a square pyramid A is similar to pyramid the volume of pyramid are 1224 cubic.meters and 73 cubic meters the height of pyramid A is 18 meters. what are the possible lengths of one side if pyramid B's base? plz help
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Answer:

Yes, the triangles are similar by SAS

Step-by-step explanation:

Looking at the picture, we see that there are two triangles with side lengths of different sides. We can deduce that the scale factor is 1 2/3, because 8 divided by 4.8 is 1 2/3, and 10 divided by 6 is the same. Now that we have clarified that the triangles share the same scale factor, we notice that the angle is also the same, as mentioned in the picture. This leads us to say that the triangles are similar by the SAS similarity theorem (Side, Angle, Side). I hope this helped and please don't hesitate to reach out with more questions!

Answer:

Step-by-step explanation:

[tex]volume of cone=\frac{1}{3} \pi r^2h\\=\frac{1}{3} \pi (4)^2 \times 3\\=16 \pi \\\approx 50 in^3[/tex]

Answer:

answer is C 50 in³are you fine with it

Step-by-step explanation:

hope it helps thank you❤

Answer:

B

Step-by-step explanation:

Answer:

Total amount of ticket free = £64.89

Step-by-step explanation:

Given:

Cost of theater ticket = £63 plus

Booking fee of theater ticket = 3%

Find:

Total amount of ticket free

Comutation:

Total amount of ticket free = Cost of theater ticket + Booking fee of theater ticket

Total amount of ticket free = 63 + 3%

Total amount of ticket free = 63 + 1.89

Total amount of ticket free = 64.89

Total amount of ticket free = £64.89

Answer:

x = 6[tex]\sqrt{5}[/tex]

Step-by-step explanation:

Here we need to use the Pythagorean Theorem

Pythagorean Theorem: a^2 + b^2 = c^2

STEP 1: Define your variables

The legs of the triangle are a and b, and the hypotenuse is c.

a = x

b = 4

c = 14

STEP 2: Plug your variables into the equation and solve

x^2 + 4^2 = 14^2

x^2 + 16 = 196

x^2 + 16 - 16 = 196 - 16

x^2 = 180

[tex]\sqrt{x^2}[/tex] = [tex]\sqrt{180}[/tex]

STEP 3: Simplify

Since the question asks you to put the equation in simplified radical form, you do not have to approximate the answer, but you do have to simplify the radical.

[tex]\sqrt{x^2}[/tex] = [tex]\sqrt{180}[/tex]

x = [tex]\sqrt{36}[/tex] * [tex]\sqrt{5}[/tex]

x = 6[tex]\sqrt{5}[/tex]

Answer:

x+115=180 x=65

90+65+y=180 y=25

Step-by-step explanation:

Answer:

[tex]b=80[/tex]°

Step-by-step explanation:

The central angles theorem states that the measure of an angle whose vertex is the center of the circle is equivalent to the arc surrounding it. One can apply this here by stating that the measure of the arc surrounding the (90) degree angle is (90) degrees.

The total degree measure of a circle is (360). Thus one can form an equation and solve it to find the measure of the arc surrounding the angle (b). Call the arc surrounding angle (b); ([tex]b_1[/tex]).

[tex](b_1)+(90)+(110)=360[/tex]

Simplify,

[tex]b_1+200=360[/tex]

Inverse operations,

[tex]b_1+200=360[/tex]

[tex]b_1=160[/tex]

The peripheral angles theorem states that if the vertex of an angle formed between a tangent and a chord, is on the circumference (outer edge) of a circle, then the measure of the angle is equal to half of the measure of the surrouding arc. Please note that a chord is a line segment in a circle that intersects the circle in two points. A tangent is a line segment that intersects a circle at one point. One can apply this here by stating the following,

[tex]b=\frac{b_1}{2}[/tex]

Substitute,

[tex]b=\frac{160}{2}[/tex]

Solve,

[tex]b=80[/tex]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3[tex]3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1[/tex]

Calculate:

[tex](3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1[/tex]

Solve using substitution:

[tex](3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1[/tex]     [tex]t=3^{y}[/tex]

Solve the equation for t:

[tex]t^{2}*\frac{1}{3}+\frac{2}{3}t=1[/tex]

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

[tex]3^{y}=1[/tex]

y=0

Step-by-step explanation:

[tex] \frac{2}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } = \frac{2(2 - \sqrt{3} )}{1} = 4 - 2 \sqrt{3} [/tex]

Answer:

B

Step-by-step explanation:

The sum of the inner angles of a quadrilateral is 360 degrees

135 + 110 + 68 + x = 360

313 + x = 360

x = 47 degrees

Answer:

47

Step-by-step explanation:

whole thing is 360 degrees

68 + 110 + 135 = 313

360 - 313 = 47

x looks small too (if you had to guess in a multiple choice question)

Answer:

plotting x = 2

see the x- axis look for the point x = 2(on right side of the origin ). Mark that point and draw a straight line parallel to the y- axis.

This is the graph of x = 2

plotting y = -4

see the y- axis and then look for the point y= -4 (that must be 4 units below the origin). Mark that point and draw a straight line parallel to the x- axis.

This is the graph of y = -4

we see that, the graph x = 2 is parallel to the y-axis whereas the graph y = -4 is parallel to the x- axis.

Answer:

if you are supposed to find m<STR, then the answer is B

Step-by-step explanation:

Answer:

i thinkits c

Step-by-step explanation:

based on the info given

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Answer:

2

Step-by-step explanation:

a2 = a1×3

a3 = a2×3 = a1×3×3

=>

an = an-1 × 3 =

[tex]a1 \times {3}^{n - 1} [/tex]

a5 = 162 = a1×3⁴ = a1×81

a1 = 162/81 = 2

Answer:

125

Step-by-step explanation:

600=150+225+100+X=475+X

600-475=125=X

X=125

Answer: 325 I believe!

Step-by-step explanation:

Answer:

The variable is y since it is a letter and is meant to hold value

The coefficient is 4 since in this equation 4 is multiplied by y

The exponent is 3 since it is after the variable

Hope This Helps!!!

Answer:

The coefficient is 4

The base and variable is y

The exponent is 3

Step-by-step explanation:

4y^3

The coefficient is 4

The base and variable is y

The exponent is 3

SSS (side-side-side) requires that all three sides of the potentially congruent triangles be congruent.

Triangle WVU & Triangle UBW are our two triangles.

The middle line, UW and WU are congruent by the reflexive property, so that is not the information we need to prove SSS.

For SSS, we need to know that sides WV and UB are congruent.

Hope this helps!

Answer:

range

Step-by-step explanation:

Answer:

The surface area is 80.9.

Step-by-step explanation:

Answer:

(a) 525 g

Since they're proportional to each other:

[tex]\frac{20cm^{3} }{210g} =\frac{50cm^{3} }{Xg}[/tex]

Cross-multiply & solve:

[tex]20x=210*50\\20x=10500\\x=\frac{10500}{20} =525[/tex]

(b) 38 cm^3

Same thing, different numbers:

[tex]\frac{20cm^{3} }{210g} =\frac{Xcm^{3} }{399g}[/tex]

Cross-multiply & solve:

[tex]210x=20*399\\210x=7980\\x=\frac{7980}{210} =38[/tex]

Answer:

[tex]y = \frac{1}{2} x + \frac{1}{2} [/tex]

Step-by-step explanation:

choose 2 points to find slope

(1,1) (-3,-1)

[tex]m = \frac{ - 1 - 1}{ - 3 - 1} = \frac{1}{2} [/tex]

y-y1 = m(x-x1)

y-1 = 1/2( x-1)

y = 1/2x + 1/2

guessing

y= 1/2x + 1/2

did y2 - y1/ x2-x1

which gave

-3

-6

also it passed through the y axis at +1/2

Answer:

therefore According to the diagram y= start over

The transformation of the parent graph of y = √x to y = (1/2)√x is a vertical compression by a factor of 1/2.

A point is transformed when it is moved from where it was originally to a new location. Translation, rotation, reflection, and dilation are examples of different transformations.

As per the shown graph, for any value of x, the output of the function y = (1/2)√x is half of the output of the function y = √x. This means that the y-values of the transformed graph are compressed vertically by a factor of 1/2 compared to the parent graph, while the x-values remain unchanged.

Visually, the graph of y = (1/2)√x will be flatter and closer to the x-axis than the graph of y = √x, with the same x-intercepts (0,0) and (1,1).

Thus, the y-values of the transformed graph are compressed vertically by a factor of 1/2 compared to the parent graph.

To learn more about the transformations click here :

https://brainly.com/question/11352944

#SPJ7

Answer:

13:11

Step-by-step explanation:

325:275

If divided by 5 all through, you get 65:55, then by 5 again you get 13:11

Answer:

13/11 = 1.1818

Step-by-step explanation:

Boys/girls = 325/275 = 13/11 = 1  2/11 = 1.1818

I don't know what simplest form means.

i will solve it first i need full form

Answer:

When i tried solving it, there was no GCF except for 1.

However, the GCF of the numerator is 7

Answer:

11

Step-by-step explanation:

(2x -9) + (x + 2) = 23

2x + x -9 + 2 = 23

3x - 7 = 23

3x = 23 + 7

x = 10

RS = 2x - 9

RS = (2 * 10) - 9

RS = 20 - 9

RS = 11

Answer:

22x 28 x 25 x 30 = 462000

whats are the units.....cm or m

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{22(28)(25)(30)}\\\large\textsf{22(28) = \bf 616}\\\large\textsf{616(25)(30)}\\\large\textsf{616(25) = \bf 15,400}\\\large\textsf{15,400(30)}\\\large\textsf{ = \bf 462,000}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 462,000}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

a shipping container ,the ones they use in large cargo ships