A spherical balloon is being inflated with helium at a rate of 20π cm3/min. How fast is the balloon's radius changing when the radius is 1 cm?

Answers

Answer 1

Answer:

5 cm/min

Step-by-step explanation:

A spherical balloon is being inflated with helium at a rate of 20π cm³/min.

The volume of a sphere is given by :

[tex]V=\dfrac{4}{3}\pi r^3[/tex] ...(1)

Differentiate equation (1) wrt t as follows :

[tex]\dfrac{dV}{dt}=3\times \dfrac{4}{3}\pi r^2\times \dfrac{dr}{dt}\\\\\dfrac{dV}{dt}=4\pi r^2\dfrac{dr}{dt}\ ....(1)[/tex]

Put dV/dt = 20π cm³/min and r = 1 cm, we can fin dr/dt

[tex]\dfrac{dV}{dt}=4\pi r^2\dfrac{dr}{dt}\\\\20\pi =4\pi (1)\times \dfrac{dr}{dt}\\\\\dfrac{dr}{dt}=5\ cm/min[/tex]

So, the radius of changing at the rate of 5 cm/min.

Answer 2

Using implicit differentiation, it is found that the radius is changing at a rate of 5 cm/min.

The volume of a sphere of radius r is given by:

[tex]V = \frac{4\pi r^3}{3}[/tex]

Applying implicit differentiation, the rate of change is of:

[tex]\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}[/tex]

A spherical balloon is being inflated with helium at a rate of 20π cm3/min, hence [tex]\frac{dV}{dt} = 20\pi[/tex]The radius is of 1 cm, hence [tex]r = 1[/tex].

Then:

[tex]\frac{dV}{dt} = 4\pi r^2\frac{dr}{dt}[/tex]

[tex]20\pi = 4\pi (1)^2\frac{dr}{dt}[/tex]

[tex]\frac{dr}{dt} = \frac{20}{4}[/tex]

[tex]\frac{dr}{dt} = 5[/tex]

The radius is changing at a rate of 5 cm/min.

A similar problem is given at https://brainly.com/question/14004755


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Answers

Answer:

240

Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

since ∠N = ∠L

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Answers

PEMDAS (parenthesis, exponents, multiplication, division, addition, subraction)

Answer:

x = 7

Step-by-step explanation:

So first, multiply everything inside the (   ) by 2

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Answers

Answer:

A

Step-by-step explanation:

A = 71 so then EG = 91

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Well to determine the unit prices you must divide the price by whatever the weight is. As so:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

34

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Given:

[tex](g\circ f)(a)=|a|-2[/tex]

To find:

The functions f(x) and g(x).

Solution:

We know that,

[tex](g\circ f)(a)=g[f(a)][/tex]

If [tex]f(a)=a^2-4[/tex] and [tex]g(a)=\sqrt{a}[/tex], then

[tex](g\circ f)(a)=g[a^2-4][/tex]

[tex](g\circ f)(a)=\sqrt{a^2-4}\neq |a|-2[/tex]

Option A is incorrect.

If [tex]f(a)=\dfrac{1}{2}a-1[/tex] and [tex]g(a)=2a-2[/tex], then

[tex](g\circ f)(a)=g[\dfrac{1}{2}a-1][/tex]

[tex](g\circ f)(a)=2(\dfrac{1}{2}a-1)-2[/tex]

[tex](g\circ f)(a)=a-2-2[/tex]

[tex](g\circ f)(a)=a-4\neq |a|-2[/tex]

Option B is incorrect.

If [tex]f(a)=5+a^2[/tex] and [tex]g(a)=\sqrt{a-5}-2[/tex], then

[tex](g\circ f)(a)=g[5+a^2][/tex]

[tex](g\circ f)(a)=\sqrt{5+a^2-5}-2[/tex]

[tex](g\circ f)(a)=\sqrt{a^2}-2[/tex]

[tex](g\circ f)(a)=|a|-2[/tex]

Option C is correct.

If [tex]f(a)=3-3a[/tex] and [tex]g(a)=4a-5[/tex], then

[tex](g\circ f)(a)=g[3-3a][/tex]

[tex](g\circ f)(a)=4(3-3a)-5[/tex]

[tex](g\circ f)(a)=12-12a-5[/tex]

[tex](g\circ f)(a)=7-12x\neq |a|-2[/tex]

Option D is incorrect.

Therefore, the correct option is C.

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Answers

The Correct Answer: $5.07

What is the decimal value of 5/6

Answers

Answer:

0.83

Step-by-step explanation:

The 3 keeps going on and on and on :)

Hey there!

• In order to CONVERT a FRACTION to a DECIMAL, all you have to do is DIVIDE the NUMERATOR (TOP number) from the DENOMINATOR (BOTTOM number)

• “What is the decimal value of 5/6?”

5 / 6 = 5 ÷ 6 → 0.83

Answer: 0.83 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

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