Answer:
We conclude that no more than 10% of its microwaves need repair during the first five years of use.
Step-by-step explanation:
We are given that a maker of microwave ovens advertises that no more than 10% of its microwaves need repair during the first 5 years of use.
In a random sample of 50 microwaves that are 5 years old, 12% needed repairs.
Let p = population proportion of microwaves who need repair during the first five years of use.
So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\leq[/tex] 10% {means that no more than 10% of its microwaves need repair during the first five years of use}
Alternate Hypothesis, [tex]H_A[/tex] : p > 10% {means that more than 10% of its microwaves need repair during the first five years of use}
The test statistics that will be used here is One-sample z-test for proportions;
T.S. = [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of microwaves who need repair during the first 5 years of use = 12%
n = sample of microwaves = 50
So, the test statistics = [tex]\frac{0.12-0.10}{\sqrt{\frac{0.10(1-0.10)}{50} } }[/tex]
= 0.471
The value of z-test statistics is 0.471.
Now, at a 0.04 level of significance, the z table gives a critical value of 1.751 for the right-tailed test.
Since the value of our test statistics is less than the critical value of z as 0.471 < 1.751, so we have insufficient evidence to reject our null hypothesis as the test statistics will not fall in the rejection region.
Therefore, we conclude that no more than 10% of its microwaves need repair during the first five years of use.
Help!!!!!!! Thank you!!!!!!!
Answer:
D
Step-by-step explanation:
The ratio of yellow paint to blue paint is 4:3. We can make the largest amount of green paint by using all of the 20 quarts of yellow paint so we have to solve for x in 4:3 = 20:x, since 4 * 5 = 20, 3 * 5 = x so we use 15 qts of blue paint, therefore we will have 20 + 15 = 35 qts of green paint.
Answer:
D
Step-by-step explanation:
In cooking class, Shivani measures a stick
of butter. It is 13 centimeters long, 3
centimeters wide, and 3 centimeters tall. What
is the volume of the stick of butter?
Answer:
117 cm³
Step-by-step explanation:
To find the volume of a rectangular prism, we can simply multiply the length, width and height so the answer is 13 * 3 * 3 = 117 cm³.
Answer:
117 cubic centimeters
Step-by-step explanation:
Assuming that the stick of butter is a perfect rectangular prism, we can calculate the volume by simply multiplying the length, width, and the height as modeled by the volume equation:
V = LWH
For this, the L = 13cm, W = 3cm, and H = 3cm
So our volume in cubic centimeters will be:
V = LWH
V = (13cm) * (3cm) * (3cm)
V = (13cm) * (9cm^2)
V = 117 cm^3
So the volume of the stick of butter is 117 cubic centimeters.
Cheers.
The mean income per person in the United States is $41,500, and the distribution of incomes follows a normal distribution. A random sample of 10 residents of Wilmington, Delaware, had a mean of $47,500 with a standard deviation of $10,600. At the .01 level of significance, is that enough evidence to conclude that residents of Wilmington, Delaware, have more income than the national average?
(a) State the null hypothesis and the alternate hypothesis.
H0: ? ?
H1: ? >
(b) State the decision rule for .01 significance level. (Round your answer to 3 decimal places.)
Reject H0 if t >
(c) Compute the value of the test statistic. (Round your answer to 2 decimal places.)
Value of the test statistic
(d) Is there enough evidence to substantiate that residents of Wilmington, Delaware have more income than the national average at the .01 significance level?
Answer:
A) Null Hypothesis; H0: μ = $41,500
Alternative hypothesis; H1: μ > $41,500
B) Reject H0 is t > 2.821433
C) t = 1.79
D) there is no sufficient evidence to support the claim that residents of Wilmington, Delaware have more income than the national average
Step-by-step explanation:
A) The hypotheses is given as;
Null Hypothesis; H0: μ = $41,500
Alternative hypothesis; H1: μ > $41,500
B) From online t-score calculator attached using significance level of 0.01 and DF = n - 1 = 10 - 1 = 9, we have;
t = 2.821433
Normally, when the absolute value of the t-value is greater than the critical value, we reject the null hypothesis. However, when the absolute value of the t-value is less than the critical value, we fail to reject the null hypothesis.
Thus, if t > 2.821433, we will reject the null hypothesis H0.
C) Formula for the test statistic is;
t = (x' - μ)/(s/√n)
We have, μ = 41500, x' = 47500, s = 10600, n = 10
t = (47500 - 41500)/(10600/√10)
t = 1.79
D) So, 1.79 is less than the t-critical value of 2.821433. Thus, we will fail to reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that residents of Wilmington, Delaware have more income than the national average
Consider the functions
JIGO
For the x-values given in the table below, determine the corresponding values of six) and plot each point on the graph...
Х
-1
0
1
2
G(x)
Answer:
g(x) = 4, 6, 9, 13.5 for the x-values given
Step-by-step explanation:
The table and graph are attached.
Suppose that the director of manufacturing at a clothing factory needs to determine whether a new machine is producing a particular type of cloth according to the manufacturer’s specifications, which indicate that the cloth should have a mean breaking strength of 70 pounds and a standard deviation of 3.5 pounds. A sample of 49 pieces reveals a sample mean of 69.1 pounds.
(a) State the null and alternative hypotheses.
(b) Is there evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength? (Use a 0.05 level of significance.)
(c) Compute the p-value and interpret its meaning.
(d) What will your answer be in (b) if the standard deviation is 1.75 pounds?
(e) What will your answer be in (b) if the sample mean is 69 pounds?
Answer:
a.H0 : u1= u2 against Ha : u1≠ u2 This is a two sided test
b) There isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
c) the p- value is 0.0359*2= 0.0718. It is greater than the value of ∝ so there isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
d) There is enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
e) There isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
Step-by-step explanation:
Formulate the null and alternative hypotheses as
a) H0 : u1= u2 against Ha : u1≠ u2 This is a two sided test
Here ∝= 0.005
For alpha by 2 for a two tailed test Z∝/2 = ± 1.96
Standard deviation = s= 3.5 pounds
n= 49
The test statistic used here is
Z = x- x`/ s/√n
Z= 69.1- 70 / 3.5 / √49
Z= -1.80
Since the calculated value of Z= -1.80 falls in the critical region we reject the null hypothesis.
b) There isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
c) the p- value is 0.0359*2= 0.0718. It is greater than the value of ∝ so there isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
d) If standard deviation is 1.75 pounds
The test statistic used here is
Z = x- x`/ s/√n
Z= 69.1- 70 / 1.75 / √49
Z= -3.6
This value does not fall in the critical region.
d) There is enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
e) If the sample mean is 69 pounds
Z = x- x`/ s/√n
Z= 69.1- 69 / 3.5 / √49
Z= 0.2
This value falls in the critical region
e) There isn't enough evidence that the machine is not meeting the manufacturer’s specifications in terms of the average breaking strength.
3(2+7) - 9 x 7 = 3+8 x 2 x 2 - 4 = 16 ÷ 2 x 5 x 3 ÷ 6 = Please answer! ✨✨
Answer:
At first, we have 3 expressions that are equal.
[tex]3(2+7) - 9 \cdot 7= 3+8 \cdot 2 \cdot 2 - 4[/tex]
[tex]6+21 - 63= 3+32 - 4[/tex]
[tex]-36=31[/tex]
[tex]-36\neq 31[/tex]
This is not true.
In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft. For a group of 1013 adults, the mean of those who do not worry about identify theft is closest to ________.
Answer: 669
Step-by-step explanation:
Given, In a Gallup poll of randomly selected adults, 66% said that they worry about identity theft.
i.e. The proportion of adults said that they worry about identity theft. (p) = 0.66
Sample size : n= 1013
Then , Mean for the sampling distribution of sample proportion = np
= (1013) × (0.66)
= 668.58 ≈ 669 [Round to the nearest whole number]
Hence, the mean of those who do not worry about identify theft is closest to 669 .
The solutions to the equation $(x+1)(x+2) = x+3$ can be written in the form $m+\sqrt n$ and $m-\sqrt n$, where $m$ and $n$ are integers. What is $m+n$?
Answer:
1
Step-by-step explanation:
Hello, please consider the following.
First, we develop and move everything to the left side, then we solve the equation, using the discriminant.
Finally, we get the expression of the two solutions and we can conclude.
[tex](x+1)(x+2)=(x+3)\\\\<=> x^2+3x+2-x-3=0\\\\<=>x^2+2x-1=0\\\\\Delta=b^2-4ac=4+4=8\\\\x_1=\dfrac{-2-\sqrt{8}}{2}=\dfrac{-2-2\sqrt{2}}{2}=-1-\sqrt{2}\\\\x_2=\dfrac{-2+\sqrt{8}}{2}=-1+\sqrt{2}[/tex]
So, m=-1 and n = 2
m+n = -1 + 2 = 1
Thank you
The value of m + n is 1.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Example:
2x + 4 - 9 is an equation.
We have,
(x + 1)(x + 2) = x + 3
x² + 2x + x + 2 = x + 3
x² + 3x + 2 - x - 3 = 0
x² + 2x - 1 = 0
This is in the form of ax² + bx + c = 0
a = 1, b = 2, and c = -1
Now,
Using the determinant.
x = -b ± √(b² - 4ac) / 2a
x = -2 ± √(4 + 4) / 2
x = (-2 ± 2√2) / 2
x = (-1 ± √2)
x = -1 + √2
x = -1 - √2
Now,
The solutions can be written in the form of (m + √n) and (m - √n).
This means,
m + √n = -1 + √2
m - √n = -1 - √2
m = -1 and n = 2
Now,
m + n
= -1 + 2
= 1
Thus,
m + n is 1.
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which rigid transformation would map triangle AQR to triangle AKP
Step-by-step explanation:
A rotation about point A a reflection across the line containing AR a reflection across the line containing AQ a rotation about point R
Answer:
A rotation about point A
Step-by-step explanation:
I am taking the test if it is wrong I will add a comment
Evaluate the expression 8p6
Answer:
Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !
Step-by-step explanation:
evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...
The value of the expression [tex]^8P_6[/tex] is 20160.
What is permutation?A permutation of a set in mathematics is, broadly speaking, the rearrangement of its elements if the set already has an ordered structure into a sequence or linear order.
The value of the expression is calculated as:-
[tex]^8P_6=\dfrac{8!}{8!-6!}=\dfrac{8!}{2!}[/tex]
[tex]^8P_6 =\dfrac{8\times 7\times 6\times 5\times 4\times 3\times 2}{2}[/tex]
[tex]^8P_6[/tex] = 20160
Hence, the value is 20160.
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Can someone help??????????
Answer:
(C) 1 and 3
Step-by-step explanation:
Corresponding angles are angles that are at the same corner at the different intersections.
We can see that 1 is on the bottom right corner of the bottom line, now we need to see what angle is at the bottom right corner of the top line?
That's 3.
So 1 and 3 are congruent because they are corresponding.
Hope this helped!
Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least integer n for which Pn(0.2) approximates ln(1.2) to within 0.01.
Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
In this exercise we have to use the knowledge of Taylor Polynomial to calculate the requested function, this way we will have;
the least integer for n is 2
The function given in this exercise corresponds to:
[tex]f(x) = ln(1+x)[/tex]
knowing that the x point will be centered on:
[tex]x=0\\Pn(0,2)\\Error < 0.01[/tex]
By rewriting the equation we have to:
[tex][[Max(f^{(n+1)} (c))]/(n + 1)!] *0.2^{(n+1)} < 0.01[/tex]
So doing the derivatives related to the first function given in the exercise we have to:
[tex]f(x) = ln(1+x)[/tex]
First derivative: [tex]f'(x) = 1/(x + 1) < 0! = 1[/tex] 2nd derivative: [tex]f"(x) = -1/(x + 1)^2 < 1! = 1[/tex] 3rd derivative: [tex]f"'(x) = 2/(x + 1)^3 < 2! = 2[/tex] 4th derivative: [tex]f""(x) = -6/(x + 1)^4 < 3! = 6[/tex]Following this we have to:
[tex]Max|f^{(n+1)} (c)| < n![/tex]
Thus, error is;
[tex](n!/(n + 1)!) * 0.2^{(n + 1)} < 0.01[/tex]
[tex](1/(n + 1))* 0.2^{(n + 1)} < 0.01[/tex]
Let's try n = 1
[tex](1/(1 + 1)) *0.2^{(1 + 1)} = 0.02[/tex]
This is greater than 0.01 and so it will not work. Let's try n = 2
[tex](1/(2 + 1)) * 0.2^{(2 + 1)} = 0.00267[/tex]
This is less than 0.01. So,the least integer for n is 2.
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Simplify -(7/x-2)+(2x/x) Simplify your answer as much possible
Answer:
[tex]\dfrac{2x-11}{x-2}[/tex]
Step-by-step explanation:
Simplify the fractions, then add.
[tex]-\dfrac{7}{x-2}+\dfrac{2x}{x}=\dfrac{-7}{x-2}+2=\dfrac{-7}{x-2}+\dfrac{2(x-2)}{x-2}\\\\=\dfrac{2x-4-7}{x-2}=\boxed{\dfrac{2x-11}{x-2}}[/tex]
_____
Note that this comes with the restriction that x ≠ 0.
Starting with x1 = 2, find the third approximation x3 to the root of the equation x3 − 2x − 2 = 0.
Answer:
0.8989
Step-by-step explanation:
Using the Newton's Raphson approximation formula.
Xn+1 = Xn - f(Xn)/f'(Xn)
Given f(x) = x³-2x+2
f'(x) = 3x²-2
If the initial value X1 = 2
X2 = X1 - f(X1)/f'(X1)
X2 = 2 - f(2)/f'(2)
f(2) = 2³-2(2)+2
f(2) = 8-4+2
f(2) = 6
f'(2) = 3(2)²-2
f'(2) = 10
X2 = 2- 6/10
X2 = 14/10
X2 = 1.4
X3 = X2 - f(X2)/f'(X2)
X3 = 1.4 - f(1.4)/f'(1.4)
f(1.4) = 1.4³-2(1.4)+2
f(1.4) = 2.744-2.8+2
f(1.4) = 1.944
f'(1.4) = 3(1.4)²-2
f'(1.4) = 3.880
X3 = 1.4- 1.944/3.880
X3 = 1.4 - 0.5010
X3 = 0.8989
Hence the value of X3 is 0.8989
is -54 rational number whole number or integersis
Answer:
-54 is a integer and rational number
Step-by-step explanation:
Ellen baked 115 cookies and shared them equally with her 23 classmates. How many whole cookies each can Ellen and her classmates have?
Step-by-step explanation:
Ellen - 115/23
Classmates and Ellen got = 5 each
A project has an initial cost of $40,000, expected net cash inflows of $10,000 per year for 8 years, and a cost of capital of 14%. What is the project's NPV? (Hint: Begin by constructing a time line.) Do not round intermediate calculations. Round your answer to the nearest cent.
Answer:
50k
Step-by-step explanation:
Listed below are numbers of Internet users per 100 people and numbers of scientific award winners per 10 million people for different countries. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the P-value of r. Determine whether there is sufficient evidence to support a claim of linear correlation between the two variables. Use a significance level of α= 0.01.
Internet Users 80.3 78.2 56.4 67.6 77.7 38.6
Award Winners 5.6 9.3 3.2 1.6 10.9 0.1
Required:
a. Construct a scatterplot.
b. Determine the null and alternative hypotheses.
c. The test statistic is:_________
d. The P-value is:_________
Answer:
There is not sufficient evidence to support a claim of linear correlation between the two variables.
Step-by-step explanation:
(a)
The scatter plot for the provided data is attached below.
(b)
The hypothesis to test significance of linear correlation between the two variables is:
H₀: There is no linear correlation between the two variables, i.e. ρ = 0.
Hₐ: There is a significant linear correlation between the two variables, i.e. ρ ≠ 0.
(c)
Use the Excel function: =CORREL(array1, array2) to compute the correlation coefficient, r.
The correlation coefficient between the number of internet users and the award winners is,
r = 0.786.
The test statistic value is:
[tex]t=r\sqrt{\frac{n-2}{1-r^{2}}}[/tex]
[tex]=0.786\times\sqrt{\frac{6-2}{1-(0.786)^{2}}}\\\\=2.5427\\\\\approx 2.54[/tex]
Thus, the test statistic is 2.54.
(d)
The degrees of freedom is,
df = n - 2
= 6 - 2
= 4
Compute the p-value as follows:
[tex]p-value=2\cdot P(t_{n-2}<2.54)=2\times 0.032=0.064[/tex]
*Use a t-table.
p-value = 0.064 > α = 0.05
The null hypothesis will not be rejected.
Thus, it can be concluded that there is not sufficient evidence to support a claim of linear correlation between the two variables.
what would it be help!
Answer:
35°
Step-by-step explanation:
If BCD is 75, then BCA is 105.
105+40=145
180-145=35
So ABC is 35°
The revenue, cost, and profit functions for a line of cell phone cases is shown. Identify the location on the profit function where the profit from sales of the phone cases is a maximum.
Answer:
approximately x = 38
Step-by-step explanation:
The maximum profit is the vertex of the profit graph parabola. The maximum occurs at approximately x = 38.
The solution is x = 38
The location on the profit function parabola where the profit from sales of the phone cases is a maximum is given by x = 38
What is a Parabola?A Parabola, open curve, a conic section produced by the intersection of a right circular cone and a plane parallel to an element of the cone. A parabola is a plane curve generated by a point moving so that its distance from a fixed point is equal to its distance from a fixed line
The equation of the parabola is given by
( x - h )² = 4p ( y - k )
where ( h , k ) is the vertex and ( h , k + p ) is the focus
y is the directrix and y = k – p
The equation of the parabola is also given by the equation
y = ax² + bx + c
where a , b , and c are the three coefficients and the parabola is uniquely identified
Given data ,
Let the revenue, cost, and profit functions for a line of cell phone cases be given as two parabolic functions R ( x ) and P ( x )
The maximum profit is given by the parabolic function R ( x )
The profit is represented by = y
The price per phone is represented by = x
Now , when y is maximum ,
The value of y = $ 2,250,000
The value of x when y = $ 2,250,000 is x = 38
So , the value of x from the parabola where profit is maximum is x = 38
Therefore, the value of x = 38
Hence , the value of x from the function is x = 38
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A plan for a dog park has a grassy section and a sitting section as shown in the figure. Which equation can be used to find the area of the grassy section?
Answer:
[tex]Area=\frac{1}{2} (B\,+\,b)\,h[/tex]
Step-by-step explanation:
The grassy area is that of a trapezoid, so recall the formula for the area of a trapezoid:
[tex]Area=\frac{1}{2} (Base\,+\,base)\,height[/tex]
where:
Base stands for the larger base (in our case the dimension "B" in the attached image)
base stands for the shorter base parallel to the largest Base (in our case the dimension "b" in the attached image)
and
height stands for the distance between bases (in our case the dimension "h" in the attached image.
Therefore the formula for the area of the grassy section becomes:
[tex]Area=\frac{1}{2} (Base\,+\,base)\,height\\Area=\frac{1}{2} (B\,+\,b)\,h[/tex]
Answer:
1/2 (b+b) h
here is the actual picture
If the sample size is increased and the standard deviation and confidence level stay the same, then the margin of error will also be increased.
a. True
b. False
False!
The answer is: False.
Whomever stated the answer is "true" is wrong.
Malia measures the longer side of a dollar bill using a ruler at school. Which of the following is most likely the quantity she measured?
Answer:
6.14 inches
Step-by-step explanation:
The one side of the dollar bill is 6.14 inch. The 6.14 inches of the dollar approximates the 156.1 mm. When Malia measures the longer side of a dollar bill from her rule it will be approximately 6.14 inches in length. The ruler normally has inches and cm sides. Very few rulers have mm scales. The most probable scale that malia would have measure is in inches.
IQ tests are scaled so that the mean score in a largepopulation should be μ =100. We suspect that the very-low-birth-weight population has mean score less than100. Infants weiging less than 1500 grams at birth are classed as "very low birth weight". Low birth weight carriesmany risks. One study followed 113 male infants with very low birth weight to adulthood. At age 20, the mean IQ score for these men was (x bar=87.6.) Iq scores vary Normally with standard deviation σ=15. Give a 95% confidence interval for the mean IQ score at age 20 for allvery-low-birth-weight males. Use the four-step process for confidence interval.
Answer:
The 95% confidence interval is [tex]84.83< \mu < 90.37[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 113[/tex]
The sample mean is [tex]\= x = 87.6[/tex]
The standard deviation is [tex]\sigma = 15[/tex]
Given that the confidence level is 95% then the level of significance is mathematically represented as
[tex]\alpha = 100 - 95[/tex]
[tex]\alpha = 5\%[/tex]
[tex]\alpha = 0.05[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the value is
[tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]
Generally the margin of error is mathematically evaluated as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{ \sigma}{ \sqrt{n} }[/tex]
=> [tex]E = 1.96 * \frac{ 15}{ \sqrt{113} }[/tex]
=> [tex]E = 2.77[/tex]
The 95% confidence interval is mathematically represented as
[tex]\= x - E < \mu < \= x + E[/tex]
substituting values
[tex]87.6 - 2.77< \mu < 87.6 + 2.77[/tex]
[tex]84.83< \mu < 90.37[/tex]
What are the approximate solutions of the graphed function?
Answer:
x = -2.6, x = 2.6
Step-by-step explanation:
The graph crosses the x-axis at approximately 2.6 and -2.6.
The required approximate solution of the function graphed is x = -2.6 and 2.6.
Given that,
A graph of a function is plotted, and the solution of the function is to be determined.
What are functions?
Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
What is a graph?The graph is a demonstration of curves that gives the relationship between the x and y-axis.
Here, the solution of the function is that value of x where the function terminates to zero, So the given curve terminates to zero at two places at x = -2.6 and x = 2.6 from the observation of the graph.
Thus, the required approximate solution of the function graphed is x = -2.6 and 2.6.
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What is the answer and how is this solved?
Answer:
Sum : 65
Step-by-step explanation:
In this notation, n is our starting value, and hence we start at 3 and go to 7. Given the set of values : { 3, 4, 5, 6, 7 }, we can substitute in our expression " 4n - 7 " for n and solve. The sum of these values is our solution.
4( 3 ) - 7 = 12 - 7 = 5,
4( 4 ) - 7 = 16 - 7 = 9,
4( 5 ) - 7 = 20 - 7 = 13,
Our remaining values for n = 6 and n = 7 must then be 17 and 21. This is predictable as we have an arithmetic series here, the common difference being 4. As you can see 9 - 5 = 4, 13 - 9 = 4, 17 - 13 = 4, 21 - 17 = 4.
Therefore we have the series { 5, 9, 13, 17, 21 }. This adds to an answer of 65.
A survey of 500 randomly selected adults found that 57% say that they would take a ride in a fully self-driving car. The 95% confidence interval for the true proportion of all adults who would take a ride in a full self-driving car is found to be (0.5266, 0.6134). Can we conclude that the majority of all adults would take a ride in a fully self-driving car?
Yes; Since the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.
No; The data does not include all adults, so we cannot make a conclusion about the population.
No; The confidence interval limits are not large enough to determine that a majority rely only on cellular phones. The proportion would need to be much greater than 50%, and the one above is only slightly larger.
Yes; Since the proportion of adults who said yes is 57%, and this is higher than 50%, we can conclude that a majority would take a ride in a fully self-driving car.
Answer:
Yes; Since the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.
Step-by-step explanation:
From the question we are told that
The sample size is n = 500
The sample proportion is [tex]\r p = 0.57[/tex]
The 95% confidence interval is (0.5266, 0.6134)
Looking at the 95% confidence level interval we see that the sample proportion is within the interval and given that the confidence interval limits are both greater than 50%, we can reasonably conclude that more than half of all adults would take a ride in a fully self-driving car.
Triangle+ Triangle + Triangle = 30 Triangle + circle + circle = 20 Circle + Square + Square = 13 Triangle + circle x half square = ?
Answer:
Below
Step-by-step explanation:
Let T be triangle, C the circle and S the square.
● T + T + T = 30
● 3T = 30
Divide both sides by 3
● 3T/3 = 30/3
● T = 10
So the triangle has a value of 10.
●30 T + C + C = 20C + S + S = 13T +C ×S/2
Add like terms together
●30 T + 2C = 20C +2S= 13T + C×S/2
Replace T by its value (T=10)
● 300 + 2C = 20C + 2S = 130 + C×S/2
Take only this part 20C + 2S = 130 + C × S/2
● 20C + 2S = 130 + C×S/2 (1)
Take this part (300+2C = 20C+2S) and express S in function of C
● 20C + 2S = 300 + 2C
Divide everything by 2 to make easier
● 10 C + S = 150+ C
● S = 150+C-10C
● S = 150-9C
Replace S by (5-9C) in (1)
● 20C + 2S = 130 + C×S/2
● 20C + 2(150-9C) = 130 +C× (150-9C)/2
● 20C + 300-18C= 130 + C×(75-4.5C)
● 2C + 300 = 130 + 75 -4.5C^2
● 2C +300-130 = 75C - 4.5C^2
● 2C -75C + 170 = -4.5C^2
● -73C + 170 = -4.5C^2
Multiply all the expression by -1
● -4.5C^2 +73C+ 170= 0
This is a quadratic equation, so we will use the discriminant method.
Let Y be the discriminant
● Y = b^2-4ac
● b = 73
● a = -4.5
● c = 170
● Y = 73^2 - 4×(-4.5)×170= 8389
So the equation has two solutions:
● C = (-b +/- √Y) /2a
√Y is approximatively 92
● C = (-73 + / - 92 )/ -9
● C = 18.34 or C = -2.11
Approximatively
● C = 18 or C = -2
■■■■■■■■■■■■■■■■■■■■■■■■■
● if C = 18
30T + 2C = 300 + 36 = 336
● if C = -2
30T + 2C = 300-4 = 296
An octagonal pyramid ... how many faces does it have, how many vertices and how many edges? A triangular prism ... how many faces does it have, how many vertices and how many edges? a triangular pyramid ... how many faces does it have, how many vertices and how many edges?
1: 8 faces and 9 with the base 9 vertices and 16 edges
2: 3 faces and 5 with the bases 6 vertices and 9 edges
3: 3 faces and 4 with the base 4 vertices and 6 edges
Hope this can help you.
Please answer quick!!!
Find the interquartile range of the data set represented by this box plot.
30
56
20
10
Answer:
A. 30
Step-by-step explanation:
The interquartile range for a box and whiskers plot, is the value from the right side of the box minus the value of the left side of the box.
In this case at the far right side of the box it is at 130, at the far left side of the box it is at 100.
130-100=30
Answer:
[tex]\huge\boxed{IQR = 30}[/tex]
Step-by-step explanation:
Q1 = 130 (Left hand edge of the box)
Q3 = 100 (Right Hand edge of the box)
Interquartile Range = Q3-Q1
IQR = 130-100
IQR = 30
