A one tonne crane increases its speed from 30km/h to 108km/h in 35 seconds. Calculate the change in momentum

Solution-1:-

[tex]\boxed{\sf \dfrac{10\times 1000}{60\times 60}}[/tex]

Solution:-2

[tex]\boxed{\sf Sodium\:and\:Potassium}[/tex]

Solution:-3

[tex]\boxed{\sf 320m}[/tex]

Solution:-4

[tex]\boxed{\sf Rough\:tiles\:are\:used\:in\:bathroom}[/tex]

Solution:-5

[tex]\boxed{\sf Mg_3N_2}[/tex]

Solution:-6

[tex]\boxed{\sf Grapes\:and\:Rambutan}[/tex]

Solution:-7

[tex]\boxed{\sf {}^{}_{}N}[/tex]

Solution:-8

[tex]\boxed{\sf Galactuse}[/tex]

Solution:-9

[tex]\boxed{\sf Y-X}[/tex]

Solution:-10

[tex]\boxed{\sf Cell\:wall}[/tex]

Answer:

C. 16 m E

Explanation:

Applying,

The law of addition of vector: Vector in the same direction are added while vector in opposite direction are substracted

From the question above,

Step 1: Total distance covered towards east = 10+12 = 22 m E

Step2: Total distance covered towards west = 6 m W

Therefore, the resultant distance traveled = 22-6 = 16 m E

Hence the right option is C. 16 m E

Answer:

(a) 31.44 m/s (b) 164.74 m/s²

Explanation:

Given that,

The diameter of a disk, d = 12 cm

Radius, r = 6 cm

Angular speed = 5.24 rad/s

(a) Linear speed,

[tex]v=r\omega\\\\v=6\times 5.24\\\\v=31.44\ m/s[/tex]

(b) Centripetal acceleration,

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{31.44^2}{6}\\\\a=164.74\ m/s^2[/tex]

[tex]\implies F_1 < F_2[/tex]

[tex] \implies F_{net} = F_2 - F1[/tex]

[tex]\implies F_{net} = 42 -15[/tex]

[tex]\implies \underline{ \boxed{ F_{net} = 27 \: N}}[/tex]

The net force on the 4.0 kg box is 27 N towards EAST.

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

[tex]M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\ M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\ M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg[/tex]

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

Answer:

E = 20.03 J

Explanation:

Given that,

The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,

Voltage, V = 12 V

We need to find the energy delivered to the lightbulb filament during 2.00 s.

The energy delivered is given by :

[tex]E=I^2Rt[/tex]. ....(1)

As,

[tex]I=\dfrac{q}{t}\\\\I=\dfrac{1.67}{2}\\\\I=0.835\ A[/tex]

As per Ohm's law, V = IR

[tex]R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.835}\\\\R=14.37\ \Omega[/tex]

Using formula (1).

[tex]E=0.835^2\times 14.37\times 2\\\\=20.03\ J[/tex]

So, the energy delivered to the lightbulb filament is 20.03 J.

Answer:

the water jet and the negative object attract

Explanation:

Let's analyze the situation. Water is a good conductor of electricity, so when an object with a positive charge is brought closer, a charge of the opposite sign is created, which is why the two objects attract each other. The charge created comes from the ground

When claiming the object, the charge is reduced to zero or the charge goes to earth since water is a good conductor of electricity, therefore when approaching an object with a negative charge, more charges go to earth and the ring is left with a positive charge and attracts it to the object.

In short, the water jet and the negative object attract

Answer:

una ess abola cola sola answer

Answer:

Option A

Explanation:

From the question we are told that:

Mass [tex]m=0.20kg[/tex]

Velocity [tex]v=4m/s[/tex]

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum

 [tex]M_{a1}=mV[/tex]

 [tex]M_{a1}=0.2*4[/tex]

 [tex]M_{a1}=0.8[/tex]

Final Momentum

 [tex]M_{a2}=-0.8kgm/s[/tex]

Therefore

 [tex]\triangle M_a=-1.6kgm/s[/tex]

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum

 [tex]M_{b1}=mV[/tex]

 [tex]M_{b1}=0.2*4[/tex]

 [tex]M_{b1}=0.8[/tex]

Final Momentum

 [tex]M_{b2}=-0 kgm/s[/tex]

Therefore

 [tex]|\triangle M_a|>|\triangle Mb|[/tex]

Option A

Answer:

1. Initial velocity = 24 m/s

2. Deceleration = –4 m/s²

Explanation:

From the question given above, the following data were obtained:

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

1. Determination of the initial velocity.

Distance travelled (s) = 72 m

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) =?

s = (u + v)t / 2

72 = (u + 0) × 6 / 2

72 = u × 3

Divide both side by 3

u = 72 / 3

u = 24 m/s

2. Determination of the deceleration.

Time (t) = 6 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 24 m/s

Deceleration (a) =?

v = u + at

0 = 24 + (a × 6)

0 = 24 + 6a

Collect like terms

0 – 24 = 6a

–24 = 6a

Divide both side by 6

a = –24 / 6

a = –4 m/s²

Answer:

1. The electric potential would stay the same.

2. The electric potential energy would double

Explanation:

1. Since the electric potential at the point is V and is not dependent on the charge q, the electric potential at the point still remains the same even if the charge q is doubled to 2q.

So, the electric potential remains the same when the charge is doubled to 2q.

2. Since potential energy U = qV where q = charge and V = electric potential. So when the charge is q and electric potential, V, the electric potential energy at the point is U = qV.

When the charge is doubled to 2q and the electic potential remains the same, the electric potential energy is now U' = 2qV = 2U (since U = qV).

So, the electric potential energy at the point is doubled when the charge is doubled.

Answer:

[tex]E=3.22*10^6 N/C[/tex]

Explanation:

From the question we are told that:

Separation Distance [tex]d=1.0cm =0.01m[/tex]

Potential difference [tex]V=3.22 * 10^4 V[/tex]

Generally the equation for Electric Field strength is mathematically given by

 [tex]E=\frac{v}{d}[/tex]

 [tex]E=\frac{3.22*10^4}{0.01}[/tex]

 [tex]E=3.22*10^6 N/C[/tex]

Answer:

imma try and still get wrong

The fielder's required speed is (D + (v * t * cos(a))) / t.

To catch the ball, the fielder must run at a speed that allows them to cover the horizontal distance D between themselves and the hitter, as well as the distance the ball travels horizontally before hitting the ground. The time it takes for the ball to hit the ground can be determined based on its initial vertical velocity and the acceleration due to gravity.

Let's call the time the ball is in the air "t." The horizontal distance the ball travels is given by D + (v * t * cos(a)), where "v" is the initial speed of the ball and "a" is the angle of the ball's flight above ground. The fielder's running speed should equal this horizontal distance divided by "t" to ensure they reach the ball's landing point just in time to catch it. Thus, the fielder's required speed is (D + (v * t * cos(a))) / t.

To know more about horizontal distance, here

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Answer:

Approximately 2*10^13 electrons must be transferred

Explanation:

Below is the given information:

First object carries charge = -8.5 µC

Number of electrons in 1st = 8.5 x 10^-6/(1.6 x 10^-19) = 5.3125 x 10^13

Second object carries a charge = -2.0 µC

The number of electrons in 2nd = 2*10^-6/(1.6*10^-19) = 1.25 x 10^13

so, approximately 2 x 10^13 electrons must be transferred

Answer:

resultant vector =0

Explanation:

because it is connected head to tail in a closed figure

Answer:

Option (c).

Explanation:

Let the mass of each cart is m and the force is F.

Time for cart A is 2t and for cart B is t.

Work done is given by the

W= force x displacement

As the distance is given by

S= u t +0.5 at^2

So, when the time is doubled the distance is four times.

So, WA = F x 4 S

WB = F x S

WA= 4 WB

Answer:

e

Explanation:

From the given information:

Suppose Q = total charge of the sphere.

here, the electric field outside the sphere at distance R/2 can be expressed as:

[tex]E_1 = \dfrac{1}{4 \pi \varepsilon _o}* \dfrac{Q}{(R + \dfrac{R}{2})^2}[/tex]

where:

[tex]k = \dfrac{1}{4 \pi \varepsilon _o}[/tex]

[tex]E_1 = \dfrac{kQ}{(\dfrac{3R}{2})^2}[/tex]

[tex]E_1 = \dfrac{4kQ}{9R^2}[/tex]

For the electric field inside the sphere, we have:

[tex]E_2 = \dfrac{kQr}{R^3}[/tex]

here:

r = distance of the point from the center = R/2

R = radius of the sphere

∴

[tex]E_2 = \dfrac{kQ * \dfrac{R}{2}}{R^3}[/tex]

[tex]E_2 = \dfrac{kQ }{2R^2}[/tex]

As such, the ratio of the electric field outside the sphere to the one inside is:

[tex]\dfrac{E_1}{E_2} = \dfrac{ \dfrac{4kQ}{9R^2}}{ \dfrac{kQ }{2R^2}}[/tex]

[tex]\dfrac{E_1}{E_2} = \dfrac{4kQ}{9R^2} \times \dfrac{ 2R^2 }{kQ}[/tex]

[tex]\mathbf{\dfrac{E_1}{E_2} = \dfrac{8}{9}}[/tex]

For a solid uniformly charged sphere of radius R, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  e) 8/9

field  [tex]E2= \frac{k(Q)}{(3R/2)^2}[/tex]

=  [tex]\frac{4}{9} \frac{k(Q)}{R^2}[/tex]

=

Thus, E2/E1

= (4/9)/(1/2)

= 8/9

Thus, the electric field at a distance R/2 outside the sphere, divided by the electric field at a distance R/2 inside the sphere is -  8/9

Learn more:

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Answer:

646.6 nm

Explanation:

Using the data given, we fit a linear model :

Spectroscope Readings Known Helium Wavelengths (nm)

3.65 388.9

4.75 486.6

4.90 501.6

5.65 587.6

6.45 667.8

7.00 706.5

Using technology like excel to fit the model, the regression model obtained is :

Y = 97.96582X + 27.48458

Where, y is the predicted or corrected wavelength value.

This mod could be used to calculate the corrected wavelength for a given Spectroscope value :

Given a Spectroscope value of 6.32 ; the corrected wavelength is obtained by replacing x in the equation by 6.32 and calculate y ;

Y = 97.96582X + 27.48458

x = 6.32

Y = 97.96582(6.32) + 27.48458

Y = 619.1439824 + 27.48458

Y = 646.6285624

Corrected wavelength value is : 646.6

Answer:

Well if you want to be sure you should just throw it to the ground so then when he lands he can catch it.

If the cannon throws the banana with the same force the monkey falls

(m.g=Fz <=> m.9,81N/kg=...N).

Then the throw will slow down because of the gravitational pull.

Because the banana cannon is selfmade you can choose what mass the bananas in question have, so let that be the same as the monkeys.

The monkey falls with the speed of 9,81m.s => so it takes the monkey 7,1s to land.

If the cannon can shoot the banana at the same speed the monkey falls then they would cross in the middle.

So to do so you need to throw the bananas with a speed of at least 9,81m.s

Soo ... throw them with a force of that is greater then the gravitational pull and things will work out.

I'm sorry I don't know why I wrote all of this irrelevant information it's 2:21 right now and I'm tired.

kind regards

Answer:

a)  T = -22796.5 N,  b)  F = 3000 N

Explanation:

a) For this part we use Newton's second law

Let's set a reference frame with the x-axis in the direction of motion and the y-axis in the vertical direction.

We make a free-body diagram for each body,

the tractor has the bar force (T) and the push force (F) and the friction force (fr₁)

Y axis

        N₁ -W₁ = 0

        N₁ = M₁ g

X axis

        F - T - fr₁ = M₁ a

the Trailer has the bar force (T) and the friction force (fr₂)

Y axis  

      N₂ - W₂ = 0

      N₂ = m₂ g

X axis

     T - fr₂ = m₂ a

let's write the system of equations

      F - T - fr₁ = M₁ a          (1)

           T - fr₂ = m₂ a

we solve

       F - (fr₁ + fr₂) = (M₁ + m₂) a

indicate that the total friction forces are fr = 3000N

       fr = fr₁ + fr₂

        F =[tex]\frac{(M_1+m_2) a}{fr}[/tex]

let's calculate

        F =[tex]\frac{(2000+1500) \ 3}{3000}[/tex]

        F = 3.5 N

The friction force is

       fr = μ N

the norm of the system is N = N₁ + N₂

       μ = [tex]\frac{fr}{N_1 + N_2}[/tex]

       μ = [tex]\frac{3000}{2000+1500}[/tex]

       μ = 0.858

with this value we can find the friction force 1 and substitute in equation 1

       F - T - μ N₁ = M₁ a

       T = F - M₁ (a + μ g)

        T = 3.5 - 2000 (3 + 0.858  9.8)

        T = -22796.5 N

b) when the system moves with constant velocity the acceleration is zero

            F - T - fr₁ = 0

                  T - fr₂ = 0

we solve

           F + (fr₁ + fr₂) = 0

           F = fr₁ + fr₂

           F = 3000 N

Explanation:

Given:

[tex]A_1[/tex] = 4.5 cm[tex]^2[/tex]

[tex]v_1[/tex] = 40 cm/s

[tex]v_2[/tex] = 90 cm/s

[tex]A_2[/tex] = ?

a) The continuity equation is given by

[tex]A_1v_1 = A_2v_2[/tex]

Solving for [tex]A_2[/tex],

[tex]A_2 = \dfrac{v_1}{v_2}A1 = \left(\dfrac{40\:\text{cm/s}}{90\:\text{cm/s}}\right)(4.5\:\text{cm}^2)[/tex]

[tex]= 2\:\text{cm}^2[/tex]

b) If the cross-sectional area is reduced by 50%, its new area [tex]A_2'[/tex] now is only 1 cm^2, which gives us a radius of

[tex]r = \sqrt{\dfrac{A_2'}{\pi}} = 0.564\:\text{cm}[/tex]

Answer:

The covalent bond is formed by pairs of electrons that are shared between two atom

Explanation:

The covalent bond is formed by pairs of electrons that are shared between two atoms, in general the electrons must have opposite spins to have a lower energy state.

In this bond, the electrons are between the two atoms and are shared between them in such a way that there is a configuration of eight electrons in the orbit.

Answer:

A spinning electron produces a magnetic field.

Explains the fine structure of Hydrogen lines.

Answer:

C Quincy

Explanation:

Both Frieda and Vladimir are too young to be making their own decisions. Lucinda has limited freedom due to having two children, while Quincy is just now becoming an adult and has his whole life still ahead of him. Therefore, Quincy has the most freedom to make their own lifestyle decisions.

I hope this helps!

Answer:

The correct answer is C. Quincy is 16 years old and lives in a dormitory

Explanation:

Quincy being 16 may be able to get a job and hold a membership at a gym even if not at a gym he still has the most freedom period with Lucinda having children and Frieda and Vladimir being to young to make the choices of exercising on their own.

Please tell me if I'm wrong so I may give you the correct answer!

Happy Holidays!!  

The period and the amplitude of the weight suspended from spring are 0.33 seconds and 10 centimeters, respectively.

1) The period is given by:

[tex] T = \frac{1}{f} [/tex]

Where:

f: is the frequency = 3 bob up and down each second = 3 s⁻¹ = 3 Hz

[tex] T = \frac{1}{f} = \frac{1}{3 Hz} = 0.33 s [/tex]

Hence, the period is 0.33 s.

2) The amplitude is the distance between the equilibrium position and the maximum position traveled by the spring. Since the spring is moving up and down over a distance of 20 cm, then the amplitude is:          

[tex] A = \frac{20 cm}{2} = 10 cm [/tex]  

Therefore, the amplitude is 10 cm.          

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I hope it helps you!                    

Answer:

a)   W = - 1.752 10⁻¹⁸ J,  b)    U = + 1.752 10⁻¹⁸ J

Explanation:

a) work is defined by

         W = F . x

the bold letters indicate vectors, in this case the force is electric

         F = q E

we substitute

         F = q E x

the charge of the electron is

         q = - e

         F = - e E x

let's calculate

         W = - 1.6 10⁻¹⁹  365  3 10⁻²

         W = - 1.752 10⁻¹⁸ J

b) the change in potential energy is

          U = q ΔV

the potential difference is

          ΔV = - E. Δs

we substitute

         U = - q E Δs

the charge of the electron is

           q = - e

          U = e E Δs

we calculate

           U = 1.6 10⁻¹⁹ 365  3 10⁻²

           U = + 1.752 10⁻¹⁸ J

Answer:

The answer is continuity ( D )

Explanation:

PLZ MARK AS BRAINLIEST

Over the first 16.4 m, the person performs

W = (60.0 N) (16.4 m) = 984 J

of work.

Over the remaining 6.88 m, they perform a varying amount of work according to

F(x) ≈ 60.0 N + (-8.72 N/m) x

where x is in meters. (-8.72 is the slope of the line segment connecting the points (0, 60.0) and (6.88, 0).) The work done over this interval can be obtained by integrating F(x) over the interval [0, 6.88 m] :

W = ∫₀⁶˙⁸⁸ F(x) dx ≈ 206.4 J

(Alternatively, you can plot F(x) and see that it's a triangle with base 6.88 m and height 60.0 N, so the work done is the same, 1/2 (6.88 m) (60.0 N) = 206.4 J.)

So the total work performed by the person on the box is

984 J + 206.4 J = 1190.4 J ≈ 1190 J

Answer:

Momentum of object A = Momentum of object C < momentum of B.

Explanation:

The momentum of an object is equal to the product of mass and velocity.

Object A has a mass m and a speed v. Its momentum is :

p = mv

Object B has a mass m/2 and a speed 4v. Its momentum is :

p = (m/2)×4v = 2mv

Object C has a mass 3m and a speed v/3. Its momentum is :

p = (3m)×(v/3) = mv

So,

Momentum of object A = Momentum of object C < momentum of B.