Answer:
1. 38.3 x 10^5
2. 6.67 x 10^9
3. 4.48 x 10^4
Step-by-step explanation:
4.2 X 10 ^6 - 1.2 X 10^5 - 2.5 x 10^5
For the above question, we need to make the exponents equal
=> 42 x 10^5 - 1.2 x 10^5 - 2.5 x 10^5
SInce, all the exponents are equal, we can now add and subtract the normally.
=> (42 - 1.2 -2.5) x 10^5
=> (42 - 3.7) x 10^5
=> 38.3 x 10^5
So, the answer to the 1st question is 38.3 x 10^5
Next question:
=> 3.3 x 10^9 + 2.6 x 10^9 +7.7 x 10^8
=> we need to make the exponents equal
=> 3.3 x 10^9 + 2.6 x 10^9 + .77 x 10^9
=> All the exponents are equal, we can now add and subtract the normally.
=> (3.3 + 2.6 + .77) x 10^9
=> 6.67 x 10^9
=> So the answer to the 2nd question is 6.67 x 10^9
Next question,
=> 8 X 10^4 - 3.4 x 10^4 - 1.2 x 10^3
=> we need to make the exponents equal
=> 8 x 10^4 - 3.4 x 10^4 - .12 x 10^4
=> All the exponents are equal, we can now add and subtract the normally.
=> (8 - 3.4 - .12) x 10^4
=> 4.48 x 10^4
=> So the answer to the 3rd question is 4.48 x 10^4
The solutions to the expressions are:
[tex]4.2 \times 10^6 - 1.2 \times 10^5 - 2.5 \times 10^5[/tex]=[tex]38.3\times 10^5[/tex]
[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 7.7 \times 10^8[/tex] = [tex]6.67\times 10^9[/tex]
[tex]8.0 \times 10^4 -3.4 \times 10^4 - 1.2 \times 10^3[/tex] = [tex]4.48 \times 10^4[/tex]
[tex]4.2 \times 10^6 - 1.2 \times 10^5 - 2.5 \times 10^5[/tex]
Combine like terms:
[tex]4.2 \times 10^6 - (1.2+2.5) \times 10^5[/tex]
[tex]4.2 \times 10^6 - 3.7 \times 10^5[/tex]
[tex]42 \times 10^5 - 3.7 \times 10^5[/tex]
[tex](42-3.7)\times 10^5[/tex]
[tex]38.3\times 10^5[/tex]
[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 7.7 \times 10^8[/tex]
Convert all terms with same power:
[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 0.77 \times 10^9[/tex]
[tex](3.3+2.6+0.77) \times 10^9[/tex]
[tex]6.67\times 10^9[/tex]
[tex]8.0 \times 10^4 -3.4 \times 10^4 - 1.2 \times 10^3[/tex]
[tex]8.0 \times 10^4 - 3.4 \times 10^4 - 0.12 \times 10^4[/tex]
[tex](8.0-3.4-0.12) \times 10^4[/tex]
[tex]4.48 \times 10^4[/tex]
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Simplify:
[tex] \frac{ {a}^{5} {b}^{8} }{ {a}^{4} {b}^{10} } [/tex]
HELP! answer if you can !
Answer:
a^5b^8/a^4b^10
= a^5-4 b^8-10
= a^1 b^-2
= a/b^2
I hope this helps
if u have question let me know in comments ^_^
The equation of line WX is 2x + y = −5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)?
Answer:
Step-by-step explanation:
y = -2x - 5
perp. slope: 1/2
y + 2 = 1/2(x + 1)
y + 4/2 = 1/2x + 1/2
y = 1/2x - 3/2
The mean of 5 numbers is 11. The numbers are in the ratio 1 : 1 : 2 : 3 : 4. Find the numbers.
Answer:
5, 5, 10, 15, 20
Step-by-step explanation:
Since the mean of the 5 numbers is 11, we know that the sum of the 5 numbers is 5 * 11 = 55. If we call the numbers x, x, 2x, 3x and 4x respectively based off of the ratio, we can write:
x + x + 2x + 3x + 4x = 55
11x = 55
x = 5 so 2x = 2 * 5 = 10, 3x = 3 * 5 = 15 and 4x = 4 * 5 = 20, therefore, the numbers are 5, 5, 10, 15, and 20.
Given that
Numbers are in ratio 1:1:2:3:4 Mean of these numbers is 11 .To Find.
We have to find these five numbers.Solution .
→ Let's assume these numbers as
→ x , x , 2x , 3x and 4x
→ Mean of any observations is = Sum of observations/ Number of observations.
→ Sum of observations = x+x+2x+3x+4x
→ 11x
→ Number of observations = 5
→ Mean = 11
→ 11 = 11x/5
→ 11 (5) = 11x
→ 11(5)/11 = x
→ value of x = 5
Putting the value of x for finding all numbers .
→ 1st number = x → 5
→ 2nd number = x → 5
→ 3rd number = 2x → 10
→ 4th number = 3x → 15
→ 5th number = 4x → 20
A truck costs $8,000 with a residual value of $1,000. It has an estimated useful life of 7 years. If the truck was bought on July 9 what would be the book value at the end of year 1?
Answer:
$7520.55
Step-by-step explanation:
Cost of truck = $8000
Residual value = $1000
Estimated useful life = 7 years
Depreciation = (cost of asset - salvage value) / useful life
Depreciation = (8000 - 1000) / 7
Depreciation = 7000 / 7
Depreciation = $1000
Truck was purchased on July 9, Therefore, Depreciation by the end of year one will be;
Number of days between July 9 and year end = 175 days
Daily Depreciation = $1000 / 365 = $2.739
Total Depreciation by year end = (daily Depreciation * 175 days) = $479.45.
Book value at the end of year 1 = (8000 - 479.45)
= $7520.55
Answer:
The answer is "$7,500".
Step-by-step explanation:
Formula:
In the month of July-December the depreciation:
[tex]\frac{\text{Cost-Residual}}{\text{Useful life}}\times \frac{6}{12} \\[/tex]
Cost-Residual= costs -residual value
Given:
Cost-Residual = $8, 000 - $ 1,00
= $7,000
Useful life= 7 years
Put the value in the above-given formula:
[tex]=\frac{7 000}{7}\times \frac{6}{12}\\\\= 1 000\times \frac{1}{2}\\\\= 5 00\\[/tex]
Therefore, the book value on point at the end of one year is:
= $8,000 -$ 500
= $7,500
Desmond is 2 inches taller than Niki. If we let w represent Nikis height in inches, write an algebraic expression for Desmonds height. Enter your answer as an expression. Example: 3x^2+1
Answer:
w + 2
Step-by-step explanation:
Niki's height = w in
Desmond height = w + 2
Answer:
w+2
Step-by-step explanation:
Since Desmonds is 2 inches taller than Niki, w+2 would make the most sense.
Help me with this please
Answer:
Hey there!
Point n is either -3+5 or -3-5.
Thus, the two possible values are 2 or -8.
Let me know if this helps :)
BRAINLIEST!!!
What are the coordinates of P?
Answer:
Step-by-step explanation:
A kite is symmetrical about its vertical axis, so
if it is a kite, P is the reflection of (b,0), so its coordinates are
(-b,0) by reflection about the y-axis.
If a = 6, which of the following is equal to a^-2?
-36
-12
1/6^2
6^2
Answer:
[tex]\frac{1}{6^{2} }[/tex]
Step-by-step explanation:
Using the rule of exponents
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]
Given a = 6, then
[tex]6^{-2}[/tex] = [tex]\frac{1}{6^{2} }[/tex]
The 3rd option is correct i.e. if a = 6, then by the property of exponentiation, we can conclude that a⁻² = 1/6².
What is exponentiation?Exponentiation is a mathematical operation that involves two numbers, the base b, and the exponent or power n, and is pronounced as "b raised to the power of n." It is written as bⁿ and is pronounced as "b raised to the power of n."
When n is a positive integer, bⁿ = b × b × b ×...× b (n times)
and b⁻ⁿ = 1/bⁿ ...(1)
When n = 0, bⁿ = 1
How to solve this problem?Given that a = 6 and n = 2.
Using (1), we get
a⁻² = 6⁻² = 1/6²
Therefore, the 3rd option is correct i.e. if a = 6, then by the property of exponentiation, we can conclude that a⁻² = 1/6².
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Please Help! Three times the quantity of a number increased by 7 is equal to the same number decreased by 15
The equation is written as 3x + 7 = x - 15. And the solution of the equation will be negative 11.
What is the solution to the equation?The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.
Multiple times the amount of a number expanded by 7 is equivalent to a similar number diminished by 15.
Let the number be 'x'.
The three times the number plus 7. Then the expression is given as,
⇒ 3x + 7
The number 'x' is decreased by 15. Then the expression is given as,
⇒ x - 15
Both expressions are equal to each other. Then we have
3x + 7 = x - 15
3x - x = - 15 - 7
2x = - 22
x = - 11
The equation is written as 3x + 7 = x - 15. And the solution of the equation will be negative 11.
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Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and angle K L J is 38 degrees. Given △JKL, sin(38°) equals cos(38°). cos(52°). tan(38°). tan(52°).
Answer:
[tex]\bold{sin(38^\circ)=cos(52^\circ)}[/tex]
Step-by-step explanation:
Given that [tex]\triangle KJL[/tex] is a right angled triangle.
[tex]\angle JKL = 52^\circ\\\angle KLJ = 38^\circ[/tex]
and
[tex]\angle KJL = 90^\circ[/tex]
Kindly refer to the attached image of [tex]\triangle KJL[/tex] in which all the given angles are shown.
To find:
sin(38°) = ?
a) cos(38°)
b) cos(52°)
c) tan(38°)
d) tan(52°)
Solution:
Let us use the trigonometric identities in the given [tex]\triangle KJL[/tex].
We have to find the value of sin(38°).
We know that sine trigonometric identity is given as:
[tex]sin\theta =\dfrac{Perpendicular}{Hypotenuse}[/tex]
[tex]sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}[/tex]....... (1)
Now, let us find out the values of trigonometric functions given in options one by one:
[tex]cos\theta =\dfrac{Base}{Hypotenuse}[/tex]
[tex]cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}[/tex]....... (2)
By (1) and (2):
sin(38°) [tex]\neq[/tex] cos(38°).
[tex]cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}[/tex] ...... (3)
Comparing equations (1) and (3):
we get the both are same.
[tex]\therefore \bold{sin(38^\circ)=cos(52^\circ)}[/tex]
Answer:
B in EDG
Step-by-step explanation:
1-Determine a solução dos sistemas abaixo pelo método de adição: a) {x + y = 5 {2x- y=9 b) {3x - y = 10 {x + y =18 Prfvr gente
a)
X + Y = 5
2X - Y = 9
X + 2X + Y - Y = 5 + 9
3X = 14
X = 14/3Para Y, basta substituir o valor de X em qualquer uma das 2 equacoes - arbitrariamente. Escolhendo a primeira:
X+ Y = 5
14/3 + Y = 5
Y = 5 - 14/3
Y = 1/3.........................
b)
3X - Y = 10
X + Y = 18
3X + X - Y + Y = 10 + 18
4X = 28
X = 7Para Y, basta substituir o valor de X em qualquer uma das 2 equacoes - arbitrariamente. Escolhendo a segunda:
X + Y = 18
7 + Y = 18
Y = 18 - 7
Y = 11solve for x 5(x+1)=4(x+8)
Answer:
x=27
Step-by-step explanation:
expanding the above expression we get
5x+5=4x+32
grouping numbers with coefficient of x at the left side and constant at the right side we get
5x-4x=32-5
x=27
The value of y varies directly with x, where LaTeX: y=50y = 50 when LaTeX: x=40x = 40. Find the value of x when y is 10.
Group of answer choices
LaTeX: x=8 x = 8 x = 8 x = 8 x = 8 x = 8 x = 8 x = 8
LaTeX: x=12.5 x = 12.5 x = 12.5 x = 12.5 x = 12.5 x = 12.5 x = 12.5 x = 12.5
LaTeX: x=1.25 x = 1.25 x = 1.25 x = 1.25 x = 1.25 x = 1.25 x = 1.25 x = 1.25
LaTeX: x=0
Answer:
x= 8
Step-by-step explanation:
The equation of direct variation is
y = kx
When y = 50 when x = 40
50 = k* 40
Divide each side by 40
50/40 = k
5/4 = k
The equation is
y = 5/4x
Let y = 10
10 = 5/4x
Multiply each side by 4/5
4/5 * 10 = 5/4 x * 4/5
8 = x
Find the vertex of f(x)= x^2+ 6x + 36
Pls help soon
Answer:
vertex(-3,27)
Step-by-step explanation:
f(x)= x^2+ 6x + 36 ( a=1,b=6,c=36)
V(h,k)
h=-b/2a=-6/2=-3
k=f(-3)=3²+6(-3)+36
f(-3)=9-18+36=27
vertex(-3,27)
-
What is the product?
(-3s +2)(4s-1)
Answer: -12s + -2
Step-by-step explanation: You need to combine the like terms so -3sx4s = -12s and 2+-1 = -2 so it’s -12s + -2 or -12s - 2
Answer:
-12s²+11s-2
Step-by-step explanation:
(-3s+2)(4s-1)
First you have to FOIL (First, inner, outter, last)
First: -3s × 4s
Inner: -3s × -1
Outter: 2 × 4s
Last: 2 × -1
Now you should have -12s² + 3s + 8s -2
----------------------
Next you combine your like terms
Finally you have your answer, -12s²+11s-2 .
solve for y: -2(5y-1)-y=-4(y-3)
Answer:
[tex]y = - \frac{10}{7} [/tex]Step-by-step explanation:
- 2(5y - 1) - y = - 4(y - 3)
Expand the terms in the bracket
That's
-10y + 2 - y = - 4y + 12
Group like terms
Send the constants to the right side of the equation and those with variables to the left side
That's
- 10y - y + 4y = 12 - 2
- 7y = 10
Divide both sides by - 7
We have the final answer as
[tex]y = - \frac{10}{7} [/tex]Hope this helps you
It is estimated that 52% of drivers text while driving . What is the probability the next driver texting while driving that a police officer pulls over is the fifth driver?
Answer:
0.0276
Step-by-step explanation:
The computation of the probability that the next driver is texting while driving is shown below:
= Fourth pull failure × fifth pull success
where,
Fourth pull failure is (1 - 0.52)^4
And, the fifth pull success is 0.52
Now placing these values to the above formula
So,
= (1 - 0.52)^4 × 0.52
= 0.0276
Hence, the probability is 0.0276
-8 + 4m = 2. What is m?
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
Let's solve your equation step-by-step.
[tex]-8 + 4m = 2[/tex]
Step 1: Simplify both sides of the equation.
[tex]4m - 8 = 2[/tex]
Step 2: Add 8 to both sides.
[tex]4m - 8 + 8 = 2 + 8 \\4m = 10[/tex]
Step 3: Divide both sides by 4.
[tex]\frac{4m}{4} = \frac{10}{4} \\m = \frac{5}{2}[/tex]
Answer : [tex]\boxed {m = \frac{5}{2} }[/tex]
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
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Have a great day/night!
❀*May*❀
(2x2 - 4x + 7) + (3x3 - 9x)
Without attempting to solve, how many solutions does this system of equations have? y=2x+1 −3y=6x+6 1. One Solution 2. No Solution 3. An infinite number of solutions 4. Cannot be determined without solving
Answer:
1. One Solution
Step-by-step explanation:
y=2x+1
−3y=6x+6
Divide the second equation by -3
−3y/-3=6x/-3+6/-3
y = -2x-2
The slopes are different so we know that the lines are not parallel
The will intersect at a point
There will be one solution
if the first step of the equation -x + 6 = 5 - 3x is "subtract 5" then what should the next step be
Answer:
The next step is add x to each side
Step-by-step explanation:
-x + 6 = 5 - 3x
Subtract 5 from each side
-x + 6-5 = 5-5 - 3x
-x+1 = -3x
Add x to each side
-x+1 = -3x+x
1 = -2x
Answer:
Step-by-step explanation:
all you need to do is solve for x right? so in that case when you subtract 5 from both sides you get -x+1=-3x
then you will add x on each side
you should now have 1=-2x
divide each side by -2 and then you will have
-1/2=x
Is MNO=PQR? If so, name the congruence postulate that applies.
Given:
ME=PQ
NO=QR
MO=PR
A. Congruent - ASA
B. Congruent - SSS
C. Congruent - SAS
D. Might not be congruent
Answer:
B. Congruent - SSS
Step-by-step explanation:
Since, corresponding sides of both the triangles are congruent. Hence, both the triangles are congruent by SSS Postulate.
ΔMNO ≅ ΔPQR due to Congruent-SSS
What are congruent triangles?Two triangles are said to be congruent if their corresponding sides and angles are equal.
Given:
In ΔMNO and ΔPQR
Side ME=Side PQ
Side NO=Side QR
Side MO=Side PR
MNO ≅PQR
Since, corresponding sides of both the triangles are congruent.
So, both the triangles are congruent by SSS Postulate.
Hence , ΔMNO ≅ ΔPQR
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Repost because someone answered without actually giving an answer. What is the mode of the data shown in the table? Scores: 5 12 13 18 Frequency: 3 2 5 4 A. 12 B. 51.5 C. 12.5 D. 13
Answer:
Option (D) : 13
Step-by-step explanation:
Mode is the observation which occurred the most number of time.
Therefore, mode = 13
A dealer bought 3 gross buttons at $.38 a dozen. He sold the buttons at 5 cents each. How much was his profit per gross?(12 dozen equals one gross)
Answer:
$2.64
Step-by-step explanation:
Selling them at 5 cents each ($0.05), he could sell 1 dozen buttons for
12 * $0.05 = $0.60
As he bought them at $0.38 per dozen, the profit per dozen would be
$0.60 - $0.38 = $0.22
As 12 dozen is 1 gross, the profit per gross would be
12 * $0.22 = $2.64
3 x 12 = 36
.5 x 36 = 18.0
36 divided by .38 is about 94.7
18 - 94.7 = -76.7
ANSWER:
about -76.7
(I may have done this wrong
Please answer this question now
Answer:
113 degrees
Step-by-step explanation:
Measure of arc ADCB = 58+108+60 = 226 degrees
Measure of angle B = 226/2 = 113 degrees
Answer:50
Step-by-step explanation:
Counting from 1 to 46, how many 4s will you encounter? 8 10 11 12 14
Answer:
11
Step-by-step explanation:
4=1
14=2
24=3
34=4
40=5
41=6
42=7
43=8
44=9
45=10
46=11
You will encounter 11 4s.
PLEASE HELP URGENT AND EXPLAIN FOR 25 POINTS MUST BE CORRECT Brielle bought an apartment building for $202,444. The value of the real estate appreciated at a constant rate per year. The table shows the value of the apartment building after the first and second years: Year 1 2 Value (in dollars) $212,566.20 $223,194.51 Which function best represents the value of the apartment building after t years? f(t) = 202,444(0.05)t f(t) = 202,444(1.05)t f(t) = 212,566.20(1.05)t f(t) = 212,566.20(0.05)t
Answer:
f(t) = 202,444(1.05)^t
Step-by-step explanation:
Simple Interest Rate Formula: A = P(1 + r)^t
A = final amount
P = principle amount
r = interest rate
t = time
Step 1: Find rate r
212,566.20 = 202,444(1 + r)¹
1.05 = (1 + r)¹
1.05 = 1 + r
r = 0.05
Step 2: Define variables
P = 202,444
r = 0.05
Step 3: Plug in variables into formula
A = 202,444(1 + 0.05)^t
A = 202,444(1.05)^t
Suppose y varies jointly as x & z. If y = -180 when z = 15and x = -3,then find y when x = 7 and z = -5. 1 point
Answer:
y = - 140
Step-by-step explanation:
The statement
y varies jointly as x & z is written as
y = kxzto find y when x = 7 and z = -5 we must first find the relationship between the variables
when y = - 180
z = 15
x = - 3
- 180 = k(15)(-3)
-180 = - 45k
Divide both sides by - 45
k = 4
The formula for the variation is
y = 4xzwhen
x = 7
z = -5
y = 4(7)(-5)
y = 4(-35)
y = - 140Hope this helps you
Work out the value of angle x
======================================================
Explanation:
The given exterior angle 97 is adjacent to the interior angle 180-97 = 83. This is the base angle of the isosceles triangle. The other base angle is directly above it. The base angles are always opposite the congruent sides.
The missing interior angle (adjacent to the blue angle x) is unknown, so we'll call it angle y. This angle adds to the other two base angles (83 each) to get a sum of 180. Adding any three interior angles of a triangle always gets you 180
y+83+83 = 180
y+166 = 180
y = 180-166
y = 14
Angle x and y are supplementary. They form a 180 degree angle
x+y = 180
x = 180-y
x = 180-14
x = 166
As you can see, the base angles combine to form the exterior angle we're after. This is because of the remote interior angle theorem.
Bart opens a bank account and deposits $10 each week. If he has $90 in his account, how many weeks has he been depositing money?
The number of weeks Bart has been depositing money is 9 weeks according to investment and time.
The number of weeks of money depositing will be given by the formula -
Number of weeks = total amount deposited each week/total number of weeks × 100
Keep the values in formula to find the number of weeks of money deposit
Number of weeks = 90/10
Perform division that will include cancelling zeroes
Number of weeks = 9
Hence, Bart deposited the money for 9 weeks.
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