Complete question:
A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?
Answer:
The acceleration of the ball is 78.98 m/s², directed inwards
Explanation:
Given;
mass of the ball, m = 175 g
radius of the circle, r = 0.5 m
angular speed of the ball, ω = 2 rev/s
The magnitude of the centripetal acceleration of the ball is calculated as follows;
[tex]a_c = \omega^2 r\\\\where;\\\omega \ is \ angular \ speed \ in \ rad/s\\\\a_c = (2\ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} )^2 \times (0.5 \ m)\\\\a_c =78.98 \ m/s^2[/tex]
The centripetal acceleration is directed inwards.
A body at rest or moving with uniform velocity will have acceleration equals
to:
A.
1
B.
0
C.
Negligible
D.
Infinity
Answer:
B:O
Explanation:
As acceleration is the rate of change of velocity with time, if velocity is uniform, there will be no change in it and acceleration will be zero.
Air pollution is an example of a. The underground economy. B. An external shock. C. A nonmarket activity. D. A negative externality.
Answer:
D. A negative externality.
Explanation:
Particulate pollution is a form of pollution that is responsible for the degradation of the environment.
Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air.
An externality is typically an unwarranted cost or benefit by a manufacturer or producer of goods and services that affects a third party.
In Economics, an externality could either be positive or negative depending on its effect on a third party.
A negative externality arises when the production or consumption of a finished product or service has negative impact (cost) on a third party.
In conclusion, air pollution is an example of a negative externality because it causes harm to a third party.
100 point!! Question song!
You gotta keep 'em separated
Like the latest fashion
Like a spreading disease
The kids are strappin' on their way to the classroom
Getting weapons with the greatest of ease
The gangs stake their own campus locale
And if they catch you slippin' then it's all over pal
If one guys colors and the others don't mix
They're gonna bash it up
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
By the time you hear the siren
It's already too late
One goes to the morgue and the other to jail
One guy's wasted and the other's a waste
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you disrespecting to me?
Take him out
You gotta keep 'em separated
Hey - man you talking back to me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
Answer:
It is a song called Come out and Play. It is released on 1994 in a Album called Smash. It comes under Punk-Rock.
I hope i answered your Question.
Answer:
Explanation:
Adding to the other answer, this song is about violence in streets and schools among young people involved in gangs; how they have little hope for their future. Band member Dexter got idea to make the song while he was in college.
A capacitor with a capacitance of 50µf when connected to a battery of 400 V. The charge and energy stored on it is? a. 0.05 C and 5 J b. 0.05 C and 10 J c. 0.02 C and 4 J d. 0.08 C and 12 J
Answer:
c. 0.02 C and 4 J
Explanation:
Applying,
Q = CV................ Equation 1
Where Q = Charge, C = Capacitance of the capacitor, V = Voltage.
From the question,
Given: C = 50 μF = 50×10⁻⁶ F, V = 400 V
Substitute these values into equation 1
Q = (50×10⁻⁶)(400)
Q = 0.02 C.
Also Applying
E = CV²/2............. Equation 2
Where E = Energy stored.
Therefore,
E = (50×10⁻⁶ )(400²)/2
E = 4 J
Hence the right option is c. 0.02 C and 4 J
The atomic mass of calcium is 40.08. What is the mass of 6.02 × 1023 atoms of calcium?
Answer:
It is 40.08 g
Explanation:
[tex]6.02 \times 10 {}^{23} \: atoms = 1 \: mole = 40.08 \: g[/tex]
Which of the motion variables is the same in both thex and y axis?
A) velocity
B) acceleration
C) time
D) displacement
Answer:
Acceleration (b) not sure tho
Explanation:
calcula el peso de un perro cuya masa es de 25 kg en la tierra
Answer:
El peso = 245 Newton
Explanation:
Dados los siguientes datos;
Masa = 25 kg
Para encontrar el peso del perro en la tierra;
El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.
Matemáticamente, el peso de un objeto viene dado por la fórmula;
[tex] El \; peso = mg [/tex]
Dónde;
m es la masa del objeto.
g es la aceleración debida a la gravedad.
Sabemos que la aceleración debida a la gravedad es igual a 9,8 m / s² en el planeta Tierra.
Sustituyendo en la ecuación, tenemos;
[tex] W = 25 * 9.8[/tex]
El peso = 245 Newton
someone pls help fast
PLS HELPP HURRYYY
The trapdoor swings open and the ball falls to the ground. The ball does not bounce when it hits the ground. Show that the final speed of the ball at the instant before it hits the ground is about 5 m/s.
Answer:
5 m/s
Explanation:
As the ball falls to the ground, it is acted upon by a force which is due to the gravitational force. Hence, the ball falls with an acceleration called the acceleration due to gravity.
Let us assume that the acceleration due to gravity (g) = 10 m/s², Since initially, the body was at rest, hence the initial velocity (u) = 0 m/s. The height to the ground (h) = 1.3 m. Hence using the equation of motion, the final velocity (v) is:
v² = u² + 2gh
Substituting:
v² = 0² + 2(10)(1.3)
v² = 26
v = √26 = 5
v = 5 m/s
When a shopping cart rolls into a parked car on the street, It hits the car with a force of 220 newtons. The shopping cart experiences a force from the car that is how many newtons?
Answer:
220 N
Explanation:
When a shopping cart rolls into a parked car on the street, it hits the car with a force of 220 newtons.
We need to find the force the shopping cart experiences from the car.
We know that, Newton's third law of motion states that for every action there is an equal and opposite reaction.
Hence, the shopping cart experiences a force of 220 N from the car.
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he placed the cup outside for several sunny days during the summer. After a week, he observed that only solid salt remained in the cup and the mass had decreased. Henry concluded that a physical and chemical change occurred in this investigation.
Which statements correctly defend or dispute his conclusion?
He is correct. Dissolving salt in water is a physical change, but evaporating the water is a chemical change. Formation of a solid is evidence that a chemical change occurred.
He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.
He is incorrect. Dissolving salt in water and evaporation of the water are both physical changes. The reappearance of salt is evidence that the change was reversible by a physical change, so it could not be a chemical change.
He is incorrect. Dissolving salt in water and evaporation of the water are both chemical
Answer:
He is incorrect. Dissolving salt in water and evaporation of the water are both physical changes. The reappearance of salt is evidence that the change was reversible by a physical change, so it could not be a chemical change.
Answer:c
Explanation:
Which is not true of friction? A. Causes wear and tear of the surfaces B. Helps us to fall easily on roads C. Produces heat D. Produces light E. Stops bodies when they move over each other.
Answer:
B.
Hope this helps
Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357° C?
Answer:
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
Explanation:
Por definición de entropía ([tex]S[/tex]), medida en joules por Kelvin, tenemos la siguiente expresión:
[tex]dS = \frac{\delta Q}{T}[/tex] (1)
Donde:
[tex]Q[/tex] - Ganancia de calor, en joules.
[tex]T[/tex] - Temperatura del sistema, en Kelvin.
Ampliamos (1) por la definición de calor latente:
[tex]dS = \frac{L_{v}}{T}\cdot dm[/tex] (1b)
Donde:
[tex]m[/tex] - Masa del sistema, en kilogramos.
[tex]L_{v}[/tex] - Calor latente de vaporización, en joules
Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:
[tex]\Delta S = \frac{\Delta m \cdot L_{v}}{T}[/tex]
Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que [tex]m = 0.50\,kg[/tex],[tex]L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}[/tex] and [tex]T = 630.15\,K[/tex], entonces el cambio de entropía es:
[tex]\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}[/tex]
[tex]\Delta S = 214.235 \,\frac{J}{K}[/tex]
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
A sound wave has a frequency of 192 Hz and travels the length of a football field at a speed of 338.5 m/s. what is the wavelength of the wave?
Explanation:
everything can be found in the picture
6. Which of the following graphs correctly demonstrates the relationship between the
electromagnetic force and distance between charges?
Answer:
But where are the graphs
Coulomb's Law describes the relationship between electromagnetic force and the distance between charges.
What is the relationship between electromagnetic force and the distance between charges?The relationship between electromagnetic force and the distance between charges is described by Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's Law is expressed as:
F = k (q₁x q₂) / r²
where F is the electromagnetic force, q1 and q2 are the charges, r is the distance between the charges, and k is the Coulomb constant.
This means that as the distance between two charges increases, the force between them decreases, and as the distance decreases, the force increases. The relationship between force and distance is inverse square, which means that the force decreases rapidly as the distance increases.
To know more about electric charges follow
https://brainly.com/question/874116
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For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is the temperature of each case?
Answer:
[tex]x=0.0498[/tex]
[tex]x'=0.659[/tex]
Explanation:
Specific Volume [tex]V=0.2m_3/kg[/tex]
Absolute Pressure (a) [tex]P_a= 40kpa[/tex]
Giving
[tex]T_a=75.87[/tex]
[tex]v_f=1.265*10^{-3}m^3/kg[/tex]
[tex]v_g=3.993m^3/kg[/tex]
(b) [tex]P_a= 630kpa[/tex]
Giving
[tex]T_b=160.13C[/tex]
[tex]v_f'=1.10282*10^{-3} m^3/kg[/tex]
[tex]v_g'=0.30286 m^3/kg[/tex]
(a)
Generally the equation for quality of Steam X is mathematically given by
[tex]x=\frac{v-v_f}{v_g-v_f}[/tex]
[tex]x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}[/tex]
[tex]x=0.0498[/tex]
(b)
Generally the equation for quality of Steam X is mathematically given by
[tex]x'=\frac{v-v_f'}{v_g'-v_f'}[/tex]
[tex]x'=\frac{0.2-1.10*10^{-3}}{3.30-1.1*10^{-3}}[/tex]
[tex]x'=0.659[/tex]
A 8.6*10^ -6 C charge is places 1.00 m away from a 2.3 * 10 ^ - 4 * C charge. How large is the force of repulsion between the two charges?
Answer:
The force of repulsion is 17.802 N
Explanation:
Given;
magnitude of the first charge, q₁ = 8.6 x 10⁻⁶ C
magnitude of the second charge, q₂ = 2.3 x 10⁻⁴ C
distance between the two charges, r = 1 m
The force of repulsion is calculated using Coulomb's law;
[tex]F = \frac{Kq_1q_2}{r^2} \\\\F = \frac{9\times 10^9 \times 8.6\times 10^{-6} \times 2.3\times 10^{-4}}{1^2} \\\\F = 17.802 \ N[/tex]
Therefore, the force of repulsion is 17.802 N
what is the frequency range of Audible sound
Answer:20Hz to 20000Hz
Explanation:
Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.
Which of the following nuclear configurations is most stable?
Answer:
D. A nucleus of 2 protons and 2 neutrons.
Explanation:
A stable nucleus is one that do not disintegrate naturally, majorly due to the even number of its protons and neutrons. Thus they are not radioactive in nature.
From the given question, it would be observed that a nucleus of 2 protons and 2 neutrons would give a helium atom. And this is a stable atoms due to the magnetic number of the components of its nucleus.
Thus, the nuclear configuration that is most stable out of the given options is a nucleus of 2 protons and 2 neutrons. Option D.
When a car velocity is negative and its acceleration is negative, what is happening to the cars motion?
Answer:
The car is speeding up in a negative direction.
Explanation:
what is matter explain verifly
Answer:
Matter is a substance that has inertia and occupies physical space. According to modern physics, matter consists of various types of particles, each with mass and size.Matter can exist in several states, also called phases. The three most common states are known as solid, liquid and gas.Matter is the Stuff Around You or Atoms and compounds are all made of very small parts of matter. Those atoms go on to build the things you see and touch every day. Matter is defined as anything that has mass and takes up space (it has volume).Solid ice, water and steam are few examples of matter touched in everyday life. Subatomic particles are also considered as matter.
Answer:
Matter is everything around you. Atoms and compounds are all made of very small parts of matter. Those atoms go on to build the things you see and touch every day. Matter is defined as anything that has mass and takes up space (it has volume).
hope it helps...
Calculate the momentum of a 4,800 kg car with a velocity of 25 m/s.
Answer:
p = 120000 kg · m/s
Explanation:
p = mv
p=momentum
m=mass
v=velocity
p = (4800)(25)
p= 120000 kg · m/s
Answer:
[tex]momentum = mass \times velocity \\ = 4800 \times 25 \\ = 120000 \: kgm {s}^{ - 1} [/tex]
what is unit of pressure?why is it called a derived unit ? give reasons
Answer:
Unit of pressure is pascal (Pa)
The SI-derived unit of measurement for pressure. The pascal is one newton (an SI-derived unit itself) per square meter.
¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!
1. ¿Cuál es el valor del potencial eléctrico en un punto si para trasladar una carga de 5 μC desde el suelo hasta el, se realizó un trabajo de 40 X 10^(-6) J?
2. ¿Calcular el potencial eléctrico en un punto B que se encuentra a 50 cm de una carga positiva q = 8 X 10^(-6) C
3. Determina el valor de una carga transportada desde un punto a otro, al realizarse un trabajo de 8 x 10^(-5) J, si la diferencia de potencial es de 4 x 10^3 V.
Answer:
(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C
Explanation:
(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J
The electric potential is given by
W = q V
[tex]40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V[/tex]
(b)
charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m
Let the potential is V.
[tex]V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V[/tex]
(c)
Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V
Let the charge is q.
W= q V
[tex]8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C[/tex]
find out the speed of the car from home to school in meters per second.
Time - 15 mins
Distance - 8 km
1.875
Explanation:
speed = distance moved ÷ time taken
What the answer to the three of them ill mark brainlest
lhormmia masng ies igentetel
Explanation:
E
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A wave has a frequency of 30 Hz and a wavelength of 10 m. What's its speed?
Answer:
Speed = 300 m/s
Explanation:
Given the following data;
Frequency = 30 Hz
Wavelength = 10 m
To find the speed of the wave;
Mathematically, the speed of a wave is given by the formula:
[tex] Speed = wavelength * frequency [/tex]
Substituting into the formula, we have;
[tex] Speed = 10 * 30 [/tex]
Speed = 300 m/s
Find new resistance of wire if it is stretched to twice its
original length. Original resistance was 20 ohm. Also how its
resistivity will change
Answer:
Original Length = L1
Stretched length =L2
From
R = pl/A
R=Resistance
p=Resistivity
A=Cross-sectional Area
l= length of wire
We can see that Resistance is directly Proportional to Length... Meaning that Resistance Increases also as Length increases.
R1/L1 = R2/L2
From the question... The key to note is this sentence
"The Stretched length is TWICE the Original Length"
Meaning
L2 = 2L1 (So replace L2 as 2L1 when solving)
R1=20ohms
Let R2 = k
Applying the formula
20/L1 = k/2L1
kL1 = 20x 2 L1
KL1 = 40L1
L1 cancels on both sides
k=40ohms.
So As the length doubled... The Resistance did too
from 20ohms to 40ohms
"" describe about black hole ""
#CarryOnLearning
A resistor of 500Ω and one of 2000Ω are placed in series with a 60V supply. What will be the reading on a voltmeter of internal resistance 2000Ω when placed across (i) 500Ω resistor and (ii) 2000Ω resistor?
Answer: 10 V, 40 V
Explanation:
Given
Resistors are [tex]500\Omega[/tex] and [tex]2000\Omega[/tex]
Power supply [tex]V=60\ V[/tex]
Voltmeter internal resistance [tex]r=2000\ \Omega[/tex]
When it connected around [tex]500\Omega[/tex] resistance, effective resistance becomes
[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{500}+\dfrac{1}{2000}\\\\\Rightarrow R=\dfrac{2000}{5}\\\\\Rightarrow R=400\ \Omega[/tex]
Total resistance in series [tex]R_{net}=2400\ \Omega[/tex]
Current in circuit
[tex]I=\dfrac{60}{2400}=\dfrac{1}{40}\ A[/tex]
Voltage around [tex]500\Omega[/tex] resistance is
[tex]V=\dfrac{1}{40}\times 400\\\\V=10\ V[/tex]
(B) when voltmeter is connected around [tex]2000\Omega[/tex] resistor
Net resistance around it
[tex]\Rightarrow \dfrac{1}{R}=\dfrac{1}{2000}+\dfrac{1}{2000}\\\\\Rightarrow R=1000\ \Omega[/tex]
Total resistance [tex]R_{net}=1500\ \Omega[/tex]
Current in circuit
[tex]I=\dfrac{60}{1500}=\dfrac{1}{25}\ A[/tex]
Voltage around [tex]2000\Omega[/tex] resistor
[tex]V=\dfrac{1}{25}\times 1000\\\\V=40\ V[/tex]
