Aless and Louis are going to put a rectangular pool in their backyard. The cost of installation is $6,000. If the dimensions of the pool are 30 meters by 20 meters by 2 meters, what is the cost of the installation of their pool per cubic meter?

Answers

Answer 1

Answer:

cost of the pool per cubic meters = $5

Step-by-step explanation:

The rectangular pool has a dimension of 30 m by 20 m by 2 m. To know the cost of the pool per cubic meter we have to calculate the volume of the pool . Then divide the total cost of the pool by it volume.

volume of the rectangular pool = length × height × width

volume of the rectangular pool = 30 × 20 × 2

volume of the rectangular pool = 1200  m²

The cost of installation is $6000 . The volume of the pool is 1200 cubic meters.

cost per cubic meters = total cost of installation/volume

cost per cubic meters = 6000/1200

cost of the pool per cubic meters = $5


Related Questions

Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necessary, round to the nearest tenth.

Answers

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

[tex]TP X TQ=TR^2[/tex]

[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

Find the height of a right cylinder with surface area 240π ft2 and radius 5 ft.

The height of the right cylinder is __
ft.

Answers

Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

d = 8 cm
h = 18 cm
What is the surface area of the cylinder

Answers

Answer:

144 (If multiplying)

Step-by-step explanation:

18x8=144.

Four students spoke to the Home and School parents for a total of 2/3 hour. Each student spoke for the same amount of time. How long did each student speak?

Answers

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :)      espero que te aya adudado auque sea un poquito

The student body of 10 students want to elect a president, vice president, secretary, and treasurer.


A) Permutation

B) Combination

C) Circular permutation

Answers

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

If the product of two whole numbers is zero then one number will be (ii) If the product of two whole numbers is zero then both number will be zero (a) OnlyIcanbetrue(b)onlyiicanbetrue(c)Bothcanbetrue(d)botharefalse

Answers

Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

The combined weight of Maia and Vashti is 102.45kg. If Maia weighs 2.15kg more than Vashti, calculate Vashti's weight.





Answers

Answer:

50.32 I think

Step-by-step explanation:

52,13+50,32=102.45

Vashti’s weight is 50.15kg Hope this helped!

Which expression is equivalent to (4 + 7(3 + 41)?
-16+37i
12-28i
16-37i
37+16i

Answers

Answer:

C

Step-by-step explanation:

PLEASE HELP!!!! NEED ANSWER ASAP

Answers

Answer:

X=25

Step-by-step explanation:

Since these 2 angles are vertically opposite angles so they are equal. (rule)

75°=(4x-25°)

75° + 25° = 4x

100=4x

X=100/4 = 25

___________

Hope this helps...

What is the distance between points A(13, 2) and B(7, 10)

Answers

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units

Whats the answer plz??

Answers

Answer:

C

Step-by-step explanation:

Absolute Value is the distance from 0, so when you have -|22| that means its the absolute value of 22 then add the negative sign so that means it's further from 0 than |-22|.

I hope this will help.

Una escalera está apoyada sobre la fachada de un edificio. Si la escalera mide 10 m de longitud y el pie de la escalera está a 5 m de la pared, ¿a qué altura de la pared llega la escalera? Expresa el resultado con radicales extrayendo todos los factores posibles.

Answers

Answer:

8.66 meters

Step-by-step explanation:

Assuming that the building is completely straight, a right angle is formed and therefore a right triangle.

Thanks to this we can calculate the height at which the ladder reaches the wall using the Pythagorean theorem, this height being one of the legs.

We have to:

c ^ 2 = a ^ 2 + b ^ 2

c = 10

a = 5

replacing

b ^ 2 = 10 ^ 2 - 5 ^ 2

b ^ 2 = 75

b = 8.66

that is to say that the height at which the ladder reaches the wall is 8.66 meters

What is the correct answer?

Answers

Answer:45

Step-by-step explanation:

Sin^-1= 5÷7

PLZ HELP I ONLY HAVE 11 points left and I need help with this question plz :( It's URGENT

Answers

Answer:

16 units

Step-by-step explanation:

The y intercept is when the x value is 0

f(0) = 2(0)+8 = 8

The y intercept of f(x) is 8  

g(0) = -8

The y intercept of g(x)  is -8

The distance between f(0) and g(0)

8 - -8 = 8+8 = 16

Divya’s recipe calls for 3.25 pounds of beef, 0.65 pounds of onions, 0.2
pounds of potatoes, 0.15 pounds of tomatoes, and 0.33 pounds of asparagus.

How much will Divya pay for all the ingredients in the recipe? Show your work.

Answers

The beef price is $10.65

Onions price is $2.49

Potatoes are $3.29

Tomatoes are $8.45

Asparagus is $4.99

3.25 pounds of beef is          3.25 * 10.65 =  34.61

0.65 pounds of onions is      0.65 * 2.49   =  1.62

0.2 pounds of potatoes is     0.2 * 3.29     =  0.66

0.15 pounds of tomatoes is   0.15 * 8.45   =  1.27

0.33 pounds of asparagus is 0.33 * 4.99  =  1.65

Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65

This is equal to 39.81

                                           

A recipe is mixture of ingredients.

Divya will pay $39.81 for all the ingredients in the recipe.

The beef price is $10.65 per pound

So, price of 3.25 pounds of beef is ,  [tex]3.25 * 10.65 = 34.61[/tex]

Onions price is $2.49 per pound

So, price of 0.65 pounds of onions is,  [tex]0.65 * 2.49 = 1.62[/tex]

Potatoes are $3.29 per pound

So, price of 0.2 pounds of potatoes is ,  [tex]0.2 * 3.29 = 0.66[/tex]

Tomatoes price are $8.45 per pound.

So, price of 0.15 pounds of tomatoes is  , [tex]0.15 * 8.45 = 1.27[/tex]

Asparagus price is $4.99 per pound.

So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]

Hence, total amount paid by Divya is,

             [tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]

Thus, Divya will pay $39.81 for all the ingredients in the recipe.

Learn more:

https://brainly.com/question/18994792

The expression two square root of three minus square root of 27 is equivalent to

Answers

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

It’s rounded to 0.954

I am donating packages for Christmas drive. After the first week, I spent 126 to donate three children packages and 8 adult packages. After two weeks I spent 108 to donate six children packages and 4 adult packages. What is the price of each type of package

Answers

Answer:

Step-by-step explanation:

Let the price for children and adults package be represented with x and y respectively.

For the first week the sum of the package will be as follows:

3x+8y = 126

For the two weeks after:

6x+4y= 108

So, we will be having two equations

3x+8y = 126..... (1)

6x+4y= 108.......(2)

These are simultaneous equations

From equation 1

3x+8y = 126

3x = 126-8y

X = 126-8y/3 ............. (3)

Put equation 3 into 2

6 ( 126-8y)/3 +4y = 108

756-48y/3 +4y = 108

756-48y+12y/3 = 108

Cross multiplying

756-48y+12y= 108×3

756-48y+ 12y = 324

Collecting like terms

756-324 = 48y-12y

432= 36y

Divide both sides by 36

432/36 = 36y/36

y= 12

Substituting y into equation 1

3x+8= 126

3x+96=126

3x= 126-96

3x= 30

Divide both sides by 3

3x/3 = 30/3

x = 10

Hence for each of the packages for children and adults. It will be 10 and 12 respectively.

how much money does ron have each month

Answers

Answer:

after paying all expenses Ron will have $10 leftover each month.

Answer:

10 on edge

Step-by-step explanation:

How do I solve this problem? I need to find the volume of this composite figure.

Answers

Step-by-step explanation:

V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)

V = 240 + 30 + 75 + 240

V = 585 cm^3

Compare the ordered pairs of the pre-image to the
image to answer these questions.
Is the dilation an enlargement or reduction?
The point of dilation is about what coordinate?
What is the scale factor?
Pre-image

Answers

Answer: Reduction

(0,0)

1/3

Step-by-step explanation:

Answer:

1-reduction

2-(0,0)

3-1/3

Step-by-step explanation:

What is the range for the number of cars, new and used, that were sold from July to December?

Answers

I think its C cuz it makes more sense then B.

Answer:

75

Step-by-step explanation:

87-12= 75

edg2020

Which expressions are equivalent to g+h+(j+k) Check all that apply

Answers

Answer:

g+h+(j+k)

Step-by-step explanation:

(g+h)+j+k

(g+k)+j+h

(g+j)+h+k

(k+h)+j+h

(j+h)+g+k

Answer:

1 and 3

Step-by-step explanation:

dont mind me this needed to be longer wait still needs no be longer

Solve for x. 2x + 3 =9

Answers

Answer:

x=3

Step-by-step explanation:

- 3 on both sides

2x=6

divide by 2 on both sides

x=3

Answer:

x = 3

Step-by-step explanation:

[tex]2x+3=9[/tex]

Subtract 3.

[tex]2x=9-3\\2x=6[/tex]

Divide by 2.

[tex]x=\frac{6}{2}\\ x=3[/tex]

Find the volume of the figure

Answers

Answer:

450

Step-by-step explanation:

GEOMETRY DESPERATE HELP

Answers

Answer: Choice C) [tex]x^2 + (y-2)^2 = 4[/tex]

==========================================================

Explanation:

The center is at (0,2). So (h,k) = (0,2) leads to h = 0 and k = 2.

The radius is 2 units, meaning r = 2.

Plug h = 0, k = 2, r = 2 into the formula below and simplify

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-2)^2 = 2^2\\\\x^2 + (y-2)^2 = 4[/tex]

Need help ASAP, marking first as brainliest. Rlly appreciate it.

Answers

Answer:

Choose answers B and D

Step-by-step explanation:

Answer:

Choose answers B and D.

Step-by-step explanation:

1. If 5tanA=4, Find the value of (5sinA-3cosA)/(4cosA+5sinA)
2. Solve for θ, sinθ/(1+cosθ) + (1+cosθ)/sinθ =4, 0°<θ<90°
3. Prove that tan⁡〖θ-cot⁡θ 〗 = (〖2sin〗^2 θ-1)/sinθcosθ
4. Without using trigonometric tables ,show that
tan 10°tan15°tan75°tan80°=1
5. If x=acosθ-bsinθ and y=asinθ + bcosθ prove that x^2+y^2=a^2+b^2

Answers

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²

At the beginning of the month, Tim has $50. He mows 2 lawns and washes 1 car. Then, he buys two video games that cost $15 each and a sweatshirt that costs $35. How much money does Tim have left? (please put just your answer with the $)

Answers

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

Can you please help me with this question please i will give you. a Brainiest

Answers

Answer:

q < 5

Step-by-step explanation:

BE5-3 Cha Company buys merchandise on account from Wirtz Company. The selling price of the goods is $780, and the cost of the goods is $470. Both companies use perpetual inventory systems. Journalize the transaction on the books of both companies.

Answers

Answer:

In the books of Wirtz, the selling party, the required entries are

Debit Accounts receivable $780

Credit Revenue $780

Being entries to recognize sales revenue on account

Debit Cost of sales $470

Credit Inventory  $470

Being entries to recognize the cost of items sold

In the books of Cha Company

Debit Inventory $780

Credit Accounts payable  $780

Being entries to record cost of inventory purchased

Step-by-step explanation:

When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.

To recognize revenue,

Debit Cash/Accounts receivable

Credit Revenue

To record the cost of the item sold

Debit Cost of sales

Credit Inventory

For the party that makes the purchase

Debit Inventory

Credit Cash/Accounts payable

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