A thunderclap sends a sound wave through the air and the ocean below. The
thunderclap sound wave has a constant frequency of 100 Hz. What is the
wavelength of the sound wave in water? (The equation for the speed of a
wave is v= f x 1.)
Water
Diamond
Glass
Air
1,493
12,000
5,640
346
Speed of
sound
(m/s)
A. 11.00 m
B. 12.00 m
C. 14.93 m
D. 3.46 m

Answer:

that when two object interact, they apply forces to one another that are equal in magnitude and opposite in direction.

Explanation:

Newton's third law: the law of action and reaction

Answer:

a. 5 batteries b. 1050 mAh

Explanation:

Here is the complete question

A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed? B) What mAh capacity should the batteries have?

Solution

A) How many batteries are needed?

Since the nominal voltage for a single NiMH battery is 1.2 V per battery and we require 6V DC power, we combine the batteries in series to obtain a total voltage of 6 V. The number of batteries required, n = total voltage/voltage per cell = 6V/1.2V per battery = 5 batteries

So, the number of batteries needed is 5.

B) What mAh capacity should the batteries have?

Since the batteries are in series, they would each deliver a current of 150 mA. Since we require a current of 150 mA for 7 hours, the number of milliampere-hours capacity mAh of batteries required is Q = It where I = current = 150 mA and t = time = 7 hours.

So, Q = It = 150 mA × 7 h = 1050 mAh.

So, the batteries should have a mAh of 1050 mAh

Answer:

Mass = 0.04 Kg

Explanation:

Given the following data;

Density = 800 kg/m³

Volume = 5 * 10^{-5} m³

To find the mass of the object;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

[tex] Density = \frac {mass}{volume} [/tex]

Making mass the subject of formula, we have;

[tex] Mass = density * volume [/tex]

Substituting the values into the formula, we have;

[tex] Mass = 800 * 5 * 10^{-5} [/tex]

Mass = 0.04 Kg

answer is

Answer:

Solition given:

focal length(f)=20cm

size of image(v)=2x

size of object(u)=x

we have

power of lens= reciprocal to focal length=1/20=0.05/cm

ii.

the position of the image is beyond C.

Explanation:

See the attachment !!!!!!!

Answer:

change waterslide according to question. and you are good to go. check photo for solve

The person moving with speed upon leaving the waterslide is equal to 0.313 m/s while ignoring the friction.

If there is a loss of energy in any part of the system, there must be the same amount of a gain of energy in some other part of the isolated system.

Kinetic energy + Potential energy = constant

Therefore, the initial kinetic and potential energy of the person must be equal to the final kinetic and potential energy.

mgh₁ + mv₁²/2 = mgh₂ + mv₂²/2

gh₁ + v₁²/2 = gh₂ + v₂²/2

2gh₁ + v₁² = 2gh₂ + v₂²

2g(h₁ - h₂) = v₂² -  v₁²

[tex]v_2=\sqrt{2g(h_2-h_1) + v^2_1}[/tex]                                               .................(1)

Given, the mass of the person, m = 63 Kg

The initial speed of the person as at rest, v₁ = 0

Consider that the speed of the person while leaving the waterslide is v₂

The initial height of the person above the ground, h₁ = 6.0 mm

The height of the person leaving the waterslide, h₂= 1.0 mm

Substitute, the value of m, v₁, h₁ and h₂ in equation (1):

[tex]v_2 = \sqrt{2(9.8m/s^2)(6mm-1mm) + (0)^2}[/tex]

[tex]v_2 =\sqrt{2(9.8)\times 5 \times 10^{-3}} \;m/s[/tex]

[tex]v_2 =\sqrt{0.098}\; m/s[/tex]

v₂ = 0.313 m/s

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Answer:

Matter is any substance that has mass and takes up space by having volume

Answer:

Explanation:

[tex]\lambda\\[/tex] = v/f

^That is the formula we are going to use.

Now, we were given the speed (v), which is 20.

Now we need to find frequency, in order to solve for the wavelength.

Frequency is the amount of waves in a fixed unit of one second, meaning our F value is the value of 5 divided by 4.

5/4 = 1.25

Therefore our F is 1.25

Now lets plug it in

[tex]\lambda\\[/tex] = v/f

[tex]\lambda\\[/tex] = 20/1.25

[tex]\lambda\\[/tex] = 16

Conversion:

[tex]\lambda\\[/tex] = 8

[tex]\boxed{\sf E=QV^2}[/tex]

[tex]\\ \sf\longmapsto Q=\dfrac{E}{V^2}[/tex]

[tex]\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{24^2}[/tex]

[tex]\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{576}[/tex]

[tex]\\ \sf\longmapsto Q=0.006\times 10^{-4}C[/tex]

[tex]\\ \sf\longmapsto Q=6\times 10^{-1}C[/tex]

[tex]\\ \sf\longmapsto Q=0.6C[/tex]

Now

[tex]\boxed{\sf Q=CV}[/tex]

[tex]\\ \sf\longmapsto C=\dfrac{Q}{V}[/tex]

[tex]\\ \sf\longmapsto C=\dfrac{0.6}{24}[/tex]

[tex]\\ \sf\longmapsto C=0.025F[/tex]

Note:-

Answer:

could and largejsjisj and we look like they can get to

Our sun is 27 million times larger than our moon. Based on its mass, the sun's gravitational attraction to the Earth is more than 177 times greater than that of the moon to the Earth. If tidal forces were based solely on comparative masses, the sun should have a tide-generating force that is 27 million times greater than that of the moon. However, the sun is 390 times further from the Earth than is the moon. Thus, its tide-generating force is reduced by 3903, or about 59 million times less than the moon. Because of these conditions, the sun’s tide-generating force is about half that of the moon.

Answer:

0.48N

Explanation:

according to the second law of motion

force=mass×acceleration

the mass in this question is 0.025,the acceleration 19

therefore f=0.025×19

=0.48N

I hope this helps

Answer:

Because of the interstellar dust and interior location of the solar system.

Explanation:

We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.

So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.

Answer:

I dont know answer Sorry For that thank u

Every particle of mass is attracted to every other particle of mass.  The magnitude of the force between two objects is proportional to the product of their masses, and inversely proportional to the square of the distance between them.  The direction of the force is along the line between their centers.

(NOTE:  Newton's 3rd law of motion tells us that gravitational forces always come in pairs.  Between two objects, there are two forces ... one in each direction.  Their strengths are equal ... Your weight on Earth is exactly equal to the Earth's weight on YOU.)

The approximate temperature of the star as determined is D) 5500 K.

The Wien's displacement law relates the maximum wavelength of a body to its absolute temperature. Wien's displacement law states that:

λ = [tex]\frac{b}{T}[/tex]

where λ is the maximum wavelength of the body, b is the constant of proportionality and T is the absolute temperature.

Thus from the given question, λ = 525 nm (525 x [tex]10^{-9}[/tex]), and b = 2.9 x [tex]10^{-3}[/tex] mK.

So that,

525 x [tex]10^{-9}[/tex] = [tex]\frac{2.9*10^{-3} }{T}[/tex]

Make T the subject of the formula to have;

T = [tex]\frac{2.9*10^{-3} }{525*10^{-9} }[/tex]

  = 5523.81

T = 5523.81 K

T ≅ 5500.00 K

The approximate temperature of the star in Kelvin is 5500 K.

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Answer:

The velocity at that time would be [tex](-67.975\; \rm s)[/tex]. The velocity of this particle is continuously changing.

Explanation:

Differentiate the expression for position [tex]x[/tex] with respect to time [tex]t[/tex] to find an expression for velocity.

[tex]\begin{aligned}v(t) &= \frac{d}{dt}[x(t)] \\ &= \frac{d}{dt} \left[ 7.4 + 9.2\, t - 2.1\, t^{3}\right]\\ &= 9.2 - 6.3\, t^{2}\end{aligned}[/tex].

Hence, at [tex]t = 3.5\; \rm s[/tex], velocity would be [tex]v(3.5) = 9.2 - 6.3 \times (3.5)^{2} = -67.975\; \rm m[/tex].

Since velocity [tex]v(t)[/tex] changes with time [tex]t[/tex], the velocity of this particle is continuously changing.

Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

[tex]T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2[/tex]

perpose of lab is to store apparatus and do some experiment

Helps someone to know the exert lengh of something

Answer:

Remember the relation:

Speed*Time = Distance.

We can estimate that the speed at which an earthquake "moves", in the surface, is:

S = 6km/s  (this is a low estimation actually)

Then if the wave is detected 12.5 minutes after the earthquake, we know that it traveled for 12.5 minutes before reaching the detector.

So we know the speed of the wave and the time it took to reach the detector, then we can use the equation:

Speed*Time = Distance.

to find the distance.

First, we should write the time in seconds

we know that:

1 min = 60 s

then:

12.5 min = 12.5*(60 s) = 750 s

Then, the wave traveled with a speed of 6 km/s for 750 seconds until it reached the detector, then the distance that it traveled is:

(6km/s)*750s = 4500 km

The distance between the detector and the site of the quake is around 4500 km.

Answer:

E_O = 96J

Explanation:

E_O = E_I*(%e/100%)

E_O = 120J*(80%/100%)

E_O = 96J

Answer:

I don't know sorry' please

Converse:

if q , then p

Inverse:

If not p , the not q.

Contra Positive:

If not q, then not p.

If then statement is a conditional statement. In this statement there is some condition at the first part of the sentence and then in the second part there is a conclusion.

The example of if then sentence is as follows,

If this camel is thirsty, then it will drink water from the well.

In this example there is a condition in first part that if camel is thirsty, in the second part there is conclusion which states that then it will drink water from well.

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Answer:

Explanation:

        16093.4

Answer:

Explanation:

Givens

t = 10 seconds

vi = 0

vf = 3600 mph

a = ?

d = 10000 feet

Formula

a = (vf - vi)/t

Solution

vf = 3600 mph * 1 hr / 3600 seconds * 5280 feet / 1 mile = 5280 ft / sec

a = (5280 - 0)/10

a = 528 ft/sec^2

Answer:

Diameter of wire = 0.00021 meters

Explanation:

Given the following data;

Number of windings = 30

Length of windings = 6.3 mm to meters = 0.0063 meters

To find the diameter of the wire, we would use this mathematical expression;

Length of windings = number of windings * diameter of wire

Substituting the values into the expression, we have;

0.0063 = 30 * diameter of wire

Diameter of wire = 0.0063/30

Diameter of wire = 0.00021 meters

Answer:

Slowly and smoothly lol

Answer:

S.I. on Rs. 1600 = T.D. on Rs. 1680. Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%. Time =100 x 80year=1year = 4 months.1600 x 153

Explanation:

Is this you are?

Answer:

The laws of liquid pressure are: ... The liquid pressure at a point inside the liquid is same in all directions. The liquid pressure at a point inside the liquid is directly proportional to the depth of that point from the free surface of liquid. The pressure of liquid at same depth is different for different liquids

Answer:

The laws of liquid pressure:

The pressure that is inside the liquid rises with the intensity from the surface of a liquid.

The term fluid:

Fluid is basically liquid and a substance that is known to have no certain shape. The opposite of the term fluid would be solid.

Answer:

About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.

Explanation:

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