A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, x in seconds, by the given equation. Using this equation, find the
time that the rocket will hit the ground, to the nearest 100th of second.
y = –16x2 + 119x + 57

Answers

Answer 1

Answer:

7.89 seconds

Step-by-step explanation:

using the quadratic formula (-b+-√(b^2-4ac))/2a

a=-16 b=119 c=57

x=-0.451

and

x=7.889

time cant be negative so use the positive x

Answer 2

Time required for the rocket to hit the ground would be 7.9 s.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

We are given the quadratic equation as;

-16x² + 119x + 57 = 0

By using the quadratic formula,

x = [-b ± √b² - 4ac]/2a

Here, a = -16, b = 119 and c = 57

b² - 4ac = (119 )² - 4(-16)(57)

= 14161 + 3648

= 17809

So, x = [-(119) ± √17809]/ 16(2)

= (-119 ± 133.4)/32

Therefore, the time is 7.9 s.

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Step-by-step explanation:

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Answers

Answer:

I guess...

Step-by-step explanation:

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Answers

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Answers

Answer:

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JK=JH

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ABCD is a parallelogram and X and Y are any point on CD and AD respectively. Prove that triangle AXB and triangle BYC are equal in area. Prove that​

Answers

Answer:

See answer below

Step-by-step explanation:

ABCD is a parallelogram                     Given

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Δ BYC = 1/2 (BC) (DC)                           Formula for the area of a Δ

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Second derivative of -2x^2+2/(x^2+1)^2

Answers

Answer:

\frac{-2x^2+2}{x^4+2x^2+1}

2x^2+2

-------------

x^4+2x^2+1

Which equation represents a line which is parallel to the line y = -5/8x + 6?

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Answers

Step-by-step explanation:

y = -5x/8 + 6

8y = 8 × (-5x/8 + 6)

8y = -5x + 42

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The equation for parallel line is 5x + 8y = 32.

The correct option is (D).

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A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the change in y coordinate with respect to the change in x coordinate as,

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Given:

Equation: y = -5/8x + 6

Now, the parallel line to above equation must have the slope same as the given equation i.e., -5/8.

Then, writing the equation in slope intercept form

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y= 10/5 - 8x/5

y= -8/5x + 2

B) 8x - 5y = 15

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Hence, the equation for parallel line is 5x + 8y = 32.

Learn more about Slope here:

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How can you use factoring to solve quadratic equations in standard form?

Answers

Step-by-step explanation:

The roots or the zeroes of a quadratic equation are its x-intercepts, which are the points on the graph where it crosses the x-axis. When a quadratic equation is in standard form, ax² + bx + c, the usual goal is to find the binomial factors that could help us determine the roots or solutions to the given equation.  Once you find the factors, then you will use the Zero-Product Property to solve for the solutions.  

For example, if you were given the following quadratic equation in standard form, x² + 6x + 8 = 0, and were tasked to find its factors.

x² + 6x + 8 = 0

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In order to find the factors of the given quadratic equation, we must find the  factors with a product ac, and sum b.  

Using 2 and 4 as possible factors produce a product that is equal to

product of ac:   2 × 4 = 8

sum of b:           2 + 4 = 6.

Therefore, the factors of the given quadratic equation, x² + 6x + 8 = 0 are:

(x + 2) (x + 4).

Using the Zero-Product Property, where it states that for any real numbers, u and v, if uv = 0, then u = 0 or v = 0.  

Thus, setting the binomial factors of the given quadratic equation to zero will provide the solutions.

(x + 2) (x + 4)

x + 2 = 0

x + 2 - 2 = 0 - 2

x = -2

x + 4 = 0

x + 4 - 4 = 0 - 4

x = -4

Therefore, the solutions to the quadratic equation, x² + 6x + 8 = 0 are x = -2, and x = -4.

What’s x? ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ 

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Answer:

I pretty sure it is F.1cm

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