After deduction of 4 paisa in a Rupee a sum of Rs 720 is left.What was it originally?​

Answers

Answer 1

Given:

After deduction of 4 paisa in a Rupee a sum of Rs 720 is left.

To find:

The original amount.

Solution:

We know that,

1 Rs. = 100 paisa

After deduction of 4 paisa in a Rupee, we get

[tex]100-4=96[/tex]

It means Rs. 720 is the 96% of the original amount.

Let x be the original amount.

[tex]720=\dfrac{96}{100}x[/tex]

[tex]72000=96x[/tex]

[tex]\dfrac{72000}{96}=x[/tex]

[tex]750=x[/tex]

Therefore, the original amount is Rs. 750.


Related Questions

Need help please....

Answers

Answer:

-14 x²

Step-by-step explanation:

10 x² - 24 x² = -14 x²

The answer is 14

if you multiply both P(x) and Q(x), the third part becomes 14x², so the coefficient of x² becomes 14.

Answered by GAUTHMATH

kxndjdkdkdkkdkskskdkdjdjdjskskskdjdjddjd​

Answers

Answer:

Not a functionFunctionFunctionNot a functionNot a function

Hope this helps!

Z varies directly as Square x and inversely as y. If z = 187 when x = 64 and y = 6, find z if and 9. (Round off your answer to the nearest hundredth.)

Answers

Answer:

Z = 50

Step-by-step explanation:

Given the following data;

Z = 187

x = 64

y = 6

Translating the word problem into an algebraic expression, we have;

Z = k√x/y

First of all, we would find the constant of proportionality, k;

187 = k√64/6

187 * 6 = k√64

1122 = 8k

k = 1122/8

k = 140.25

To find z, when x and y = 9

Z = 140.25√9/9

Z = (140.25 * 3)/9

Z = 420.75/9

Z = 46.75 ≈ 50

Note: The values in the latter part of the question isn't explicitly stated, so I assumed a value of 9 for both x and y.

Time Remaining 59 minutes 49 seconds00:59:49 PrintItem 1 Time Remaining 59 minutes 49 seconds00:59:49 At the end of Year 2, retained earnings for the Baker Company was $2,950. Revenue earned by the company in Year 2 was $3,200, expenses paid during the period were $1,700, and dividends paid during the period were $1,100. Based on this information alone, what was the amount of retained earnings at the beginning of Year 2?

Answers

Answer:

$2550

Step-by-step explanation:

Calculation to determine the amount of retained earnings at the beginning of Year 2

Using this formula

Beginning Retained Earnings + Revenue − Expenses − Dividends = Ending Retained Earnings

Let plug in the formula

Beginning Retained Earnings + $3,200 − $1,700 − $1,100 = $2950

Beginning Retained Earnings= $2,950-$400

Beginning Retained Earnings = $2,550

Therefore the amount of retained earnings at the beginning of Year 2 is $2550

Jose bought 217 shares of Darien Electric for $21.96 apiece. His broker charged him a commission of $106.12 for the
purchase. If the yearly dividend on Darien Electric is 77 cents per share, what is the annual yield on Jose's stock? Show
work.

Answers

Answer:

what is photosynthic ..

p.l.e.a.s.e join eti-fgdd-xjs

why do plant need it

I need help please and thank you.

Answers

Answer:

option a.

[tex] + - \frac{13}{5} [/tex]

Step-by-step explanation:

[tex]25x^2\: - \:169 = 0 [/tex]

[tex]25x^2 = 169[/tex]

[tex] {x}^{2} = \frac{169}{25} [/tex]

[tex]x = + - \sqrt{ \frac{169}{25} } [/tex]

[tex]x = + - \frac{13}{5} [/tex]

f(X) = 10x^3 find inverse

Answers

1000 is you answer
Or
10x10x10
Or
10/3

Answer: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Step-by-step explanation:

[tex]f(x)=10x^{3}\\y=10x^{3}[/tex]

switch the x and y:

[tex]x=10y^{3}[/tex]

Now solve for y:

[tex]x=10y^{3} \\\frac{x}{10} =y^{3} \\\sqrt[3]{\frac{x}{10} } =y\\[/tex]

Therefore, the inverse of that function is: [tex]y=\sqrt[3]{\frac{x}{10} }[/tex]

Choose the algebraic description that maps the image ABC onto A'B'C'.

Answers

(X,Y-4) this is the answer to the question since the y value of the translated image is moved down from the preimage

Find the length of CE

Answers

Answer:

C. 37.8 units

Step-by-step explanation:

ED = 17/ cos(38°) = 17 / 0.7880 = 21.6 units

DF = 17× tan (38°) = 17× 0.7813 = 13.3 units

CD = 10/13.3 × 21.6 = 16.2 units

so, the length of CE = 21.6+16.2 = 37.8 units

A car took 6 minutes to travel between two stations that are 3 miles apart find the average speed of the car in mph

Answers

Answer: 30 mph is the answer.

Step-by-step explanation:

s = 3 miles

t = 6 minutes

so,

60 minute = 1 hour

1 minute = 1/60 hour

6 minutes = 1/60 * 6 = 0.1 hour

so

average speed = s/t

= 3/0.1 = 30 mph

(c) Construct a 99% confidence interval for u if the sample
size, n, is 35.

Answers

Answer:

The confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

In this question:

[tex]M = 1.99\frac{\sigma}{\sqrt{35}}[/tex]

The lower end of the interval is the sample mean subtracted by M, while upper end of the interval is the sample mean added to M. Thus, the confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.


Compute the mean deviation of the following set of data; 9,6, 3, 9, 7, 2, 1, 5, 6, 8.

Answers

Answer:

5.6

Step-by-step explanation:

( 9 + 6 + 3 + 9 + 7 + 2 + 1 + 5 + 6 + 8 ) / 10

= 56 / 10

= 5.6

The answer is gonna be = 5.6

Quality control. As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.
(a) What population is under consideration in the data set?
(b) What parameter is being estimated?
(c) What is the point estimate for the parameter?
(d) What is the name of the statistic can we use to measure the uncertainty of the point estimate?
(e) Compute the value from part (d) for this context.
(f) The historical rate of defects is 10%. Should the engineer be surprised by the observed rate of defects
during the current week?
(g) Suppose the true population value was found to be 10%. If we use this proportion to recompute the value in part (e) using p = 0.1 instead of pˆ, does the resulting value change much?

Answers

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

Given That, As part of a quality control process for computer chips, an engineer at a factory randomly samples 212 chips during a week of production to test the current rate of chips with severe defects. She finds that 27 of the chips are defective.

(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.

(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.

(c) Estimate the parameter using the data: phat = 27/212 = 0.127.

(d) Standard error (or SE).

(e) Compute the SE using phat = 0.127 in place of p:

SE ≈ √(phat(1−phat)/n) = 0.023.

(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.

(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).

What is the probability of drawing 1 red marble out of a bag containing 4 red marbles, 3 green marbles, 2 blue marbles, and 1 purple marble?

Answers

Answer:

2/5

Step-by-step explanation:

There are a total of 4+3+2+1=10 marbles in the bag. Since there is an equal chance of drawing any marble from the bag, the chances of drawing a red marble is equal to the number of red marbles divided by the total number of marbles.

What we're given:

4 red marbles10 total marbles

Therefore, the probability of drawing a red marble is:

[tex]\frac{4}{10}=\boxed{\frac{2}{5}}[/tex]

Answer: Most probably

Step-by-step explanation:

At one point in history, the NBA finals required that one of the two teams win at least three of five games in order to win the Championship. If one team wins the first two games, what is the probability that the same team wins the Championship, assuming that the two teams are well matched and each team is equally likely to win each game

Answers

Answer:

50% i believe

Step-by-step explanation:

because in every scenario theres 2 teams and if they are well matched it be half and half on every game assuming they're the same level of comp

I need help with this math problem not sure what to do?​

Answers

Answer:

B. 14

Step-by-step explanation:

It's asking for function f + function g. Then it wants you to use 2 as the x value. So you have:

(f+g)(x) = 2x^2 + 3x + x - 2

(f+g)(x) = 2x^2 + 4x -2

Then using 2 as x:

(f+g)(2) = 2(2^2) + 4* 2 -2

(f+g)(2) = 8 + 8 - 2

(f+g)(2) = 14

Hope that helps, and let me know if I did any of that wrong.

I need some help please!

Answers

Answer:

See below

Step-by-step explanation:

Given :-

y || z

To Prove :-

m∠5 + m∠2 + m∠6 = 180°

Proof :-

Here we are required to prove that ,

[tex]\rm\implies m\angle 5 + m\angle 6 + m\angle 2 = 180^o [/tex]

And here it's given that , y || z . Therefore ,

∠3 = ∠6 ( alternate interior angles )∠1 = ∠5 ( alternate interior angles )

Now we know that the measure of a straight line is 180°. Therefore ,

[tex]\rm\implies m\angle 1 + m\angle 2 + m\angle 3 = 180^o \\\\\implies\boxed{\rm m\angle 5 + m\angle 6 + m\angle 2 = 180^o} [/tex]

From 1 and 2 .

Hence Proved !

2x+2y=38 y=x+3 solve by the solution

Answers

Answer:

x = 8 , y = 11

Step-by-step explanation:

[tex]2x + 2y = 38 => x + y = 19 - -- ( 1 ) \\\\y = x + 3 ---- ( 2 ) \\\\Substitute \ ( 2 ) \ in \ ( 1) :\\\\ x + y = 19\\\\x + ( x+ 3) = 19\\\\2x + 3 = 19\\\\2x = 19 - 3 \\\\2x = 16 \\\\x = \frac{16}{2} = 8\\\\Substitute \ x = 8 \ in \ ( 1 ) : \\\\x + y = 19\\\\8 + y = 19\\\\y = 19 - 8 = 11[/tex]

1 red marble 4 blue marbles 3 green marbles probability of drawing 2 blue marbles

Answers

Answer:

3/14

Step-by-step explanation:

Assuming you draw one after the other without replacement, you have a 1/2 chance of drawing blue the first time, and after one is taken out, you have 7 left. In order to draw 2 blues you would have to have a blue the first time, so there would be 3 blue left. Multiplying the 2 probabilities gets 1/2*3/7= 3/14. Double check that though.

A manufacturer inspects a sample of 500 smart phones and finds that 496 of them have no defects. The manufacturer sent a shipment of 2000 smartphones to a distributor. Predict the number of smartphones in the shipment that are likely to have no dects.

Answers

Answer:

1984

Step-by-step explanation:

Please help asap!!! :(

Answers

Answer:

Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3

Step-by-step explanation:

First, we can graph these inequalities out. As you can see in the picture, the three vertices where the inequalities all connect form a triangle. We can check each of these vertices to find our minimum and maximum.

First, we have (3,7). 4y-3x = 4(7)-3(3)=28-9=19

Next, for (3, -3), we have 4y-3x = 4(-3)-3(3) = -12-9=-21

Finally, for (0.5, 2), we have 4y-3x=4(2)-3(0.5)=8-1.5 = 6.5

Our maximum is 19 when x=3 and y=7 and our minimum is -21 when x=3 and y = -3


Solve the expression using the correct order of operations.
0.75x3.2+ (9.1)2-((-2.3)-(-0.9))2

Answers

Answer:

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Step-by-step explanation:

Given

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]

Required

Solve

Start with the bracket

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]

Evaluate all exponents

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]

Evaluate all products

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Mathematics I need help

Answers

(X-3)^2 +4. Is the answer

Suppose the age that children learn to walk is normally distributed with mean 12 months and standard deviation 2.5 month. 34 randomly selected people were asked what age they learned to walk. Round all answers to 4 decimal places where possible.

Answers

Answer:

Step-by-step explanation:

a.) it's just mean, variance

so here it's just 12,6.25

b.) For the x bar thing just divide the variance by the number of people (mean stay the same)

the variance is then (2.5²/34)= .1838

which makes it (12,.1838)

c.) here we don't use x bar (and so it's normal (12,2.5²))

p(11.6) = (11.6-12)/(2.5)= -.16 = .4364

p(12.4)= (12.4-12)/2.5 = .16= .5636

.5636-.4364= .1272

d.) here we use x bar because it's asking for an average so it's normal (12, .1838)

same deal

p(11.6)=(11.6-12)/√.1838= -.93295= .1762

p(12.4)= (12.4-12)/√.1838= .93295= .8238

.8238-.1762= .6476

d.) no because they're probably IID

f.) It's average so here we use x bar

q1 is just the 25th percentile

the 25th percentile is -.6745

-.6745=(x-12)/(√.1838)= 11.711

q3 is the 75th percentile

.6745=(x-12)/√.1838

x=12.289

The interquartile range is just the difference between the two

12.289-11.711= .5784

Please help me on this real quick

Answers

Answer: x=17


Step 1: Write an equation

To start solving this problem, we will need to first write an equation. We can do so by adding together all of the angles, and having them equal 180, since this is the sum of the angles in a triangle. Let’s do so now.

4x+3+x+7+5x+0=180

Step 2: Combine like terms

The next step will be to combine like terms. To do this, we need to combine the terms with the same variable, or lack of. In this case, the like terms with the same variable are 4x, x, and 5x. The like terms with no variable are 3, 7, and 0. Let’s add these together now.

4x+3+x+7+5x+0=180
10x+10=180

Step 3: Get 10x alone on the left side

Before we find x, we need to get 10x alone on the left side. To do this, we need to move the constant to the right side.

10x+10=180
10x=170

Step 4: Find x

Now let’s solve the last step of the equation. We need to get x alone to find its value. To do so, we need to get rid of the coefficient next to it. We can do this by dividing each term by 10. Let’s do this now.

10x=170
x=17


Hope this helps! Comment below for more questions.

1/4+3+11/2=
NEEED ANSWER ASAP BTW

Answers

Answer:

8.75 or 8 3/4

Step-by-step explanation:

To do this question, many do it differently. But for now, we will convert the fractions into decimals.

1/4 = 0.25

11/2= 5.5

0.25 + 3 + 5.5

3.25 + 5.5 =

8.75

The answer is 8.75 or 8 3/4

Answer:

[tex] \frac{35}{4} \: \: \: or \: \: \: 8 \frac{3}{4} [/tex]

Decimal form :

8.75

Step-by-step explanation:

Hope it is helpful....

what is the value of -3^2+(4+7)(2)?​

Answers

Answer:

[tex] { - 3}^{2} + (4 + 7)(2) \\ = - 9 + 22 \\ = 13[/tex]

it is known that the population proton of utha residnet that are members of the church of jesus christ 0l6 suppose a random sample of 46 selceted and prioon of the sample that belongs to the churh is calcutated what is the problaity of obtaining a sample priton less than 0;50 g

Answers

Answer:

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Proportion of 0.6

This means that [tex]p = 0.6[/tex]

Sample of 46

This means that [tex]n = 46[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.6[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.6*0.4}{46}} = 0.0722[/tex]

Probability of obtaining a sample proportion less than 0.5.

p-value of Z when X = 0.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.5 - 0.6}{0.0722}[/tex]

[tex]Z = -1.38[/tex]

[tex]Z = -1.38[/tex] has a p-value of 0.0838

0.0838 = 8.38% probability of obtaining a sample proportion less than 0.5.

There are two points of the form (x,-4) that have a distance of 10 units from the point (3,2). Give the x value for one of those points.​

Answers

Answer:

x = - 5

Step-by-step explanation:

[tex]Let \ (x _ 1 , y _ 1 ) \ and \ (x _ 2 , y _ 2 ) \ be \ the \ points. \\\\The \ distance \ between \ the \ points \ be ,\ d = \sqrt{(x_2 - x_1)^2 + ( y _ 2 - y_1)^2}[/tex]

Given : d = 10 units

         And the points are ( x , - 4) and ( 3 , 2 ).

Find x

[tex]d = \sqrt{( 3 - x)^2 + ( -4 - 2)^2} \\\\10 = \sqrt{( 3 - x)^2 + ( -6)^2} \\\\10^2 = [ \ \sqrt{( 3 - x)^2 + 36} \ ]^2 \ \ \ \ \ \ \ \ \ [ \ squaring \ both \ sides \ ] \\\\100 = ( 3 - x )^2 + 36\\\\100 - 36 = ( 3 - x )^ 2\\\\( 3 - x ) = \sqrt{64}\\\\3 - x = \pm 8\\\\3 - x = 8 \ and \ 3 - x = - 8\\\\-x = 8 - 3 \ and \ -x = - 8 - 3\\\\-x = 5 \ and \ -x = - 11\\\\x = - 5 \ and \ x = 11\\\\[/tex]

Check which value of x satisfies the distance between the points.

x = 11

[tex]d = \sqrt{(3-11)^2 + (-2--4)^2} = \sqrt{(-8)^2 + (-2+4)^2}= \sqrt{64+4} = \sqrt {68} \ units[/tex]

does not satisfy.

x = - 5:

[tex]d = \sqrt{ (3 -- 5)^2 + ( - 4 - 2)^2} = \sqrt{8^2 + 6^2} = \sqrt{100} =10 \ units[/tex]

Therefore , x = - 5

3х + 2 +(-5)? I need help pls

Answers

Answer:

3x + 2 - 5

3x - 3

x = 3 ÷ 3

x = 1

I hope this helped!

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