A sample of a gas is kept at constant pressure while
its temperature is cooled from 100°C to 0°C. What
was its original volume if its final volume is 1.83 L?

Answer:

fe oo andffffe

aiejand iefjwe

eekkfwefwe f

opw fwfwfew

efefwefwefwi

Explanation:

Answer: This satisfies the law of definite proportion or constant proportion and it can be proven below.

Explanation:

The law of constant or definite proportion states that all pure samples of the same compound no matter how they are made; are made up of the same elements combined in the same proportion by mass. The can be verified by finding the ratio of copper to oxygen in the both experiment listed above.

In the first experiment:

1.37 g of cupric oxide contains 1.098 g copper therefore oxygen = 1.37 − 1.098

=0.272 g

The ratio of copper to oxygen is=

1.098 ÷ 0.272

= 4:1

In the SECOND or next experiment:

1.476 g of cupric oxide contains 1.17 g copper Therefore oxygen = 1.476−1.17

=0.306g

The ratio of copper to oxygen is =

=1.176 ÷ 0.306

=3.8:1

Which is approximately≃4:1.

In conclusion, despite the different methods of the experiments, composition of copper of copper in the two different samples are the same and the cupric oxide obtained from different sources contain the same elements ( copper and oxygen) combined in the SAME ratio.

Answer:

The gas formed in the experiment could catch fire easily. So, he named the gas inflammable air.

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

Explanation:

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

Answer:

The gas formed in the experiment could catch fire easily. So, he named the gas inflammable air.

Explanation: your welcome

Answer:

Mg is oxidized and Pb is the oxidizing agent

Explanation:

Answer:

Ba

Explanation:

Answer:

volume in Liter = 2.50 L

Explanation:

Given:

Na2CO3 = 0.2 M

Molar mass of Na2CO3 = 106 g/mol

Mass of Na2CO3 solution = 53 gram

Find:

Volume of Na2CO3

Computation:

Number of mol of Na2CO3  = (53 g) / (1.06 x 10² g/mol)

Number of mol of Na2CO3  = 0.5 mol

M = Number of mol / volume in Liter

0.2 = 0.5/ volume in Liter

volume in Liter = 0.5 / 0.2

volume in Liter = 2.50 L

Answer:

1.67g H2CO3 are produced

Explanation:

Based on the reaction:

2NaHCO3 → Na2CO3 + H2CO3

2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3

To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:

Moles Na2CO3 -Molar mass: 105.99g/mol-

2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3

Mass H2CO3 -Molar mass: 62.03g/mol-

0.02698 moles  * (62.03g/mol) =

Answer:

Lines of longitude

Explanation:

Lines of direction and lines of longitude are horizontally and vertically lines, respectively.

The phrases vertical and horizontal are frequently used to define directions: a vertical line runs up and down, whereas a horizontal line crosses.

Explanation:

Los tejidos que conforman el tejido fundamental son los siguientes:

-Parénquima

-Colénquima

-Esclerénquima.

El tejido fundamental constituye la parte principal del cuerpo de la planta porque intervienen en funciones tan importantes para el desarrollo  y sostenimiento de la planta como el proceso de  la fotosíntesis, el almacenamiento de agua y  de  nutrientes .

Answer:

Hard water is water that has high mineral content, Soft water is free from dissolved salts of such metals as calcium, iron, or magnesium

Explanation:

Answer:

Explanation:

2,5M

Answer:

2,5m

Explanation:

c=n:v

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

0.20 mol of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

 The reduction of iron from an aqueous solution of iron (II).

[tex]Fe^{+2} +2e^{-} \rightarrow Fe[/tex]

The formula for number of moles is as follows:-

[tex]Number \ of \ moles=\frac{Mass}{Molar\ mass}[/tex]

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

[tex]5.6 g \times\frac{1\ mol}{55.85\ g} = 0.10 \ mol[/tex]

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are:-

[tex]0.10 mol Fe\times\frac{2\ mol\ e^{-} }{1\ mol\ e^{-}} = 0.20 \ mol e^{-}[/tex]

Hence, 0.20 mol of electrons is required to deposit 5.6g of iron.

To know more about:-

brainly.com/question/12513822

Explanation:

When chlorine bonds and becomes stable, (had a full outer electron shell), because we know that chlorine has 7 electrons in it’s outer shell, it requires 1 to gain noble gas structure. So, when if bonds with an element and then becomes stable, the gaining of an electron means it becomes a negatively charged ion. (an ion being a charged particle.)

Answer:

A

Explanation:

I think the answer would be A

The concentration of hydronium ions (H₃O⁺) is generally greater than 1 × 10⁻⁷ for all acidic solutions: True.

An acidic solution can be defined as a type of aqeous solution that has a high concentration of hydrogen ions (H⁺), which is typically greater than that of pure water.

As a result of the fact that an acidic solution has a power of hydrogen ions (pH) below 7, the concentration of hydronium ions (H₃O⁺) derived from the protonation of water would be greater than 1 × 10⁻⁷ for all acidic solutions.

In conclusion, we can deduce that a property of all acidic solution is a concentration of hydronium ions (H₃O⁺) that is greater than 1 × 10⁻⁷.

Read more on acidic solution here: https://brainly.com/question/24753206

Answer:

here: "salt and sugar"

Explanation:

I dunno, looks pretty, gives 5 points. even tough any context is missing

but seriously:

salt and sugar look the same. just someone with a split personality

Answer:

A

Explanation:

Electrons are significantly smaller than neutrons and protons.

Electrons have a diameter of less than 10^-16 centimeters, whereas protons and neutrons have a radius of about 10^-13 centimeters.

Answer:

5511 J

Explanation:

Applying,

Q = Cm.................... Equation 1

Where Q = amount of heat required to convert ice, C = Heat of fusion of water, m = mass of ice

From the question,

Given: C = 334 J/g, m = 16.5 g

Substitute these values into equation 2

Q = 334(16.5)

Q = 5511 J

Hence, the amount of heat required is 5511 J

The missing options are;

A) in

B) to

C) of

D) about

Answer:

B: To

Explanation:

In the question, for the gap to be filled, we need to find a preposition that will show the direction of the reason for canceling.

The most appropriate one will be "to" because it is the one that most qualifies the reason for canceling as a result of bad weather.

Answer:

what is in your chemistry home work I can try for...

Answer:

1: A substance made by mixing other substances together.

2: Solutions, Suspensions, Colloids and Emulsion.

3: A particular kind of matter with uniform properties.

4: A homogenous mixture is that mixture in which the components mix with each other and its composition is uniform throughout the solution. A heterogenous mixture is that mixture in which the composition is not uniform throughout and different components are observed.

5: A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm. Common examples of solutions are the sugar in water and salt in water solutions, soda water, etc. In a solution, all the components appear as a single phase.

6: A solution forms when one substance dissolves in another. The substance that dissolves is called the solute. The substance that dissolves it is called the solvent. For example, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

7: Common examples of suspension include the mixture of chalk and water, muddy water, the mixture of flour and water, a mixture of dust particles and air, fog, milk of magnesia, etc. Q2. Give the definition of suspension. Ans: A suspension is a heterogeneous mixture of two or more substances.

8: The Tyndall effect is light scattering by particles in a colloid or in a very fine suspension.

Explanation:

Answer:

i dont know why a, i here

Explanation:

Answer:

5

Explanation:

Carbon tetrachloride has molecular formula as  CCl4 , so from this it is evident that there are 4 atoms of Chlorine & 1 atom of carbon is present, in total 5 molecules are present in carbon tetra

Answer:

its 5

Explanation:

Answer:

lemon juice............

Answer:

Mg

Explanation:

Mg forms 2+ ions and mgcl2 has a melting point over 700°C I believe.

Answer:

This answer is 108g mass of aluminum is produced from 100g of aluminum oxide

Answer:

Therefore mole ratio is [tex]H_{2}O[/tex] : [tex]KAl(SO_{4} )_{2}[/tex] is 12 :1  

Empirical formula is [tex]KAl(SO_{4} )_{2}. 12 H_{2}O[/tex].

Explanation:

The chemical formula of a hydrate  

Moles of anhydrous [tex]KAl(SO_{4} )_{2}[/tex]  

Molar mass of [tex]KAl(SO_{4} )_{2}[/tex] = 258.21 g /mol  

Mass of anhydrous [tex]KAl(SO_{4} )_{2}[/tex] = [mass of aluminum cup + alum after 2nd heating] –[ mass of empty cup]  

                                                   = 3.5 g – 2.4 g  

                                                   = 1.1 g

Moles of [tex]KAl(SO_{4} )_{2}[/tex]= mass / molar mass  

                                    = 1.1 g / 258.21 g per mol  

                                   = 0.00426 mol [tex]KAl(SO_{4} )_{2}[/tex]

The mole ratio of the H2O to [tex]KAl(SO_{4} )_{2}[/tex]

Mole ratio = moles of H2O/ moles of [tex]KAl(SO_{4} )_{2}[/tex]

                  = 0.05 mol H2O / 0.00462 mol [tex]KAl(SO_{4} )_{2}[/tex]

                 = 11.7

We can round the 11.7 to closest whole number = 12

Therefore mole ratio is [tex]H_{2}O[/tex] : [tex]KAl(SO_{4} )_{2}[/tex] is 12 :1  

Empirical formula = [tex]KAl(SO_{4} )_{2}. 12 H_{2}O[/tex]  

So we have 12 moles of water as the water of hydration in the empirical formula.  

Alum hydrate is that the white crystalline solid after heating it'll start melting due to the water of hydration present in it then again solid will remain within the aluminum cup once all the water is given off within the sort of vapors.  

b) if the scholar used 2.20 g of the sample but within the calculation, he started with 2.0 g sample then  

when the mass of water is calculated using this data the mass of water is going to be higher therefore it gives more moles of water within the hydrate.  

So the final answer is going to be artificially high.

Answer:

conjugate base

Explanation:

The following equation is given in this question:

HCI(g) + H2O(l) → H30+(aq) + Cl-(aq)

In accordance to Brønsted–Lowry acid–base theory, an acid is a substance that loses an hydrogen ion (H+) or proton in an aqueous solution. This theory further indicated that the substance formed after an acid loses its hydrogen ion is called a CONJUGATE BASE.

In the above equation, HCl is the acid because it loses H+ while the substance formed after the loss of H+, which is Cl- is a conjugate base.

Answer:

A balanced chemical equation must always include coefficients on every reactant and product.

Explanation:

A balanced chemical equation does not need to include coefficients on every reactant and product.

For example, below is a balanced chemical equation in which the reactants and the products have no coefficients whatsoever:

NaOH(aq) + HCl (aq) -----> NaCl (s) + H2O (l)

Of course, a properly written chemical equation must include the states of matter of all the substances in the reaction and the number of atoms of each element must balance both in the reactant and product sides of the equation. Generally, a balanced chemical equation must obey the law of conservation of matter which opines that matter can neither be created nor destroyed but can only be converted from one form to another.

Hence, that a balanced chemical equation must always include coefficients on every reactant and product is not true.