A website developer wished to analyze the clicks per day on their newly updated website. Let the mean number of clicks per day be μ. If the website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average, what are the null and alternative hypotheses?

Answers

Answer 1

Answer:

Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 200 clicks a day

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 200 clicks a day

Step-by-step explanation:

We are given that a website developer wished to analyze the clicks per day on their newly updated website.

The website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average.

Let [tex]\mu[/tex] = mean number of clicks per day.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 200 clicks a day

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu\neq[/tex] 200 clicks a day

Here, the null hypothesis states that the mean number of clicks per day is 200 clicks a day.

On the other hand, the alternate hypothesis states that the mean number of clicks per day is different than 200 clicks a day.

Hence, this is the correct null and alternative hypotheses.

Answer 2

Answer: Null Hypothesis [tex]H_0:\mu=200[/tex]

Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]

Step-by-step explanation:

Let [tex]\mu[/tex] be the mean number of clicks per day.

Given, a website developer wished to analyze the clicks per day on their newly updated website.

The website developer wants to know if the number of clicks per day is different than 200 clicks a day, on average.

i.e. he wants to check either [tex]\mu=200\text{ or }\mu\neq 200[/tex]

Since a null hypothesis is a hypothesis believes that there is no difference between the two variables whereas an alternative hypothesis believes that there is a statistically significant difference between two variables.

So,  Null Hypothesis [tex]H_0:\mu=200[/tex]

Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]

Hence, the required null and alternative hypotheses.

Null Hypothesis [tex]H_0:\mu=200[/tex]

Alternate Hypothesis[tex]H_a:\mu\neq200[/tex]


Related Questions

The graph below represents the function f.
f(x)

if g is a quadratic function with a positive leading coefficient and a vertex at (0,3), which statement is true?

А.
The function fintersects the x-axis at two points, and the function g never intersects the x-axis.

B
The function fintersects the x-axis at two points, and the function g intersects the x-axis at only one point.

c.
Both of the functions fand g intersect the x-axis at only one point.

D
Both of the functions fand g intersect the x-axis at exactly two points.

Answers

Answer: А.

The function f intersects the x-axis at two points, and the function g never intersects the x-axis.

Step-by-step explanation:

In the graph we can see f(x), first let's do some analysis of the graph.

First, f(x) is a quadratic equation: f(x) = a*x^2 + b*x + c.

The arms of the graph go up, so the leading coefficient of f(x) is positive.

The vertex of f(x) is near (-0.5, -2)

The roots are at x = -2 and x = 1. (intersects the x-axis at two points)

Now, we know that:

g(x) has a positive leading coefficient, and a vertex at (0, 3)

As the leading coefficient is positive, the arms go up, and the minimum value will be the value at the vertex, so the minimum value of g(x) is 3, when x = 0.

As the minimum value of y is 3, we can see that the graph never goes to the negative y-axis, so it never intersects the x-axis.

so:

f(x) intersects the x-axis at two points

g(x) does not intersect the x-axis.

The correct option is A.

Answer:

The answer is A.) The function f  intersects the x-axis at two points, and the function g never intersects the x-axis.

Step-by-step explanation:

I took the test and got it right.

Find the area of the surface generated by revolving x=t + sqrt 2, y= (t^2)/2 + sqrt 2t+1, -sqrt 2 <= t <= sqrt about the y axis

Answers

The area is given by the integral

[tex]\displaystyle A=2\pi\int_Cx(t)\,\mathrm ds[/tex]

where C is the curve and [tex]dS[/tex] is the line element,

[tex]\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt[/tex]

We have

[tex]x(t)=t+\sqrt 2\implies\dfrac{\mathrm dx}{\mathrm dt}=1[/tex]

[tex]y(t)=\dfrac{t^2}2+\sqrt 2\,t+1\implies\dfrac{\mathrm dy}{\mathrm dt}=t+\sqrt 2[/tex]

[tex]\implies\mathrm ds=\sqrt{1^2+(t+\sqrt2)^2}\,\mathrm dt=\sqrt{t^2+2\sqrt2\,t+3}\,\mathrm dt[/tex]

So the area is

[tex]\displaystyle A=2\pi\int_{-\sqrt2}^{\sqrt2}(t+\sqrt 2)\sqrt{t^2+2\sqrt 2\,t+3}\,\mathrm dt[/tex]

Substitute [tex]u=t^2+2\sqrt2\,t+3[/tex] and [tex]\mathrm du=(2t+2\sqrt 2)\,\mathrm dt[/tex]:

[tex]\displaystyle A=\pi\int_1^9\sqrt u\,\mathrm du=\frac{2\pi}3u^{3/2}\bigg|_1^9=\frac{52\pi}3[/tex]

h(x) = -x² + 3x + 10

Answers

Answer:

x = 5 or x = -2 or 3 - 2 x (derivative)

Step-by-step explanation:

Solve for x over the real numbers:

-x^2 + 3 x + 10 = 0

Multiply both sides by -1:

x^2 - 3 x - 10 = 0

x = (3 ± sqrt((-3)^2 - 4 (-10)))/2 = (3 ± sqrt(9 + 40))/2 = (3 ± sqrt(49))/2:

x = (3 + sqrt(49))/2 or x = (3 - sqrt(49))/2

sqrt(49) = sqrt(7^2) = 7:

x = (3 + 7)/2 or x = (3 - 7)/2

(3 + 7)/2 = 10/2 = 5:

x = 5 or x = (3 - 7)/2

(3 - 7)/2 = -4/2 = -2:

Answer: x = 5 or x = -2

____________________________________

Find the derivative of the following via implicit differentiation:

d/dx(H(x)) = d/dx(10 + 3 x - x^2)

Using the chain rule, d/dx(H(x)) = ( dH(u))/( du) ( du)/( dx), where u = x and d/( du)(H(u)) = H'(u):

(d/dx(x)) H'(x) = d/dx(10 + 3 x - x^2)

The derivative of x is 1:

1 H'(x) = d/dx(10 + 3 x - x^2)

Differentiate the sum term by term and factor out constants:

H'(x) = d/dx(10) + 3 (d/dx(x)) - d/dx(x^2)

The derivative of 10 is zero:

H'(x) = 3 (d/dx(x)) - d/dx(x^2) + 0

Simplify the expression:

H'(x) = 3 (d/dx(x)) - d/dx(x^2)

The derivative of x is 1:

H'(x) = -(d/dx(x^2)) + 1 3

Use the power rule, d/dx(x^n) = n x^(n - 1), where n = 2.

d/dx(x^2) = 2 x:

H'(x) = 3 - 2 x

Simplify the expression:

Answer:  = 3 - 2 x

Consider the polynomial 2x5 + 4x3 - 3x8


Part A The polynomial in standard form is:



Part B: The degree of the polynomial is:



Part C: The number of terms in the polynomial is:



Part D: The leading term of the polynomials:



Part E: The leading coefficient of the polynomial is:

Answers

Answer:

Step-by-step explanation:

Considering the polynomial 2x⁵ + 4x³ - 3x⁸. The polynomial is not yet in standard form. For a polynomial to be in standard form, the power of the variables must decrease as we progress to the right of the expression.

A) The polynomial in standard form is therefore   - 3x⁸ + 2x⁵ + 4x³. We can see that the power are reducing as we move through each terms i.e from 8 to 5 then to 3.

B) The degree of a polynomial is the maximum degree among all the terms of the polynomial. The term that has the maximum degree is -3x⁸. Hence, the degree of the polynomial is 8

C) There are only 3 terms in the polynomial given. The terms are separated by mathematical signs. The terms if the polynomial are 2x⁵,  4x³ and - 3x⁸.

D) The leading term of the polynomial is the term that comes first after rewriting the polynomial in standard format. Given the standard from of the polynomial given as  -3x⁸ + 2x⁵ + 4x³, the leading term will be  - 3x⁸

E) Given the leading term to be  - 3x⁸, the leading coefficient of the polynomial will be the coefficient of the leading term. The coefficient of -3x⁸ is -3

In the graph above, which of the following would most likely cause the line to shift from D1 to D2?

A - An increase in consumer expectations

B - An increase in price

C - A decrease in consumer expectations

D - A decrease in price

Answers

Answer:

A - An increase in consumer expectations

Step-by-step explanation:

Both the quantity and price increased, so the store most likely stocked more items and began charging more as a result of high demand.

Answer: A

Step-by-step explanation: i took the test

In a recent year, a sample of grade 8 Washington State public school students taking a mathematics assessment test had a mean score of 281 with a standard deviation of 34.4. Possible test scores could range from 0 to 500. Assume that the scores are normally distributed. Question 9 (2.5 points) If 2000 students are randomly selected, how many would you expect to have a score between 250 and 305?

Answers

Answer:

The  number is  [tex]N =1147[/tex] students

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 281[/tex]

     The standard deviation is  [tex]\sigma = 34.4[/tex]

    The sample size is  n = 2000

percentage of the would you expect to have a score between 250 and 305 is mathematically represented as

      [tex]P(250 < X < 305 ) = P(\frac{ 250 - 281}{34.4 } < \frac{X - \mu }{\sigma } < \frac{ 305 - 281}{34.4 } )[/tex]

Generally  

             [tex]\frac{X - \mu }{\sigma } = Z (Standardized \ value \ of \ X )[/tex]

So  

         [tex]P(250 < X < 305 ) = P(-0.9012< Z<0.698 )[/tex]

       [tex]P(250 < X < 305 ) = P(z_2 < 0.698 ) - P(z_1 < -0.9012)[/tex]

From the z table  the value of  [tex]P( z_2 < 0.698) = 0.75741[/tex]

                                         and  [tex]P(z_1 < -0.9012) = 0.18374[/tex]

     [tex]P(250 < X < 305 ) = 0.75741 - 0.18374[/tex]

      [tex]P(250 < X < 305 ) = 0.57[/tex]

The  percentage is  [tex]P(250 < X < 305 ) = 57\%[/tex]

The  number of students that will get this score is

           [tex]N = 2000 * 0.57[/tex]

           [tex]N =1147[/tex]

Randy is walking home from school. According to the diagram above, what is his total distance from school to home? Show your work and include units. If he had a jet pack, would you use distance or displacement? Why?

Answers

Answer:

if he needs to walk, we can see that between the street and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.

Now he has a jet-pack, he can ignore the buildings and just travel in the shorter path, so we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.

One of the cathetus is the vertical distance, in this case, is 1km, and the other one is the horizontal distance, also 1km.

So the actual distance is given by the Pythagorean's theorem:

A^2 + B^2 = H^2

Where A and B are the cathetus, and H is the hypotenuse, then:

H^2 = 1km^2 + 1km^2

H = (√2)km = 1.41km.

Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, so in this case the distance and the displacement would be the same.

Distance: "how much ground an object has covered"

Displacement: "Difference between the final position and the initial position"

When he walks, the distance is 2km, but the displacement is 1.41km

When he uses the jet-pack, both the distance and the displacement are 1.41km

Answer and Step-by-step explanation:

The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km.  The result of this is a total of 4¨*0.5 km = 2 km.  The second thing is that he must walk 2 kilometers.  On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings.  This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home.  As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km.  The result is that these catheti have a length of 2*0.5 km = 1 km.  The other is the distance of the horizontal line, which is 1 km.  The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2.  Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2.  As well, H = (√2)km = 1.41 km.  Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow.  For this specific situation, the displacement, and the distance would be the exact same.  The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered.  Also, when he walks, the distance is 2 km and the displacement is 1.41 km.  Also, when he utilizes the jet pack, the distance is equal to the displacement.  Both of these are 1.41 km.

Find the value of the test statistic to test for a difference in the areas. Round your answer to two decimal places, if necessary.

Answers

Answer:

hello your question has some missing parts attached below is a picture of the complete question

Answer : 3.59

Step-by-step explanation:

Calculating the standard deviation, mean and standard error of the hourly wages

Area 1 : mean = 12.75 , std = 4.9497 , std error = 1.75

Area 2 : mean = 18.25, std = 4.3671,  std error = 1.54399

Area 3 : mean = 16.25, std = 2.8660, std error = 1.01330

mean = sum of terms / number of terms

std = [tex]\sqrt{}[/tex] (X − μ)2 / n

std error = std / [tex]\sqrt{n}[/tex]

The value of the test statistic to test for a difference in the areas is

3.59 ( using anova table attached below )

Please answer this correctly without making mistakes

Answers

Answer:

151 9/19

Step-by-step explanation:

Step-by-step explanation:

Option A is the correct answer because it is equal to 151.47

Please help. I’ll mark you as brainliest if correct

Answers

Answer:

32  20  17  -57  13

-24  15  -31  31  -28

27  10  -7  18  22

Step-by-step explanation:

Matrices and determinants What is 4c?

Answers

Answer:

Answer is D.

Step-by-step explanation:

do 4 times every value in the ( )

Answer:

[tex]\boxed{\sf D}[/tex]

Step-by-step explanation:

What is f ( 1/3)? When the function is f(x) =-3x+7

Answers

Answer:

f(1/3) = 6

Step-by-step explanation:

f(x) =-3x+7

Let x = 1/3

f(1/3) =-3*1/3+7

        = -1 +7

       = 6

Answer:

f(1/3) = 6

Step-by-step explanation:

The function is:

● f(x) = -3x+7

Replace x by 1/3 to khow the value of f(1/3)

● f(1/3) = -3×(1/3) +7 = -1 +7 = 6

Can someone explain and tell me how to go about solving this? Will mark brainliest

Answers

Answer:

58 cm

Step-by-step explanation:

Assuming that the squares’s sides are whole numbers, we can find the size of the squares by looking at numbers squared.  We find three that equal 153.

10²=10x10=100

7²=7x7=49

2²=2x2=4

100+49+4=153

Now we look at how they are put together to find the perimeter.

The 2x2 has 3 exposed sides totaling 6.

The 7x7 has a top and bottom of 7, and part of a third side of 7-2=5. 7+7+5=19

The 10x10 has 3 exposed sides of 10, and part of a third side of 10-7=3. 10+10+10+3=33

TOTAL Perimeter = 6+19+33=58 cm

If the length of the legs of a right triangle are 13 and 13,what is the length of the hypotenuse? Round your answer to the nearest tenth,if necessary.

Answers

Answer:

a² + b² = c²

13² + 13² = c²

169 + 169 = c²

338 = c²

c = √338 or 18.385 or 13√2

Answer:

18.4

Step-by-step explanation:

13² + 13² = x²

169 + 169 = x²

338 = x²

x = 18.38477....

What is the name of a geometric figure that looks an orange


A. Cube

B. Sphere

C. Cylinder

D. Cone

Answers

Answer:

b . sphere

Step-by-step explanation:

help help help help help help

Answers

Answer:

75 yards long and 90 yards wide.

Step-by-step explanation:

Let's first find the perimeter of the main rectangle:

100x2 + 65x2 =

330

_________________________________________

Next we need to find two numbers that match:

75 and 90

75x2 + 90x2 =

330

_________________________________________

75x90 is 6750 (More Area)

100x60 is 6500 (Less Area)

5* (?)-8= 77
Please help me!!!

Answers

Answer:

work is shown and pictured

List three methods of assigning probabilities. (Select all that apply.)

a. histogram.
b. intuition .
c. guessing .
d. equally likely outcomes .
e. relative frequency.
f. cumulative frequency.

Answers

Answer:

a,b and d

Step-by-step explanation:

●You can assign a probality based on your judgement and intuition.

●You can also assigni it based on the data of an histogram, in wich you see the frequency of the event you are interested in.

● Then there is the classical method based on mathematical calculations of equaly likely outcomes.

The three methods of assigning probabilities are:

b. intuition

e. relative frequency

d. equally likely outcomes

What are probabilities?

Probabilities may occasionally be determined by a person's subjective opinion or personal conviction. This approach depends on the individual's perception of an event's probability or intuition. It is crucial to remember that probabilities based on intuition may not always be precise or trustworthy.

With this approach, probabilities are calculated based on the relative frequencies of historical events that have been observed. Probabilities can be calculated based on the relative frequency of different outcomes by gathering data and calculating their frequencies.

This approach makes the supposition that each potential result has an equal likelihood of happening.

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the length of a triangle is x and its width is 2x. what is the area if the length and width are each increased by 1?
A. 2x^2+ 3x+ 1
B. 2x^2+ 1
C. 2x^2+ 2x+ 1
D. 2x^2+ 3x+ 2

Answers

The answer to the question is B.

Answer:

Hey there!

(2x+1)(x+1)

2x^2+1x+2x+1

2x^2+3x+1

The answer would be A.

Let me know if this helps :)

what is empowerment and radication please that is not from google

Answers

Answer:

In MATH:

Empowerment - Gaining the skills required in language and practices to fully understand math.

Radication - The process of extracting a number's root.

In ENGLISH:

Empowerment - The process of gaining more power over anything, including yourself, others, society, government, and corporations.

Ex - In the spirit of empowerment, the company has implemented a new system that asks employees to nominate one another for bonuses.

Radication - The process of establishing, fixing, or creating.

Ex - The high prestige of the premier is radicated in the hearts of the people.

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you!

Answers

Answer:

More number of words that can be made: [tex]\bold{2^n}[/tex]

Please refer to below proof.

Step-by-step explanation:

Given that:

The number of binary code words that can be made:

[tex]B(n) =2^n[/tex]

where n is the length of binary numbers.

Binary numbers means 2 possibilities either 0 or 1.

Here, suppose if we have 5 as the length of binary number.

And there are 2 possibilities for each digit.

So, total number of possibilities will be [tex]2\times 2\times 2\times 2\times 2 = 2^5[/tex]

If the length of binary number is 2.

The total words possible are [tex]2^2[/tex].

These numbers are:

{00, 01, 10, 11}

If the length of binary number is 3. (increasing the 'n' by 1)

The total words possible are [tex]2^3[/tex].

These words are:

{000, 001, 010, 100, 011, 101, 110, 111}

So, number of More binary words = 8 - 4 = 4 or [tex]2^2[/tex] or [tex]2^n[/tex].

So, the answer is [tex]2^n[/tex].

Let us try to prove in generic terms:

[tex]B(n) = 2^n[/tex]

Increasing the n by 1:

[tex]B(n+1) = 2^{n+1}[/tex]

Number of more words made by increasing n by 1:

[tex]B(n+1) -B(n)= 2^{n+1} -2^n\\\Rightarrow 2\times 2^{n} -2^n\\\Rightarrow 2^n(2-1)\\\Rightarrow \bold{2^n}[/tex]

Hence, proved that:

More number of words that can be made: [tex]\bold{2^n}[/tex]

find the area of this figure to the nearest hundredth. Use 3.14 to approximate pi.

Answers

Answer:

86.28 ft²

Step-by-step explanation:

The figure given consists of a rectangle and a semicircle.

The area of the figure = area of rectangle + area of semicircle

Area of rectangle = [tex] l*w [/tex]

Where,

l = 10 ft

w = 8 ft

[tex] area = l*w = 10*8 = 80 ft^2 [/tex]

Area of semicircle:

Area of semicircle = ½ of area of a circle = ½(πr²)

Where,

π = 3.14

r = ½ of 8 = 4 ft

Area of semi-circle = ½(3.14*4) = 6.28 ft²

Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)

Answer:

the area of the figrue is 105.12

Step-by-step explanation:

area of rectangle A= l · w10 x 8= 80area of simi-circle= 1/2(3.14 x r²)1/2 x 3.14 x 4²=25.1280+25.12=105.12 (nearest Hundredth)

Nine less than the quotient of
twice a number and four.

Answers

Answer:

-1

Step-by-step explanation:

Twice a number of 4 equals 8

4×2=8

less than 9 of the quotient (answer) of twice a number of 4, is -1

8-9= -1

The required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.

An expression Nine less than the quotient of twice a number and four. is to be determined.

What is simplification?

The process in mathematics to operate and interpret the function to make the function simple or more understandableis called simplify and the process is called simplification.

The quotient is the result when one value gets divided by some other value.

Using simple arithmetic,
Let the number be x,
A number y is equal to nine less than the quotient of twice of x and four. So,
y = quotient of 2x and four - 9
y = 2x/4 - 9

Thus, the required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.


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a vegetable garden and he's around the path of seemed like a square that together are 10 ft wide. The path is 2 feet wide. Find the total area of the vegetable garden and path​

Answers

Answer:

Garden: 36 square feet

Path: 64 square feet

Step-by-step explanation:

Let's first find the total area. The total area will be 100 square feet since the side length is 10. Since the path is 2 feet wide and on all sides, that means that the inside square will have a side length of 6. That means that the vegetable garden is 36 square feet. The path will be 100 - (the garden), and the garden is 36 square feet, which means the outer path will be 64.

You missed your payment due date and now have $300 on your card that has a 24% APR. You are able to pay $100 in one month and then every month after that. How many months will it take you to pay this credit card off?

Answers

It would take you 4 months to pay the credit card off.

Help please, I don't understand :(

Answers

Answer:

38 = JKL

Step-by-step explanation:

JKM = JKL + LKN + NKM

Substituting what we know

104 = JKL + LKN +33

KN  bisects LKM so NKM =  LKN

33 =  LKN

104 = JKL + 33 +33

104 = JKL + 33 +33

Combine like terms

104 = JKL +66

104 - 66 = JKL

38 = JKL

Answer:  ∡JKL=38°

Step-by-step explanation:

KN bidects ∡LKM => ∠KLN=∡NKM=33°

=> ∡LKM=∠KLN+∡NKM=33°+33°=66°

=>∡JKL= ∡JKM-∡LKM= 104°-66°=38°

∡JKL=38°

ASAP!!!!!!!asap!!!!!!!!!!!! asap asap asap

Answers

Answer:

7). x = 3.2, AC = 42.8

8). a = 6, YZ = 38

Step-by-step explanation:

It is given in the question that a point B is between A and C of the line segment AC.

⇒ AB + BC = AC

By substituting the values of segments,

5x + (9x - 2) = (11x + 7.6)

14x - 2 = 11x + 7.6

14x - 11x = 7.6 + 2

3x = 9.6

x = 3.2

Therefore, AC = 11x + 7.6

                        = 11(3.2) + 7.6

                        = 35.2 + 7.6

                        = 42.8

Question (8).

If Y is a point between X and Z,

⇒ XY + YZ = XZ

By substituting the measures of these segments given in the question,

(3a - 4) + (6a + 2) = (5a + 22)

9a - 2 = 5a + 22

9a - 5a = 22 + 2

4a = 24

a = 6

Since, length of segment YZ = 6a + 2

                                                = 6(6) + 2

                                                = 38

6 people consists of 3 married couples. Each couple wants to sit with older partner on the left.

Required:
a. How many ways can they be seated together in the row?
b. Suppose one of the six is a doctor who must sit on the aisle in case she is paged. How many ways can the people be seated together in the row with the doctor in an aisle seat?
c. Suppose the six people consist of three married couples and each couple wants to sit together with the husband on the left. How many ways can the six be seated together in the row?

Answers

a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,

6! = 6 [tex]*[/tex] 5

= 30 [tex]*[/tex] 4

= 360 [tex]*[/tex] 2 = 720 possible ways to order 6 people in a row

b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.

5! = 5 [tex]*[/tex] 4

= 20 [tex]*[/tex] 3

= 120 [tex]*[/tex] 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.

In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )

c. With each husband on the left, there are 3 people left, all women, that we have to consider here.

3!  = 3 [tex]*[/tex] 2 6 ways to arrange 3 couples in a row, the husband always to the left

LOOK AT CAPTURE AND ASNWER 100 POINTS

Answers

Answer:

132 degrees

Step-by-step explanation:

Looking at angle A and angle B, they are alternate interior angles. That means they are congruent to one another. Knowing that, we can set up an equation A=B

We can now fill A and B with their given equations

5x-18=3x+42

Now we solve

2x=60

x=30

Now that we know x is 30, we can replace it in the equation for A

5x-18

5(30)-18

150-18

132 degrees

Answer:

132

Step-by-step explanation:

ANGLE A = ANGLE B

(INTERIOR ALTERNATE ANGLES)

5x - 18 = 3x  + 42

2x = 60

x = 30

angle a = 150 - 18

= 132

Which relationships have the same constant of proportionality between y and x as the equation 3y=2x? SELECT 3 ANSWERS

Answers

*Correct Question:

Which relationships have the same constant of proportionality between y and x as the equation 3y=27x?

Answer:

A, B, C

Step-by-step explanation:

Given that [tex] 3y = 27x [/tex] , we can simplify to get a proportionality statement that exists between X and y. Thus

[tex] 3y = 27x [/tex]

Divide both sides by 3

[tex] \frac{3y}{3} = \frac{27x}{3} [/tex]

[tex] y = 9x [/tex]

Thus, we can say, y would always be 9 times the quantity of x.

From the options given, examine which options have this proportionality statement as well.

Option A, y = 9x is same as the statement.

Option B, 2y = 18x, conforms to the same statement. If we simply further, we would have y = 9x

Option C, the graph shows that when x = 1, y = 9. This also confirms to the same constant of proportionality in the given equation.

Option D and E do not have same constant of proportionality.

The right options are A, B, and C.

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