The student would have success in experiment with using copper in a closed circuit as it allows conduction and is a good conductor of electricity.
What is conduction?Conduction is defined as a process as a means of which heat is transferred from the hotter end of the body to it's cooler end.Heat flows spontaneously from a body which is hot to a body which is cold.
In the process of conduction,heat flow is within the body and through itself.In solids the conduction of heat is due to the vibrations and collisions of molecules while in liquids and gases it is due to the random motion of the molecules .
When conduction takes place, heat is usually transferred from one molecule to another as they are in direct contact with each other.There are 2 types of conduction:1) steady state conduction 2) transient conduction.According to the type of energy conduction is of three types:
1) heat conduction
2) electrical conduction
3)sound conduction
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An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Answer: The percent yield of the reaction is 77.0 %
Explanation:
[tex]2Pb+O_2\rightarrow 2PbO[/tex]
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
[tex]\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles[/tex]
[tex]\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles[/tex]
According to stoichiometry:
2 moles of [tex]Pb[/tex] produces = 2 moles of [tex]PbO_2[/tex]
2.18 moles of [tex]Pb[/tex] is produced by=[tex]\frac{2}{2}\times 2.18=2.18moles[/tex] of [tex]PbO_2[/tex]
Mass of [tex]PbO_2[/tex] =[tex]moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6[/tex]
percent yield =[tex]\frac{374.7g}{486.6g}\times 100=77.0\%[/tex]
is the movement of particles from an area of higher concentration to an area of lower concentration
Answer:
The answer is Diffusion.
Answer:
Hypertonic
Explanation:
We can identify unknown elements in a star by matching the ___________ spectrum of the star to those of known elements. *
mass
emission
atoms
A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milliliters. How many moles of N2 gas are in the sample
Answer: 0.025 moles of nitrogen gas are there in the sample.
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1.03 atm
V = Volume of gas = 568 ml = 0.568 L (1L=1000ml)
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]279K[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles[/tex]
0.025 moles of nitrogen gas are there in the sample.
Calculate the number of moles of solute in 431.9 L of 0.722 M sodium cyanide.
Answer:
[tex]312 \ mol \ solute[/tex]
General Formulas and Concepts:
Chemistry
Molarity = moles of solute / liters of solutionExplanation:
Step 1: Define variables
M = 0.722
L = 431.9
m = x
Step 2: Solve for x
Substitute: [tex]0.722 \ M=\frac{x \ mol}{431.9 \ L}[/tex]Isolate x: [tex]311.832=x \ mol[/tex]Rewrite: [tex]x=311.832 \ mol[/tex]Step 3: Check
Our smallest sig figs is 3. Follow sig figs rules.
[tex]311.832 \ mol \approx 312 \ mol \ solute[/tex]
Solubility
Mixtures and Solutions
Acellus
If 1.23 g of chlorine gas dissolves in
0.95 L of water at 15.6 psi, at what
pressure (in psi) would you be able
to dissolve 1.89 g in the same
amount of water?
The pressure : 23.48 psi
Further eplanationHenry's Law stated that the solubility of a gas is proportional to its partial pressure
Can be formulated
S = kH. P.
S = gas solubility, mol / L
kH = Henry constant, mol / L.atm
P = partial gas pressure
1.23 g Cl₂MW Cl₂ = 71 g/mol
mol of 1.23 g Cl₂ :
[tex]\tt mol=\dfrac{1.23}{71}=0.017[/tex]
Solubility O₂ : 0.017 mol/0.95 L =0.01789 mol/L
Henry's constant for O₂ :
P = 15.6 psi= 1.061517 atm
[tex]\tt S=kH.P\\\\kH=\dfrac{0.01789}{1,061517}=0.0169[/tex]
1.89 g Cl₂[tex]\tt \dfrac{1.89}{71}=0.026[/tex]
[tex]\tt S=0.026:0.95=0.027\\\\P=\dfrac{S}{kH}=\dfrac{0.027}{0.0169}=1.598~atm=23,48~psi[/tex]
Answer:24.0
Explanation:
Calculate the time required for a constant current of 0.868 A to deposit 0.387 g of Tl(III) as Tl(s) on a cathode.
Answer:
632.7 secs
Explanation:
Equation of the reaction:
Tl^3+ + 3e ------> Tl
If 1F = 96500 C
Q= It
Where;
I= current
t= time
3× 96500 C deposited 204 g of Tl
0.868 × t deposited 0.387 g of Tl
3 × 96500 × 0.387 = 204 × 0.868 × t
t= 3 × 96500 × 0.387/ 204 × 0.868
t= 632.7 secs
The time required for a constant current of 0.868 A to deposit 0.387 g of Tl(III) as Tl(s) is 2689 s
We'll begin by calculating the quantity of electricity needed to deposit 0.387 g of Ti
Ti³⁺ + 3e —> Ti
Recall:
1 mole of Ti = 48 g
1 electron (e) = 96500 C
Thus,
3 electrons = 3 × 96500 = 289500 C
From the balanced equation above,
48 g of Ti was deposited by 289500 C of electricity.
Therefore,
0.387 g of Ti will be deposited by = (0.387 × 289500) / 48 = 2334.09375 C of electricity
Finally, we shall determine the time required.Quantity of electricity (Q) = 2334.09375 C
Current (I) = 0.868 A
Time (t) =?t = Q / I
t = 2334.09375 / 0.868
t = 2689 sTherefore, the time required for the reaction is 2689 s
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What is the density of a glass piece that has mass of 18 g and a volume of 24 mL?
Answer:
The answer is 0.75 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{18}{24} = \frac{3}{4} \\ [/tex]
We have the final answer as
0.75 g/mLHope this helps you
what is the most likely oxidation state of nitrogen
In comparing the chemistry of the amines with alcohols and ethers, we discover many classes of related compounds in which nitrogen assumes higher oxidation states, in contrast to limited oxidation states of oxygen. In this context, keep in mind that the oxidation state of elemental oxygen (O 2) and nitrogen (N 2) is defined as zero.
Answer:
-3
Explanation:
What mass in grams of MgSO4 is required to make 59.3 mL of 2.68 M
solution?
Answer:
Approximately [tex]19.1\; \rm g[/tex].
Explanation:
Number of moles of formula units of magnesium sulfate required to make the solutionThe unit of concentration in this question is "[tex]\rm M[/tex]". That's equivalent to "[tex]\rm mol \cdot L^{-1}[/tex]" (moles per liter.) In other words:
[tex]c(\mathrm{MgSO_4}) = 2.68\; \rm M = 2.68\; \rm mol \cdot L^{-1}[/tex].
However, the unit of the volume of this solution is in milliliters. Convert that unit to liters:
[tex]\displaystyle V = 59.3\; \rm mL = 59.3 \; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.0593\; \rm L[/tex].
Calculate the number of moles of [tex]\rm MgSO_4[/tex] formula units required to make this solution:
[tex]\begin{aligned}n(\rm MgSO_4) &= c \cdot V \\ &= 2.68 \; \rm mol \cdot L^{-1} \times 0.0593\; \rm L \approx 0.159\; \rm mol \end{aligned}[/tex].
Mass of magnesium sulfate in the solutionLook up the relative atomic mass data of [tex]\rm Mg[/tex], [tex]\rm S[/tex], and [tex]\rm O[/tex] on a modern periodic table:
[tex]\rm Mg[/tex]: [tex]24.305[/tex].[tex]\rm S[/tex]: [tex]\rm 32.06[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Calculate the formula mass of [tex]\rm MgSO_4[/tex] using these values:
[tex]M(\mathrm{MgSO_4}) = 24.305 + 32.06 + 4 \times 15.999 \approx 120.361\; \rm g \cdot mol^{-1}[/tex].
Using this formula mass, calculate the mass of that (approximately) [tex]0.159\; \rm mol[/tex] of [tex]\rm MgSO_4[/tex] formula units:
[tex]\begin{aligned}m(\mathrm{MgSO_4}) &= n \cdot M \\&\approx 0.159 \; \rm mol \times 120.361 \; \rm g \cdot mol^{-1} \approx 19.1\; \rm g\end{aligned}[/tex].
Therefore, the mass of [tex]\rm MgSO_4[/tex] required to make this solution would be approximately [tex]19.1\; \rm g[/tex].
Which element has the lowest first ionization energy?
Be
Sr
OCa
Mg
28. A gas exerts pressure at 5atm at 300K. What is the pressure of the gas at 600K?
a) 1 atm b) 10 atm c).1 atm d) 100 atm
PLEASE HELP!! (I will mark brainiest) (REAL ANSWERS ONLY PLEASE!)
In one paragraph, using your own words, describe the structure of DNA using the following terms: phosphate, sugar, pyrimidines, purines, and bonding.
The phosphate group of one nucleotide bonds covalently with the sugar molecule of the next nucleotide, and so on, forming a long polymer of nucleotide monomers. The sugar–phosphate groups line up in a “backbone” for each single strand of DNA, and the nucleotide bases stick out from this backbone. The carbon atoms of the five-carbon sugar are numbered clockwise from the oxygen as 1′, 2′, 3′, 4′, and 5′ (1′ is read as “one prime”). The phosphate group is attached to the 5′ carbon of one nucleotide and the 3′ carbon of the next nucleotide. In its natural state, each DNA molecule is actually composed of two single strands held together along their length with hydrogen bonds between the bases.
Answer:
Explanation:
The discovery that DNA is the prime genetic molecule, carrying all the hereditary information within chromosomes, immediately focused attention on its structure. It was hoped that knowledge
of the structure would reveal how DNA carries the genetic messages that are replicated when chromosomes divide to produce two identical copies of themselves. During the late 1940s and early 1950s, several research groups in the United States and in Europe engaged in serious efforts—both cooperative and rival—to understand how the atoms of DNA are linked together by covalent bonds and how the resulting molecules are arranged in three-dimensional space. Not surprisingly, there initially were fears that DNA might have very complicated and perhaps bizarre structures that differed radically from one gene to another. Great relief, if not general elation, was thus expressed when the fundamental DNA structure was found to be the double helix. It told us that all genes have roughly the same three-dimensional form and that the differences between two genes reside in the order and number of their four nucleotide building blocks along the complementary strands.
Now, some 50 years after the discovery of the double helix, this simple description of the genetic material remains true and has not had to be ap- preciably altered to accommodate new findings. Nevertheless, we have come to realize that the structure of DNA is not quite as uniform as was first thought. For example, the chromosome of some small viruses have single-stranded, not double-stranded, molecules. Moreover, the precise orientation of the base pairs varies slightly from base pair to base pair in a manner that is influenced by the local DNA sequence. Some DNA se- quences even permit the double helix to twist in the left-handed sense, as opposed to the right-handed sense originally formulated for DNA’s general structure. And while some DNA molecules are linear, others are circular. Still additional complexity comes from the supercoiling (further twisting) of the double helix, often around cores of DNA-binding proteins.
Likewise, we now realize that RNA, which at first glance appears to be very similar to DNA, has its own distinctive structural features. It is principally found as a single-stranded molecule. Yet by means of intra-strand base pairing, RNA exhibits extensive double-helical character and is capable of folding into a wealth of diverse tertiary structures. These structures are full of surprises, such as non-classical base pairs, base-backbone interactions, and knot-like configurations. Most remarkable of all, and of profound evolutionary significance, some RNA molecules are enzymes that carry out reactions that are at the core of information transfer from nucleic acid to protein.
Clearly, the structures of DNA and RNA are richer and more intricate than was at first appreciated. Indeed, there is no one generic structure for DNA and RNA. As we shall see in this chapter, there are in fact vari- ations on common themes of structure that arise from the unique physi- cal, chemical, and topological properties of the polynucleotide chain
Type in the name of the following compounds. Be sure to use the periodic table if needed.
Answer: Sulfuric Acid
Explanation: correct on edg
Answer:
Sulfuric Acid
Explanation:
correct on edg
The process through which professional scientists evaluate the quality of each other’s research is called
group counsel.
group review.
peer counsel.
peer review.
Answer:
peer reveiw
Explanation:
Answer:
Peer review.
Explanation: Ask Edu
Two moles of acetyl chloride was mixed with two moles of dimethylamine. After the reaction is complete, what species can be found in the mixture
Answer:
See explanation
Explanation:
The reaction is shown in the image attached. This reaction occurs by a carbocation (ionic) mechanism.
The lone pair on the nitrogen atom attacks the carbocation leading to the formation of the product as shown in the image attached.
Since the reaction occurs in a 1:1 ratio, two moles of reactants yields two moles of product.
Please help
It’s super quick
Answer:
1. a
Explanation:
2. c
Answer:
1 is A number two is C
Arrange the elements in order of increasing atomic size: Li, N, B
Answer:
N, B, Ni
Explanation:
Answer:
Explanation:
Polonium crystallizes in a simple cubic unit cell with an edge length of 3.36 Å.
a. What is the mass of the unit cell?
b. What is the volume of the unit cell?
c. What is the density of polonium?
a. The unit cell is the smallest group of atom which have overall symmetry of a crystal, and from which is the entire letters can be buled built up by repetition in 3 dimensions.
b. The volume(v) of the unit cell is equal to the cell edge length (a)cubed.
c. density of polonium is 9.32g/cm3.
A rock rolls down a hill. Which form of energy is this an example of?
Chemical
Electrical
Mechanical
Thermal
Answer:
Mechanical
Explanation:
chemical
Explanation:
I took test 2020
1. With the aid of a Hess cycle, determine the enthalpy of the decomposition reaction of sodium nitrate, NaNO3 to sodium nitrite, NaNO2 and oxygen, O2. [5]
Enthalpy of formation of NaNO3 = -468 kJ/mol
Enthalpy of formation of NaNO2 = -369kJ/mol
Answer:
Explanation:
2NaNO₃ = 2NaNO₂ + O₂
NaNO₃ = NaNO₂ + 1/2 O₂
- 468 kJ -369 kJ 0 kJ
enthalpy of decomposition reaction
= - 369 - ( - 468 ) kJ
= 99 kJ / mol .
which type of rection has the general formuial ab+cd
Whenever the same two elements form more than one
compound, the different masses of one element that combine
with the same mass of the other element are in the ratio of
small whole numbers.
TRUE
FALSE
Answer:
The answer is true
Explanation: Because The law of multiple proportions states that when two elements react to form more than one compound, a fixed mass of one element will react with masses of the other element in a ratio of small, whole numbers.
The period that an element is in on the periodic table can tell you how many _____ the element’s atom have.
A. Energy level(electron shells)
B. valence electrons
C. protons
D. isotopes
WILL BE MARKED BRAINLIEST
PLUS 15 Points
Answer: It's D
Explanation:
Why is it necessary to add concentrated HCl, then water, rather than a solution of HCl to the eudiometer tube
If we add water to a concentrated acid, then the solution may boil very violently, splashing concentrated acid. If add acid to water, the solution that forms is very dilute and a small amount of heat is released.
Why do we add acid to water?When a strong acid is poured into water, it flows down the flask and mixes much better, so no boiling takes place. The addition of water to acid forms an extremely concentrated solution of acid initially. A large amount of heat is released and the solution may boil very violently, splashing concentrated acid out of the beaker and all this because the reaction is exothermic in nature.
The reason this takes place is due to a large amount of energy liberated in the hydration reaction of concentrated ions. Therefore, we add acid to water dropwise for the dilution with constant stirring and not water to acid directly.
If we add water to acid, then an exothermic reaction occurs and the solution may boil very violently. To form the dilute solution of any strong acid, you should add acid to water and the small amount of heat released is not sufficient to vaporize and spatter it.
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The amount of force needed to keep a 10 kg box moving at a constant
speed of 0.4 m/s on frictionless ice is *
ON,
0.04N
40 N
1.4 N
Answer:
ON
Explanation:
Frictional force is a force that opposes the motion of body. It is because of friction that motion can be controlled and even walking is made possible.
Now, on a frictionless surface, there is no opposition to motion. Therefore, to keep the body moving there is no force required.
If surface lacks friction, motion will continue perpetually without any hinderance.Use the van der Waals equation to calculate the pressure exerted by 1.475 molmol of Cl2Cl2 in a volume of 4.635 LL at a temperature of 299.0 KK .
Answer:
7.812atm
Explanation:
Using Van der Waals equation, which goes as follows:
Pv = nRT
Where;
P is the pressure
V is the volume (4.635L)
n is the number of moles (1.475mol)
T is the temperature (299K)
R is the universal gas constant (0.082057 L atm mol-1K-1)
Pv = nRT
P = nRT/V
P = 1.475 × 0.0821 × 299/4.635
P = 36.2081/4.635
P = 7.812atm
Explain how Bohr's model built on the ideas of Einstein and Planck.
Explanation:
Bohr built on Nicholson's idea by adopting the requirement that the angular momentum can have only certain discrete values related to Planck's constant. However Bohr's atom has many orbits for the electrons.
How does Kinetic energy and how does it relates to diffusion and temperature.
HURRY HELPPP!!!!!!!!!!!!!!!!!!!!
Answer:
ok
Explanation:
khfdnkv Klein pick pick or en la Web outta
What volume of 0.150 M 2 M Li2S solution is required to completely react with 120 mLmL of 0.150 M Co(NO3)2 MCo(NO3)2
Answer:
Explanation:
M1V1=M2v2
M1=0.150M
M2=0.150M
V2=120*10^-3
V1=M2V2/M1
V1=0.150*120*10^-3/0.150
V1=0.12
0.12 mL volume of 0.150M 2M Li₂S solution is required to completely react with 120 mL of 0.150M Co(NO₃)₂ MCo(NO₃)₂.
What is the relation of volume with molarity?
With M1 and M2 representing the molarity of the solutions, expressed as mol/L or M, and V1 and V2 representing their respective volumes, this calculator may be used to calculate a missing number for the dilution equation.
A solution's concentration is determined by multiplying its volume by its molarity (M1V1 = M2V2) On both sides of the equation, the units should stay the same.
Here
M₁V₁=M₂V₂
M₁=0.150M
M₂=0.150M
V₂=120 × 10⁻³
V₁=M₂V₂/M₁
V₁=0.150 × 120 × 10⁻³/0.150
V₁=0.12.
Therefore, 0.12 mL volume of 0.150M 2M Li₂S solution is required to completely react with 120 mL of 0.150M Co(NO₃)₂ MCo(NO₃)₂.
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