A mixture is made by combining 1.29 lb of salt and 5.35 lb of water.
What is the percentage of salt (by mass) in this mixture?

Answer:

0.089

Explanation:

2.5/ 14= .178 then 0.178/ 2 again and you get 0.089

The moles of nitrogen in 2.5 grams of the compound is 0.089 moles. Thus option A is correct.

Moles can be calculated as the ratio of mass to molecular mass.

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

The mass of Nitrogen = 14 g/mol

The mass of diatomic nitrogen = 2 [tex]\times[/tex] mass of nitrogen

The mass of diatomic nitrogen = 2 [tex]\times[/tex] 14 g/mol

The mass of diatomic nitogen = 28 g/mol

The molecular weight of Nitrogen = 28g/mol

Given, the mass of Nitrogen = 2.5 g

Moles of nitrogen = [tex]\rm \dfrac{2.5}{28}[/tex]

Moles of Nitrogen = 0.089 moles.

The moles of nitrogen in 2.5 grams of the compound is 0.089 moles. Thus option A is correct.

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Answer:

A yan hehehehe

salamat puso ma ah

Answer:

C

Explanation:

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

Note: The question is incomplete. The complete question is given as follows:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

Answer:

Na2O (the 2 is small the o is not a 0 but and OOh)

Explanation:

Hey there, The formula for the compound formed between sodium and oxygen will be Na2O

Though since sodium is a metal and oxygen is a nonmetal, Na2O is expected to be ionic.

An ionic compound is a chemical compound made up of ions held together by electrostatic forces known as ionic bonding.

To determine an ionic compound's formula, first identify the cation and record its symbol and charge.

After that, identify the anion and record its symbol and charge. Finally, mix the two ions together to make an electrically neutral compound.

After two or more atoms lose or gain electrons to form an ion, an ionic bond can form.

Ionic bonds form when metals lose electrons and nonmetals gain electrons. Ions with opposite charges attract each other, forming an ionic bond.

The symbol for sodium is Na+, and the symbol for oxygen is O2. The resulting compound here in the given condition is Na2O.

Thus, this is the formula for the ionic compound formed between sodium and oxygen.

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Which of the statements about liquids and gases are true?

The particles in liquids and gases can move past one another freely.

Which of the statements about liquids and gases are true?

Both liquids and gases have a definite volume.

The particles in liquids and gases can move past one another freely

Both liquids and gases have a definite shape.

Neither liquids nor gases have a definite shape.

The particles in liquids and gases can move past one another freely.

Answer:

A. Empirical formula => SiCl₂I₂

B. Molecular formula = SiCl₂I₂

Explanation:

From the question given above, the following data were:

Silicone (Si) = 7.962 %

Chlorine (Cl) = 20.10 %

Iodine (I) = 71.94 %

Molar mass of compound = 352.8 g/mol

Empirical formula =?

Molecular formula =?

A. Determination of the empirical formula of the compound.

Si = 7.962 %

Cl = 20.10 %

I = 71.94 %

Divide by their molar mass

Si = 7.962 / 28 = 0.284

Cl = 20.10 / 35.5 = 0.566

I = 71.94 / 127 = 0.566

Divide by the smallest

Si = 0.284 / 0.284 = 1

Cl = 0.566 / 0.284 = 2

I = 0.566 / 0.284 = 2

Empirical formula => SiCl₂I₂

B. Determination of the molecular formula of the compound.

Empirical formula => SiCl₂I₂

Molar mass of compound = 352.8 g/mol

Molecular formula =?

Molecular formula = [SiCl₂I₂]ₙ

[SiCl₂I₂]ₙ = 352.8

[28 + (2×35.5) + (2×127)]n = 352.8

[28 + 71 + 254]n = 352.8

353n = 352.8

Divide both side by 353

n = 352.8 / 353

n = 1

Molecular formula = [SiCl₂I₂]ₙ

Molecular formula = [SiCl₂I₂]₁

Molecular formula = SiCl₂I₂

Answer: Coefficient 0

subscript for V 2

subscript for O 5

Explanation: yes

There is no coefficient in V₂O₅ and the subscript of vanadium V is 2 and the subscript of oxygen is 5.

Vanadium pentoxide is an ionic compound formed by donating electrons from the vanadium metal to oxygen.  The chemical formula of vanadium pentoxide is V₂O₅.

The chemical formula of a compound is written in terms of the chemical symbol of each constituent elements and the number of their atoms. The number of atoms is written as subscript for the chemical symbols.

In V₂O₅, there are are 2 vanadium atoms and 5 oxygen atoms. Coefficients are numbers prior to the formula in reaction. Here there is no coefficient and the subscript for V is 2 and that of O is 5.

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Answer: a) [tex]1.7\times 10^{-4}[/tex]

b) [tex]3.4\times 10^{-4}[/tex]

Explanation:

The reaction is :

[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]

Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]

Rate =  [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]

a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]

Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

b) Rate of appearance of [tex]NO_2[/tex] =  [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]

A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s

[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]

B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s

According to rate law,

[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]

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Answer:

a = 2m/s²

Explanation:

Given data:

Mass of sofa = 150 Kg

Force applied = 300 N

Acceleration = ?

Solution:

Formula:

F = ma

F = force

m = mass

a = acceleration

by putting values,

300 N = 150 Kg × a

a =  300 N /150 Kg

a = 300 Kg m/s² / 150 Kg   ( N = Kgm/s²)

a = 2m/s²

Answer:

dating and correlating the strata in which it is found

Explanation:

Answer:

The correct answer is A:The age of an unfamiliar layer of rock

Explanation:

I promise that I got it correct on A P E X <3

Answer:

Chalcogen

Explanation:

Answer:

a parallel circuit has two or more paths for current to flow through voltage is the same across each component of the parallel circuit the sum of the current through each path is equal to the total current that follows from the source another definition is in a parallel circuit all components are connected across each other formally exactly two sets of electricity common points a branch in a parallel circuit in a path of electricity current formed by one of the load component

Answer:

0.071 moles of Na₃PO₄ .

Explanation:

Given data:

Number of molecules of Na₃PO₄ = 4.3× 10²² molecules

Number of moles = ?

Solution:

1 mole contain 6.022 × 10²³ molecules

4.3× 10²² molecules × 1 mol / 6.022 × 10²³ molecules

0.71× 10⁻¹ mol

0.071 mol

The number 6.022 × 10²³ is called Avogadro number.

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"

Answer:

I think the answer is A the Afracan plate

Explanation:

hope this helps:)

Answer: 2 electrons

Explanation: Good luck! :D

Answer:

D

Explanation:

I hope this helps and have a great day

Answer:

RbF2 + Ca

Explanation:

Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+

Hence CaF2 + Rb → RbF2 +Ca

Please be reminded, this answer may not be 100% correct

Answer:

XY4Z2- dsp2

XY4Z- sp3d

XY5Z- sp3d2

XY2Z3- sp3d

XY2Z- sp2

XY3Z- sp3

XY2Z2- sp3

XY3Z2- sp3d

XY2 - sp

,XY3- sp2

XY4- sp3

,XY5- sp3d

XY6- sp3d2

Explanation:

In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.

Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.

Answer:

A. 1.02 moles .

Explanation:

Hello!

In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:

[tex]n=\frac{PV}{RT}[/tex]

Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:

[tex]n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol[/tex]

Therefore, the correct answer is A. 1.02 moles

Best regards!

Answer:

7x10⁴.

Explanation:

Hello!

In this case, when rounding big number to a representation with less significant figures than it, we need to make sure we remove the spare figures and round up whether the next digit is five or more.

In such a way, for 74,000, we notice that 4 is not enough to round up the 7, that is why the number would contain a 7 only; moreover, to get rid of the thousand places, we need to introduce an exponent in 4 places, which means that the result would be:

7x10⁴.

Best regards!

Answer:

E = 7.11 × [tex]10^{-7}[/tex]  Cal

Explanation:

given data

efficiency = 25 %

solution

first we get here E by the power that is express as

p = [tex]\frac{E}{t}[/tex]     ...........1

E = p × t

E = 1 ×  2 × [tex]\frac{1hp}{746w} \times \frac{1hr}{3600 s}[/tex]  

E = 7.447 × [tex]10^{-7}[/tex] J

and

Ein is get by efficiency

Ein = [tex]\frac{Eout}{\eta }[/tex]        ..................2

Ein = [tex]\frac{7.447 \times 10^{-7}}{.25 }[/tex]

Ein = 29.788 × [tex]10^{-7}[/tex]  J

so required energy is

E = 29.788 × [tex]10^{-7}[/tex]  ×  [tex]\frac{1Cal}{4.184J}[/tex]

E = 7.11 × [tex]10^{-7}[/tex]  Cal

Explanation:

Let the mass of the compound be 100g.

There are 60.2g of sulfur.

Moles of sulfur

= 60.2g / (32.07g/mol) = 1.877mol

There are 100g - 60.2g

= 39.8g of manganese.

Moles of manganese

= 39.8g / (54.94g/mol) = 0.724mol

Mole ratio of manganese to sulfur

= 0.724mol : 1.877mol = 1 : 2.5.

Answer: [tex]CsF[/tex] > [tex]SrF_2[/tex] >  [tex]OF_2[/tex]  > [tex]F_2[/tex]

Explanation:

The percent ionic character is used to determine if a bond is more ionic or covalent. More is the percent ionic character, the more ionic the molecule is. If the electronegativity difference between two elements is higher than 1.7 it will be considered as ionic.

The electronegativity difference for CsF is (3.98-0.79) = 3.19

The electronegativity difference for [tex]OF_2[/tex] is = (3.98-3.44) = 0.54

The electronegativity difference for [tex]SrF_2[/tex] is (3.98-0.95) = 3.0

The electronegativity difference for [tex]F_2[/tex] is  0.

Thus decreasing order of  ionic character of the bonds is CsF >  [tex]SrF_2[/tex] >  [tex]OF_2[/tex]  > [tex]F_2[/tex]

Answer:

1. 10moles

2. Find the summarized equation below

Explanation:

Mole = mass ÷ molar mass

Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)

= 2 + 64 + 112

= 178g/mol

According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:

Mole = 1780/178

Mole = 10moles

2. The summarized equation of the contact process is:

1) S + O2 → SO2

2) 2SO2 + O2 → 2SO3

3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7

4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)