure inside a container of 3 moles of gas with a volume of 60 Liters at a temperature of 400 K?


I just need the answer not a link please :)

Answers

1.64 atm

PV = nRT —> P = nRT / V

n = 3 moles
R = 0.08206 L atm / mol K
T = 400 K
V = 60 L

P = (3)(0.08206)(400) / 60 = 1.64 atm

What happens to the solar energy absorbed by plants during photosynthesis ?

Answers

Answer:

Photosynthesis in plants converts solar energy into chemical energy using electrons and protons from water. in plants involves a series of steps and reactions that use solar energy, water, and carbon dioxide to produce organic compounds and oxygen.

Explanation:

Answer:

its is used to make sugar which plants eat think it goes through like glycose or something

Explanation:

help me, please - i will make you brainliest

Answers

Answer:the correct answer is a.

PlEASE HELP! 40!

A radioactive form of sodium pertechnetate is used as a brain-scanning agent in medicine. Quantitative analysis of a sample with a mass of 0.8961 g found 0.1114 g of sodium and 0.4749 g of technetium. The remainder was oxygen. Determine the empirical formula.

Answers

Answer:

moles Na = 0.1114 g / 22.9898 g/mol=0.004846

moles Tc = 0.4562g /98.9063 g/mol=0.004612

mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g

moles O = 0.3285 g/ 15.999 g/mol=0.02053

divide by the smallest

0.02053/ 0.004612 =4.45 => O

0.004846/ 0.004612 = 1.0 => Tc

to get whole numbers multiply by 2

Na2Tc2O 9

Explanation:

Hope it right hope it helps

g Consider (12.5 A) micro-grams of a radioactive isotope with a mass number of (78 B) and a half-life of (32.6 C) million years. If energy released in each decay is 32.6 keV, determine the total energy released in joules (J) in 1 (one) year. Give your answer with three significant figures.

Answers

Answer:

Energy released =  18.985 J

Explanation:

The  exponential decay of radioactive substance is given by -

N(t) = N₀ [tex]e^{-kt}[/tex]

where

N₀ = initial quantity

k = decay constant

Half life, [tex]t_{1/2} = \frac{ln 2}{k}[/tex]

⇒[tex]k = \frac{ln 2}{t_{1/2} }[/tex]

Given,

N₀ = 12.5 + 3 = 15.5 × 10⁻⁶ gm

[tex]t_{1/2}[/tex] = 32.6 + 18 = 50.6 × 10⁶ years

So,

[tex]k = \frac{ln 2}{50.6 * 10^{6} }[/tex] = 1.361 × 10⁻⁸ year⁻¹

Now,

N(1) = 15.5 × 10⁻⁶  [tex]e^{-1.361*10^{-8} *1}[/tex]

      = 15.49999978904

Now,

Substance decayed = N₀ - N(t)

                                 = 15.5 × 10⁻⁶ - 15.49999978904 × 10⁻⁶

                                 = 21.095 × 10⁻¹⁷ kg

⇒Δm = 21.095 × 10⁻¹⁷ kg

So,

Energy released = Δmc²

                           = 21.095 × 10⁻¹⁷ × 3 ×10⁸ × 3 × 10⁸

                          = 189.855 ×10⁻¹

                          = 18.985 J

⇒Energy released =  18.985 J

Check all that apply...helppppp

Answers

Answer:

dfgh

Explanation:

Do these two points (equivalence point and titration endpoint) in a titration occur when the same volume of titrant has been added? please Explain.

Answers

Answer:

Show a picture

Explanation:

PLEASE HELP ME PLEASEEE AND QUICK.

NO TROLL ACCOUNT AND POSTING A LINK TO NO WHERE, PLEASE. DONT. UR WASTING MY TIME.
SOMEONE PLEASE BE NICE.

Please answer ALL THREE if u can, thank you so so so so much!!!

Answers

Answer:

Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

Today, there are ____ GMO crops currently produced in the US.

A. 120
B. 10
C. 55
D. 1000

Answers

Answer: I think that is 55

Explanation: I hope I help

The answer is c. Have a good day/night.

Given a volume of 47.8 mL of gas at STP, _______________ moles of O2 exist

Answers

At STP, a mole of any gas occupies 22.4 L. So given 48.7 mL—or 0.0487 L—of O2 gas at STP, the number of moles of O2 that exist is 0.00217 moles.

Due today please answer! Can we make electricity in the ocean?
1: Certainly can
2: No way
3: Yes but fossil fuels will pollute the water and the air
4: Yes by grabbing on to an electric eel

Answers

Answer:

3

Explanation: good luck dude I believe in u

Pls help I need help ASAP!!! Be accurate

Answers

2nd choice is answer
121.2 is the awnser

What is the minimum temperature
needed to dissolve 35 grams of KCl in 100 grams of water?

Answers

Answer:

[tex]30^{\circ}\text{C}[/tex]

Explanation:

To know the temperature at which KCl dissolves in water we need to refer to the general solubility curves.

In the case of [tex]KCl[/tex], [tex]35\ \text{g}[/tex] of it will dissolve in [tex]100\ \text{g}[/tex] of water at a minimum temperature of [tex]30^{\circ}\text{C}[/tex].

So, the the minimum temperature needed to dissolve 35 grams of KCl in 100 grams of water is [tex]30^{\circ}\text{C}[/tex].



What is the energy of an electron in a Li+ ion when an electron moves from n = 2 to n =3?

Answers

Answer:

The question wants you to determine the energy that the incoming photon must have in order to allow the electron that absorbs it to jump from

n

i

=

2

to

n

f

=

6

.

A good starting point here will be to calculate the energy of the photon emitted when the electron falls from

n

i

=

6

to

n

f

=

2

by using the Rydberg equation.

1

λ

=

R

(

1

n

2

f

1

n

2

i

)

Here

λ

si the wavelength of the emittted photon

R

is the Rydberg constant, equal to

1.097

10

7

m

1

Plug in your values to find

1

λ

=

1.097

10

7

.

m

1

(

1

2

2

1

6

2

)

1

λ

=

2.4378

10

6

.

m

1

This means that you have

λ

=

4.10

10

7

.

m

So, you know that when an electron falls from

n

i

=

6

to

n

f

=

2

, a photon of wavelength

410 nm

is emitted. This implies that in order for the electron to jump from

n

i

=

2

to

n

f

=

6

, it must absorb a photon of the same wavelength.

100.00 mL of 0.15 M nitrous acid (HNO2) are titrated with a 0.15 M NaOH solution. (a) Calculate the pH for the initial solution. (b) Calculate the pH for the point at which 80.0 mL of the base has been added. (c) Calculate the pH for the equivalence point. (d) Calculate the pH for the point at which 105 mL of the base has been added.

Answers

Answer:

a. pH = 2.04

b. pH = 3.85

c. pH = 8.06

d. pH = 11.56

Explanation:

The nitrous acid is a weak acid (Ka = 5.6x10⁻⁴) that reacts with NaOH as follows:

HNO₂ + NaOH → NaNO₂(aq) + H₂O(l)

a. At the beginning there is just a solution of 0.12M HNO₂. As Ka is:

Ka = [H⁺] [NO₂⁻] / [HNO₂]

Where [H⁺] and [NO₂⁻] ions comes from the same equilibrium ([H⁺] = [NO₂⁻] = X):

5.6x10⁻⁴ = X² / 0.15M

8.4x10⁻⁵ = X²

X = [H⁺] = 9.165x10⁻³M

As pH = -log [H⁺]

pH = 2.04

b. At this point we have HNO₂ and NaNO₂ (The weak acid and the conjugate base), a buffer. The pH of a buffer is obtained using H-H equation:

pH = pKa + log [NaNO₂] / [HNO₂]

Where pH is the pH of the buffer,

pKa is -log Ka = 3.25

And [NaNO₂] [HNO₂] could be taken as the moles of each compound.

The initial moles of HNO₂ are:

0.100L * (0.15mol / L) = 0.015moles

The moles of base added are:

0.0800L * (0.15mol / L) = 0.012moles

The moles of base added = Moles of NaNO₂ produced = 0.012moles.

And the moles of HNO₂ that remains are:

0.015moles - 0.012moles = 0.003moles

Replacing in H-H equation:

pH = 3.25 + log [0.012moles] / [0.003moles]

pH = 3.85

c. At equivalence point all HNO2 reacts producing NaNO₂. The volume added of NaOH must be 100mL. That means the concentration of the NaNO₂ is:

0.15M / 2 = 0.075M

The NaNO₂ is in equilibrium with water as follows:

NaNO₂(aq) + H₂O(l) ⇄ HNO₂(aq) + OH⁻(aq) + Na⁺

The equilibrium constant, kb, is:

Kb = Kw/Ka = 1x10⁻¹⁴ / 5.6x10⁻⁴ = 1.79x10⁻¹¹ = [OH⁻] [HNO₂] / [NaNO₂]

Where [OH⁻] = [HNO₂] = x

[NaNO₂] = 0.075M

1.79x10⁻¹¹ = [X] [X] / [0.075M]

1.34x10⁻¹² = X²

X = 1.16x10⁻⁶M = [OH⁻]

pOH = -log [OH-] = 5.94

pH = 14-pOH

pH = 8.06

d. At this point, 5mL of NaOH are added in excess, the moles are:

5mL = 5x10⁻³L * (0.15mol / L) =7.5x10⁻⁴moles NaOH

In 100mL + 105mL = 205mL = 0.205L. [NaOH] = 7.5x10⁻⁴moles NaOH / 0.205L =

3.66x10⁻³M = [OH⁻]

pOH = 2.44

pH = 14 - pOH

pH = 11.56

A compound with an approximate molar mass of
65.0g/mol is made up of C, H and Cl. This same
Compound contains 55% of Cl by mass .lf 9g
of the compound contains 4.19 x 10²³ atoms,
determine the compound's:
a empirical formular and molecular formular​

Answers

g about the answer if I don’t do this I Will fail!!!!!! NO LINKS NO LYING

Plz answer the first two questions and maybe the third​. I will give brainliest.

Answers

Answer:

1. 24.45 moles

2. 437.90 grams

Bonus :

0.75 grams

Explanation:

Hope it was helpful ;)

how many moles are there in 2.20 x 10^23 molecules of Na2SO4

Answers

Answer:

Explanation:

450 grams of Na2SO4? 450 Na soullnol Na2SO4 16.02x1023 molec, Na₂SO4 = 119x1024. | 142.05g Na25041 Imol Naz

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