A line l2 is perpendicular to the line x + 2y – 5 = 0 without computing the gradient of this
line find the equation of l2 if it passes through (3, 4)​

Answer:

the answer is c square root 52

Step-by-step explanation:

just got a 100

The distance from Beth’s house to the coffee shop, which are graphed on a coordinate plane is √(52) units.

The distance formula is used to measure the distance between the two points on a coordinate plane.

Let the two coordinate  point on a coordinate plane is ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]). Thus, the distance between these two can be given as,

[tex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

When graphed on a coordinate plane Beth’s house is located at (4, 3) and the coffee shop is located at the point (–2, –1).

Here, each grid line on the coordinate plane represents 1 mile.

Using the distance formula for these point, the distance from Beth’s house to the coffee shop can be given as,

[tex]d=\sqrt{(4-(-2)^2)+(3-(-1))^2}\\d=\sqrt{6)^2+(4)^2}\\d=\sqrt{36+16}\\d=\sqrt{52}[/tex]

Hence, the distance from Beth’s house to the coffee shop, which are graphed on a coordinate plane is √(52) units.

Learn more about the distance formula here;

https://brainly.com/question/661229

Multiply the length by the height:

6.5 x 2 = 13

The width is the volume divided by 13

Width = 52/13 = 4 m

Answer:

Step-by-step explanation:

at x = -7, the polynomail function f(x) has a zero (x-intercept)

Sorry I did it wrong.

Answer:

(0, -5) and (-16, -17)

Step-by-step explanation:

You can plug in the points into the function to test them.

(0, -5)

3(0) - 4(-5) - 8 = 12

20 - 8 = 12

12 = 12

(8, 2)

3(8) - 4(2) - 8 = 12

24 - 8 - 8 = 12

8 ≠ 12

(-16, -17)

3(-16) - 4(-17) - 8 = 12

-48 + 68 - 8 = 12

12 = 12

3(-1) - 4(-8) - 8 = 12

-3 + 32 - 8 = 12

21 ≠ 12

3(-40) - 4(-34) - 8 = 12

-120 + 136 - 8 = 12

8 ≠ 12

Answer:

15 x /2

Step-by-step explanation:

Answer:

V= 160 ft

Step-by-step explanation:

First 10×8×6 then ÷ 3 = 160

Answer: C. 10x-3

Step-by-step explanation: I got this question correct on Edmentum.

The value of the expression will be 10x – 3. Then the correct option is C.

The value that approaches the output for the given input value. Limits are a very important tool in calculus.

The function is defined as,

f(x) = 5x² – 3x + 2

Then the value of the expression will be

[tex]\rightarrow \displaystyle \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}[/tex]

Substitute the value of the function, then the value of the expression will be

[tex]\rightarrow \displaystyle \lim_{h \to 0} \dfrac{5(x+h)^2 - 3(x + h) + 3- 5x^2 + 3x - 3}{h}\\\\\\\rightarrow \displaystyle \lim_{h \to 0} \dfrac{5x^2 + 5h^2 + 10xh - 3x - 3h + 3- 5x^2 + 3x - 3}{h}\\\\\\\rightarrow \displaystyle \lim_{h \to 0} \dfrac{ 5h^2 + 10xh - 3h }{h}\\[/tex]

Simplify the equation further, then we have

[tex]\rightarrow \displaystyle \lim_{h \to 0} 5h + 10x - 3 \\[/tex]

Substitute the value of the h = 0, then the value of the expression will be

⇒ 5(0) + 10x – 3

⇒ 10x – 3

Then the correct option is C.

More about the limit link is given below.

https://brainly.com/question/8533149

#SPJ2

Answer:

A

Step-by-step explanation:

Answer:

$192

Step-by-step explanation:

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

[tex]L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}[/tex]

When t = 0, A(0) = 0 (since the forest floor is initially clear)

[tex]A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L[/tex]

[tex]A = \frac{L}{k} - \frac{L}{k} e^{kt}[/tex]

So, D = R - A =

[tex]D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}[/tex]

when t = 0(at initial time), the initial value of D =

[tex]D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}[/tex]

Step-by-step explanation:

.........................

.......

Answer:

a) σ  =  4933,64

b) CI 99%  = ( - 5746  ;  7194 )

c) No difference in brands

Step-by-step explanation:

Brand 1:

n₁   =  8

x₁   = 38222

s₁   = 4974

Brand 2:

n₂  = 8

x₂  = 37498

s₂  = 4893

As n₁  =  n₂  = 8       Small sample  we work with t -student table

degree of freedom      df  = n₁  +  n₂  - 2    df = 8 +8 -2  df = 14

CI = 99 %   CI  =  0,99

From  t-student table we find   t(c)  = 2,624

CI  =   (  x₁  -  x₂ ) ±  t(c) * √σ²/n₁   +  σ²/n₂

σ² = [( n₁  -  1 ) *s₁² +  ( n₂  -  1  ) * s₂² ] / n₁ +n₂ -2

σ² = 7* (4974)² + 7*( 4893)² / 14

σ² = 24340783       σ  =  4933,64

√ σ²/n₁  +  σ²/n₂     =  √ 24340783/8   +  24340783/8

√ σ²/n₁  +  σ²/n₂     =  2466

CI 99%  =  (  x₁  -  x₂ ) ± 2,624* 2466

CI 99%  =   724  ± 6470

CI 99%  = ( - 5746  ;  7194 )

As we can see CI 99% contains 0 and that means that there is not statistical difference between mean life of the two groups

Answer: 120cm squared

Step-by-step explanation: To do this you can cut off one of the 'triangle ends' on the trapezoid and add it to the other side to make a rectangle. Since the top is 10cm, each triangle will have a base of 5cm, so the bases will be 15cm when you subtract 20-5. Then you just have 8 * 15 which is 120cm SQUARED. This may have been a little confusing so i attachecd a diagram.

Answer:1,250

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

80 miles per hour, each hour it will travel 80 miles so for two hours tou do

80 x 2 = 160

Answer:

D

Step-by-step explanation:

80x2=40

it's just simple multiplecation but then again I cant spell multiplication so I mean

Answer:

27) x = 2^(y) – 5.

Asymptote: x = -5.

D: x > -5; (-5, infinity).

R: -infinity < f(x) < infinity; ARN;

(-infinity, infinity).

x → -infinity, f(x) → -infinity.

x → +infinity, f(x) → +infinity.

________________________

28) x = 2^-(y–3).

Asymptote: x = 0.

D: x > 0; (0, infinity).

R: -infinity < f(x) < infinity; ARN;

(-infinity, infinity).

x → -infinity, f(x) → +infinity.

x → +infinity, f(x) → -infinity.

________________________

29) x = 4^(y–2) + 1.

Asymptote: x = 1.

D: x > 1; (1, infinity).

R: -infinity < f(x) < infinity; ARN;

(-infinity, infinity).

x → -infinity, f(x) → -infinity.

x → +infinity, f(x) → +infinity.

________________________

Answer:

its 4

Step-by-step explanation:

Answer:

hello your question is incomplete below is the complete question

verify the conclusion of Green's Theorem by evaluating both sides of the equation for the field F= -2yi+2xj. Take the domains of integration in each case to be the disk. R: x^2+y^2 < a^2 and its bounding circle C: r(acost)i+(asint)j, 0<t<2pi. the flux is ?? the circulation is ??

answer :  attached below

Step-by-step explanation:

Attached below is the required verification of the conclusion of Green's Theorem

In the attached solution I have  proven that Green's theorem ( ∫∫c F.Dr ) .

i.e. ∫∫ F.Dr = ∫∫r ( dq/dt - dp/dy ) dx dy = 4πa^2

Answer:

34.5 × 2 = 69

Step-by-step explanation:

pretty self explanatory

Answer:

d

Step-by-step explanation:

V=whl=3·4·6=72

D. 6*4*6≠72

Answer:

D 6x6x4

Step-by-step explanation:

the dimensions are 3x6x4 so 6x6x4 is not the volume of this rectangular prism

Answer:

x = 13/8

Step-by-step explanation:

(4x−1)(2)=11

Simplify both sides of the equation.

(4x−1)(2)=11

(4x)(2)+(−1)(2)=11 (Distribute)

8x+−2=118x+−2=11

8x−2=11

Add 2 to both sides.

8x−2+2=11+2

8x=13

Divide both sides by 8.

8x/8 = 13/8

which brings you to the answer of

x = 13/8

(Note:If this was a little confusing,feel free to ask me any questions revolving around this topic)

Answer:

Type 1 error.

Step-by-step explanation:

H0 : μ = 5.1

H1 : μ ≠ 5.1

The Pvalue of the test = 0.003

Decision made by the researcher was conclude that mean weight is not as advertised, that is the researcher rejected the Null hypothesis.

However, when the Pvalue is < α - value , we reject the null ; The type of error the researcher could have made is that ; The mean weight may be truly as advertised, Hence, leading us to make a false positive error, thus is rejecting a true null. This is a TYPE 1 error.

Answer:

The 4th one (bottom)

Step-by-step explanation:

[tex]\frac{2}{3}x - 5 > 3\\\frac{2}{3}x > 3 + 5\\\frac{2}{3}x > 8\\x > 8 / \frac{2}{3} \\x > 12\\[/tex]

> sign means an open circle over 12, shaded/pointing to the right. The 4th option is your answer

Answer:

0.16 probability that in a sample of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The body temperatures of all mosquitoes in a county have a mean of 57∘F and a standard deviation of 10∘F.

This means that [tex]\mu = 57, \sigma = 10[/tex]

Sample of 25:

This means that [tex]n = 25, s = \frac{10}{\sqrt{25}} = 2[/tex]

of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal?

This is 1 subtracted by the pvalue of Z when X = 59. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{59 - 57}{2}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a pvalue of 0.84

1 - 0.84 = 0.16

0.16 probability that in a sample of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal.

Answer:

3

Step-by-step explanation:

For x<=0, f is constant: f(x) =3

-4<0, so f(-4)=3

Answer:

[tex]- 1 \frac{13}{60} [/tex]

Step-by-step explanation:

[tex] - \frac{4}{5} + - \frac{5}{12} \\ \frac{ - 48 - 25}{60} \\ \frac{ - 73}{60} \\ = - 1 \frac{13}{60} [/tex]

Hope this helps you.

Can I have the brainliest please?

Find where the two curves intersect:

y = 6x - 2x ²

y = x ²

6x - 2x ² = x ²   →   3x ² - 6x = 3x (x - 2) = 0   →   x = 0 and x = 2

Now, for a shell of radius x units away from the axis of revolution, the height of the shell would be the vertical distance between the upper curve and the lower curve. For 0 ≤ x ≤ 2, we have 6x - x ² ≥ x ², so the height of any given shell is (6x - x ²) - x ² = 6x - 2x ².

Then volume of the solid is

[tex]\displaystyle 2\pi \int_0^2 x(6x-2x^2)\,\mathrm dx = 2\pi \left(2x^3-\frac{x^4}2\right)\bigg|_0^2 = \boxed{16\pi}[/tex]