Answer:
y = 4x² - 43x + 178
Step-by-step explanation:
Given that data:
1 __ 137
2 __ 110
3 __ 93
4 __ 70
5 __ 65
6 __ 77
Usibg technology, the quadratic regression equation obtained is written in the form:
Ax² + Bx + C
A = 4.34 = 4 ( nearest whole number)
B = - 43.46 = - 43 (nearest whole number)
C = 178.3 = 178 ( nearest whole number)
Hence, the quadratic model is
y = 4x² - 43x + 178
By rounding the coefficients to the nearest whole number, the quadratic function that models the data is[tex]f(x) = 5x^2 - 42x + 174[/tex]
How to Find a quadratic function that models the data.To find a quadratic function that models the data, use a quadratic equation of the form:
[tex]f(x) = ax^2 + bx + c[/tex]
Let's use the given data points to form a system of equations and solve for the coefficients a, b, and c.
Using the first data point (month 1 with 137 births):
[tex]f(1) = a(1)^2 + b(1) + c = 137[/tex]
a + b + c = 137 (Equation 1)
Using the second data point (month 2 with 110 births):
[tex]f(2) = a(2)^2 + b(2) + c = 110[/tex]
4a + 2b + c = 110 (Equation 2)
Using the third data point (month 3 with 93 births):
[tex]f(3) = a(3)^2 + b(3) + c = 93[/tex]
This simplifies to:
9a + 3b + c = 93 (Equation 3)
Solve this system of equations will give us the values of a, b, and c.
Subtract Equation 1 from Equation 2
3a + b = -27 (Equation 4)
Subtract Equation 1 from Equation 3
8a + 2b = -44 (Equation 5)
Now solve Equations 4 and 5 simultaneously.
Multiply Equation 4 by 2 and subtracting it from Equation 5:
8a + 2b - (6a + 2b) = -44 - (-54)
2a = 10
Divide both sides by 2:
a = 5
Now substitute the value of a back into Equation 4:
3(5) + b = -27
15 + b = -27
Subtract 15 from both sides:
b = -42
Finally, substitute the values of a and b into Equation 1
5 + (-42) + c = 137
-37 + c = 137
Add 37 to both sides:
c = 174
Therefore, the quadratic function that models the data is:
[tex]f(x) = 5x^2 - 42x + 174[/tex]
Rounding the coefficients to the nearest whole number, the quadratic function becomes:
[tex]f(x) = 5x^2 - 42x + 174[/tex]
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A point P(3, k) is first transformed by E¹[0, 2] and then by E²[0,3/2] so that the final image is (9, 12), find the value of k.
Hello,
The first transform E1 is the homothetie of center (0,0) and ratio=2
The second transform E2 is the homothetie of center (0,0) and ratio=3/2
P=(3,k)
P'=E1(P)= E1((3,k))=(2*3,2*k)=(6,2k)
P''=E2(P')=E2(6,2k)=(3/2*6,3/2*2*k)=(9,3k)=(9,12)
==> 3k=12
k=4
Which expression can be used to find the difference of the polynomials?
(10m – 6) – (7m – 4)
Answer:
3m -2
Step-by-step explanation:
(10m – 6) – (7m – 4)
Distribute the minus sign
(10m – 6) – 7m + 4
Combine like terms
3m -2
Solve |x - 5| = 7 ......
Answer:
12,-2
Step-by-step explanation:
Find the value of x.
16.2
0.03
38.5
34.8
Hi there!
[tex]\large\boxed{x = 38.5}}[/tex]
To solve, we can use right triangle trig.
We are given the value of ∠A, and side "x" is its adjacent side. We are also given its opposite side, so:
tan (A) = O / A
tan (33) = 25 / x
Solve:
x · tan(33) = 25
x = 38.49 ≈ 38.5
Divisor mayor común de 28 y 48
Answer:
mcd(28,48) = 4
Para encontrar el mcd de 28 y 48:
Los factores de 28 son 28, 14, 7, 4, 2, 1.
Los factores de 48 son 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.
Los factores en común de 28 y 48 son 4, 2, 1, los cuales intersectan los dos conjuntos arriba.
En la intersección de los factores de 28 ∩ factores de 48 el elemento mayor es 4.
Por lo tanto, el máximo común divisor de 28 y 48 es 4.
Water is filling a swimming pool at a constant rate. After 4 hours, 2 inches of water have filled the pool. Write an equation that gives the amount of water, w, after t hours.
Answer:
Step-by-step explanation:
Inches per hour is the rate we are looking for here, which will then be the slope of the linear equation. Slope is the same thing as the rate of change. While this may not seem all that important right now, it's actually a HUGE concept in higher math, especially calculus!
If the pool is filling at a rate of 2 inches per every 4 hours, then by dividing, we get that the rate is 1 inch every 2 hours, which translates to a slope of 1/2. Creating an equation with this slope:
[tex]w=\frac{1}{2}t[/tex] Let's check it. We are told that after 4 hours there are 2 inches of water in the pool. That means if we plug in 4 for t and solve for w, we should get w = 2:
[tex]w=\frac{1}{2}(4)[/tex] and
w = 2. So we're good!
The volume of a cone is 329.6 cubic inches, and the height is 5.4 inches. Which of the following is the closest to the radius r of the cone, in inches?
Answer:
329.6=1/3×16.97r
5.66r=329.6/÷5.66
r=58.23
Can someone please be generous & help I’ve been struggling all night
Answer:
Slope-intercept
y = 3/4(x) - 7
Point slope
y -5= 3/4(x - 16)
Step-by-step explanation:
In slope-intercept
We have the general slope intercept as;
y = mx + b
where m is the slope and b is the y-intercept
in this case, m = 3/4 and b = -7
So we have;
y = 3/4(x) - 7
In point-slope
we have the general form as;
y-y1 = m(x-x1)
So what we have is as follows;
y -5= 3/4(x - 16)
Where we have (x1,y1) = (16,5)
Find the value of sin H rounded to the nearest hundredth, if necessary
Answer:
7/25 or .28
Step-by-step explanation:
sin=opp/hyp
7/25
What is the slope of the line whose equation is y-4=5/2(x-2)?
Answer:
[tex]slope = \frac{ - 1 - 4}{0 - 2} \\ = \frac{ - 5}{ - 2} \\ = { \tt{ \frac{5}{2} }}[/tex]
please help answer these!!!!
Jimmy’s family moved to a tropical climate. For the year that followed, he recorded the number of days that had a temperature above 400C each month. His data contained -
14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13 and 8
1) Find the mean for his data set of days that had a temperature above 400C.
2) Find the median for his data set of days that had a temperature above 400C.
3) Find the mode for his data set of days that had a temperature above 400C.
4) If, instead, there are 5 more days per month that had a temperature above 400C, what will be the mean for the data?
5) If, instead, there are 2 more days per month that had a temperature above 400C, what will be the mode for the data?
Answer:
1) 11.75
2) 11.5
3) 11 and 14
4) 16.75
5) 13, and 16
Step-by-step explanation:
The given data is 14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13, 8
1) The mean, [tex]\overline x[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8)/12 = 11.75
2) The data arranged in increasing order is presented as follows;
8, 10, 10, 11, 11, 11, 12, 13, 13, 14, 14, 14
The count of he data points = 12
The median = The data at the (n + 1)/2 = (12 + 1)/2 = 6.5th position = 11 + (12 11)/2 = 11.5
The median = 11.5
3) The mode of the data set are 11 and 14
4) Where there are 5 more days per month that had a temperature above 40°C, we get;
The mean, [tex]\overline x_1[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8+5×12 )/12 = 16.75 = [tex]\overline x[/tex] + 5
5) Given that there are 2 more days per month that had a temperature above 40°C, we get the days per month with temperatures above 40°C as follows;
8 + 2, 10 + 2, 10 + 2, 11 + 2, 11 + 2, 11 + 2, 12 + 2, 13 + 2, 13 + 2, 14 + 2, 14 + 2, 14 + 2
10, 12, 12, 13, 13, 13, 14, 15, 15, 16, 16, 16
Therefore, the mode are 13, and 16
true or false? A circle could be circumscribed about the quadrilateral below.
Answer: the answer is true
Answer:
false
Step-by-step explanation:
here the opposite angle of quadrilateral aren't supplematary the circle have no chance to be circumscribed
Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes how many miles does he walks in 1 minutes
Answer:
1/12 mile
Step-by-step explanation:
We can use a ratio to solve
7/12 miles x miles
---------------- = ---------------
7 minutes 1 minute
Using cross products
7 /12 * 1 = 7x
Divide each side by 7
7/12 * 1/7 = x
1/2 = x
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
⠀Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes ⠀⠀⠀[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
⠀how many miles does he walks in 1 minutes⠀⠀⠀[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
⠀
Randy walks 7/12 miles in 7 minutes
Sooo
He walks in one minutes is
7/12 miles in 7 minutes one minutes is [tex]\sf{\dfrac{\dfrac{7}{12}}{7} }[/tex] one minute =[tex]\sf{\dfrac{7}{12}×\dfrac{1}{7} }[/tex] one minute=[tex]\sf{\dfrac{1}{12} }[/tex][tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
Hence,
he walks in 1 minutes is 1/12 miles.
the area of the rectangle is 48cm^2
show that x satisfies the equation x^2 + 7x -78 = 0
Answer:
No its doesn't satisfy the equation.
[tex]{ \bf{area = 2(l + w)}} \\ { \tt{48 = 2((x + 10) + (x - 3))}} \\ { \tt{24 = 2x + 7}} \\ 2x = 17 \\ x = 8.5 \\ \\ { \bf{in : \: {x}^{2} + 7x - 78 = 0 }} \\ x = 6 \: \: and \: \: - 13[/tex]
Can someone please help me with this?
Intercept Form
Point (-3,4)
Slope 5
m= b=
Answer:
y = 5x + 19
Step-by-step explanation:
y = 5x + b
4 = 5(-3) + b
4 = -15 + b
19 = b
I you borrow 500 for 4 years at an annual interest rate of 6% HOW MUCH WILL YOU PAY altogether
Answer:
620
amount= p+i , to find interest .I=500*4*6/100 =120 amount=500+120=620
**who can help me**
Answer:
.
Step-by-step explanation:
Write the following phrase as an expression c less than 27
A C +27
B C -27
C c/27
D 27 - C
Answer:
(D) 27 - C
Step-by-step explanation:
The "less than" means we are subtracting C from 27, so 27 - C.
Hope it helps (●'◡'●)
x = 4y + 3, 2x + y = -3
System of Equations
Answer:
(- 1, - 1 )
Step-by-step explanation:
Given the 2 equations
x = 4y + 3 → (1)
2x + y = - 3 → (2)
Substitute x = 4y + 3 into (2)
2(4y + 3) + y = - 3 ← distribute parenthesis and simplify left side
8y + 6 + y = - 3
9y + 6 = - 3 ( subtract 6 from both sides )
9y = - 9 ( divide both sides by 9 )
y = - 1
Substitute y = - 1 into (1) for corresponding value of x
x = 4(- 1) + 3 = - 4 + 3 = - 1
solution is (- 1, - 1 )
A new school has x day students and y boarding students.
The fees for a day student are $600 a term.
The fees for a boarding student are $1200 a term.
The school needs at least $720 000 a term.
Show that this information can be written as x + 2y ≥ 1200.
Given:
The fees for a day student are $600 a term.
The fees for a boarding student are $1200 a term.
The school needs at least $720000 a term.
To show:
That the given information can be written as [tex]x + 2y\geq 1200[/tex].
Solution:
Let x be the number of day students and y be the number of boarding students.
The fees for a day student are [tex]\$600[/tex] a term.
So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.
The fees for a boarding student are [tex]\$1200[/tex] a term.
The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.
Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:
[tex]\text{Total fees}=600x+1200y[/tex]
The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.
[tex]600x+1200y\geq 720000[/tex]
[tex]600(x+2y)\geq 720000[/tex]
Divide both sides by 600.
[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]
[tex]x+2y\geq 1200[/tex]
Hence proved.
Ah what is the length of XB? I really need to learn how to solve this
Answer:
5.28
Step-by-step explanation:
we use the formula
H²=B²+P²
and we will get the answer
branliest if it is helpful
Answer:
Angle BXY
using pythogoras theory which is
hyp*2= opp*2 +adj*2
hypothenus being the longest part of the angle BX=?
Step-by-step explanation:
hyp= 4.2*2+ 3.2*2
hyp*2 =17.64 + 10.24
hyp*2 = 27.88
hyp =√27.88
hyp=5.28...Ans
note *2...square
Which of the following represents the factorization of the polynomial function
graphed below? (Assume it has no constant factor.)
o
A. y - (x - 1)(x+3)
B. y - (x + 1)(x+3)
O
C. y = (x - 1)(x-3)
Answer:
c: y=(x-1)(x-3)
Step-by-step explanation:
PLEASE HELP DESPERATE
tan=sin/cos so tan=3/5/4/5=3/4
Answer:
SOH CAH TOA
3/5 opposite over hypotenuse
4/5 adjasent over hypotenuse
tan= opposite over adjasent which is 3/4
Step-by-step explanation:
Find the coordinates of the other endpoint when given midpoint (point M) and one of the endpoints (point P). P=(3,5) and M=(-2,0)
Answer:
About Points
S = (x,y) searched point (it will be in the third quadrant )
M = (-2,0) Midpoint | SP |
P = (3,5) one end of the segment | SP |
You have to draw Cartesian.
we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .
We use the information that | SM | = | MP |
Answer : S = (-7,-5)
Step-by-step explanation:
[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad \underline{Q}(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+3}{2}~~,~~\cfrac{y+3}{2} \right)=\stackrel{M}{(-2,0)}\implies \begin{cases} \cfrac{x+3}{2}=-2\\[1em] x+3=-4\\ \boxed{x = -7}\\[-0.5em] \hrulefill\\ \cfrac{y+3}{2}=0\\[1em] y+3=0\\ \boxed{y=-3} \end{cases}[/tex]
Drag each expression to the correct category.
Apply the produc rules to determine the sign of each expression.
[tex]( - \frac{4}{9} )( \frac{7}{4} ) = \: \: negative [/tex]
[tex]( - 2 \frac{3}{4} )( - 1 \frac{1}{5} ) = \: \: positive[/tex]
[tex](3)( - 3)( - 3)( - 3)( - 3) = \: \: positive[/tex]
[tex]( - \frac{1}{6} )( - 2)( - \frac{3}{5} )( - 9) = \: \: positive[/tex]
[tex]( - \frac{4}{7} )( - \frac{3}{5} )( - 9) = \: \: negative[/tex]
[tex]( - \frac{10}{7} )( \frac{8}{3} ) = \: \: negative[/tex]
Michele was making tuna salad for a party. The recipe for 10 servings called for 8 oz of mayonnaise. A total of 240 people were expected to be at the brunch. How much mayonnaise would Michele need?
1. Divide 240 by 10 = 24
2. Multiply 24 • 8 = 192
Michele will need 192 oz. of mayonnaise.
Answer:
192 oz
Step-by-step explanation:
Hi there!
1) Create a proportion
[tex]\frac{8 (oz)}{10(servings)} =\frac{x(mayo)}{240(servings)} \\\frac{8}{10} =\frac{x}{240}[/tex]
2) Solve for x
[tex]\frac{8}{10} =\frac{x}{240}[/tex]
Multiply both sides by 240
[tex]\frac{8}{10} *240=x\\192=x[/tex]
Therefore, Michele would need 192 oz of mayonnaise.
I hope this helps!
If A =
[tex]if \: a \: = \binom{53}{24} \: and \: b = \binom{32}{10} then \: prove \: that |ab| = |a| . |b| [/tex]
and B = Prove that |AB| = |A| . |B|
Which equation represents a line that passes through (2,-) and has a slope of 3?
Oy-2 = 3(x + 2)
Oy - 3 = 2(x+)
Oy+ 1 = 3(x - 2)
Oy+ < = 2(x-3)
Help?
The equation of the line is y + 1 = 3(x - 2).
The correct option is (3).
What is an equation?Equation: A statement that two variable or integer expressions are equal. In essence, equations are questions, and the motivation for the development of mathematics has been the systematic search for the answers to these questions.
As per the given data:
The line passes through the point (2, -1)
slope of the given line is 3
By using the slope intercept form of line:
y = mx + c
where m is the slope
c is the y intercept
The line passes through the point (2, -1) so substituting the point in the equation also m = 3
y = 3x + c
-1 = 3(2) + c
c = -7
The equation of the line now can be written as:
y = 3x - 7
y + 1 = 3x - 7 + 1
y + 1 = 3(x - 2)
Hence, the equation of the line is y + 1 = 3(x - 2).
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Describe what a vaccine is made of and how it helps prevent infection.
Answer:
Vaccines are made of mixtures that contain either parts of pathogens or whole pathogens that prepare the body's defenses to fight against the pathogens.
hope it helps.
stay safe healthy and happy...Answer:Vaccines are made of mixtures that contain either parts of pathogens or whole pathogens that prepare the body's defenses to fight against the pathogens.
Step-by-step explanation:
