Answer:
No, it would not still be water. it would be hydrogen peroxide
Explanation:
water is [tex]H_{2} O[/tex]. Adding another oxygen would make it [tex]H_{2} O_{2}[/tex], which is hydrogen peroxide
Answer:
It would be Hydrogen peroxide
Explanation:
Atoms actually prefer being configured as water (H2O). Adding on the extra oxygen takes a lot of energy (and other chemicals). That's why we see lots of water and not much hydrogen peroxide around in nature. The reason hydrogen peroxide (H2O2) is dangerous is because it actually wants to drop off that extra oxygen and become water. Anything that does this is called an oxidising agent. An oxygen atom on it's own is pretty unstable and really wants to snatch up electrons from somewhere. First it'll probably gobble up some free floating hydrogen and make some more water with it. In our bodies we don't have much free floating hydrogen, so it runs out pretty quick. The oxygen atom army then has to start breaking up bigger molecules to steal the hydrogens and sometimes even the nitrogens. This breaks up the molecules that form the structures of your body and leaves you with a jumble of random configurations of atoms where the oxygen atoms passed through. Now, before you ask, normally oxygen doesn't do it to you because it exists in the air as O2, bonded to itself. The isolated oxygen atoms only exist for a brief time after they've split up from the hydrogen peroxide.
diffrence between:- movable pulley and fixed pully
Answer:
fixed pulley: A pulley system in which the pulley is attached to a fixed point and the rope is attached to the object. ... movable pulley: A pulley system in which the pulley is attached to the object; one end of the rope is attached to a fixed point and the other end of the rope is free.
Explanation:
If the angle between the net force and the displacement of an
object is greater than 90 degrees, then which option holds
true?
aThe object stops
b Kinetic energy decreases
C Kinetic energy increases
d Kinetic energy remains the same
Answer: kinetic energy decreases
Explanation:
When the angle between the net force and the displacement of an
object is greater than 90 degree, the Kinetic energy decreases.
The work done by a net force in moving an object over a given distance is given as;
[tex]W = F \times d \ cos(\theta)[/tex]
where;
θ is the angle between the net force and the displacementThe value of cos(θ) decreases from 0 to 180, consequently, the value of work-done will decrease as well.
Based on work-energy theorem, the work done on the object is equal to kinetic energy of the object.
[tex]W = K.E[/tex]
Thus, we can conclude that when the angle increases, the Kinetic energy decreases.
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Suppose that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat. The change in internal energy of the spring is?
Answer: 85J
Explanation:
From the question, we are informed that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat.
Therefore, the change in internal energy of the spring will be calculated as:
ΔU = q + w
where, q = -15J
w = 100J
ΔU = -15J + 100J
= 85J
Do you know how to do this clever ones hmmm?? Describe and explain the motion of a small ball floating on a pond when waves travel across the pond.
Answer:
Ball moves up and down repeatedly on surface because waves consist of successive crests and troughs moving across surface, each crest pushes ball up and each trough allows it to move down.
Explanation:
why does the force of air resistance affect the motion of a person traveling at high speed more than a person walking across the room?
Answer:
yes .
Explanation:
...
;-; :) have a good day
Answer:
because on air the speed is high compared to walking
What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. transmission
slight reflect but most goes through because glass is transparent
Most of the light waves that strike a clear pane of glass reflects. Details about reflection can be found below.
What is reflection?Refection in physics is the property of a propagated wave being thrown back from a surface such as a mirror.
Mirror is an example of an object that could be hit by an incumbent wave, however, most of the light waves that hit the mirror surface gets reflected back.
Therefore, most of the light waves that strike a clear pane of glass reflects.
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Using a pulley, you apply a force of 10 Newtons to life an object that weighs 100 Newtons. What is the mechanical advantage of that pulley?
Answer: 10
Explanation:
The mechanical advantage of that pulley is 10.
What is mechanical advantage?The force amplified by utilizing a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement. The law of the lever serves as a paradigm for this.
Mechanisms are machine parts made to control forces and motion in this way.
Given that: the weighs of the object: W = 100 Newton.
Applied force: F = 10 N.
For using a pulley, you have to apply a force of 10 Newtons to lift an object that weighs 100 Newtons.
Hence, the mechanical advantage of the pulley is
= Weighs of the object/applied force
= 100 Newton / 10 Newton.
= 10.
The mechanical advantage of it is 10.
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How can land that was formerly used as dumps, mines, or factory sites be.
rehabilitated?
Answer:
clear out the junk, and plant some stuff
Explanation:
clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.
which is true about the way air flows
A. high pressure to low pressure
B. low pressure to high pressure
C. cold air to hot air
D. hot air to cold air
Answer:
A High-to-Low
Explanation:
its like water running down a hill.
A bullet has a mass of 0.06 kg. Starting from rest, after the gun's trigger is pulled, a constant force acts on the bullet for the next 0.025 seconds until the bullet leaves the barrel of the gun with a speed of 992 m/s.
What is the change in momentum of the bullet?
The change in momentum of the bullet : 59.52 kg m/s
Further explanationGiven
m=0.06 kg
Δt=0.025 s
vo=0(from rest)
vt= 992 m/s
Required
The change in momentum
Solution
The change in momentum = ΔP
ΔP =m(vt-vo)
ΔP =0.06(992-0)
ΔP =59.52 kg m/s
5) Choose the best revision of the following statement: "All the isotopes of a particular element decay radioactively by
emitting electrons."
A. All the isotopes of a particular element are stable and do not decay.
B. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting various subatomic
particles and radiation
C. Some isotopes are stable and others are unstable. Unstable isotopes decay by emitting protons or
electrons.
D. The statement is correct as it is currently written.
Answer:
B. some isotopes are stable and others are unstable. unstable isotopes decay by emitting various subatomic particles and radiation.
Explanation:
test gave me the answer so yeah :/ XD
1. Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s,
Answer:
104653.13J
Explanation:
Given parameters:
Mass of roller coaster = 625kg
Speed = 18.3m/s
Unknown:
Kinetic energy = ?
Solution:
The kinetic energy is the energy due to the motion of a body.
Kinetic energy = [tex]\frac{1}{2}[/tex] x m x v²
m is the mass
v is the speed
Kinetic energy = [tex]\frac{1}{2}[/tex] x 625 x 18.3² = 104653.13J
Why do astronomers use spectroscopes to analyze light from distant objects?
how much KE does the car have if it weighs 450kg and moves at the speed of 23 m/s?
Answer:-The formula of to calculate KE = 1/2 m v^2
so we,
KE = 1/2 (450kg)(23m/s)^2
KE = 1/2 ×238050
KE = 119025
Explanation: In Physics Formulas mean everything.
Which of these is another name for Newton's
first law?
A. the law of action-reaction
B. the law of force and acceleration
C. the law of gravity
D. the law of inertia
a string attached to a 60.0 Hz vibr.ator creates a standing wave with 5 loops. What frequency would make 7 loops? (Unit = Hz)
Answer:
F=84.0 Hz
Explanation:
Using the equation f= n (v/2L), frequency equals number of loops times velocity over 2 times the length, in order to get 60.0 Hz of frequency from 5 loops, v/2L would have to equal 12. (12*5=60) v/2L is constant, so to find the frequency of 7 loops you would times 7 by 12 to get 84.0.
Hope this helped! :)
A 47.5-g ball moves at 30.0 m/s. If its speed is measured to an accuracy of 0.20%, what is the minimum uncertainty in its position
Answer:
The minimum uncertainty in its position is 1.85 x 10⁻³² m.
Explanation:
Given;
mass of the ball, m = 47.5 g = 0.0475 kg
speed of the ball, v = 30 m/s
measuring accuracy of the speed, = 0.2% = 0.002
The uncertainty in measurement of momentum;
ΔP = mΔv
ΔP = (0.0475)(30 x 0.002)
ΔP = 2.85 x 10⁻³ kgm/s
The uncertainty in position is calculated as;
[tex]\delta x \geq \frac{h}{4\pi (\delta P)}[/tex]
where;
h is Planck's constant
[tex]\delta x \geq \frac{6.626 \ \times \ 10^{-34}}{4\pi (2.85 \ \times \ 10^{-3})} \\\\\delta x \geq 1.85 \ \times \ 10^{-32} \ m[/tex]
Thus, the minimum uncertainty in its position is 1.85 x 10⁻³² m.
the combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
cm what is the focal length of the other
Answer: f = -12 cm
Explanation: Combined lenses is an array of simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.
When two lenses are in contact and are thin, focal lengths are related as:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
If there is a distance between the lenses, the focal length will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}[/tex]
Since the lenses in the question above are thin and in contact, the focal length of one of them will be:
[tex]\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}[/tex]
[tex]\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}[/tex]
[tex]\frac{1}{f_{2}} =\frac{-2}{24}[/tex]
[tex]f_{2}=[/tex] -12
The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.
A volleyball experiences 494 Ns of impulse over a time period of 7 seconds. What was the magnitude of the force that acted on the volleyball during this time period?
Answer:
70.6N
Explanation:
Given parameters:
Impulse = 494Ns
Time = 7s
Unknown:
Force applied = ?
Solution:
To solve this problem, we use the formula of impulse;
Impulse = Force x time
Now insert the parameters and solve;
494 = Force x 7
Force = [tex]\frac{494}{7}[/tex]
Force = 70.6N
A person lifts a heavy load to a vertical height of 2.0 m in 3 seconds. If he/she had done this more slowly in 6 seconds, the
work on the load would have been:
Four times as great
half as great
the same
twice as great
Answer:
If the heavy load had been lifted more slowly, the work done on the load would have been the same.
Explanation:
Work done on an object is given as;
W = Fd
where;
F is the force applied on the object
d is the displacement of the object
for the given question, the applied force on the load = mg (mass of the load multiplied by acceleration due to gravity).
Also, the displacement of the object = vertical height the load was lifted.
W = mgh
The work done on the load is independent of time.
Thus, if the heavy load had been lifted more slowly, the work done on the load would have been the same.
A person lifting a heavy load to a vertical height of 2.0 m in 3 seconds does the same work as if he/she lifts it in 6 s.
A person lifts a heavy load to a vertical height of 2.0 m in 3 seconds.
We want to compare the work done with the one that he/she would have done if the process had taken 6 seconds.
What is work?In physics, work (W) is the energy transferred to or from an object via the application of force (F) along a displacement (s).
W = F × s
Given the displacement is the same (2.0 m) and the force needed is also the same (weight of the object), the work is the same for both processes.
A person lifting a heavy load to a vertical height of 2.0 m in 3 seconds does the same work as if he/she lifts it in 6 s.
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How long does it take for a bee traveling 11.34 m/s to fly 120 m?
What is the standard form for 2 × 10−3 ?
Answer:
17
Explanation:
2 x 10 = 20
20-3 = 17
A 1.3-kg model airplane flies in a circular path on the end of a 23-m line. The plane makes
4.3 revolutions each minute.
a. What is the period of the motion?
b. What is the speed of the plane?
c. What is the acceleration of the model plane?
d. How much force must the line exert on the plane to keep it moving in the circular
motion?
(a) The plane makes 4.3 revolutions per minute, so it makes a single revolution in
(1 min) / (4.3 rev) ≈ 0.2326 min ≈ 13.95 s ≈ 14 s
(b) The plane completes 1 revolution in about 14 s, so that in this time it travels a distance equal to the circumference of the path:
(2π (23 m)) / (14 s) ≈ 10.3568 m/s ≈ 10 m/s
(c) The plane accelerates toward the center of the path with magnitude
a = (10 m/s)² / (23 m) ≈ 4.6636 m/s² ≈ 4.7 m/s²
(d) By Newton's second law, the tension in the line is
F = (1.3 kg) (4.7 m/s²) ≈ 6.0627 N ≈ 6.1 N
I need help with this please
Answer:
1. The respiratory system functions when our involuntary nervous system sends impulses to the muscles in the diaphragm; thereby, causing the lungs to expand and contract.
2. The respiratory system oxygenates the blood which is vital for bodily function as oxygenated blood is carried from your lungs to the left side of your heart, to be circulated throughout the body. Furthermore deoxygenated blood is carried back to the right side of your heart to get oxygenated once more.
3. The other body systems that are crucial for the lungs to function are the nervous system and the muscular system.
4. without the raspatory system the body wouldn't receive any oxygen and the brain would slowly die. therefore, without the brain the heart would stop functioning and atrophy etc.
Explanation:
Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through flourite. The wavelength of the light from the laser is 632.8 nm in air and the index of refraction of flourite is 1.434.
Answer and Explanation:
The computation is shown below:
As we know that
Frequency = Speed ÷ wavelength
= (3 × 10^8 )÷ (632.8 × 10^-9)
= 4.74 × 10^14 Hz
Speed in flourite is
= Vaccum speed ÷ refraction index
= 3 × 10^8 ÷ 1.434
= 2.092 × 10^8 m/s
wavelength is
= Speed in flourite ÷ frequency
= (3 × 10^8 × 632.8 × 10^-9) ÷ (1.434 × 3 × 10^8)
= 441.28nm
Question 3 (1 point)
here were 2cars racing a quarter mile. The green car had a mass of 1200kg and crossed the finish line with a velocity of 53m/s. The red car had
a mass of 1100Kg and crossed the finish line with a velocity of 55m/s.,Which car had the great momentum?
Black car
Blue car
Green car
Red car
Answer:
The green car had the greatest momentum
Explanation:
Momentum
Momentum can be defined as "mass in motion" and is calculated as the product of the mass of the object by its velocity.
Being v the magnitude of the velocity and m the mass of the object, the momentum is calculated with:
p = mv
The green car had a mass of m1=1200 kg and crossed the finish line at v1=53 m/s. Hence, its momentum was:
p1 = 1200 Kg * 53 m/s = 63600 Kg.m/s
The red car had a mass of m2=1100 kg and crossed the finish line at v2=55 m/s. Hence, its momentum was:
p2 = 1100 Kg * 55 m/s = 60500 Kg.m/s
Since p1 > p2, then the green car had the greatest momentum
fill in the blank:
the more people (greater mass) you load into a car, the ___ (more or less) it will accelerate with the same force applied by the engine.
the more people (greater mass) you load into a car, the more it will accelerate with the same force applied by the engine.
Find the applied voltage of a telephone circuit that draws 0.017A through a resistance Of 5,000 ohms
A dynamite blast blows a heavy rock straight up from the ground with a launch velocity of 160ft/sec. a) Write the height function.
Answer:
y = 160t - 16t²
Explanation:
Using y = ut -1/2gt² where y = height of heavy rock above the ground, u = initial launch velocity of rock = 160 ft/s, g = acceleration due to gravity = 32 ft/s² and t = time.
So, substituting the values of the variables into y, we have
y = (160 ft/s)t -1/2 × 32 ft/s² × t²
y = (160 ft/s)t - (16 ft/s²)t²
y = 160t - 16t²
So, the height function is y = 160t - 16t²
A block of mass m is hung from the ceiling by the system of massless springs consisting of two layers. The upper layer consists of 3 strings in paralle, and the lower layer consists of 2 strings in parallel. The horizontal bar between the two layers has negligible mass. The force constants of all springs are k. Calculate the period of the vertical oscillations of the block.
Answer:
T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex] T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀
Explanation:
When the block is oscillating it forms a simple harmonic motion, which in the case of a spring and a mass has an angular velocity
w = [tex]\sqrt{k/m}[/tex]
To apply this formula to our case, let's look for the equivalent constant of the springs.
Let's start with the springs in parallels.
* the three springs in the upper part, when stretched, lengthen the same distance, therefore the total force is
F_total = F₁ + F₂ + F₃
the springs fulfill Hooke's law and indicate that the spring constant is the same for all three,
F_total = - k x - k x - kx = -3k x
therefore the equivalent constant for the combination of the springs at the top is
k₁ = 3 k
* the two springs at the bottom
following the same reasoning the force at the bottom is
F_total2 = - 2 k x
the equivalent constant at the bottom is
k₂ = 2 k
now let's work the two springs are equivalent that are in series
the top spring is stretched by an amount x₁ and the bottom spring is stretched x₂
x₂ = x -x₁
x₂ + x₁ = x
if we consider that the springs have no masses we can use Hooke's law
[tex]-\frac{F_{1} }{k_{1} } - \frac{F_{2}}{k_{2} } = \frac{F}{k_{eq} }[/tex]
therefore the equivalent constant is the series combination is
[tex]\frac{1}{k_{eq} } = \frac{1}{k_{1} } + \frac{1}{k_{2} }[/tex]
we substitute the values
\frac{1}{k_{eq} } = \frac{1}{3k } + \frac{1}{2k }
\frac{1}{k_{eq} } = \frac{5}{6k} }
k_eq = [tex]\frac{6k}{5}[/tex]
therefore the angular velocity is
w = [tex]\sqrt{\frac{6k}{5m} }[/tex]
angular velocity, frequency, and period are related
w = 2π f = 2π / T
T = 2π / w
T = 2π [tex]\sqrt{\frac{5m}{6k} }[/tex]
T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex]
T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀
