A map was created using the scale 1 inch :25
miles. If the river is 5.5 inches long on the map, then it is actually how many miles long?

Answer: Missing segment = 45

Step-by-step explanation:

Concept:

Here, we need to know the idea of a similar triangle, ratio, and cross-multiplication.

In similar triangles, one can be obtained from the other by uniformly scaling (enlarging or reducing), possibly with additional translation, rotation and reflection. If two objects are similar, each is congruent to the result of a particular uniform scaling of the other.

A ratio is a quantitative relation between two amounts showing the number of times one value contains or is contained within the other.

Cross-multiplication means multiplying the numerator of each fraction by the other's denominator or the other way round.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

Let x be the length of missing segment

Step One: write the proportion ratio

56 / 56 + 24 = 105 / 105 + x

Step Two: Cross-multiplication

56 (105 + x) = 105 ( 56 + 24)

Step Three: Simplify parenthesis and expand it

56 ( 105 + x) = 105 (80)

5880 + 56x = 8400

Step Four: Subtract 5880 on both sides

5880 + 56x - 5880 = 8400 - 5880

56x = 2520

Step Five: Divide 56 on both sides

56x / 56 = 2520 / 56

x = 45

Hope this helps!! :)

Please let me know if you have any questions

Answer:

c. 2

Step-by-step explanation:

 2 (3x – y = -2)               6x - 2y = -4

6x - 2y = -4

First

[tex]\\ \sf\longmapsto BD^2=AD\times DC[/tex]

[tex]\\ \sf\longmapsto BD^2=18^2+7^2[/tex]

[tex]\\ \sf\longmapsto BD^2=324+49[/tex]

[tex]\\ \sf\longmapsto BD^2=363[/tex]

[tex]\\ \sf\longmapsto BD=\sqrt{363}[/tex]

[tex]\\ \sf\longmapsto BD=19.2[/tex]

Now

Using Pythagorean theorem

[tex]\\ \sf\longmapsto BD^2+CD^2=m^2[/tex]

[tex]\\ \sf\longmapsto m^2=7^2+19.2^2[/tex]

[tex]\\ \sf\longmapsto m^2=49+363[/tex]

[tex]\\ \sf\longmapsto m^2=412[/tex]

[tex]\\ \sf\longmapsto m=\sqrt{412}[/tex]

[tex]\\ \sf\longmapsto m=20.3[/tex]

Nearest value in options is 18

Hence option a is correct

Answer:

(0.3478, 0.5522)

Step-by-step explanation:

Given:

Total number of red marbles, x = 45

Total number of marbles, n = 100

Phat = x / n = 45 / 100 = 0.45

The confidence interval, C.I is given by :

Phat ± Zcritical * standard error

Phat ± Zcritical * √Phat(1 - Phat) / n

Zcritical at 96% = 2.0537

The standard error = √Phat(1 - Phat) / n

S.E = √(0.45 * 0.55) / 100 = 0.0497493

C.I = 0.45 ± (2.0537 * 0.0497493)

C.I = 0.45 ± 0.10217013741

C. I = (0.3478, 0.5522)

Answer:

The butter for one portion cost $ 0.375.

Step-by-step explanation:

Given that you buy butter for $ 3 a pound, and one portion of onion compote requires 2 oz of butter, to determine how much does the butter for one portion cost, the following calculation must be performed:

2 oz = 0.125 lb

1 = 3

0.125 = X

3 x 0.125 = X

0.375 = X

Therefore, the butter for one portion cost $ 0.375.

please mark this answer as brainlist

Answer:

I think you can go with:

The margin of error is equal to half the width of the entire confidence interval.

so  try .74 ± [tex]\frac{.032}{2}[/tex]  =   [ .724 , .756] as the confidence interval

Step-by-step explanation:

Step-by-step explanation:

[tex]\triangle{ABC}[/tex] is similar to [tex]\triangle{ADE}[/tex] so we can write the ratio

[tex]\dfrac{x}{6+4} = \dfrac{2}{6}[/tex]

Solving for x, we get

[tex]x = \left(\dfrac{2}{6}\right)(10) = \dfrac{10}{3}[/tex]

Step-by-step explanation:

When adding two fractions with different bases (bottom numbers), we can use this function:

[tex]\frac{a}{b} + \frac{c}{d} = \frac{ad + cb}{bd}[/tex]

So, to apply this to the given question:

[tex]\frac{x+3}{x-6} +\frac{1}{x-2}[/tex]

= [tex]\frac{(x+3)(x-2)+(1)(x-6)}{(x-6)(x-2)}[/tex]

From the given answers, we see we don't need to simplify the resulting base number, which makes things a lot easier.

= [tex]\frac{[(x*x) + (x*-2)+(3*x)+(3*-2)]+(x-6)}{(x-6)(x-2)}[/tex]

= [tex]\frac{[x^2 -2x+3x-6]+(x-6)}{(x-6)(x-2)}[/tex]

= [tex]\frac{x^2 -2x+3x-6+x-6}{(x-6)(x-2)}[/tex]

= [tex]\frac{x^2 +2x-12}{(x-6)(x-2)}[/tex]

Now if we wanna be a little smart, we can see that from here, the only answer that has x^2 and something else, is A. But, just for show, lets factor.

= [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]

Answer:

A) [tex]\frac{x(x+2)}{(x-6)(x-2)}[/tex]

Answer:

Hello,

Step-by-step explanation:

Area of the sphere:

[tex]S=4*\pi *r^2[/tex]

Volume of the sphere:

[tex]V=\dfrac{4*\pi *r^3}{3}[/tex]

[tex]\dfrac{S}{3} =\dfrac{V}{7} \\\\\dfrac{4*\pi *r^2}{3} =\dfrac{4*\pi *r^3}{3*7} \\\\1=\dfrac{r}{7} \\\\\\r=7\\\\great \ circle: 2*\pi* r=14*\pi\\[/tex]

[tex]Volume=\dfrac{4*\pi *7^3}{3} =\dfrac{1372*\pi }{3} \approx{1436,7550...(cm^3)}[/tex]

Step-by-step explanation:

Hope it is helpful.

Thank you.

Answer:

D

Step-by-step explanation:

First of all, there are 2 different points. That lets out B.

The graph crosses the x axis at 3 and -1 Those two are x values. That lets out C and A.

So all you are left with is D. The y values have to be 0. The x values are 3 and - 1

Answer:

y = 3x

Step-by-step explanation:

abscissa is the x coordinate

ordinate is the y coordinate

y = 3x

Answer:

f(-4) = -1

f(-1) = -4

f(1) = 4

Step-by-step explanation:

We need to find the y value for the x values

f(-4) means find the y value for x= -4

f(-4) = -1

f(-1) = -4

f(1) = 4

9514 1404 393

Answer:

  55 units

Step-by-step explanation:

If two angles have the same measure, the triangle is isosceles. That means two sides have the same measure. Since the two given sides are different measures, the remaining side must be one of those. The perimeter will be greatest if the congruent sides are the longest. The greatest perimeter is ...

  15 + 20 + 20 = 55 . . . units

Answer:

cannot understand the language man

but please follow

Data for all 50 samples cannot be obtained, however, the solution below uses the 10 samples below to show how the hypothesis can be tested.

Answer:

Step-by-step explanation:

Average diameter, μ = 2.30

H0 : Average diameter is equal to 2.30cm

H1 : Average diameter is greater than 2.30 cm

The hypothesis :

H0 : μ = 2.30

H1 : μ > 2.30

Using the readings from the data above :

3.46, 2.64, 1.89, 2.56, 2.09, 3.10, 2.04, 2.18, 2.60, 2.76

Sample size, n = 10

Mean, xbar = ΣX/ n = 25.32 / 10 = 2.532

Sample standard deviation, s = 0.4973 (from calculator)

The test statistic :

(xbar - μ) ÷ (s/√(n))

T = (2.532 - 2.30) ÷ (0.4973/√(10))

T = 1.475

The Pvalue :

Degree of freedom, df = n - 1 ; 10 - 1 = 9

Pvalue(1.475, 9) = 0.087

Decision region :

Reject H0 ; If Pvalue < α;

Since 0.087 > 0.01 ; we fail to reject the Null and conclude that there is no evidence to suggest that the average diameter is greater than 2.30 cm

Answer:

j = $7.38 / 18

Step-by-step explanation:

1. We have to find the total cost of a 18 juice bottles pack

= $ 9.63 - $ 2.25

= $ 7.38

2. To find how much each bottle of juice costs :

j = $ 7.38 / 18 #

Answer:

length = 20 inches

width = 13 inches

Step-by-step explanation:

l = length

w = width

area = l×w

perimeter = (2×l) + (2×w)

l = w + 7

l×w = 4×(2×l + 2×w) - 4

(w+7)×w = 4×(2×(w+7) + 2×w) - 4

w² + 7w = 4×(2w + 14 + 2w) - 4

w² + 7w = 8w + 56 + 8w - 4 = 16w + 52

w² - 9w - 52 = 0

the solution for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

here we use now w instead of x.

and a=1

b=-9

c=-52

w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =

= (9 ± sqrt(289))/2 = (9 ± 17)/2

w1 = (9+17)/2 = 26/2 = 13

w2 = (9-17)/2 = -8/2 = -4

and a negative length does not make any sense for a geometric shape.

so, only w1 = 13 applies.

l = w + 7 = 13 + 7 = 20

Answer:

-12

Step-by-step explanation:

√50-3√2(2√2-5) -5√32​

= 5√2 -12+15√2-5(4)√2

= 5√2 -12+15√2-20√2

= -12

Answer:

not sure

Step-by-step explanation:

a+B+C+=d

Answer:

y = 2/5x + 1/5

Step-by-step explanation:

y = 2/5x + b

-1 = 2/5(-3) + b

-1 = -6/5 + b

1/5 = b

9514 1404 393

Answer:

  94.9

Step-by-step explanation:

It is straightforward addition to find the sum of the two numbers to be 94.871. Perhaps you're interested in rounding to the appropriate precision.

Here, the number with the fewest digits right of the decimal point is 10.9. In order to round the addition result appropriately, that "exact" result must be rounded so it has this same number of digits to the right of the decimal point (1 digit).

  94.871 ≈ 94.9

_____

Additional comment

When you're asked to round a sum (or difference) to the appropriate precision, always first compute the exact result using the full precision of all contributors. Then determine the contributor with the least precision (least significant digit is farthest to the left), and round the result to that same precision.

Answer:

im not sure but i do have a tip when you go to goo gle i want you to simplify your question (not what you asked on here) then copy your question as it is simple then search it on here because its slightly  for others to understand

Step-by-step explanation:

.

Answer:

y=x216–6x16+4116

Step-by-step explanation:

plato :)

The equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.

It is defined as the graph of a quadratic function that has something bowl-shaped.

(x - h)² = 4a(y - k)

(h, k) is the vertex of the parabola:

a = √[(c-h)² + (d-k²]

(c, d) is the focus of the parabola:

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

It is given that:

The equation of a parabola that has a vertical axis, passes through the point (–1, 3)

The vertex of the parabola is at (3, 2)

As we know, in the standard form of the parabola (h, k) represents the vertex of the parabola.

h = 3

k = 2

Plug the above point in the equation:

[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]

x = 3

y = 2

[tex]\rm 2\ =\ \dfrac{3^{2}}{16}-\dfrac{6(3)}{16}+\dfrac{41}{16}[/tex]

= 9/16 - 18/16 + 41/16

= (9-18+41)/16

= 32/16

2 = 2 ( true)

The equation of the parabola is:

[tex]\rm y\ =\ \dfrac{x^{2}}{16}-\dfrac{6x}{16}+\dfrac{41}{16}[/tex]

Thus, the equation of the parabola is in option (C) if the parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2) option (C) is correct.

Learn more about the parabola here:

brainly.com/question/8708520

#SPJ2

Answer:

[tex]a_5= 14[/tex]

[tex]a_{20}= 80[/tex]

[tex]a_{18}= 340[/tex]

Step-by-step explanation:

Solving (a):

We have:

[tex]a_1=2[/tex] --- first term

[tex]d = 5 -2 = 3[/tex] common difference

The 5h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_5= 2+ (5 - 1)*3[/tex]

[tex]a_5= 14[/tex]

Solving (b):

We have:

[tex]a_1 = 4[/tex] --- first term

[tex]d = 8 -4 = 4[/tex] common difference

The 20h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{20}= 4+ (20 - 1)*4[/tex]

[tex]a_{20}= 80[/tex]

Solving (c):

We have:

[tex]a_1 = 0[/tex] --- first term

[tex]d = 20 -0 = 20[/tex] common difference

The 18th term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{18}= 0+ (18 - 1)*20[/tex]

[tex]a_{18}= 340[/tex]

Answer: Choice A

The number line graph is visually showing every number that is 19 or smaller; hence [tex]x \le 19[/tex]

Note the use of a closed or filled in circle at the endpoint (in contrast to an open circle). This indicates we are including the endpoint 19 as part of the solution set, and that's why we go for "or equal to" as part of the inequality sign.

Answer:

[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]

Step-by-step explanation:

Given

[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]

Required

Determine [tex]\cos(\theta)[/tex]

We have:

[tex]\tan(\theta) = -\sqrt{\frac{19}{17}}[/tex]

Split

[tex]\tan(\theta) = -\frac{\sqrt{19}}{\sqrt{17}}[/tex]

tan is calculated as:

[tex]\tan(theta) = \frac{opposite}{adjacent}[/tex]

So:

[tex]Opposite = -\sqrt{19[/tex]

[tex]Adjacent = \sqrt{17[/tex]

And:

[tex]Hypotenuse^2 = Opposite^2 + Adjacent^2[/tex] --- Pythagoras theorem

[tex]Hypotenuse^2 = (-\sqrt{19})^2 + (\sqrt{17})^2[/tex]

[tex]Hypotenuse^2 = 19 + 17[/tex]

[tex]Hypotenuse^2 = 36[/tex]

Take square roots

[tex]Hypotenuse = 6[/tex]

[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(\theta) = \frac{\sqrt{17}}{6}[/tex]

Since it is in the second quadrant, then:

[tex]\cos(\theta) = -\frac{\sqrt{17}}{6}[/tex]

Answer:x2.2

Step-by-step explanation: