A softball pitcher throws a softball to a catcher behind home plate. The softball is 3 feet above the ground when it leaves the pitcher's hand at a velocity of 50 feet per second. If the softball's acceleration is –16 ft/s2, which quadratic equation models the situation correctly?

Answers

Answer 1

Answer:

The function is:

[tex]f(t) = -16t^2 + 50t + 3[/tex]

Step-by-step explanation:

Given

[tex]height = 3ft[/tex]

[tex]velocity = 50ft/s[/tex]

[tex]acceleration = -16ft/s^2[/tex]

Required

The function

Let t represents time;

So, we have:

[tex]f(t) = acceleration * t^2 + velocity * t + height[/tex]

So, we have:

[tex]f(t) = -16* t^2 + 50* t + 3[/tex]

[tex]f(t) = -16t^2 + 50t + 3[/tex]

Answer 2

Answer:

b on edge

Step-by-step explanation:


Related Questions

Someone be generous & help me please I’ll return the favor

Answers

Answer:

Step-by-step explanation:

environment is not ___ uniform all form​

Answers

environment is not natural uniform all from

Simple percent question!!!!
My question says that line segment DC is 50% longer than line segment BD, and BD is 40 ft. Does that mean DC is 60 ft or 80? Please explain, brainliest to whoever explains it properly and quickly

Answers

Answer:

60ft

Step-by-step explanation:

DC is 50% longer than BD (given)

BD is 40ft (given)

DC is 50% longer than BD this means that DC= BD+50% of  BD

40ft +50/100 * 40

=40ft +20ft

=60ft

Another way to solve this could be DC is 150%of BD as BD =40ft=100% of it's length.

So, 150/100 *40

=60ft

Hope this helps.

Please mark me as brainliest.

Mrs. Nygaard needs 12 hours to grade all of her students’ projects. She made a chart to show how much time she could spend grading the projects during the week. Project Grading Day Hours Grading Monday 1 and three-fourths Tuesday 1 and one-half Wednesday 1 and one-fifth Thursday 2 Friday 1 and one-fourth How many hours will Mrs. Nygaard need to work over the weekend to finish grading the projects? 1 and three-fifths hours 4 and StartFraction 3 over 10 EndFraction hours 6 and one-half hours 19 and StartFraction 7 over 10 EndFraction hours

Answers

Answer:

B

Step-by-step explanation:

Option B is correct, 4 and 3/10 hours  will Mrs. Nygaard need to work over the weekend to finish grading the projects.

What is Fraction?

A fraction represents a part of a whole.

To find the total amount of time Mrs. Nygaard has available during the week to grade projects, we need to add up the hours for each day:

1 and three-fourths + 1 and one-half + 1 and one-fifth + 2 + 1 and one-fourth = 7 and five-tenths hours

This means that Mrs. Nygaard has 7.5 hours during the week to grade projects.

If she needs 12 hours to grade all the projects, then she will need to work for an additional:

12 - 7.5 = 4.5 hours over the weekend to finish grading the projects.

Therefore, 4 and 3/10 hours  required to Mrs. Nygaard need to work over the weekend to finish grading the projects.

To learn more on Fractions click:

https://brainly.com/question/10354322

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Consider the line y=7x-8.

Find the equation of the line that is parallel to this line and passes through the point (6, – 4).
Find the equation of the line that is perpendicular to this line and passes through the point (6, - 4).

Answers

Answer:

a). y = 7x - 46      b). y = -1/7x - 22/7

Step-by-step explanation:

a). y = 7x + b

-4 = 7(6) + b

-4 = 42 + b

-46 = b

y = 7x - 46

b). y = -1/7x + b

-4 = -1/7(6) + b

-4 = -6/7 + b

-22/7 = b

y = -1/7x - 22/7

hello! I'm having a bit of trouble trying to solve this, could anyone help explain it to me?

Answers

[tex]\displaystyle\ 60^2 =36(36+x)\\\\1296+36x=3600\\\\36x=2304\\\\\boxed{x=64}[/tex]

×=64

Step By Step Explanation:

[tex] {60}^{2} = 36(36 + x)[/tex]Step 1

Calculate 60 to the power of 2 and get 3600.

[tex]3600 = 36(36 + x)[/tex]Step 2

Use the distributive property to multiply 36 by 36 + ×.

[tex]3600 = 1296 + 36 \times [/tex]Step 3

Swap sides so the all variable terms are on the left hand side.

[tex]1296 + 36 \times = 3600[/tex]Step 4

Subtract 1296 from both sides.

[tex]36 \times = 3600 - 1296[/tex]Step 5

Subtract 1296 from 3600 to get 2304.

[tex]36 x = 2304[/tex]Step 6

Divide both side by 36.

[tex] \times = \frac{2304}{36} [/tex]Step 7

Divide 2304 by 36 to get 64

My Answer is

[tex]\color{GREEN} \times = 64[/tex]

Which equation can be used to determine the reference angle

Answers

Answer:

2nd option

Step-by-step explanation:

[tex]\frac{7\pi }{12}[/tex] is an angle in the second quadrant

Thus to find the reference angle, subtract from π , that is

r = π - θ

PLS HELP I WILL GIVE BRAINLIEST

Kimberly will be riding her bike to school this year. The distance from her house to the end of the street is 1/6 mile. The distance from the end of the street to school is 3/8 mile. About how far is Kimberly's house from school?

Answers

it’s about 13/24 miles away, you just combine the fractions

Answer:

Step-by-step explanation:

The total distance = 1/6 + 3/8 miles Change the denominators to 24

D = 1/6 + 3/8 = 4*1/6*4 + 3*3 / 8 * 3

D = 4/24 + 9/24

D = 13/24 of mile.

Sandra y José son dos amigos que se encuentran en diferentes partes de la ciudad de Lima (Observa el plano), la distancia que los separa en el plano es de 7 cm ellos quisieran saber ¿Cuál es la distancia real en metros que los separa? Sabiendo que el plano ha sido dibujado a escala 1: 20 000.

Answers

Respuesta:

1,4 kilometros

Explicación paso a paso:

Dado que :

Distancia que separa a Sandra y José en el mapa = 7cm

Dibujo a escala = 1: 20.000; Esto se puede interpretar en el sentido de que 1 cm en el mapa equivale a 20.000 cm en el suelo.

Por tanto, una distancia de 7 cm en el mapa será:

20.000 * 7 = 140.000 cm en el suelo = distancia real

Por lo tanto, la distancia real = 140.000 cm.

Recordar :

1 cm = 10 ^ -5 km

140000 cm = 1.4 kilometros

Por lo tanto, la distancia real entre Sandra y José es de 1,4 km.

Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO

Answers

Answer:

La norma de los signos es para el producto de números reales, y la norma es la siguiente.

(+)*(+) = (+)

(+)*(-) = (-)

(-)*(+) = (-)

(-)*(-) = (+)

Es decir, el producto de dos números de mismo signo es siempre positivo

El producto de dos números de distinto signo es siempre negativo.

Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)

Pero en casos como:

5 - (-4)  

(esto sería: "la diferencia entre cinco y menos cuatro")

notar que podemos reescribir esto como:

5 + (-1)*(-4)

Ahora podemos aplicar la norma de los signos:

5 + 4 = 9

Donde aplicamos la norma de los signos,  

Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.

Por lo podemos concluir que la respuesta correcta es verdadero.

helpppppppppppppppp//////////////////////////////////////////

Answers

Answer:

m(x)

Step-by-step explanation:

PLZ HELP WILL GIVE BRAINLIEST
(sat prep) For the figure, which of the following is true?
I m∠1+m∠2=m∠6+m∠5 m
II∠1+m∠3=m∠6+m∠4
III m∠1+m∠3+ m∠6=m∠2+m∠4+m∠5
A I only
B I and II only
C II only
D II and III only

Answers

Thank the answer is B

One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such packets of biscuits will be?

Answers

Answer:

Hey Mate! Here's your answer.

Step-by-step explanation:

One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25

One packet of biscuits requires 1 \times \frac{2}{3}1×32

One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35

Total ingradiants for one packet of biscuits =

Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625

Then, total quantity of both ingredients used in 10 such packets of biscuits =

Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32

Hope it helped you!

Work out the area of this circle.
Give your answer in terms ofand state its units.
units:
Submit ANSWEI
6 mm
Plss help due in very soon

Answers

Answer:

36π mm²

Step-by-step explanation:

Formula: πr²

r=radius

r=6

π6²=36π

Tegan is checking her tax bill for the last year.
The tax rates were as follows:
• No tax on the first £11 000 of earnings
• Earnings in excess of £11 000 and up to £43 000 taxed at a rate of 20%
• Earnings in excess of £43000 and up to £150 000 taxed at a rate of 40%
• Earnings over £150 000 taxed at a rate of 45%
Last year, Tegan earned £48 300 before tax.
How much tax did she pay in total?

Answers

Answer:

£8520

43000-11000=32000

20/100×32000

£6400

48300-43000=5300

40/100×5300=2120

£8520

Bajo que método de inventario se usa la cuenta de compra

Answers

Answer:

Estimating the economic impact of climate change from weather variation

Step-by-step explanation:

Estimating the economic impact of climate change from weather variation:If economists are going to be able to offer clear guidance about the appropriate ambition of climate change policy, we need firmer damage estimates.This column introduces a new model that prices farmers’ ex-post and ex-ante adaptations to weather changes and forecasts. #accelerationism

The equation of line r is y = 1/2 * x + 1 line runs parallel to line r and passes through (2, 5) what would be the equation of line 8 ?help please

Answers

Answer:

x - 2y + 8 = 0

Step-by-step explanation:

that is the procedure above

Sales of a certain product are declining at a rate proportional to the amount of sales. If at the end of the first year the sales have declined by 22%, then how many years will have passed (since the beginning of the first year) when sales become only 31% of their original value? Express your answer as a decimal, correct to within 0.001 years.

Answers

Answer:

The answer is "6.093 years".

Step-by-step explanation:

The rate of decline in sales in [tex]22\%[/tex] per year.

The starting sales is 100 units:

Using compounding formula:

[tex]\to 100 \times (1-\frac{22}{100})^t=22\% \ of \ 100\\\\\to 100 \times (\frac{100-22}{100})^t=\frac{22}{100} \times \ 100\\\\\to (\frac{78}{100})^t=\frac{22}{100}\\\\\to 0.78^t=0.22\\\\\text{taking \log on both the sides}\\\\[/tex]

taking log on both sides

[tex]\to \log_e \ 0.78^t= \log_e\ 0.22\\\\\to t \log_e \ 0.78= \log_e\ 0.22\\\\\to t = \frac{\log_e 0.22}{\log_e 0.78}\\\\[/tex]

      [tex]= \frac{-0.6575}{-0.1079}\\\\= \frac{0.6575}{0.1079}\\\\=6.093[/tex]

Question 4 of 10
Which describes the graph of y=-(x - 3)^2 + 2?
O A. Vertex at (-3,2)
O B. Vertex at (3,-2)
C. Vertex at (3,2)
O D. Vertex at (-3,-2)

Answers

The correct answer is b

Answer:Vertex at (3, -2)

Step-by-step explanation:

Please help ASAP and please explain how you got the answer.

Answers

Answer:

The third one

Step-by-step explanation:

All show complementary angles ( angles that add up to 90 degrees ) except for the third one

First one: shows a square within the two angles which indicates that the angles form a right angle ( 90 degree angle ) meaning that they are complementary angles

Second: the angles add up to equal 90 ( 50 + 40 = 90 ) hence they are complementary angles

Third one: the angles form a straight line. Angles that form a straight line add up to equal 180 and are known as supplementary angles

Fourth: the angles shown add up to 90 ( 65 + 25 = 90) hence they are complementary angles

All are complementary but the third one

I have a lot of algebra problems. Someone help me even with this one please!

Answers

Answer: Choice D

The graph will be discrete because there is no such thing as a partial person to sign up, and the booth is set up once each day for sign ups.

=========================================================

Explanation:

Let's start with the independent variable d. This acts as the variable x. It's the input. The value of d only takes on positive whole numbers (eg: d = 1, d = 2, d = 3, etc). We cannot have something like d = 2.718

So this bit of evidence shows that our function is discrete. Discrete input values (d) plug into the function to produce corresponding discrete output values (m).

Furthermore, we know that m is discrete because the number of people cannot be a fractional or decimal number. We can't have half a person for instance.

---------------

A quick way to see if a set is discrete or continuous is to ask the question: "is it possible to apply the midpoint formula for ANY two values, and have the output make sense?"

So a set like {1,2,3,4,5,...} is discrete because the midpoint of 2 and 3 is 2.5, but that value is not in the set mentioned.

In other words, discrete sets have "gaps" so to speak, while continuous ones do not.

---------------

Another useful property is that let's say that a < x < b, and x is drawn from the domain set. This reduced set will be finite if we're dealing with discrete data. Eg: The set {1,2,3,4,5,...} has the subset {2,3,4} which is finite and discrete.

In contrast, the subset of real numbers x such that [tex]2 \le x \le 4[/tex] is continuous and this subset is infinitely large (has infinitely many members) because we could have things like 2.718 or 3.14 etc

PLS HELP (algebra 1)

solve 4( -15x - 2) + 8

Answers

Answer:

-60x

Step-by-step explanation:

The equation px²+px+3q=1+2x has roots 1/p and q


(a) Find the values of p and of q​

Answers

Answer:

p = 2/3

q = 1/2

Step-by-step explanation:

The given equation is ,

[tex]\sf\to px^2 + px + 3q = 1 + 2x [/tex]

We can write it as ,

[tex]\sf\to px^2 + px + 3q - 1 -2x=0 [/tex]

Rearrange the terms ,

[tex]\sf\to px^2 - 2x + px + (3q -1)=0 [/tex]

This can be written as ,

[tex]\sf\to px^2 + x ( p - 2) + (3q -1) =0[/tex]

Now wrt Standard form of a quadratic equation ,

[tex]\bf \implies ax^2+bx + c = 0 [/tex]

we have ,

a = p b = p - 2 c = 3q - 1

We know that product of zeroes :-

[tex]\to \sf q \times \dfrac{1}{p} = \dfrac{3q-1}{p } \\\\\sf\to 3q - 1 = q \\\\\sf\to 2q = 1 \\\\\sf\to \boxed{ q =\dfrac{1}{2}}[/tex]

Sum of roots :-

[tex]\to \sf q + \dfrac{1}{p} = \dfrac{2-p}{p} \\\\\sf\to \dfrac{ qp + 1}{p}= \dfrac{2-p}{p} \\\\\sf\to qp + 1 = 2 - p \\\\\sf\to p/2 + p = 1 \\\\\sf\to 3p/2 = 1 \\\\\sf\to \boxed{ p =\dfrac{2}{3}}[/tex]

Solve 4x + 11 = k for x.
O A. x= -11
O B. x=-11
O C. x = 4k - 44

D. x= k-7

Answers

Answer:

4x + 11 = k

<=> 4x = k - 11

<=>

[tex]x = \frac{k - 11}{4} [/tex]

3 miles. 128 yards. Converted to feet

Answers

It’s 16334 feet ....

question 2 help pls

Answers

x=-2
5-4=1
so whatever is square rooted must be equal to 1
1 squared is 1
-2+3 is one

Answer:

[tex](\sqrt{x+3} )^{2} + 4^{2} = 5^{2}[/tex]

x + 3 + 16 = 25

x + 19 = 25

x = 6

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

write an expression for 8 less than 2 times a number
show your work ​

Answers

Answer:

Step-by-step explanation:

Let's call the number x. The statement "...2 times a number" if the number is x looks like this:

2x

"8 less than" that looks like this:

... - 8

Putting the whole thing together:

2x - 8

Evaluate the expression 42 +6.52 – 33 = 32,

Answers

The answer is 223

P.S I did the math by using PEMDAS

Someone tell me where everyone is going right please !!

Answers

For the 1st picture,

[tex]2(3x - 1) \geqslant 4x - 6[/tex]

[tex]6x - 2 \geqslant 4x - 6[/tex]

[tex] - 2 \geqslant - 2x - 6[/tex]

[tex]4 \geqslant - 2x[/tex]

[tex]x \geqslant - 2[/tex]

This means x has to be greater than -2 so -1 is the answer.

For the 2nd picture the answer is -10.

For the 3rd picture, the answer is the first three options.

For the 4th picture, the answer is the 3rd option.

again again again again again again again hello or merhaba dude

merhaba = hello

answers are at the photos

GOOD LUCK:D

greetings from Turkey (≧▽≦)

For every quarter in his pocket, John also has 5 pennies in his pocket. If the total of the coins in John’s pocket is $ 5.40, how many quarters does John have in his pocket.

Answers

If a student receives a score of 80, how many questions did this student answer ... (5). Let x = the first number, and y = the second number ... If John only has 25 coins in his pocket, how many of the coins are quarters?

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