A speed training service wants to explore the effectiveness of some of the classes offered to their clients. They randomly select 300 high school athletes and record their 50-meter dash time. The 300 high school athletes are then randomly assigned to three groups with 100 in each. One hundred athletes will take a circuit training class, 100 athletes will take an interval training class, and 100 athletes will take a plyometrics training class. At the end of 10 weeks of taking these classes, their 50-meter dash time will be recorded a second time. Their times will be analyzed to see which class showed the greatest overall improvement in times.


Select all the sentences that correctly identify the components of the experiment.


The experimental units are subjects.

The subjects are the 50 athletes.

There is one treatment, the 50-meter dash.

There are three treatments.

One treatment is a circuit training class.

The factor is the type of class.

There are 10 levels of the factor.

Answer:

60 sq in

Step-by-step explanation:

Perimeter = 2l + 2w

If l = w+4

Perimeter = 2(w+4) + 2w

Perimeter = 4w+8

32 = 4w + 8

24 = 4w

6 = w

If w = 6, l = 6+4 = 10

Area = l * w

Area = 10 * 6

Area = 60

Answer:

[tex]R(x) = -0.00051x^2 + 5x[/tex]

[tex]P(x) = -0.00049x^2 + 3x-600[/tex]

Step-by-step explanation:

Given

[tex]p = -0.00051x + 5[/tex] [tex]\to[/tex] [tex](0 \le x \le 12,000)[/tex]

[tex]C(x) = 600 + 2x - 0.00002x^2[/tex] [tex]\to[/tex] [tex](0 \le x \le 20,000)[/tex]

Solving (a): The revenue function

We have:

[tex]R(x) = x * p[/tex]

Substitute [tex]p = -0.00051x + 5[/tex]

[tex]R(x) = x * (-0.00051x + 5)[/tex]

Open bracket

[tex]R(x) = -0.00051x^2 + 5x[/tex]

Solving (b): The profit function

This is calculated as:

We have:

[tex]P(x) = R(x) - C(x)[/tex]

So, we have:

[tex]P(x) =-0.00051x^2 + 5x - (600 + 2x - 0.00002x^2)[/tex]

Open bracket

[tex]P(x) =-0.00051x^2 + 5x -600 - 2x +0.00002x^2[/tex]

Collect like terms

[tex]P(x) = 0.00002x^2-0.00051x^2 + 5x - 2x-600[/tex]

[tex]P(x) = -0.00049x^2 + 3x-600[/tex]

Answer:

see explanation

Step-by-step explanation:

Using the identities

tan x = [tex]\frac{sinx}{cosx}[/tex] , sin²x = 1 - cos²x

sin2x = 2sinxcosx

Consider left side

cosθ × sin2θ

= [tex]\frac{sin0}{cos0}[/tex] × 2sinθcosθ ( cancel cosθ )

= 2sin²θ

= 2(1 - cos²θ)

= 2 - 2cos²θ

= right side , then established

f(x) = 2x³ - 3x² + 7

f(-1) = 2(-1)³ - 3(-1)² + 7

=> f(-1) = 2(-1) - 3(1) + 7

=> f(-1) = -2 -3 + 7

=> f(-1) = 2

f(1) = 2(1)³ - 3(1)² + 7

=> f(1) = 2(1) - 3(1) + 7

=> f(1) = 2 -3 + 7

=> f(1) = 6

f(2) = 2(2)³ - 3(2)² + 7

=> f(2) = 2(8) - 3(4) + 7

=> f(2) = 16 - 12 + 7

=> f(2) = 11

Answer: Volume of Cylinder A is                          pi times the area of the base times the height

                                                             π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3

Volume of Cylinder B is likewise             pi times the area of the base times the height

                                                             π r2 h = (3.1416)(6)(6)(7)   = 791.68 ft3

After pumping all of Cyl A into Cyl B

there will remain empty space in B         791.68 – 753.98 = 37.7 ft3  

The percentage this empty space is

of the entire volume is                            37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth  

.

Step-by-step explanation: I hope that help you.

Note: you may not need to type in the percent sign.

===========================================================

Explanation:

Let's find the volume of water in container A.

Use the cylinder volume formula to get

V = pi*r^2*h

V = pi*5^2*8

V = 200pi

The full capacity of tank A is 200pi cubic feet, and this is the amount of water in the tank since it's completely full.

We have 200pi cubic feet of water transfer to tank B. We'll keep this value in mind for later.

-----------------------

Now find the volume of cylinder B

V = pi*r^2*h

V = pi*6^2*6

V = 216pi

Despite being shorter, tank B can hold more water (since it's more wider).

-----------------------

Now divide the results of each section

(200pi)/(216pi) = 200/216 = 25/27 = 0.9259 = 92.59%

This shows us that 92.59% of tank B is 200pi cubic feet of water.

In other words, when all of tank A goes into tank B, we'll have tank B roughly 92.59% full.

This means the percentage of empty space (aka air) in tank B at this point is approximately 100% - 92.59% = 7.41%

Then finally, this value rounds to 7.4% when rounding to the nearest tenth of a percent.

Step-by-step explanation:

10v-6v=28

4v=28

v=28/4

v=7

Answer:

10v-6v=28

or, 4v = 28

or, v = 28/4

or, v = 7

hence 7 is the required value of v

Answer:

Here is your answer.....

Hope it helps you....

Answer: positive

Step-by-step explanation: because it is going up from the left to the right

Answer:

[tex]2^2+b=256[/tex]

b=252

Step-by-step explanation:

[tex]2^2+b=256[/tex]

4+b=256

b=252

I wasn't very sure about what you are asking, but I hope this helps!

IT supposed to be 2 because 1/2 1/3 of 1/5 of 60 is "2".

Answer:

2

Step-by-step explanation:

Of means multiply

1/2 * 1/3* 1/5 * 60

1/6 * 1/5*60

1/30 *60

60/30

2

Step-by-step explanation:

6 carpets=1month

10 carpets=?

1month=31 days

10 /6*31

51

Step-by-step explanatio

9514 1404 393

Answer:

  y = 16

Step-by-step explanation:

Perhaps you want to solve ...

  10 +√y = 14

  √y = 4 . . . . . . subtract 10

  y = 4² = 16 . . . square both sides

Step-by-step explanation:

use the equation of the straight line

y-y1=m (x-x1)

y-2=-2(x+4)

y-2= -2x-8

y= -2x-8+2

y= -2x-6

I hope this helps

9514 1404 393

Answer:

  120 days

Step-by-step explanation:

Using the formula for simple interest, we can solve for t:

  I = Prt

  t = I/(Pr) = 608/(22800×.08) = 608/1824 = 1/3 . . . . year

For "ordinary interest", a year is considered to be 360 days, so 1/3 year is ...

  (1/3)(360 days) = 120 days

It will take 120 days for the loan to earn 608 in interest.

Answer:

3.51%

Step-by-step explanation:

From the given information:

For the first stream, the present value can be computed as:

[tex]= 100 +\dfrac{200}{(1+i)^n}+ \dfrac{300}{(1+i)^{2n}}[/tex]

Present value for the second stream is:

[tex]=\dfrac{600}{(1+i)^{10}}[/tex]

Relating the above two equations together;

[tex]100 +\dfrac{200}{(1+i)^n}+ \dfrac{300}{(1+i)^{2n}} =\dfrac{600}{(1+i)^{10}}[/tex]

consider [tex]v = \dfrac{1}{1+i}[/tex], Then:

[tex]\implies 100+200v^n + 300v^{2n} = 600 v^{10}[/tex]

where:

[tex]v^n = 0.75941[/tex]

Now;

[tex]\implies 100+200(0.75941) + 300(0.75941))^2 = 600 (v)^{10}[/tex]

[tex](v)^{10} = \dfrac{100+200(0.75941) + 300(0.75941))^2 }{600}[/tex]

[tex](v)^{10} = 0.7082[/tex]

[tex](v) = \sqrt[10]{0.7082}[/tex]

v = 0.9661

Recall that:

[tex]v = \dfrac{1}{1+i}[/tex]

We can say that:

[tex]\dfrac{1}{1+i} = 0.9661[/tex]

[tex]1 = 0.9661(1+i) \\ \\ 0.9661 + 0.9661 i = 1 \\ \\ 0.9661 i = 1 - 0.9661 \\ \\ 0.9661 i = 0.0339 \\ \\ i = \dfrac{0.0339}{0.9661} \\ \\ i = 0.0351 \\ \\ \mathbf{i = 3.51\%}[/tex]

Answer:

<T = 81

x = 10, angle = 60

Angle 5 and Angle 3 are vertical angles.  They are acute angles

Step-by-step explanation:

Supplementary angles add to 180

(7x+11) + (8x+19) = 180

Combine like terms

15x + 30 = 180

Subtract 30 from each side

15x +30-30 = 180-30

15x= 150

Divide by 15

15x/15 = 150/15

x = 10

We want angle T

T = 7x+11 = 7(10)+11 = 70+11 = 81

The two angles add to 90

5x+10 + 30 = 90

Combine like terms

5x+40 = 90

5x+40-40 = 90-40

5x = 50

Divide by 5

5x/5 = 50/5

x=10

5x+10 = 5(10) +10 = 50+10 = 60

Angle 5 and Angle 3 are vertical angles.  They are acute angles

Step-by-step explanation:

Just using the Pythagoras theorem

Answer:

1197 miles.

Speed(s) = 63 mph

Time(t) = 19 hours

Distance(d) = ?

We know,

D = S × T

= 63 × 19

= 1197 miles

Answer:

16.17 cm

Step-by-step explanation:

The solution triangle attached below :

To obtain BC ; we use the sine rule ;

a/ sin A = b / sin B

A = (180 - (68 + 24))

A = 180 - 92

A = 88°

a / Sin 88 = 15 / sin 68

Cross multiply :

(a * sin 68) = (15 * sin 88)

a = 14.990862 / sin 68

a = 16.168165

a = 16.168 cm

Answer:

i. A bar graph is an appropriate display.

ii. A bar graph is appropriate because the frequencies are given.

Step-by-step explanation:

A bar graph is a graphical method that can be used to present an information from a sample of data. It requires drawing of bars of equal width and distance with respect to the information given.

While a pie chart is a method that requires presenting information in a circular chart with respect to each data in sectors of different central angles.

For the given question, the most appropriate method to use is the bar graph with respect to the given information. Thus, the statements that are correct about the data in the table are:

i. A bar graph is an appropriate display.

ii. A bar graph is appropriate because the frequencies are given.

Answer:

The answers are:

A.)A bar graph is an appropriate display.

D.)A pie chart is not appropriate because the categories do not add to 100%.

E.)A bar graph is appropriate because the frequencies are given.

Step-by-step explanation:

Got it right on edge2021, hope this helps you out

Answer:      The slope of p is 1/3

Step-by-step explanation:    

If the lines are perpendicular, this means they are opposite.

Thus, O is opposite P and since O = -3, P = 1/3

Answer:

How should we proceed with this question

Answer:

Given the proposed interrogate, as well as the graph provided, the correct answer is B. Y = 1/2 x + 4

Step-by-step explanation:

To evaluate such, a comprehension of linear Cartesian planes are obligated:

Slopes = rise/run

X- intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y- intercept: The peculiar point in which linear data is observed to intersect the y-axis.

Slope: 1/2 as for every individual space endeavored, a space of 2 to the right is required.

Y- intercept: (4,0)

Thus, the ameliorated answer to such interrogate is acknowledged as B. Y = 1/2 x + 4.

*I hope this helps.

For this question it’s asking for it in slope intercept form. So all you need to find is the slope and the y intercept.To find the y int look at where the line passes y. In this case it is y=4, then find slope by finding change in y/ change once which is 1/2, so you get y=1/2x+4

Answer:

Step-by-step explanation:

We have:

Substitute x and solve for y:

Find x:

Tom's speed is 12.5 mph

Carl's speed is 7.5 mph

Now

From eq(2)

From eq(1)

Adding these recent two

Putting in eq(1)

Answer:

No

Explanation:

A coin which has a head and a tail has 1/2 probability of each which is a 50% chance of getting either a head or a tail. This means that given two sides of a coin, probability looks at the number of favorable outcomes and total number of outcomes, a formula that reflects a pattern seen in past experiences. Probability isn't absolute but relative. When we say there is a 50% chance of getting a head in a coin flip, it is relative to past experiences but doesn't assure of particular future occurrences regarding the coin flip.

Answer:

b = -13/3

Step-by-step explanation:

Plug in the 13/3 into the t and then try to solve it. Like this:

(13/3 - 8/3)(13/3 + b) = 0 ---->  5/3(13/3+b) = 0 ----> from here you have to distribute  ---->  65/9 + b = 0 (here you have to subtract from both sides)

b = -65/9 (you could simplified) ---> b = -13/3

Answer: Around 38.2°

Step-by-step explanation:

Substitute them into the formula for the law of sines:

[tex]\frac{sinA}{a} =\frac{sinB}{b} \\\\\frac{sinx}{15}=\frac{sin27}{11} \\[/tex]

Cross-multiply:

[tex]11sinx=15sin27[/tex]

Solve for x:

[tex]sinx=\frac{15sin27}{11} \\\\x=sin^{-1} (\frac{15sin27}{11})\\\\=38.2488[/tex]

Answer:

C

Step-by-step explanation:

you can divide y/x

1.2/4= 0.3

2.4/8= 0.3

3.9/13= 0.3

Given a matrix [tex]A[/tex] an element inside a matrix is denoted by [tex]A_{ij}[/tex] where [tex]i[/tex] is a number of a row and [tex]j[/tex] is a number of a column in which the element is in.

Your matrix is called [tex]W[/tex] and it equals to,

[tex]W=\begin{bmatrix}28&21&19\\17&24&15\\22&29&17\\\end{bmatrix}[/tex]

So [tex]W_{11}[/tex] will denote the element in the first row and first column that is [tex]\boxed{W_{11}=28}[/tex].

Hope this helps :)

Step-by-step explanation:

here are the answers for your problems