If DF =61 and EF = 18 find DE

Answer:

H0 : μ ≥ 98.6

H1 : μ < 98.6

Step-by-step explanation:

The population mean temperature, μ = 98.6

The null hypothesis takes up the value of the population mean temperature as the initial truth ;

The alternative hypothesis on the other hand is aimed at using a sample size of 109 to establish if the mean temperature is less than the population mean temperature.

The hypothesis ;

Null hypothesis, H0 : μ ≥ 98.6

Alternative hypothesis ; H1 : μ < 98.6

Answer:

If you want the area of something with the sides 14cm and 7cm then it would be 98 cm.

Step-by-step explanation:

Area = length * width

Area = 14 cm * 7 cm

Area = 98 cm

14. largest 9510

15. smallest 1000000

16. n+6=22 —> n=22-6 —>n = 16

17. Add : 204 + 38429= 38633

Answer:

c=cost of one chair rental

t=cost of one table rental

8c+3t=42

2c+5t=53

multiply the second equation, each term on both sides, by -4

8c+3t=42

-8c-20t=-212

add the two equations

-17t=-170

divide both sides by -17

t=$10 to rent one table

substitute t=10 into either original equation

2c+5(10)=53

2c+50=53

2c=3

c=$1.50 to rent one chair

Answer:

54, 55, 56, 57, 58

Step-by-step explanation:

Answer:

56 problems

Step-by-step explanation:

Set up an equation.

[tex]\frac{3}{5}x<35<\frac{13}{20}x[/tex]

Why do we do this? We are told that she solved MORE than 60%, or [tex]\frac{3}{5}[/tex], and LESS than 65%, or [tex]\frac{13}{20}[/tex]. Therefore, if we set the TOTAL number of problems to x, we have an equation we can solve.

[tex]\frac{3}{5}x<35<\frac{13}{20}x\\[/tex]

Multiply all parts of the inequality by 20 to get rid of the denominators.

[tex]20*\frac{3}{5}x<20*35<20*\frac{13}{20}x\\ \\12x<700<13x[/tex]

Now we can solve TWO individual inequalities to isolate the x variable.

[tex]12x<700\\x<\frac{700}{12}\\x < 175/3\\x<58[/tex]

We can approximate 175/3 to about 58 (rounding down). We will sometimes round down when we have to deal with whole numbers.

The second inequality is as follows.

[tex]13x>700\\x>700/13\\x>53[/tex]

Therefore, we can combine the two inequalities.

[tex]53<x<58[/tex]

There were in between 53 and 58 questions. Since the number of questions must be a whole number, there can be 54, 55, 56, 57, OR 58. Why does 58 also work? When you plug 58 back into the original equation, you get that it STILL works. This is due to the fact that inaccuracies in computations allow you to round UP.

However, the last thing to keep in mind is that there are four sections with an equal number of questions. Meaning, the final answer has to be a multiple of four. The only multiple of 4 is 56; therefore, the final answer is 56.

AS IN THE PICTURE...........

Answer:

if you mean 15k as is 15 thousand then the answer would be 15,010

Answer:

[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]S = \{V,W,X,Y,Z\}[/tex]

[tex]n(S) = 5[/tex]

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

[tex]P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20[/tex]

[tex]P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20[/tex]

So, the probability model is:

[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]

Answer:

answer is V=.20, W=.20, X=.20, Y=.20, X=.20

Step-by-step explanation:

Answer:

the answer could be B i think cause that makes total sense

Answer & Step-by-step explanation:

Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)

w = 2h (twice the price)

t = h - 4 ($4 less)

3w + 2h + 5t = 136 (total purchasing and cost)

We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t

3(2h) + 2h + 5(h-4) = 136

Simplify

6h + 2h + 5h - 20 = 136

13h = 136 + 20

13h = 156

h = 156/13

h = $12

Using this information, we can solve for w and t

w = 2h

w = 2(12)

w = $24

And finally

t = h - 4

t = 12 - 4

t = $8

Answer:

Step-by-step explanation:

ΔABC has the vertices as A(1, 1), B(4, 1) and C(4, 5).

Rule for the transformation has been given as,

f(x, y) → (x - 5, -y - 2)

By this rule vertices of the transformed image will be,

A(1, 1) → A'(1 - 5, -1 - 2)

         → A'(-4, -3)

B(4, 1) → B'(4 - 5, -1 - 2)

          → B'(-1, -3)

C(4, 5) → C'(4 - 5, -5 - 2)

           → C'(-1, -7)

Answer:

arithmetic

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bm.hg

hgjm

hgjgshmih

mhh

jhuu

Answer:

x = -3  or x = 3  or x = 6

Step-by-step explanation:

x3 – 6x2 – 9x + 54 = 0

There is no common factor to factor out. There are 4 terms. We try factoring by grouping. Factor a common factor out of the first two terms. Factor a common factor out of the last two terms.

x^2(x - 6) - 9(x - 6) = 0

x - 6 is a common factor, so we factor it out.

(x^2 - 9)(x - 6) = 0

x^2 - 9 is the difference of 2 squares, so we factor it.

(x + 3)(x - 3)(x - 6) = 0

x + 3 = 0  or  x - 3 = 0  or x - 6 = 0

x = -3  or x = 3  or x = 6

Answer:

x=6     x=3   x=-3

Step-by-step explanation:

x^3 – 6x^2 – 9x + 54 = 0

Factor by grouping

x^3 – 6x^2     – 9x + 54 = 0

x^2(x-6)    -9(x-6 ) =0

Factor out x-6

(x-6)(x^2 -9) =0

Notice x^2 -9 is the difference of squares

(x-6)(x-3)(x+3) = 0

Using the zero product property

x-6 =0    x-3 =0   x+3 =0

x=6     x=3   x=-3

Answer:

= 3 11/20

Sorry I am not doing the step by step.

9514 1404 393

Answer:

  D. Logistic growth

Step-by-step explanation:

The logistic growth function models a situation where the rate of growth is jointly proportional to the population and to the difference between the population and the carrying capacity.

Attached is an example of such a function.

Answer:

2+6=8

Step-by-step explanation:

Start at 2

Then since we are adding 6 move 6 units to the right

Answer:

1st degree

Step-by-step explanation:

You look at the largest exponet, right here, there are none so it would be 1st degree.

Answer:

1

Step-by-step explanation:

The degree of an expression with multiple exponents is the highest exponent in it. In this expression, there is no expression, so the answer will be 1 because there is no exponent and every variable and number has an invisible 1 as its exponent.

Hope this helps.

Answer:

B

Step-by-step explanation:

$3 per gallon

that is the procedure above

Answer:

4.67 mph

Step-by-step explanation:

Speed with no wind = 14 mph

Let wind speed = w mph

Thus;

Speed with wind = 14 + w

Speed against the wind = 14 - w

Now, we are told that against the wind he bikes 10 miles.

Thus, from; time = distance/speed, we have;

Time = 10/(14 - w)

Also, we are told he biked 20 miles with the wind. Thus;

Time = 20/(14 + w)

We are told the times he used in both cases are the same.

Thus;

10/(14 - w) = 20/(14 + w)

Divide both sides by 10 to get;

1/(14 - w) = 2/(14 + w)

Cross multiply to get:

1(14 + w) = 2(14 - w)

14 + w = 28 - 2w

w + 2w = 28 - 14

3w = 14

w = 14/3

w = 4.67 mph

Answer:

The mean and median number of apples in a bag are 21.71 and 22 respectively.

Step-by-step explanation:

The mean is the arithmetic mean of a set of numbers. In other words, the mean is the average value of all my data.

The mean is calculated by adding all the values ​​and dividing the sum by the total number of values. In this case:

[tex]Mean=\frac{23+19+26+17+21+24+22}{7}[/tex]

[tex]Mean=\frac{152}{7}[/tex]

Mean= 21.71

The median of a set of numbers is the average number in the set, that is, it is the value that occupies the central place of all the values.

The median can be calculated by putting the numbers in ascending order and then:

In this case:

Putting the numbers in ascending order: 17, 19, 21, 22, 23, 24, 26

Since the quantity is odd numbers, the median is the number in the center of that distribution. So Median= 22

The mean and median number of apples in a bag are 21.71 and 22 respectively.

Answer:

Step-by-step explanation:

684 dollars

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

If a point A(x, y) is translated a units right and b units up, the new point is at A'(x + a, y + b).

If a point A(x, y) is reflected across the line y = -x, the new point is at A'(-y, -x).

If a point A(x, y) is rotated counterclockwise by 270 degrees, the new point is at A'(y, -x).

Let us assume that triangle ABC has vertices at A(-6, -1), B(-3, -3) and C(-1, -2).

If it is moved 5 units to the right and 2 units up, the new point is at A'(-1, 1), B'(1, -1) and C'(3, 0). If it is reflected across the line y = -x, the vertices are at A"(-1, 1), B"(1, -1) and C"(0, -3). If it is then rotated counterclockwise about the origin by 270°, the new point is at A'"(-1, -1), B"'(1, 1), C"'(3, 0)

Answer:

[tex]Given:[/tex] Δ ABC ≈ ΔDEF

[tex]therefor:[/tex] A(ΔABC)/A(ΔDEF)=(BC)²/(EF)²

⇒ 34/A(ΔDEF)=9²/(13.5)²

⇒34/A(ΔDEF)=81/182.25

⇒A(ΔDEF)=34×182.25/81

⇒Area of ΔDEF=76.5 cm²

----------------------------------

Hope it helps...

Have a great day!!!

Answer:

Hence the probability that the mean weight of the sample of 55 cows would differ from the population mean by less than 12 lbs is 0.66545.

Step-by-step explanation:

Answer:

[tex]{ \tt{slope, \: m = \frac{1 - ( - 1)}{1 - 0} }} \\m = 2 \\ y - intercept : y = mx + c \\ { \tt{1 = (2 \times 1) + c}} \\ c = - 1 \\ { \boxed{ \bf{y = 2x - 1}}}[/tex]

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Answer:

option b

Step-by-step explanation:

both are rectangles and similar measures  

Yes, because both figures are rectangles and all rectangles are similar

The rectangle EFGH is a result of the dilation of rectangle ABCD

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the first rectangle be represented as ABCD

Now , the rectangle is dilated by a scale factor k

And , the transformed rectangle is given by EFGH

where the center of origin is the scale factor of dilation

Now , the ratios of the sides of the rectangles will be similar

So , the rectangles ABCD and EFGH are similar

Hence , the dilated rectangle is EFGH

To learn more about dilation click :

https://brainly.com/question/13176891

#SPJ7

Answer:

[tex]\frac{73,331}{75,516}\approx 97.11\%[/tex]

Step-by-step explanation:

The probability that she will find at least one student cheating is equal to the probability that she finds no students cheating subtracted from 1.

Each time she randomly chooses a student the probability she will catch a cheater is equal to the number of cheaters divided by the number of students.

Therefore, for the first student she chooses, there is a [tex]\frac{9}{35}[/tex] chance that the student chosen is a cheater and therefore a [tex]\frac{26}{35}[/tex] chance she does not catch a cheater. For the second student, there are only 34 students to choose from. If we stipulate that the first student chosen was not a cheater, then there is a [tex]\frac{9}{34}[/tex] chance she will catch a cheater and a [tex]\frac{25}{34}[/tex] chance she does not catch the cheater.

Therefore, the probability she does not catch a single cheater after randomly choosing ten students is equal to:

[tex]\frac{26}{35}\cdot \frac{25}{34}\cdot \frac{24}{33}\cdot \frac{23}{32}\cdot \frac{22}{31}\cdot \frac{21}{30}\cdot \frac{20}{29}\cdot \frac{19}{28}\cdot \frac{18}{27}\cdot \frac{17}{26}[/tex]

Subtract this from one to get the probability she finds at least one of the students cheating after randomly selecting nine students. Let event A occur when the professor finds at least one student cheating after randomly selecting ten students from a group of 35 students.

[tex]P(A)=1-\frac{26}{35}\cdot \frac{25}{34}\cdot \frac{24}{33}\cdot \frac{23}{32}\cdot \frac{22}{31}\cdot \frac{21}{30}\cdot \frac{20}{29}\cdot \frac{19}{28}\cdot \frac{18}{27}\cdot \frac{17}{26},\\\\P(A)=1-\frac{2,185}{75,516},\\\\P(A)=\boxed{\frac{73,331}{75,516}}\approx 0.97106573441\approx \boxed{97.11\%}[/tex]

Answer:

A. More students prefer Model A1 calculators than the Model C3 calculators.