Answer:
C. 32
Step-by-step explanation:
The shipment for 100 parts is received by a manufacturer. Shipment will be rejected if more than 5 parts are defective. The manufacturer selects a sample and based on that selected sample he accepts or rejects the whole shipment. The minimum size of the sample should be 32 based on the probability of less than 0.1 and then decision should be made whether to accept or reject the shipment. If no defective part is found in the sample, shipment should be accepted.
please find the answer
there are options given below
plz give answer asap
Answer
33.3
Step-by-step explanation:
if u multiply the 2, and then find the ratio of them in comparison to the number under, you will find the rate decreases by 10 percent every time, the first situation it is 4/8 = 5/10, second situation is it 32/80= 4/10, and htis situation is most like 3/10, right ? so the answer would be 33.3 :)
explain why if you answer it , thanks
Answer:
B.
Step-by-step explanation:
Table B has x values that go to multiple y values. A function has inputs that only go to one output.
write an equation of the function in the form y=a(b)^x -c that has a y intercept of -6, asymptote of y= -2 and goes through (2,-18)
Step-by-step explanation:
Asymptote: y = 2 y-intercept: (0,8)
Step-by-step explanation:
The given function is
f(x) = 6(0.5)^{x} + 2f(x)=6(0.5)
x
+2
This function is of the form:
f(x) = a {b}^{x} + cf(x)=ab
x
+c
where y=c is the horizontal asymptote.
By comparing , we have c=2 hence the horizontal asymptote is
y = 2y=2
To find the y-intercept, we put x=0 into the function to get:
f(0) = 6(0.5)^{0} + 2 = 6 + 2 = 8f(0)=6(0.5)
0
+2=6+2=8
Therefore the y-intercept is (0,8).
Given positive integers x and y such that x doesn't equal y and $1/x+1/y=1/18$ what is the smallest possible value for x+y?
Answer:
Hello,
[tex]\boxed{Answer: 75}[/tex]
Step-by-step explanation:
x,y integers, x,y >0 ,x≠y
[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\[/tex]
[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\\begin{array}{|c|c|c|c|}y-18&y&x&x+y\\---&---&---&---\\1&19&18+324=342&362\\2&20&18+162=180&200\\3&21&126&147\\4&22&99&121\\6&24&108&132\\12&30&45&75\\18&36&36&72\\\end{array}\\\\\\\boxed{Answer: 75}\\\\[/tex]
Can anyone help me with this?
I thing it lies on the negativity side of the number line between -2,24
what is the height of the water prism
Answer:
32 because I Don't know please vote my answer please
Answer:
12 (10) cm 937 637 = hafe 2929888389292822
Please help with this question
9514 1404 393
Answer:
27.932 in
Step-by-step explanation:
The initial angle (or height) is not shown, so we have assumed it is 30°. The equation for the height of the valve cap can be written as a function of angle:
y = 15.375 +14.5·sin(x +30) . . . . . . where x is in degrees
The angle measured from the +x axis is already 30° when the rotation angle is zero. Evaluating the above equation with x = 390° gives an angle of 420°, or 60° beyond one full rotation.
y = 15.375 +14.5·sin(60°) ≈ 27.932 . . . . inches above the ground.
The valve cap is 27.932 in. above the ground.
A parabola is graphed below.
What is the equation in vertex form of this parabola?
A
y=2(x−2)2−3
B
y=2(x+2)2−3
C
y=12(x−2)2−3
D
y=12(x+2)2−3
thank you so much! please hurry <3
Answer:
B
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here the vertex = (- 2, - 3 ) , then
y = a(x - (- 2))² - 3 , that is
y = a(x + 2)² - 3
To find a, substitute any point on the graph into the equation
Using the coordinates of the y- intercept (0, 5 )
5 = a(0 + 2)² - 3 ( add 3 to both sides )
8 = a(2)² = 4a ( divide both sides by 4 )
2 = a
y = 2(x + 2)² - 3 → B
Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?
Which expression best estimates 6 and three-fourths divided by 1 and two-thirds?
Answer: The expression is 7/2.
Lucia quiere repartir 4/5 litros de leche entre sus dos hijos en partes iguales. ¿Cuánto le dará a cada hijo?
Does 8in to 1ft reduce it or enlarge it
Answer:
enlarge it
Step-by-step explanation:
I ft = 12 inches
Thus 8 in → 12 in makes the transformation larger.
Thus going from 8 in to 12 in is an enlargement
The speed (S) an object falls varies directly with time. If the speed is 49.0 m/s after 5 seconds, then what is the speed after 3 seconds?
S= 16.3 m/s
S=29.4 m/s
S= 3.3 m/s
S= 81.6 m/s
Answer:
29.4 m/s
Step-by-step explanation:
When finding ordered pairs for a table of values for a function, the selection of x-coordinates can be
random
True
O False
What is the area for the circle?
Answer:
108 squared centimeters
Step-by-step explanation:
Let's exchange π for 3:
area = πr^2
= 3r^2
Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:
area = 3r^2
= 3 · 6^2
Simplify 6^2:
area = 3 · 6^2
= 3 · 36
Multiply 3 by 36:
area = 3 · 36
area = 108
108 squared centimeters
Menos 10 * 12 * -4 + 40 * -2 * 6 - 2 por favor
Answer:
-2
Step-by-step explanation:
-10 x 12 x -4 + 40 x -2 x 6 - 2
-120 x -4 - 80 x 6 - 2
480 - 480 - 2
0 - 2
-2
helpppp please.......
The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).
This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).
[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]
[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]
note1: I use the identity [tex]\tan^2(\theta)+1 = \sec^2(\theta)[/tex] which is derived from the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1[/tex]note2: based on the previous note, we can say [tex]\tan^2(\theta) = \sec^2(\theta)-1[/tex]So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.
Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.
What is the length of the altitude of the equilateral triangle below?
A. /240
B. 144
C. 12
D. 4
E. 12/3
F. 4/3
Answer:
its C option which is 12
Answer:
A
Step-by-step explanation:
Using Pythagoras' identity in either of the 2 right triangles
a² = (4[tex]\sqrt{3}[/tex] )² + (8[tex]\sqrt{3}[/tex] )² = 48 + 192 = 240 ( take square root of both sides )
a = [tex]\sqrt{240}[/tex] → A
factorize the expression:
mn² + mnp + 3mn + 3mp
Answer:
(mn+3m)(n+p)
Step-by-step explanation:
Answer:
(mn + 3m)(n + p)
Step-by-step explanation:
Factorize by grouping:
[tex]mn^2+mnp\\mn(n+p)\\\\3mn+3mp\\3m(n+p)\\\\(mn+3m)(n+p)[/tex]
Your classmate is unsure about how to use side lengths to determine the type of triangle. How would you explain this to your classmate?
Answer:
To determine the type of triangle using side lengths, you could use the converse of the Phythagorean theorem, acute triangle inequality theorem, and the obtuse inequality theorem. For example, if the square of the longest side of a triangle is greater than the sum of the squares of the other two sides, than its obtuse. And if the square of the longest side is less than the sum of the squares of the other two sides, then it would be acute. And if the square of the longest side is equal to the sum of the squares of the two other sides, then it would be a right triangle.
Step-by-step explanation:
it marks it correct on edge and it is not a sample answer.
have a jolly day!
find x you know
|8-x|=x^2+x
please solve part c.d.e and f
SEE THE IMAGE FOR SOLUTION
HOPE IT HELPS
HAVE A GREAT DAY
Find the largest prime factor of 18! + 19! + 20!
Answer: Prime Factors for 18: 2, 3, and 3
Prime Factors for 19: 19
Prime Factors for 20: 2, 2, and 5
Can you mark brainlest
Step-by-step explanation:
In math class, Jose earns 10 points for each A in his homework. If he already has 50 points, how many A’s does he need to get 120 points?
Answer jose needs to get 7 more A's because 5+7=12 so if 50+70=120 then he will need to get 7 more a's hope this helps :)
Step-by-step explanation:
Answer:
He needs 7 A's.
Step-by-step explanation:
The pictures.
Hope this helps!!! :)
[tex]\sqrt{x^{2} +4x+4[/tex] -3=0
Answer:
Given,
[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]
But if we put the value of x = 5 then it doesn’t satisfy the equation.
So,
X = 1
Answer:
The answer is [tex]x=1[/tex].
Step-by-step explanation:
To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].
Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].
Write all the possible two-digit numbers which can be formed using the digits 0,3,5
Answer:
i) where the digits can repeat
1. 30
2. 50
3. 33
4. 55
5. 35
6. 53
ii) where the digits cannot be repeated
1. 30
2. 50
3. 35
4. 53
what is 5 divided by 20.9
Answer:
0.23923444976
Question 12
What is the value of x in the following equation?
2/3x + 2 = 4
1. Ms. Rogers earns $___ each month. She pays 25% of her earnings, or $____ in federal taxes and 6% of her earnings, or $____ in state taxes. She pays ____ % of her earnings, or $____ for insurance. After these deductions, Ms. Rogers takes home $_____
131.76
8
175.68
549
2,196
1,339.56
Answer:
2,196; 549; 131.76; 8; 175.68; 1339.56
Step-by-step explanation:
2,196 is the biggest number, so use that as the first number.
.25x2196=549
.06x2196=131.76
.08x2196=175.68
2196-(549+131.76+175.68)=1339.56
8. Colleen times her morning commute such that there is an equal likelihood that she will arrive early or late to work on any given day. If she always arrives either early or late, what is the probability that Colleen will arrive late to work no more than twice during a five-day workweek
Solution :
Case I :
If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]
[tex]$=\frac{1}{32}[/tex]
Case II :
When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]
[tex]$=\frac{1}{32} \times 5$[/tex]
[tex]$=\frac{5}{32}[/tex]
Case III :
When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.
[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]
[tex]$=\frac{1}{32} \times 10$[/tex]
[tex]$=\frac{5}{16}[/tex]
Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :
[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]
[tex]$=\frac{1}{2}$[/tex]
Sally and Mia run a furniture making company. They work together to build and paint custom dressers.
Sally charges a $100 flat fee for each dresser she builds, plus $420 for each hour she spends building.
Mia charges a $150 flat fee for each dresser she paints, plus $390 for each hour she spends painting.
a) Represent what Sally charges for one dresser as a polynomial. Remember to define any variables!
b) Represent what Mia charges for one dresser as a polynomial. Remember to define any variables!
c) Write a new SIMPLIFIED polynomial that represents their total charges, together, for one dresser.
Answer:
y = 250 + 810x
Step-by-step explanation:
Let
y = total charges
x = cost per hour
Sally: building
y = 100 + 420x
Mia: painting
y = 150 + 390x
Find their total charges of building and painting
Add the total charges of both of them
y = 100 + 420x + 150 + 390x
y = 250 + 810x
