A student has $78 in his checking account. If the student spends $12 on lunch, which number could be combined with the amount left in the account to make zero?

Answer:

c

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Amplitude is the number in front of the sin or the number multiplied by the whole equation.  In this case its 3

Answer:

x = -3 and y = 0

Step-by-step explanation:

It would be more direct to apply elimination in this problem, rather than substitution:

  2x + 6y = -6       ⇒      2x + 6y = -6       ⇒      10x = - 30

+ 2(4x - 3y = -12)        +  8x - 6y = -24

Now let us solve for x through simply algebra:

10x = -30,

  x = -3

Substitute this value of x into the first equation to get the value of y:

2( -3 ) + 6y = -6,

-6 + 6y = -6,

  6y = 0,

    y = 0

Answer:

-3 and 0

Step-by-step explanation:

i hope this helps :)

Answer:

i dont know what is it

den

Answer:

x =7.5

Step-by-step explanation:

We can use cross products to solve

3x / 10 = 9 / 4

3x*4 = 10*9

12x = 90

Divide each side by 12

12x/12 = 90/12

x =7.5

Answer: 18 minutes: 27 minutes

Here the steps see attachment

Answer:

16 people

Step-by-step explanation:

First subtract the cost of the rental from the amount of money:

$400-$150 = $250

Therefore Tia has $250 to spend for additional people. Then if each person is $15, divide the remaining amount of money by the amount of money per person:

$250/$15 = 16.67

Since you can't have 0.67 of a person she can have 16 people go with her.

This can also be modeled by this inequality:

[tex]150 + 15x \leqslant 400[/tex]

Answer:

The number of potential members predicted in next year's estimate becomes 193. The further explanation is given below.

Step-by-step explanation:

The slope of the model,

m = 15.345

c = 24

After comparing with the equation,

⇒  [tex]y=mx+c[/tex]

we get,

⇒     [tex]=15.345x + 24[/tex]

The slope seems to be a positive value which also means that another always improves this as component decreases. Which ensures that perhaps the number of contributors rising as time went by.

So that the above is the right answer.

Answer:

Half way

Step-by-step explanation:

Half way, because the dog can run all the way through the woods, but only half of the time he is going in, the rest of the time he is going out.

Answer:

  d(t) = -20t -260

Step-by-step explanation:

We are given two points ...

  (t, d) = (3, -320) and (8, -420)

The 2-point form of the equation of a line can be useful when 2 points are given.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

Substituting the given points, we have ...

  d(t) = (-420 -(-320))/(8 -3)(t -3) -320

  d(t) = -20(t -3) -320

  d(t) = -20t -260

Answer:

[tex]c = \frac{2}{0.42} [/tex]

Step-by-step explanation:

AB = c

[tex] \frac{a}{sin \: A} = \frac{c}{sin \: C} \\ \frac{2}{sin \: 25} = \frac{c}{sin \: 90} \\ \frac{2}{0.42} = \frac{c}{1} \\ 0.42 \: c = 2 \\ c = \frac{2}{0.42} [/tex]

Answer:

4.73

Step-by-step explanation:

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Answer:

x=12

Step-by-step explanation:

4x+5 (5x-39) = 153

4x + 25x - 195 = 153

29x - 195 = 153

29x =  348

x = 12

Answer:

1320 feet

Step-by-step explanation:

All we have to do is multiply the rate of change of altitude by the time it took the altitude to change.

The altitude of an airplane is decreasing at a rate of 44 feet per second. After 30 seconds, the change is altitude is:

44 * 30 = 1320 feet

The altitude of the airplane has changed by 1320 feet.

Answer:

Your answer will be [tex]12[/tex] cups of popcorn.

Step-by-step explanation:

To find out how much the new bags hold, you need to find out the discount.

[tex]\frac{20}{100 } = .2[/tex]

[tex]15 * .2 = 3[/tex]

We know that the discount is [tex]3[/tex].

To figure out how much the new bags hold, subtract by the old bags.

[tex]15 - 3 = 12[/tex]

The new bags hold 12 cups of popcorn.

Answer:

64

Step-by-step explanation:

x^2 +16x+c

Take the coefficient of x

16

Divide by 2

16/2 =8

Square it

8^2 = 64

This is c

Answer:

c = 64

Step-by-step explanation:

The value for c is A. 64.  That comes from the process of completing the square where you take half the linear term, square it, and add it in.  Our linear term is 16.  Half of 16 is 8, and 8 squared is 64. 

Answer:

(49 - 29) + 1 =(50 - 29)

Step-by-step explanation:

The 20 comes from the subtraction of 29 in both sides of the previous step equality. In the following, I transcript the complete procedure and I add the step that you need to understand why 20 appears (in bold numbers):

29+20=49

49+1=50

(49 - 29) + 1 =(50 - 29)

20+1=21

50-29=21

hence, it was only nesseraty to subtract 29

Answer:

4/15

Step-by-step explanation:

Bag A

3 red marbles and 6 blue marbles.  = 9 marbles

P(blue) = blue/total =6/9 = 2/3

Bag B

6 green marbles and 4 yellow marbles.  = 10 marbles

P(yellow) = yellow/total=4/10 = 2/5

P(blue,yellow) = 2/3 * 2/5 = 4/15

Answer:

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

Step-by-step explanation:

h(x) = ln x / √(x² + 1)

You can either use quotient rule, or you can rewrite using negative exponents and use product rule.

h(x) = (ln x) (x² + 1)^(-½)

h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)

h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)

h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))

h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)

h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))

Solution:

h(x) = ln(x)/√x^2+1

h(x) = ln(x) * (x^2 + 1)^-1/2

h(x) = ln(x) * (-1/2) * (x^2 + 1)^-3/2 * 2x + 1/x * (x^2 + 1)^-1/2

h(x) = -x ln(x) * (x^2 + 1)^-3/2 + 1/x * (x^2 + 1)^-1/2

h(x) = (x^2 + 1)^-3/2 * (-x ln(x) + 1/x * (x^2 + 1))

h(x) = -x^2ln(x)+x^2+1/(x(x^2+1)^3/2)

Best of Luck!

Answer:

[tex] y = 300 (2)^x[/tex]

Where x represent the number of period of times of 22 minutes. If we want to know the value of the population after 66 minutes we need to find the value of x on this way:

[tex] x = 66 minutes *\frac{1period}{22 minutes}= 3[/tex]

So then we need to replace the value of x =3 and we got:

[tex] y= 300 (2)^3 = 2400[/tex]

Step-by-step explanation:

For this case we have the following function:

[tex] y = 300 (2)^x[/tex]

Where x represent the number of period of times of 22 minutes. If we want to know the value of the population after 66 minutes we need to find the value of x on this way:

[tex] x = 66 minutes *\frac{1period}{22 minutes}= 3[/tex]

So then we need to replace the value of x =3 and we got:

[tex] y= 300 (2)^3 = 2400[/tex]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ([tex]\mu_1-\mu_2[/tex]) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

                            P.Q. =  [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex]  ~ [tex]t__n__1-_n__2-2[/tex]

where, [tex]\bar X_1[/tex] = sample mean sales receipts for mail-order sales = $81.70

[tex]\bar X_2[/tex] = sample mean sales receipts for internet sales = $74.60

[tex]s_1[/tex] = sample standard deviation for mail-order sales = $18.75

[tex]s_2[/tex] = sample standard deviation for internet sales = $28.25

[tex]n_1[/tex] = size of sales receipts for mail-order sales = 7

[tex]n_2[/tex] = size of sales receipts for internet sales = 11

Also, [tex]s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} }[/tex] = 25.11

Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.

So, 80% confidence interval for the difference between population means, ([tex]\mu_1-\mu_2[/tex]) is ;

P(-1.337 < [tex]t_1_6[/tex] < 1.337) = 0.80  {As the critical value of t at 16 degree

                                         of freedom are -1.337 & 1.337 with P = 10%}  

P(-1.337 < [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < 1.337) = 0.80

P( [tex]-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < [tex]{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}[/tex] < [tex]1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ) = 0.80

P( [tex](\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < ([tex]\mu_1-\mu_2[/tex]) < [tex](\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ) = 0.80

80% confidence interval for ([tex]\mu_1-\mu_2[/tex]) =

[ [tex](\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] , [tex](\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ]

= [ [tex](81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }[/tex] , [tex](81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }[/tex] ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ([tex]\mu_1-\mu_2[/tex]) is [-9.132 , 23.332].

Answer:

dont know need points

Step-by-step explanation:

Answer:

What points are needed?

Answer:

They lost a total of -12 yards.

Step-by-step explanation:

Do the calculation.

5- 13= -8

-8 + 2 + 6= 0

0 - 12 = -12

Answer:

Option A

Step-by-step explanation:

22+(-32) is the same thing as 22-32.

[tex]22-32=-10[/tex]

Option A:

[tex]22+(-22)+(-10) \\22-22-10\leftarrow \text{Distribute -1 into the Parentheses.} \\0-10\\\boxed {-10}[/tex]

Option A's expression has the same value as the expression given.

Option B:

22+(22)+(-10)

[tex]22+22-10\\44-10\\\boxed {34}[/tex]

Option B's expression does not have the same value as the expression given.

Option C:

[tex]22+(-22)+(10)\\22-22+10\\0+10\\\boxed {10}[/tex]

Option C's expression does not have the same value as the expression given.

Option D:

[tex]22+0+32\\22+32\\\boxed{54}[/tex]

Option D's expression does not have the same value as the expression given.

Answer:

the answer is A

hoped this helped

Answer: this is the right answer Graph A represents j(x). The y-intercepts for f(x) and g(x) can be 1 and 3. And The rate of change of the sum of f(x) and g(x) is greater than that of either function. your welcome

Step-by-step explanation:

The rate of change of the sum of f(x) and g(x) is greater than that of either function.

From the question, we have the following parameters:

The graphs of the functions are not given;

However, if all the functions are linear functions, then the slopes of the sum of functions f(x) and g(x) could be greater than the slopes of h(x) and j(x)

Hence, the true statement (by observation) is (c)

Read more about linear functions at:

https://brainly.com/question/4025726

#SPJ1

Answer:

a) [tex] z= \frac{34-34}{2.5}= 0[/tex]

[tex] z= \frac{39-34}{2.5}= 2[/tex]

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) [tex] P(X<31.5) [/tex]

[tex] z= \frac{31.5-34}{2.5}= -1[/tex]

So one deviation below the mean we have: (100-68)/2 = 16%

c) [tex] z= \frac{29-34}{2.5}= -2[/tex]

[tex] z= \frac{36.5-34}{2.5}= 1[/tex]

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

[tex] X \sim N(\mu = 34, \sigma=2.5)[/tex]

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

[tex] P(34 < X<39)[/tex]

We can find the number of deviation from the mean with the z score formula:

[tex] z= \frac{X -\mu}{\sigma}[/tex]

And replacing we got

[tex] z= \frac{34-34}{2.5}= 0[/tex]

[tex] z= \frac{39-34}{2.5}= 2[/tex]

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

[tex] P(X<31.5) [/tex]

[tex] z= \frac{31.5-34}{2.5}= -1[/tex]

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

[tex] P(29 < X<36.5)[/tex]

And replacing we got:

[tex] z= \frac{29-34}{2.5}= -2[/tex]

[tex] z= \frac{36.5-34}{2.5}= 1[/tex]

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Answer:

4.24

Step-by-step explanation:

To solve this, use the Pythagorean therom. A^2 + b^2 = C^2

in this case a = 3  and b = 3

so 9 + 9 =  sqrt 18  

4.24

Answer:3√(2)

Step-by-step explanation:

DF=3

EF=3

DE=√(3^2 + 3^2)

DE=√(3x3 + 3x3)

DE=√(9+9)

DE=√(18)

DE=√(2 x 9)

DE=√(2) x √(9)

DE=√(2) x 3

DE=3√(2)

Answer:

The correct test statistic for the hypothesis test is [tex]t = -1.87[/tex]

Step-by-step explanation:

The null hypothesis is:

[tex]H_{0} = 16[/tex]

The alternate hypotesis is:

[tex]H_{1} < 16[/tex]

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

In this question:

[tex]X = 15.6, \mu = 16, s = 0.8, n = 14[/tex]

So

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{15.6 - 16}{\frac{0.8}{\sqrt{14}}}[/tex]

[tex]t = -1.87[/tex]

The correct test statistic for the hypothesis test is [tex]t = -1.87[/tex]

Hypothesis test used to check the results of the experiments gives true for the meaningful results.. The correct test statistic for the hypothesis test is -1.871.

Given information-

The mean battery life of the laptop is 16 hours claimed by the company.

The random sample for the test is 14.

Average life of the batteries found out as 15.6 hours.

The deviation for this result is 0.8 hours.

Hypothesis test used to check the results of the experiments gives true for the meaningful results.

As the mean battery life of the laptop is 16 hours claimed by the company.The null hypothesis for the given problem is,

[tex]H_o\mu=16[/tex]

As average life of the batteries found out as 15.6 hours. Thus the alternate hypothesis for the given problem is,

[tex]H_1\mu<16[/tex]

One sample t test can be found using the below formula,

[tex]t=\dfrac{\overline x -\mu_o}{\dfrac{s}{\sqrt{n} } }[/tex]

Here, [tex]\overline x[/tex] is mean value, [tex]n[/tex] is the number of random sample and [tex]s[/tex] is the deviation.

Put the values,

[tex]t=\dfrac{15.6 -16}{\dfrac{0.8}{\sqrt{14} } }\\t=-1.871[/tex]

Thus the correct test statistic for the hypothesis test is -1.871.

Learn more about the hypothesis here;

https://brainly.com/question/2695653

Answer:

2.33 units

Step-by-step explanation:

[tex]\tan 25\degree =\frac{AC}{5}\\\\0.46630 = \frac{AC}{5}\\\\AC = 0.46630 \times 5\\AC =2.3315\\AC = 2.33 \: units[/tex]

Answer:

Let's denote:

x: number of ticket 28$

y: number of ticket 40$

Then, we have:

x + y =5000

28x + 40y = 153200

=> 28(5000 - y) + 40y = 153200

=> 12y = 153200 - 140000

=> 12y =13200

=> y = 1100 (ticket 40$)

=> x = 5000 - 1100 = 3900 (ticket 28$)

Answer:

Step-by-step explanation:

These equations are all written in slope-intercept form, so the question is relatively easy to answer. These rules apply.

1. y=-6x-2; y=-6x-2 --- infinitely many

2. y=0.5x+5; y=0.5x+1 --- zero

3. y=0.25x-2; y=5x-4 --- one

4. y=2x+3; y=4x-1 --- one

5. y=2x+1.5; y=2x+1.5 --- infinitely many

6. y=-x-3; y=-x+3 --- zero

_____

Slope-intercept form is ...

  y = mx +b

m is the slope

b is the y-intercept

Answer:

Step-by-step explanation: 1. y=-6x-2; y=-6x-2 --- infinitely many

2. y=0.5x+5; y=0.5x+1 --- zero

3. y=0.25x-2; y=5x-4 --- one

4. y=2x+3; y=4x-1 --- one

5. y=2x+1.5; y=2x+1.5 --- infinitely many

6. y=-x-3; y=-x+3 --- zero