Professor Iron always gives two exams in his communications class. He only uses the lower of the two scores that a student gets on the exams when he calculates the course grade. Put the grade on the first exam on the horizontal axis and the grade on the second exam on the vertical axis. What kind of preference a student should have for these two grades. Group of answer choices Perfect Complements Perfect Substitutes Cobb-Douglas Preference Neutral Preference
Answer:
Perfect complements
Step-by-step explanation:
Since minimum score of tests is to be considered. It is a case of perfect complements.
Correct option is
Perfect complements
Write the sum using summation notation, assuming the suggested pattern continues.
2, -10, 50, -250, +…
Is this sequence arithmetic or geometric? How do you know?
Answer:
Step-by-step explanation:
It's geometric. The nth term differs by -5 when compared to the n+1 term.
Sum 0 to n a(-5)^n-1 where a = 2
I think this is what you want, but there is also a formula. See below.
Sum = a (r^n - 1)/(r - 1)
Người ta tiến hành bài kiểm tra được thiết kế để đánh giá thái độ đối với bệnh nhân đang
hấp hối trên 60 sinh viên y năm nhất, kết quả tính được điểm trung bình của mẫu là 73,8 và độ
lệch chuẩn mẫu là 8,3. Với mức ý nghĩa 5%, số liệu trên có đủ mạnh để cho rằng điểm trung bình
bài đánh giá thái độ của sinh viên y năm nhất là trên 70 hay không?
Answer:
cannot understand the language man
but please follow
What type of polynomial is: sqrt 7x^4 - x^3
Answer:
Quartic cause highest degree is 4
M is the midpoint of HA. The coordinate of His
(3x + 5,3y) and the coordinate of A is (x-1, -y). What is
the coordinate of M?
Step-by-step explanation:
ANSWER:(2x+2,y)
__ (5 + 4) = 2 * 5 + 2 * 4
PLEASE EXPLAIN HOW YOU GOT THE ANSWER
Answer:
x = 2
Step-by-step explanation:
→ Simplify
x × ( 9 ) = 10 + 8
→ Further simplify
9x = 18
→ Divide both sides by 9
x = 2
rewrite 7/10 and negative 2/5
I need help ASAP thank you
Answer:
√9 × √6
√54
√27 × √2
Step-by-step explanation:
We can obtain the answer to the question given above as illustrated below:
3√6
Recall
a√b = √(a×a×b)
Thus,
3√6 = √(3×3×6)
3√6 = √(9 × 6)
Recall
√(a × b) = √a × √b
√(9 × 6) = √9 × √6
Therefore,
3√6 = √9 × √6
Recall
√9 × √6 = √(9 × 6)
√9 × √6 = √54
Thus,
3√6 = √54
Recall
√54 = √(27 × 2)
√54 = √27 × √2
Therefore,
3√6 = √27 × √2
Therefore,
3√6 = √9 × √6 = √54 = √27 × √2
Find f(-2) if f(x) =x^4 +2x^2-1
Answer:
Plug -2 in for x of f(x)
--> -2^4 + 2(-2)^2 - 1
---> 23
f(-2) = 23
What are the common factors of 24 and 60
2 and 3 are the common factor of 24 and 60
A physician orders Diflucan oral suspension 200 mg now followed by 100 mg daily for a total of two weeks. How many 35 mL bottles of Diflucan 10 mg/ml suspension are needed to fill this prescription?
Answer:
Step-by-step explanation:
Total amount = 200 mg + (13 days)×(180 mg)/day = 2620 mg
One 35 mL bottle contains (35 mL)×(10 mg)/mL) = 350 mg of medication.
(2620 mg)×(1 bottle)/(350 mg) ≈ 7.5 bottles
8 bottles are needed.
A building security code has 2 numeric
digits, O through 9, followed by 2 letters.
What is the probability that the first digit
is 9 and the last letter is A?
Answer:
Step-by-step explanation:
First number is 1/10
Last letter is 1/26
The second digit is 1/9
The first letter is 1/25
1/10 * 1/26 * 1/9 * 1/25
0.00001709
This assumes no duplication is allowed,
If there are duplications
then 1/10 * 1/10 * 1/26 * 1/26
0.000014782
Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. That tree can be seen when one walks 14 bu from the south gate, turns west and walks 1775 bu. Find the length of each side of the city.
Answer:
The length of each side of the city is 250b
Step-by-step explanation:
Given
[tex]a = 20[/tex] --- tree distance from north gate
[tex]b =14[/tex] --- movement from south gate
[tex]c = 1775[/tex] --- movement in west direction from (b)
See attachment for illustration
Required
Find x
To do this, we have:
[tex]\triangle ADE \sim \triangle ACB[/tex] --- similar triangles
So, we have the following equivalent ratios
[tex]AE:DE = AB:CB[/tex]
Where:
[tex]AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775[/tex]
Substitute these in the above equation
[tex]20:x/2 = 20 + x + 14: 1775[/tex]
[tex]20:x/2 = x + 34: 1775[/tex]
Express as fraction
[tex]\frac{20}{x/2} = \frac{x + 34}{1775}[/tex]
[tex]\frac{40}{x} = \frac{x + 34}{1775}[/tex]
Cross multiply
[tex]x *(x + 34) = 1775 * 40[/tex]
Open bracket
[tex]x^2 + 34x = 71000[/tex]
Rewrite as:
[tex]x^2 + 34x - 71000 = 0[/tex]
Expand
[tex]x^2 + 284x -250x - 71000 = 0[/tex]
Factorize
[tex]x(x + 284) -250(x + 284)= 0[/tex]
Factor out x + 284
[tex](x - 250)(x + 284)= 0[/tex]
Split
[tex]x - 250 = 0 \ or\ x + 284= 0[/tex]
Solve for x
[tex]x = 250 \ or\ x =- 284[/tex]
x can't be negative;
So:
[tex]x = 250[/tex]
Find the missing side of the right triangle.
Answer:
√65
Step-by-step explanation:
you have to use the pythagoras theorem to find x which is the hypotenuse
x²=7²+4²
x²=49+16
√x²=√65
x=√65
I hope this helps
GIVING 25 POINTS AND BRAINIER IF ANSWERED!
What is one thing you would not do when finding the question in a word problem?
A. Look for a problem similar to the word problem you are trying to solve.
B. The question may not be directly stated.
C. So you can understand what the facts are in the word problem.
D. To define your strategy or game plan to solve the word problem.
Answer:
B. The question may not be directly stated.
simplify the following without using calculator
√50 + √98
Answer:
The exact answer is 12*√2, if you need approximately answer it is 12*1.4= 16.8
Step-by-step explanation:
√50 + √98 = √(25*2)+√(49*2)= √25√2+√49*√2= 5√2+7*√2=12*√2
What's the value of n if 13+19= n+25
.
.
..
.
.............
Answer:
[tex]13+19=n+25[/tex]
[tex]n+25=13+19[/tex]
Add 13+19= 32
[tex]n+25=32[/tex]
Now Subtract 25 from both sides
[tex]n+25-25=32-25[/tex]
[tex]n=7[/tex]
OAmalOHopeO
A restaurant operator in Accra has found out that during the lockdown,if she sells a plate of her food for Ghc 20 each,she can sell 300 plates but for each Ghc5 she raises the price,10 less plates are sold. A.Draw a table relating 5 different price levels with their corresponding number of plates sold.
B.Use the table to find the slope of the demand
C.Find the equation of the demand fraction.
D.Use your equation to determine the price in Ghc if she sells one plate of food to maximize her revenue
The demand equation illustrates the price of an item and how it relates to the demand of the item.
The slope of the demand function is -1/2The equation of the demand function is: [tex]R(x) = (300 - 10x) \times (20 + 5x)[/tex]The price that maximizes her revenue is: Ghc 85From the question, we have:
[tex]Plates = 300[/tex]
[tex]Price = 20[/tex]
The number of plates (x) decreases by 10, while the price (y) increases by 5. The table of value is:
[tex]\begin{array}{cccccc}x & {300} & {290} & {280} & {270} & {260} \ \\ y & {20} & {25} & {30} & {35} & {40} \ \end{array}[/tex]
The slope (m) is calculated using:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
So, we have:
[tex]m = \frac{25-20}{290-300}[/tex]
[tex]m = \frac{5}{-10}[/tex]
[tex]m = -\frac{1}{2}[/tex]
The equation of the demand is as follows:
The initial number of plates (300) decreases by 10 is represented as: (300 - 10x).
Similarly, the initial price (20) increases by 5 is represented as: (20 + 5x).
So, the demand equation is:
[tex]R(x) = (300 - 10x) \times (20 + 5x)[/tex]
Open the brackets to calculate the maximum revenue
[tex]R(x) =6000 + 1500x - 200x - 50x^2[/tex]
[tex]R(x) =6000 + 1300x - 50x^2[/tex]
Equate to 0
[tex]6000 + 1300x - 50x^2 =0[/tex]
Differentiate with respect to x
[tex]1300 - 100x =0[/tex]
Collect like terms
[tex]100x =1300[/tex]
Divide by 100
[tex]x =13[/tex]
So, the price at maximum revenue is:
[tex]Price= 20 + 5x[/tex]
[tex]Price= 20 + 5 * 13[/tex]
[tex]Price= 85[/tex]
In conclusion:
The slope of the demand function is -1/2The equation of the demand function is: [tex]R(x) = (300 - 10x) \times (20 + 5x)[/tex]The price that maximizes her revenue is: Ghc 85Read more about demand equations at:
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Which proportion would you use to solve the following problem?
A map has a scale of 1 cm : 5 km. Determine how far apart two cities are if they are 4 cm apart on the map.
A.
B.
C.
D.
Answer:
20 km
Step-by-step explanation:
We can use ratios to solve
1 cm 4 cm
-------- = ------------
5 km x km
Using cross products
1 * x = 4 * 5
x = 20
20 km
Answer:
1/5 = 4/x
Step-by-step explanation:
Each cm on the map represents 5 km. If it shows 4 cm apart of the map, you can use the proportion 1 cm : 5 km = 4 cm : x km.
Factor the following expressions completely. Show and check all work on your own paper.
x^2+169
I need you guy’s help answer thanks so much
Answer:
D
Step-by-step explanation:
inverse just means opposite so if its shown dividing it first then adding, then the inverse is multiplying then subtracting
find the surface area of the prism HURRY HURRY
Answer:
should be 192
Step-by-step explanation:
pls help! I need the answer quickly! thank you!
The perimeter of a triangle is the summation of the three sides of the triangle. Base on the assumed values, the length of side BD is 2.
For [tex]\triangle ACD[/tex], the sides are: AC, AD and CD
So, the perimeter is:
[tex]P_{\triangle ACD} = AC + AD + CD[/tex]
For [tex]\triangle ABD[/tex], the sides are: AB, AD and BD
So, the perimeter is:
[tex]P_{\triangle ABD} = AB + AD + BD[/tex]
The difference in the perimeters is:
[tex]P_{\triangle ACD} - P_{\triangle ABD} =1 + \sqrt 3[/tex]
So, we have:
[tex](AC + AD + CD) - ( AB + AD + BD) =1 + \sqrt 3[/tex]
Open brackets
[tex]AC + AD + CD - AB - AD - BD =1 + \sqrt 3[/tex]
Evaluate like terms
[tex]AC + CD - AB - BD =1 + \sqrt 3[/tex]
Make BD the subject
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex]
The solution cannot be completed because the side lengths of [tex]\triangle ACD[/tex] and [tex]\triangle ABD[/tex] are not given; so, I will assume the following values.
[tex]AC =2; CD = 1; AB = \sqrt 3[/tex]
[tex]BD = AC + CD - AB - (1 + \sqrt 3)[/tex] becomes
[tex]BD = 2 + 1 + \sqrt 3 - (1 + \sqrt 3)[/tex]
Open bracket
[tex]BD = 2 + 1 + \sqrt 3 - 1 - \sqrt 3[/tex]
Evaluate like terms
[tex]BD = 2[/tex]
Base on the assumed values, the length of side BD is 2.
Read more about perimeters at:
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14feet 23feet round each measurement to the nearest ten
Solve this inequality: 14 <-7x
Answer:
x > -2
Step-by-step explanation:
14 <-7x
or, 14/-7=-7x/-7
or, -2 < x
Y= 3x-1
2x+6=y substitution method
Answer: (7, 20)
Concept:
There are three general ways to solve systems of equations:
EliminationSubstitutionGraphingSince the question has specific requirements, we are going to use substitution to solve the equations.
Solve:
Given equations
y = 3x - 1
2x + 6 = y
Substitute the y value since both equations has isolated [y]
2x + 6 = 3x - 1
Add 1 on both sides
2x + 6 + 1 = 3x - 1 + 1
2x + 7 = 3x
Subtract 2x on both sides
2x + 7 - 2x = 3x - 2x
[tex]\boxed{x=7}[/tex]
Find the value of y
y = 3x - 1
y = 3(7) - 1
y = 21 - 1
[tex]\boxed{y=20}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Evaluate the expression 2x-xy if x= -1/2 and y=8
Answer:
3
Step-by-step explanation:
2x-xy
2(x)-(x)(y)
2(-1/2)-(-1/2)(8)
-1 - (-4)
-1 + 4
3
Answer:
3
Step-by-step explanation:
2x-xy
Let x = -1/2 and y = 8
2(-1/2) - (-1/2)(8)
Multiply
-1 - (-4)
Subtracting a negative is like adding
-1+4
Add
3
What are the solutions?
It's the third option.
Completing the square yields
x ² + 9x + 7 = 0
(x ² + 9x + 81/4) + 7 = 81/4
(x + 9/2)² + 7 = 81/4
Now solving for x gives
(x + 9/2)² = 53/4
x + 9/2 = ± √(53/4) = ± √53/2
x = (-9 ± √53)/2
(4m-n-3). 12n13
8m 20
Answer:
24n^7/m^16
Step-by-step explanation:
Just simplify and rewrite what ever you get simplify again 2 times and now make the calculation as you see every big number is a whole number and is a pair.
Sierra used the following steps to copy angle ABC:
1. Draw a ray with the endpoint D.
2. Place the compass on point B. Swing an arc that intersects rays BA and BC that creates point E on BA and Fon BC.
3. Keeping the compass at the same width, place it on point D, and swing an arc that creates point G on the ray.
4. Open the compass to the distance between points A and E.
5. Keeping the compass at the same width, place it on point G and swing an arc that intersects the arc created from point D.
6. Label the intersection of the arcs created from point D with point H, and draw a ray from point D through point H.
In which step did the error occur? Explain. (1 point)
Step 2. She did not set the proper compass length.
O Step 2. She drew an arc Instead of a circle.
Step 3. She placed the compass at an incorrect point.
Step 4. She measured the incorrect length.
The process of copying an angle through construction involve ensuring
that the distance between the two rays forming the angle is the same or
equal in the original and copy of the angle at a given equal distance from
the vertex of both angles
The step where the error occur is step 4. She measured the incorrect length
The reason for the above selection is as follows:
The steps to copy an angle are as follows;
Draw the initial line, l, (the working line) of the copy of the angle as a ray with an endpoint, DIn the given angle ∠ABC, with the compass placed at point B, construct an arc that intersect the two sides of the given line (BA at point E, and BC at point F) by opening the compass to a radius, rPlace the compass at the point D on the line l and with the radius r from above, draw an arc (D, r) that intersects the line l at the point GPlace the compass at point E on line AB, and construct an arc passing through point F, therefore having radial length EFPlace the compass at point G and construct an arc with radial length EF that intersects the arc (D, r) at point H and draw a ray from the point D passing through point H to complete the constructionA critical step in the copying process involves the finding the distance
between the initial line and the terminal line EF at a given distance DG =
AE from the angle vertex
The step where the error occur is in step 4. by opening the compass
between points A and E which are points on the same line and placing the
compass at point G on line l to draw an arc intersecting the arc created
from point D at H, thereby making the radial distance between the two lines
forming the angle, in the copied angle at a distance E from the vertex,
equal to AE rather than EF
Therefore, the error occurred in step 4. She measured the incorrect length
Learn more about the steps to copy an angle here:
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