Answer:[tex]12x+25y=300[/tex]
Step-by-step explanation:
Answer:
12x + 25y = 300
Step-by-step explanation:
7z+15+27, z, plus, 15, plus, 2
Answer:
[tex]7z + 15 + 27 \\ 7z + 42 \\ z = 42 \div 7 \\ z = 6[/tex]
please help asap! ----------------------------
Answer:
[tex]f^{-1}(f(58))=58[/tex]
[tex]f(f(5))=11[/tex]
Step-by-step explanation:
We are given that the table which shows some inputs and outputs of the invertible function f with domain all real numbers.
We are given that
x f(x)
5 9
3 -2
1 -5
18 -1
0 1
9 11
We have to find
[tex]f^{-1}(f(58))[/tex] [tex]f(f(5))[/tex]
We know that
[tex]f^{-1}(f(x))=x[/tex]
Using the property
[tex]f^{-1}(f(58))=58[/tex]
[tex]f(5)=9[/tex]
[tex]f(f(5))=f(9)[/tex]
[tex]f(f(5))=11[/tex]
PLEASE HELP ASAP!!!!!!
Describe the graph of a function g by observing the graph of the base function ƒ.
g(x) = ƒ(x + 5) + 3
g(x) = ƒ(x + 3) + 5
g(x) = 2ƒ(x + 3)
g(x) = ƒ(x – 3) – 5
Answer:
g(x)=f(x+3)+5
Step-by-step explanation:
[tex]factorise \: \\ \\ r {}^{2} - 10r + 21[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (r - 7)(r - 3) }}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]
[tex] {r}^{2} - 10r + 21[/tex]
[tex] = {r}^{2} - 7r - 3r + 21[/tex]
Taking [tex]r[/tex] as common from first two terms and [tex]3[/tex] from last two terms, we have
[tex] = r(r - 7) - 3(r - 7)[/tex]
Taking the factor [tex](x-7)[/tex] as common,
[tex] = (r - 7)(r - 3)[/tex]
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
Step-by-step explanation:
Your Answer with
Explanation is given in the attachment
Hope it is helpful to you
✌️✌️✌️✌️✌️✌️✌️
does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?
Answer:
Inside
Step-by-step explanation:
Given equation of the Circle is ,
[tex]\sf\implies x^2 + y^2 = 25 [/tex]
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]
Here we can see that the distance of poiñt from centre is less than the radius.
Hence the point lies within the circle
In the diagram, ABC is an equilateral triangle, BCFG is a square and CDEF is a rectangle. The perimeter of the whole diagram is 65cm, find the length of GE
Answer:
22 cm
Step-by-step explanation:
the perimeter = AB+BG+GF+FE+ED+DC+CA
= 65 cm
7+7+7+FE+7+DC+7=65 => FE = CD
35+ 2FE = 65
2FE = 65-35
= 30
FE = 30/2 = 15
so, GE = GF + FE
= 7+15 = 22 cm
ANSWER PLZ ILL GIVE BRAINLEST
Answer:
y is 4
Step-by-step explanation:
x is 3
y is 4 coordinate is (3,4)
Answer:
4
Step-by-step explanation:
In ΔVWX, the measure of ∠X=90°, XW = 20, WV = 29, and VX = 21. What ratio represents the cosine of ∠W?
the first three terms of a series of which the nth term is 2n+1.
Answer:
3, 5, 7
Step-by-step explanation:
Substitute n = 1, 2, 3 into the nth term rule
a₁ = 2(1) + 1 = 2 + 1 = 3
a₂ = 2(2) + 1 = 4 + 1 = 5
a₃ = 2(3) + 1 = 6 + 1 = 7
Answer:
3, 5, 7
Step-by-step explanation:
n = 1, 2, 3 into the nth term rule
a₁ = 2(1)+1=2+1=3
a2=2(2)+1=4+1=5
a3 = 2(3)+1=6+1=7
find the coefficient of variation from the following data mean=4 variance=25
Help me with the diagram please!!!
Answer:
(B) 30
Step-by-step explanation:
Imagine you drew a line from Point T until it touched Line PR. Let's call that point where it touched Line PR "Point Z".
That line (called Line TZ) would be perpendicular to PR, forming a 90 degree angle.
Now, TZW is a triangle.
To find x, we need to find the angle measurment of Angle ZTW.
This is where we use the hexagon.
A hexagon's interior angle sum is 720, meaning each interior angle is equal to 120 degrees. So Angle UTS would equal 120 degrees.
However, Line TZ bisects that 120 degree angle, so Angle ZTW would equal 60 degrees (because 120/2 = 60).
Now we have two angles of the triangle: 90 & 60.
A triangle's interior angle sum is 180.
Add 90 & 60, which is 150, and subtract 150 from 180.
The result is 30, which is the angle measurement of x.
Hope it helps (●'◡'●)
Help me please PLEAASEEEE
A group of friends wants to go to the amusement park. They have $214.25 to spend on parking and admission. Parking is $6.75, and tickets cost $20.75 per person, including tax. Write and solve an equation which can be used to determine pp, the number of people who can go to the amusement park.
Answer:
10 friends can go to the amusement park
Step-by-step explanation:
214.25 = 6.75 + 20.75x
207.50 = 20.75x
x = 10 friends can go
Evaluate without a calculator:
CSC -120°
Answer:
- [tex]\frac{2\sqrt{3} }{3}[/tex]
Step-by-step explanation:
Using the identity and the exact value
csc x = [tex]\frac{1}{sinx}[/tex] and sin60° = [tex]\frac{\sqrt{3} }{2}[/tex]
- 120° is in the third quadrant where sin < 0 , then
csc - 120° = - sin60° , then
csc - 120°
= [tex]\frac{1}{-sin60}[/tex]
= - [tex]\frac{1}{\frac{\sqrt{3} }{2} }[/tex]
= - [tex]\frac{2}{\sqrt{3} }[/tex] ( rationalise the denominator )
= - [tex]\frac{2}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex]
= - [tex]\frac{2\sqrt{3} }{3}[/tex]
The equivalent value of the trigonometric relation cosec ( -120 )° = 2√3/3
What are trigonometric relations?Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles
The six trigonometric functions are sin , cos , tan , cosec , sec and cot
Let the angle be θ , such that
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
tan θ = sin θ / cos θ
cosec θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ
Given data ,
We know that the cosecant function is defined as the reciprocal of the sine function:
cosec (θ) = 1 / sin(θ)
Therefore, to evaluate cosec(-120°), we first need to find sin(-120°).
We know that sine is an odd function, which means that sin(-θ) = -sin(θ). Therefore,
sin(-120°) = -sin(120°)
We can now use the fact that the sine function has a period of 360 degrees, which means that sin(120°) is the same as sin(120° - 360°) = sin(-240°).
Using the same logic as before, we get:
sin(-240°) = -sin(240°)
Now , from the trigonometric relations , we get
Now, we can use the fact that sin(240°) = sin(240° - 360°) = sin(-120°), which means that:
sin(-240°) = -sin(-120°)
Therefore, we have:
sin(-120°) = -sin(120°) = -sin(-240°) = sin(240°)
Now, we can use the unit circle or trigonometric identities to find sin(240°). One way to do this is to draw a 30-60-90 degree triangle in the third quadrant of the unit circle, with the angle of 240° as the reference angle:
In this triangle, the opposite side (O) has a length of √3, the adjacent side (A) has a length of -1, and the hypotenuse (H) has a length of 2.
Therefore, sin(240°) = O/H = (√3)/2.
Finally, we can use the definition of the cosecant function to find cosec(-120°):
cosec(-120°) = 1/sin(-120°) = 1/sin(240°) = 1/((√3)/2) = 2/√3 = (2√3)/3.
Hence , cosec(-120°) is equal to (2√3)/3.
To learn more about trigonometric relations click :
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Find the area of the region between the curve x^3+2x^2-3x and the x-axis over the interval [-3,1]
Answer:
[tex]\displaystyle A = \frac{32}{3}[/tex]
General Formulas and Concepts:
Calculus
Integrals
Definite IntegralsArea under the curveIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Area of a Region Formula: [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify
Curve: x³ + 2x² - 3x
Interval: [-3, 1]
Step 2: Find Area
Set up: [tex]\displaystyle A = \int\limits^1_{-3} {(x^3 + 2x^2 - 3x)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + \int\limits^1_{-3} {2x^2} \, dx - \int\limits^1_{-3} {3x} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + 2\int\limits^1_{-3} {x^2} \, dx - 3\int\limits^1_{-3} {x} \, dx[/tex][Integrals] Integrate [Integration Rule - Reverse Power Rule]: [tex]\displaystyle A = (\frac{x^4}{4}) \bigg| \limits^1_{-3} + 2(\frac{x^3}{3}) \bigg| \limits^1_{-3} - 3(\frac{x^2}{2}) \bigg| \limits^1_{-3}[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle A = -20 + 2(\frac{28}{3}) - 3(-4)[/tex]Evaluate: [tex]\displaystyle A = \frac{32}{3}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Given P(A) = 0.36, P(B) = 0.2 and P(ANB) = 0.122, find the value of P(AUB), rounding to the nearest thousandth, if necessary.
Answer:
The value of P(AUB) = 0.438
Step-by-step explanation:
Given:
P(A) = 0.36
P(B) = 0.2
P(A∩B) = 0.122
Find:
The value of P(AUB)
Computation:
P(AUB) = P(A) + P(B) - P(A∩B)
The value of P(AUB) = 0.36 + 0.2 - 0.122
The value of P(AUB) = 0.56 - 0.122
The value of P(AUB) = 0.438
We are given that angle ABC and are congruent, and that angle GHI and angle DEF are congruent. By the , the measure of angle ABC is equal to the measure of angle DEF, and the measure of angle GHI is equal to the measure of angle DEF. By the substitution property, the measure of angle ABC is equal to .
Answer:
By the Substitution property, the measure of angle ABC is equal to GHI.
Step-by-step explanation:
According to the Question,
Since we have,
Angle ABC and angle DEF are congruent ⇒ ∠ABC = ∠DEF-------(1 ) Similarly,angle GHI and angle DEF are congruent ⇒ ∠GHI = ∠DEF------(2)On substituting the value of from equation (1) to equation (2)
We get, ∠ABC = ∠GHI ∴ ∠ABC ≅ ∠GHI
Thus, By the Substitution property
The measure of angle ABC is equal to angle GHI.
Maths assignment
9p^2-16q^2
Answer:
[tex]9p^2-16q^2[/tex]
[tex](3p)^{2} -(4p)^{2}[/tex]
[tex]\underline{x^2-y^2=\left(x+y\right)\left(x-y\right)}[/tex]
[tex]\left(3p\right)^2-\left(4q\right)^2=\left(3p+4q\right)\left(3p-4q\right)[/tex]
[tex]=\left(3p+4q\right)\left(3p-4q\right)[/tex]
------------------------
hope it helps....
have a great day!!
Chloe baked 6 brownies with nuts on top and 9 brownies without nuts. What is the ratio of the number of brownies without nuts to the total number of brownies?
Answer:
6:9 ÷3
2:3
Step-by-step explanation:
1st write the ratio then simplify it with dividing with the Highest common factor on both sides
find area of the figure
thanks for any help
Answer:
8050 m²
Step-by-step explanation:
We can divide the diagram up into two components: a rectangle with a width of 60 m and a height of 80 m, and a triangle with a base of 130 m (190 - 60) and a height of 50 m (80 - 30).
The area of the rectangle:
A = lw
A = 60 m (80 m)
A = 4800 m²
The area of the triangle:
A = 1/2 b*h
A = 1/2 (130 m) (50 m)
A = 1/2 (6500 m²)
A = 3250 m²
Now, we can add the areas of the two separate components:
A = 4800 m² + 3250 m²
A = 8050 m²
which polygon has an interior angle sum of 1080
Answer:
octagon which has eight sides.. (1st option )
Whose solution strategy would work?
Answer:
1452628383763637£838
Answer:
B
Step-by-step explanation:
A garden store pays $85 for a planter. The percent of markup is 35%. What is the selling price of the planter
Answer:
Step-by-step explanation:
To get the selling price.
Selling price=100÷ 100-x × 85
Where x is the markup.
Sp= 100 ÷ 100-35× 85
Sp= 100÷ 65×85
Sp= $130.7692
What is the length of DK?
A) 8.5
B) 12.7
C) 7.0
D) 3.5
Answer:
A
8.5 is the answer
If you test is going on so
all the best!
y=x+2 y=-x +8 What is the solution for this system of equations?
Answer:
x = 3 y = 5
Step-by-step explanation:
y=x+2
+ y=-x +8
2y = 10
y = 5
y = -x + 8
5 = -x + 8
x = 3
line F has a slope of. -6/3 and line G has a slope of -8/4.
what can be determined about distinct lines F and G?
Given:
Slope of line F = [tex]-\dfrac{6}{3}[/tex]
Slope of line G = [tex]-\dfrac{8}{4}[/tex]
To find:
The conclusion about distinct lines F and G.
Solution:
We have,
Slope of line F = [tex]-\dfrac{6}{3}[/tex]
= [tex]-2[/tex]
Slope of line G = [tex]-\dfrac{8}{4}[/tex]
= [tex]-2[/tex]
The slopes of lines F and G are equal and we know that the slopes of two parallel lines are always equal.
Therefore, the line F and line G are parallel to each other.
What is the total value of digit 7 in the number 32.8794
What is the variable expression for 6 less than the difference of 5 and a number? * 3 points 6 - 5 - n 6 - n - 5 (5 - n) -6 6 - (5 - n)
Given:
The given statement is "6 less than the difference of 5 and a number".
To find:
The variable expression for the given statement.
Solution:
Let n be the unknown number or the variable.
We know that minus sign is used to represent the difference between two numbers.
Difference of 5 and a number is [tex](5-n)[/tex].
6 less than the difference of 5 and a number is [tex](5-n)-6[/tex].
The required expression for the given statement is [tex](5-n)-6[/tex].
Therefore, the correct option is C.
PLEASE HURRY Aline has a slope of -1/2 and a y-intercept of -2. What is the x-intercept of the line?
Answer:
x- intercept = - 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - [tex]\frac{1}{2}[/tex] and c = - 2 , then
y = - [tex]\frac{1}{2}[/tex] x - 2 ← equation of line
To find the x- intercept let y = 0
0 = - [tex]\frac{1}{2}[/tex] x - 2 ( add 2 to both sides )
2 = - [tex]\frac{1}{2}[/tex] x ( multiply both sides by - 2 to clear the fraction )
- 4 = x
The x- intercept is - 4
plz help ASAP with explanation
Answer:
Kindly check attached picture
Step-by-step explanation:
Based d on the instruction given.
1.)
-3 * 6 = 18
6 * - 2 = - 12
-3 * - 2 = 6
2.)
We use logical reasoning to find 2 numbers whichbwhen multiplied gives the number in the box in between :
The answers are given in the picture attached.
