A projectile is fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. How long
will it take for the projectile to reach the ground?

Answer:

Sine Theta is a negative number, Tan Theta is a greater number then zero.

Step-by-step explanation:

If Sine Theta is less then zero, she is a negative number. So 0 - y = -y.

So if Tan Theta is a greater number than zero, her number is not negative. So 0 + y = y

I hope this helped! I didn’t really understand the question though.

Answer:

altitude = 30 cm

lateral surface area = 301 cm² (approximately)

Step-by-step explanation:

let the altitude be x,

240=6*4*x/3

or, x=30 cm

Lateral surface area,

=l×√(w/2)²+h²]+w×√[(l/2)²+h²]

=6×√[(4/2)²+30²]+4×√[(6/2)²+30²]

≈300.99806

≈ 301 cm²

Answered by GAUTHMATH

AnsweStep-by-step explanation:

lol

Explanation:

This is known as a cyclic quadrilateral since all four points are on the circle's edge, and the quadrilateral is entirely inside the circle (no parts of the quadrilateral spill outside the circle). Another term is "inscribed quadrilateral"

Since we have an inscribed quadrilateral, this means the opposite angles of the quadrilateral are supplementary.

B+D = 180

120+x = 180

x = 180-120

x = 60

Answer:

1) g is the dependent variable.(A)

2) u is the independent variable.(D)

Step-by-step explanation:

Explanation:

The range is the set of y outputs of a relation. So we just list the y coordinates of the points shown.

We could sort the values to get {-1, 4, 11, 13}, but order doesn't matter in a set. So this step is optional.

Step-by-step explanation:

Since an interior angle is 150 degrees, its adjacent exterior angle is 30 degrees.  Exterior angles of any polygon always add up to 360 degrees.  With the polygon being regular, we can just divide 360 by 30 to get 12 sides.

Answer:

en la calasa ni esta en la estacion

Answer: Hi some data is missing attached below is the missing data

answer:

WMA = 174.53

Step-by-step explanation:

Determine the three-week weighted moving average with weights

( 1/2, 1/3, 1/6 )

Weighted moving average ( WMA ) = 174.53

MSE = ∑ (xi - WMA)^2 / n

        = 9.71

attached below is the detailed solution/table

Answer:

Face card= 12/52

(52 cards in a deck and 12 are face cards)

Red face card= 6/12

(12 face cards in a deck cards in a deck and 6 are red face cards)

Black face card= 6/52

(6 are black)

Black card= 26/52

(52 cards in a deck and 26 are black)

Red card= 26/52

(26 are red)

Answer:

We know that every number can be written as a product of prime numbers.

The method to find the factorized form of a number depends on the number, we just try to find the different factors by dividing by them, for example for the number 1000 we have:

1000 is an even number, then we can divide it by 2 (2 is a prime number)

1000 = 2*500   (so we already found a prime factor)

500 is also an even number, so we can divide it by 2

1000 = 2*500 = 2*2*250  (we found another prime factor)

dividing by 2 again we get:

1000 = 2*2*250 = 2*2*2*125

1000 = (2*2*2)*125

now we just need to factorize 125

we know that 125 is a multiple of 5, such that:

125 = 5*25 = 5*5*5

(5 is a prime number, so it is completely factorized).

Then the factorization of 1000 is:

1000 = (2*2*2)*(5*5*5) = 2^3*5^3

Now with another example, 1422

1422 is an even number, so we again start using the factor 2:

1422 = 2 = 711

then:

1422 = 2*711

we already found a factor.

711 is a multiple of 3 (the sum of its digits is a multiple of 3), then:

711/3 = 237

We can write our number as:

1422 = 2*3*237

237 is also a multiple of 3

237/3 = 79

then:

1422 = 2*3*3*79

and 79 is a prime number, so we already have 1422 completely factorized.

Given:

The average number of songs performed there in a 10 day period is 167.

To find:

The number of songs performed there in a year time.

Solution:

We have,

Number of songs performed in 10 days = 167

Number of songs performed in 1 day = [tex]\dfrac{167}{10}[/tex]

                                                              = [tex]1.67[/tex]

We know that 1 year is equal to 365 days. So,

Number of songs performed in 365 day = [tex]1.67\times 365[/tex]

Number of songs performed in 1 year     = [tex]609.55[/tex]

                                                                   [tex]\approx 610[/tex]

Therefore, the number of songs performed there in a year time is about 610.

Answer:

335%

Step-by-step explanation:

Answer:

a) See step by Step explanation

b) z(s) = 48.88

c) We reject H₀. The sample is not representative of American Adult Population

Step-by-step explanation:

From sample

sample mean .    x = 49.28

sample standard deviationn   s = 17.21

sample size  n₁  = 4857

Population mean according to Census data

μ  = 37.2

a) Test Hypothesis

Null Hypothesis .                  H₀ .                    x =  μ  = 37.2

Alternative Hypothesis        Hₐ .                    x ≠ μ

b) We have sample size (4857) we can use normal distribution

z (c) for    α = 0.01   α/2 . = 0.005  is from z-table . z(c) = 2.575

To calculate  z(s) =  ( x  - μ ) / s /√n

z(s) =  12.08 * √4857 / 17.21

z(s) = 12.08* 69.64 / 17.21

z(s) = 48.88

z(s) > z(c)

We should reject H₀. The sample is not representative of American Adult population

Answer:

729π ft³

Step-by-step explanation:

Applying,

Volume of a cone

V = πr²h/3.............. Equation 1

Where r = radius of the base, h = height, π = pie

From the question,

Given: r = 9 ft, h = 27 ft

Substitite these values into equation 1

V = π(9²)(27)/3

V = 729π ft³

Hence the volume of the figure in terms of π is 729π ft³

Answer:

3/20

Step-by-step explanation:

By question it's given that ,

[tex]\implies \dfrac{a}{b}=\dfrac{2}{5}[/tex]

[tex]\implies \dfrac{b}{c}=\dfrac{3}{8}[/tex]

And we need to find out the value of a/c .For that Multiply both of them , we have ;

[tex]\implies \dfrac{a}{b} \times\dfrac{b}{c}=\dfrac{2}{5}\times \dfrac{3}{8} \\\\\implies \dfrac{a}{c}= \dfrac{3}{20}[/tex]

Hence the required answer is 3/20 .

Answer:

Hello?

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

2+2+82-72

86 - 72 = 14

Find the negative reciprocal of the slope of the orginal line. Undefined

Answer:

800

Step-by-step explanation:

100%-0%=100%

100% is also equal to the number 1.

We now have 1x=800

Simplify that and get 800

Answer:

the image is hard to read... this is the best that I can see

Step-by-step explanation:

[tex]\sqrt[3]{x^{3} } = x^{3/3} = x\\\sqrt[3]{x^{5} } = x^{5/3} \\\\\sqrt[5]{x } = x^{1/5} \\\\\sqrt[2]{x ^3 } = x^{3/2} \\[/tex]

~~~~~~~~~~~~~~~~~~~

Answer:

The 3rd

Step-by-step explanation:

If x goes to infinity, f(x) goes to infinity too:

[tex]lim \: \frac{2 {x}^{2} }{3x - 1} = lim \frac{2x}{3 - \frac{1}{x} } = \frac{ 2 \times \infty }{3 - 0} = \infty [/tex]

Answer: hello there here are your answers:

8) B multiplication property of zero

9) C additive identify

1) 8

2) -2a-7

Step-by-step explanation:

1) [tex]\frac{3+u}8^{2} \\u=5 \\so\\ \frac{3+5}8^{2} \\3+5=8^{2} \\8^{2} =\\64 \\\\ 64/8=\\\\\\8 \\there.\\\\\\[/tex]

2)[tex]-2(a-7)\\\\-2(a)(-7)\\\\=-2a+14\\\\\\there[/tex]

You have some data points labeled by [tex]x[/tex]. They form the set {3, 5, 7}.

The mean, [tex]\bar x[/tex], is the average of these values:

[tex]\bar x = \dfrac{3+5+7}3 = \dfrac{15}3 = 5[/tex]

Then in the column labeled [tex]x-\bar x[/tex], what you're doing is computing the difference between each data point [tex]x[/tex] and the mean [tex]\bar x[/tex]:

[tex]x=3 \implies x-\bar x = 3 - 5 = -2[/tex]

[tex]x=5 \implies x-\bar x = 5-5 = 0[/tex]

[tex]x=7 \implies x-\bar x = 7 - 5 = 2[/tex]

These are sometimes called "residuals".

In the next column, you square these values:

[tex]x=3 \implies (x-\bar x)^2 = (-2)^2 = 4[/tex]

[tex]x=5 \implies (x-\bar x)^2 = 0^2 = 0[/tex]

[tex]x=7 \implies (x-\bar x)^2 = 2^2 = 4[/tex]

and the variance of the data is the sum of these so-called "squared residuals".

9514 1404 393

Answer:

  (b)  x -3 ≥ 0

Step-by-step explanation:

The square root function will return non-negative values, so the inequality √(x-3) ≥ 0 gives no new information. What is required is that the argument of the square root function be non-negative:

  x -3 ≥ 0

9514 1404 393

Answer:

Step-by-step explanation:

The attached graph shows the various company costs for x number of hours. The graph nearest the x-axis represents the lowest cost.

We can see that cost is lowest using Company A for 2 hours or less, and Company C for 5 hours or more. For times between those, Company B has the lowest charges.

Of course, the equation for charges in each case is the sum of the service fee and the product of hourly charge and number of hours (x).

__

I find the graphing calculator to be the most efficient tool for solving these. The alternative is to compare the equations pairwise to see which gives lower rates. With a little practice, you learn that the "break even hours" will be the difference in service fees divided by the difference in hourly cost.

For example A will cost the same as B when the $20 service fee and the $10/hour cost difference are the same: for 2 hours. A and C will cost the same when the $45 service fee and the $15/hour cost difference are the same, after 3 hours. B and C will cost the same when the $25 difference in service fees and the $5/hour cost difference are the same, after 5 hours.

So B is cheaper above 2 hours, and C is cheaper than that above 5 hours. With no service fee, A is cheaper for small numbers of hours (<2).

Answer:

Test statistic = 1.25

Degree of freedom = 3

Step-by-step explanation:

The following data were obtained from 4 people

Pre-Test Value Post-test Value __ d

43 ________42 _________ 1

28_______ 29 ________ - 1

31 ________30 _________ 1

28 ________ 25 _________ 3

μd = (1 + - 1 + 1 + 3) / 4 = 4 /4 = 1

The mean difference, μd = 1

The standard deviation of difference, Sd = 1.6

The test statistic = μd / (Sd / √n)

Test statistic = 1 / (1.6/2) = 1 / 0.8

Test statistic = 1.25

Degree of freedom, = n - 1 = 4 - 1 = 3

Answer:

7.5 ft³/min

Step-by-step explanation:

Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.

Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²

So, V = Ah = 2h = 2(10 - x)

The rate of change of volume is thus

dV/dt = d[2(10 - x)]/dt = -2dx/dt

Since dV/dt = 15 ft³/min,

dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min

Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt

= -dx/dt

= -(-7.5 ft³/min)

= 7.5 ft³/min

And the height at this point when x = 8 inches = 8 in × 1 ft/12 in  = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft

Hi there!

[tex]\large\boxed{\approx 43.33 min}}[/tex]

Recall:

d = st, where:

d = distance

s = speed

t = time

We can set up an expression where the extra ten minutes is taken into account:

50x = 65(x - 10) <--- because J left 10 minutes after, we must subtract from the time variable, or "x".

Solve for x:

50x = 65x - 650

Subtract 65x from both sides:

-15x = -650

Divide both sides by -15:

x ≈ 130/3 or 43.33 min