Answer:
56
Step-by-step explanation:
clearly, the sequence is built by adding 5 for every new term.
so, an = an-1 + 5
a1 = 25 (the starting value)
a2 = a1 + 5 = 25 + 5 = 30
a3 = a2 + 5 = a1 + 5 + 5 = a1 + 2×5 = 25 + 10 = 35
...
an = an-1 + 5 = a1 + (n-1)×5
now, we know, the last term is 300.
when we determine for which n we get an = 300, we know that n is the number of terms in the sequence.
so,
300 = a1 + (n-1)×5 = 25 + 5n - 5 = 20 + 5n
280 = 5n
n = 56
a56 = 300
so, we have 56 terms in this sequence
Answer:
56
Step-by-step explanation:
nth term = a+d(n-1) =25+5(n-1) = 25+5n-5 = 20+5n
300 = 20 + 5n
5n = 280
n = 56
since 300 is the last term in the sequence, the total number would be 36
2 men can build a wall in 10 days. in how many days will 8 men build the wall?
Step-by-step explanation:
8 men can do 60 man days of work by dividing 60 man days by the 8 men, which gives us 60/8 = 7 1/2 da
I need the help ASAP please
Answer:
Option B
Answered by GAUTHMATH
relationship between the two number
b 70.908
7.908
Which one is greater
Answer:
70.908 is greater than 7.908 .
I hope your day goes nice
Answer:
70.9 0 8 is Greaterboth are different because of different placement of point.
There is 3m wide path around a circular cricket ground having the diameter of 137 m. Find the area of the path.
Answer:
1320 m^2
Step-by-step explanation:
area of ground = π r ^2
= (22/7) × (137/2)^2
= 14,747.0714286 m^2
area of ground and path
=( 22/7)(143/2)^2
= 16,067.0714286 m^2
area of path
=16,067.0714286 -14,747.0714286
= 1320 m^2
note :
r = radius = diameter /2
area of a circle = π r^2
diameter of circle created with path and ground = 137 + 2 × width of path
= 137 + 2× 3 = 143 m
Angelica’s bouquet of dozen roses contains 5 white roses. The rest of the roses. What fraction of the bouquet is pink? There are 12 roses in a dozen
Answer:
7/12
Step-by-step explanation:
total: 12 roses
white roses: 5
pink roses: 7
fraction of pink roses = 7/12
express 111 as a sum of two primes
Answer:
2 + 109 = 111
Step-by-step explanation:
.............
the length of a rectangle is 4 meters longer than the width. if the area is 22 square meters , find the rectangle dimension
Let breadth be x
Length=x+4We know
[tex]\boxed{\sf Area_{(Rectangle)}=Length\times Breadth}[/tex]
[tex]\\ \sf\longmapsto x(x+4)=22[/tex]
[tex]\\ \sf\longmapsto x^2+4x=22[/tex]
[tex]\\ \sf\longmapsto x^2+4x-22=0[/tex]
By solving[tex]\\ \sf\longmapsto x=-2\pm\sqrt{26}[/tex]
It doesnot have any real roots
A representative for a soup company conducted a survey
to determine whether people in a city were aware of the
soup company's new advertising campaign. The
researcher set up a booth outside a local supermarket for
7 days and asked randomly selected patrons as they
entered the store whether they would be willing to
participate in a survey. Of the 530 selected patrons,
482 agreed to take the survey, and 48 refused. Which of
the following factors makes it least likely that a reliable
conclusion can be drawn about the awareness of the soup
company's advertising campaign by all people in the
city?
A) Sample size
B) Population size
C) The number of days the survey was given
D) Where the survey was given
Answer:
Step-by-step explanation:
hol sinaoteentnedbieinlrpeagntaaau
I need to know the answer and explaining how to do it please
Answer:
Its 0.11
Step-by-step explanation:
When you divide any number by 10, you just move the decimal place one to the left, as for this number 1.1, you move it one place to the left which makes it 0.11. Mathmatically, to check your work you can do 0.11 x 10 to get 1.1
Mark brainliest and helpful
..............................
Answer:
[tex]x=17[/tex]
Step-by-step explanation:
[tex](6x+10)(x+17)(4x-34)[/tex]
[tex]6x+10+x+17+4x-34=180[/tex]
Add:- [tex]6x+x+4x=11x[/tex]
and [tex]10+17-34=-7[/tex]
So, [tex]11x-7=180[/tex]
Add 7 to both sides:-
[tex]11x=187[/tex]
Divide both sides by 11:-
[tex]\frac{11x}{11}=\frac{187}{11}[/tex]
[tex]x=17[/tex]
OAmalOHopeO
find the exact value of tan(165°) using a difference of two angles
Answer: [tex]-2+\sqrt{3}[/tex]
=========================================================
Work Shown:
Apply the following trig identity
[tex]\tan(A - B) = \frac{\tan(A)-\tan(B)}{1+\tan(A)*\tan(B)}\\\\\tan(225 - 60) = \frac{\tan(225)-\tan(60)}{1+\tan(225)*\tan(60)}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+1*\sqrt{3}}\\\\\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\[/tex]
Now let's rationalize the denominator
[tex]\tan(165) = \frac{1-\sqrt{3}}{1+\sqrt{3}}\\\\\tan(165) = \frac{(1-\sqrt{3})(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\\tan(165) = \frac{(1-\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{(1)^2-2*1*\sqrt{3}+(\sqrt{3})^2}{(1)^2-(\sqrt{3})^2}\\\\\tan(165) = \frac{1-2\sqrt{3}+3}{1-3}\\\\\tan(165) = \frac{4-2\sqrt{3}}{-2}\\\\\tan(165) = -2+\sqrt{3}\\\\[/tex]
----------------------
As confirmation, you can use the idea that if x = y, then x-y = 0. We'll have x = tan(165) and y = -2+sqrt(3). When computing x-y, your calculator should get fairly close to 0, if not get 0 itself.
Or you can note how
[tex]\tan(165) \approx -0.267949\\\\-2+\sqrt{3} \approx -0.267949[/tex]
which helps us see that they are the same thing.
Further confirmation comes from WolframAlpha (see attached image). They decided to write the answer as [tex]\sqrt{3}-2[/tex] but it's the same as above.
what is the area of the triangle ://
Answer:
The area of a triangle is:
Area = 1/2(bh)
Area = 1/2(70)
Area = 35 square inches
Let me know if this helps!
Find:P(large or blue)
Answer:
7/10
Step-by-step explanation:
Total number = 17+3+8+12 = 40
The ones that are large are 17 and 8
The ones that are blue are 17 and 3
Do not count the 17 twice
P(large or blue) = (17+3+8)/40
= 28/40
=7/10
If f(x) = x2 + 7x and g(x) = 3x - 1, what is f(g(x))?
Answer:
f(g(x)) = 9x^2 + 15x - 6
Step-by-step explanation:
We are using function g(x) = 3x - 1 as the input to function f(x) = x^2 + 7x.
Starting with f(x) = x^2 + 7x, substitute g(x) for x on the left side and likewise substitute x^2 + 7x for each x on the right side. We obtain:
f(g(x)) = (3x - 1)^2 + 7(3x - 1).
If we multiply this out, we get:
f(g(x)) = 9x^2 - 6x + 1 + 21x - 7, or
f(g(x)) = 9x^2 + 15x - 6
Can someone explain this to me please
Answer: Choice B
Explanation:
Everywhere you see an x, replace it with a+2.
[tex]f(x) = 3(x+5)+\frac{4}{x}\\\\f(a+2) = 3(a+2+5)+\frac{4}{a+2}\\\\f(a+2) = 3(a+7)+\frac{4}{a+2}\\\\[/tex]
What is the dimension of the null space Null (A) of A =
Answer:
the nullity of a matrix A is the demision of its null space:nullity A = dim (n(A).
if a bicycle is 2.5 feet in diameter and races for 345 feet how many time does the wheel turn
A state lottery sells instant-lottery scratch tickets. 12% of the tickets have prizes. Neil goes to the store and buys 10 tickets. What is the probability that exactly three of Neil's tickets will have prizes?
Answer:
The probability of success is .12
The probability of failure is .88
According to the binomial theorem the probability of 3 success is
10! / (3! * 7!) * .12^3 * .88^7 = .085
Find the area of the shape shown below.
Answer:
28 units²
Step-by-step explanation:
Area of trapezoid =
2(8 + 4)/2 = 12
Area of rectangle =
2 x 8 = 16
16 + 12 = 28
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Can someone please help me with this math problem
We have [tex]f\left(f^{-1}(x)\right) = x[/tex] for inverse functions [tex]f(x)[/tex] and [tex]f^{-1}(x)[/tex]. Then if [tex]f(x) = 2x+5[/tex], we have
[tex]f\left(f^{-1}(x)\right) = 2f^{-1}(x) + 5 = x \implies f^{-1}(x) = \dfrac{x-5}2[/tex]
Then
[tex]f^{-1}(8) = \dfrac{8-5}2 = \boxed{\dfrac32}[/tex]
In a model, a submarine is located at point (0, 0) on the coordinate plane. The submarine’s radar range has an equation of 2x2 + 2y2 = 128
Draw the figure on a graph and label the location of the submarine. Make sure your name is on the paper, and label this activity Part 2.
Can the submarine’s radar detect a ship located at the point (6, 6) ? Mark that location on your graph, and explain how you know whether or not the ship will be detected in the space provided on the Circles Portfolio Worksheet.
Answer:
Remember that for a circle centered in the point (a, b) and with a radius R, the equation is:
(x - a)^2 + (y - b)^2 = R^2
Here we know that the submarine is located at the point (0, 0)
And the radar range has the equation:
2*x^2 + 2*y^2 = 128
You can see that this seems like a circle equation.
If we divide both sides by 2, we get:
x^2 + y^2 = 128/2
x^2 + y^2 = 64 = 8^2
This is the equation for a circle centered in the point (0, 0) (which is the position of the submarine) of radius R = 8 units.
The graph can be seen below, this is just a circle of radius 8.
We also want to see if the submarine's radar can detect a ship located in the point (6, 6)
In the graph, this point is graphed, and you can see that it is outside the circle.
This means that it is outside the range of the radar, thus the radar can not detect the ship.
Maria is using a meter stick to determine the height of a door. If the smallest unit on the meter stick is centimeters, which measurement could Maria have used to most accurately record the height of the
door?
Answer:
2.31 m
Step-by-step explanation:
with marking down to centimeter length, one can only estimate accurately to the nearest centimeter or hundredth of a meter.
Answer:2.31 meter
Step-by-step explanation: none
What is the volume of the cylinder below?
Height 4
Radius 7
Answer:
V ≈ 615.75
r Radius 7
h Height 4
When A = 200, solve the equation x2 - 40x + A=0 using the quadratic formula. Show all your working and give your answers correct to 2 decimal places.
Answer:
Solution given:
equation is:
x²-40x+A=0
when A=200
equation becomes
x²-40x+200=0
Comparing above equation with ax²+bx+c=0 we get
a=1
b=-40
c=200
By using quadratic equation formulax=[tex]\displaystyle \frac{-b±\sqrt{b²-4ac}}{2a}[/tex]
substituting value
x=[tex]\displaystyle \frac{-*-40±\sqrt{(-40)²-4*1*200}}{2*1}[/tex]
x=[tex]\displaystyle \frac{40±\sqrt{800}}{2}[/tex]
x=[tex]\displaystyle \frac{40±20\sqrt{2}}{2}[/tex]
taking positive
x=[tex]\displaystyle \frac{40+20\sqrt{2}}{2}[/tex]
x=34.14
taking negative
x=[tex]\displaystyle \frac{40-20\sqrt{2}}{2}[/tex]
x=5.86
x=34.14 or 5.86What is the correct answer?
Answer:
Option D
Only the equation in option D matches with the table
Answered by GAUTHMATH
rewrite the following statements into algebraic expression
the sum of x and y
5 is subtracted from y
How to find Joint and Combined variation?
Answer:
W is multiplied by 8
Step-by-step explanation:
If W varies jointly with x, y, and z, we can say that
W = k (xyz), with k being a constant for our original equation. We are asked what will happen to W if x, y, and z are each doubled. To figure this out, we can go back to our equation,
W = k (xyz)
First, we can double x, meaning that we multiply it by 2. Doing this, we get
W = k (2x * y * z)
Then, we can double y and z in a similar fashion, resulting in
W = k (2x * 2y * 2z)
W = 8 * k (xyz)
The new W, after all the doubling, is equal to 8 * k * x * y * z. The old W is equal to k * x * y * z. It can be determined that the new W is equal to 8 * the old W, so W is multiplied by 8
Write the polynomial in standard form. Then name the polynomial based on its degree and number of
terms.
y-7y3 + 15y9
Answer:
[tex]15y^9 - 7y^3 + y[/tex]
Nonic polynomial
Step-by-step explanation:
Given
[tex]y - 7y^3 + 15y^9[/tex]
Required
Write in standard form
The standard form of a polynomial is:
[tex]ay^n + by^{n-1} + ......... + k[/tex]
So, we have:
[tex]y - 7y^3 + 15y^9[/tex]
The standard form is:
[tex]15y^9 - 7y^3 + y[/tex]
And the name is: Nonic polynomial (because it has a degree of 9)
I will mark as brainliest:)
Answer:
Point E.
.................
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes. An operator in the call center is required to answer 76 calls each day. Assume the call times are independent.
What is the expected total amount of time in minutes the operator will spend on the calls each day?
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day? Give your answer to four decimal places.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95? Give your answer to four decimal places. Use the standard deviation as you entered it above to answer this question.
Answer:
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
n instances of a normally distributed variable:
For n instances of a normally distributed variable, the mean is:
[tex]M = n\mu[/tex]
The standard deviation is:
[tex]s = \sigma\sqrt{n}[/tex]
Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes.
This means that [tex]\mu = 2.3, \sigma = 2[/tex]
An operator in the call center is required to answer 76 calls each day.
This means that [tex]n = 76[/tex]
What is the expected total amount of time in minutes the operator will spend on the calls each day?
[tex]M = n\mu = 76*2.3 = 174.8[/tex]
The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.
What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day?
[tex]s = \sigma\sqrt{n} = 2\sqrt{76} = 17.4356[/tex]
The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.
What is the approximate probability that the total time spent on the calls will be less than 166 minutes?
This is the p-value of Z when X = 166.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
For this problem:
[tex]Z = \frac{X - M}{s}[/tex]
[tex]Z = \frac{166 - 174.8}{17.4356}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.6915.
1 - 0.6915 = 0.3085.
0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.
What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95?
This is X = c for which Z has a p-value of 0.95, so X = c when Z = 1.645. Then
[tex]Z = \frac{X - M}{s}[/tex]
[tex]1.645 = \frac{c - 174.8}{17.4356}[/tex]
[tex]c - 174.8 = 1.645*17.4356[/tex]
[tex]c = 203.4816[/tex]
The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]