A medium-sized apple provides about 95.0 Calories of energy.

(a) Convert 95.0 Cal to joules.

(b) Suppose that amount of energy is transformed into kinetic energy of a 2.03 kg object initially at rest. Calculate the final speed of the object (in m/s).

(c) If that same amount of energy is added to 3.79 kg (about 1 gal) of water at 21.7°C, what is the water's final temperature (in °C)? The specific heat of water is

c = 4186

J

(kg · °C)

.

Answers

Answer 1

A. 95 Cal is equivalent to 397480 J

B. The final speed of the object is 625.78 m/s

C. The final temperature of the water is 46.8 °C

A. Converting 95 Cal to Joules

1 Cal = 4184 J

Therefore,

95 Cal = 95 × 4184

95 Cal = 397480 J

Thus, 95 Cal is equivalent to 397480 J

B. Determination of the speed of the object

Kinetic energy (KE) = 397480 J

Mass (m) = 2.03 Kg

Velocity (v) =?

KE = ½mv²

397480 = ½ × 2.03 × v²

397480 = 1.015 × v²

Divide both side by 1.015

v² = 397480 / 1.015

Take the square root of both side

v = √(397480 / 1.015)

v = 625.78 m/s

Therefore, the speed of the object is 625.78 m/s

C. Determination of the final temperature of the water

Mass of water (M) = 3.79 kg

Initial temperature of water (T₁) = 21.7 °C

Specific heat capacity of water (C) = 4186 J/KgºC

Heat (Q) = 397480 J

Final temperature (T₂) =?

Q = MC(T₂ – T₁)

397480 = 3.79 × 4186 (T₂ – 21.7)

397480 = 15864.94 (T₂ – 21.7)

Clear the bracket

397480 = 15864.94T₂ – 344269.198

Collect like terms

397480 + 344269.198 = 15864.94T₂

741749.198 = 15864.94T₂

Divide both side by 15864.94

T₂ = 741749.198 / 15864.94

T₂ = 46.8 °C

Therefore, the final temperature of the water is 46.8 °C

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Related Questions

A 400g ball moving toward the east at 3.7m/s suddenly collides head-on with a 200g ball sitting at rest. Determine the velocity of the first ball just after collision

Answers

The final velocity of the first ball after the collision is 1.167 m/s to the west.

The given parameters;

mass of the moving ball, m₁ = 400 g = 0.4 kgvelocity of the moving ball, u₁ = 3.7 m/smass of the ball at rest, m₂ = 200 g = 0.2 kg

Let the velocity of the first ball after collision = v₁

Let the velocity of the ball at rest after collision = v₂

Apply the principle of conservation of linear momentum;

[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2\\\\0.4(3.7)+ 0.2(0) = 0.4(-v_1) + 0.2v_2\\\\1.48 = -0.4v_1 + 0.2v_2[/tex]

Apply one-directional velocity formula;

[tex]u_1 + v_1 = u_2 + v_2\\\\3.7 - v_1 = 0 + v_2\\\\v_2 = 3.7 -v_1[/tex]

substitute the value of v₂ into the above equation;

[tex]1.48 = -0.4v_1 \ + \ 0.2(3.7 -v_1)\\\\1.48 = -0.4v_1 + 0.74 - 0.2v_1\\\\0.74 = -0.6v_1\\\\v_1 = \frac{-0.74}{0.6} \\\\v_1 = -1.167 \ m/s[/tex]

[tex]v_2 = 3.7 + 1.167\\\\v_2 = 4.867 \ m/s[/tex]

Thus, the final velocity of the first ball after the collision is 1.167 m/s to the west.

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A chemical lab isolates a gaseous element from the atmosphere that does not form chemical compounds. In which group of the periodic table is this element most likely found?

A. 18

B. 17

C. 1

D. 2​

Answers

Answer:

A- 18

Explanation:

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what is the rotational kinetic energy of the earth? assume the earth is a uniform sphere. data for the earth can be found inside the back cover of the book.

Answers

The rotational kinetic energy of the earth is 2.587 × 10²⁹ J

The rotational kinetic energy of the earth is given by K = 1/2Iω² where I = rotational inertia of earth = 2MR²/5 where M = mass of earth = 5.972 1× 0²⁴ kg and R = radius of earth = 6.4 × 10⁶ m. ω = angular speed of earth = 2π/T where T = period of earth = 24 hours = 24 × 60 ×  60 = 86400 s = 8.64 × 10⁴ s

So, K = 1/2Iω²  

K = 1/2 × 2MR²/5 × (2π/T)²  

K = 4π²MR²/5T²  

Substituting the values of the variables into the equation, we have

K = 4π²MR²/5T²

K = 4π² × 5.972 × 10²⁴ kg × (6.4 × 10⁶ m)²/[5(8.64 × 10⁴ s)²]  

K = 4π² × 5.972 × 10²⁴ kg × 40.96 × 10¹² m²/[5(74.6496 × 10⁸ s)²]  

K = 4π² × 244.61312 × 10³⁶ kgm²/373.248 × 10⁸ s²  

K = 9656.93890286 × 10³⁶ kgm²/373.248 × 10⁸ s²  

K = 25.87 × 10²⁸ kgm²/s²

K = 2.587 × 10²⁹ J

So, the rotational kinetic energy of the earth is 2.587 × 10²⁹ J

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Answer:

40 m/s

Explanation:

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Answer:

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3.A

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Explanation:

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Answers

Answer:

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Answers

Deductive reasoning

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Deductive reasoning is a type of deduction used in science and in life. It is when you take two true statements, or premises, to form a conclusion. For example, A is equal to B. B is also equal to C. Given those two statements, you can conclude A is equal to C using deductive reasoning.

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Answers

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Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature

Explanation:

A kangaroo hops at 55 m to the west in 5 s. What is the velocity of the kangaroo?
5.5 m/s W
55 m/s W
11 m/s W
11 m/s/s W

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Explanation:

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A car weighs 3,000 kg. What is the momentum of a car travelling at 60 km/h?

Answers

Answer:

GIVEN,

        MASS, m                    = 1500 kg

        INITIAL VELOCITY,u  = 36 km/h = 36*5/18 = 10 m/s

        FINAL VELOCITY ,v   = 72 km/h =  72*5/18=  20 m/s

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Answers

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Efficiency = output / input

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Answer :

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Explanation:

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Answer:

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Explanation:

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Explanation:

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Answers

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Answer:

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Answer:

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Answers

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