am i correct i chose c but i might think is wrong (valid answer only!!)
Graph the linear inequality.

4x+5y≥−15

Answer:

705.3 repeated I don't know if that's what you want but

3 times of 705.33 and 2 subtracted is equal to 2114.

Simplification in mathematical terms is a process to convert a long mathematical expression in simple and easy form.

Given that,

2 less than 3 times a number equal to 2114.

Let the required number is x.

According to given condition,

3x - 2 = 2114

3x = 2114 + 2

3x = 2116

x = 2116 / 3

x = 705.33

The required number is 705.33.

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Answer: 350000

Step-by-step explanation: Hope this helps :) (if wrong please make sure next time add answer that can be picked from it better or if theres no answers maybe give some more detail?)

Answer:

The answer is C

Step-by-step explanation:

Hope that helps ;)

Answer:

-5x+2

Step-by-step explanation:

1. Multiply number 2 and 2=4 so it is

4-5x-2

2. Combine like terms

-5x+4-2

3. Subtract the numbers

-5x+2

Answer:

the nwser is 8 please mark brainliest

Step-by-step explanation:

Answer:

Megan's plant is 457 Inches tall

Step-by-step explanation:

Answer:

The answer is D

Step-by-step explanation:

The line has 2 points: (-1;0) and (0;-4)

=> x1 = -1; x2 = 0 => x1 - x2 = -1 - 0 = -1

   y1 = 0; y2 = -4 => y1 - y2 = 0 - 4 = -4

=> slope = (y1 - y2)/(x1 - x2) = [tex]\frac{-4}{-1}[/tex] = 4 => D

Answer:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

Answer:

64%

Step-by-step explanation:

Step 1: Divide 16 by 25

Step 2: Multiply quotient by 100.

Therefore, 16/25 as a percentage is 64%.

Answer:

Well you can make a proportion

Percentage means ”Out of a hundred”

So you can make a proportion with any fraction Equal to x/100 since

X is the unknown perctange.

in this case it’s 16/25

16/25 = x/100

So cross multiply To solve for X

1600= 25x

x= 64

So 64 Percent

In this case you can use benchmarks. If you do it more or long enough, you’d memorize them.

In this case 25 is a bench mark of 1/4 or 25. 25 goes into 100 4 times so you can multiply 16 by 4 to get your percentage since if you do multiply 4, you have to do it to both the numerator and the Denominator.

so 16/25

16*4= 64

25*4=100

64/100 or 64 percent.

Common benchmarks for percentages

5, 10, 20, 25, 50

5 is always multiply by 20

10 is always multiply by 10

20 is always multiplied by 5

25 is always multiplied by 4

50 is always multiplied by 2

Answer:

[tex]x^{2} +11x-10[/tex]

Step-by-step explanation:

[tex](13x^{2} +9x-4)-(12x^{2} -2x+6)[/tex]

Remove the brackets and multiply the minus sign through all the numbers in the second polynomial

[tex]13x^{2} +9x-4-12x^{2} +2x-6[/tex]

Rearrange in the highest order

[tex]13x^{2} -12x^{2} +9x+2x-4-6[/tex]

Simplify

[tex]x^{2} +11x-10[/tex]

Step-by-step explanation:

the second one (with the -5 as x values) is not a function, because the valid x value -5 has more than one associated different solution value y.

for a function a valid x value can lead only to exactly one result y value.

Answer:

The expression would be (x + 3)(x - 8) and if we multiplied those together we would get x^2 - 5x - 24

Step-by-step explanation:

Answer:

Step-by-step explanation:

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?

Pick one:

5cm

20cm

200cm

720cm

--------------------

scale = 1:6000

so

1200 : 6000 =  0.2m

0.2m = 20 cm

Answer:

20cm

Step-by-step explanation:

«A scale of 1:6000» means the model is smaller than the bridge by a factor of 6000. We can also make up a proportion [tex]\dfrac{1}{6000}=\dfrac{x}{1200}[/tex], where the left side is the scale, x is the model length, 1200 is the bridge length (in meters). So, finding x or just dividing 1200 by 6000, we get 0.2 meters. Provided 1 m = 100 cm, 0.2 m is 0.2 × 100 = 20 cm.

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

Answer:

24

Step-by-step explanation:

m=8x4 n=3x4 so that is the answer

Answer:

B. 7 1/2

Step-by-step explanation:

1. To solve this problem, we have to multiply 2 1/2 by the reciprocal of 1/3.

2. (Solving)

Therefore, the answer is B. 7 1/2.

Answer:

its B mark branli.est pls

Step-by-step explanation:

Answer:

1.25 g

Step-by-step explanation:

you start with 20g at 0 seconds.

divide by half after 2 seconds and you have 10g.

at 4 seconds you have 5g.

at 6 seconds you have 2.5g.

at 8 seconds you have 1.25g.

The size of the substance after 8 seconds will be 1.25 g

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a radioactive substance has a half-life of 2 seconds. A scientist begins with a sample of 20 grams.

Start with 20g at 0 seconds and divide by half after 2 seconds and you have 10g.

4 seconds you have 5g.

6 seconds you have 2.5g.

8 seconds you have 1.25g.

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Answer:

1:6

Step-by-step explanation:

2:12

\/

1:6

Have a nice day!

     If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

1:6

Step-by-step explanation:

2/12 = 1/6

Answer:

80% of 20 is 16.

Step-by-step explanation:

Hello darling, the answer is 20 ^^

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[tex] {x}^{2} = 100[/tex]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

Answer:

your equation is this... x2 - 100

since you have no x term to the first power you can write 0x... like this

x2 + 0x - 100

Now, what numbers will add to 0 and multiply to -100

The numbers 10 and -10 will

10 + -10 = 0

10 * -10 = -100

therefore

(x - 10)(x + 10) is the way you factor it

Step-by-step explanation:

Answer:

y = 7/8

Step-by-step explanation:

12y+18=-4y+32

12y+18-18=-4y+32-18

12y=-4y+14

12y+4y=-4y+14+4y

16y=14

16y/16=14/16

y = 7/8

Answer:

The value of A is 2

Step-by-step explanation:

F = 2 , B = 3 , K = 10

K = F( A + B )

10 = 2(A + 3)

10 = 2A + 6

Now, Subtract 6 from each side we get,

10 - 6 = 2A + 6 - 6

4 = 2A

2A = 4

Now, divide both side by 2 we get,

2A/2 = 4/2

A = 2

Thus, The value of A is 2

K = F( A + B )

10 = 2(2 + 3)

10 = 2(5)

10 = 10

L.H.S = R.H.S

Hence Proved!

-TheUnknownScientist 72

Answer:

Where's the Answer? There's No

Hello there!

Remember that equivalent fractions have the same value.

[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]

Hope this helps you!

~Just a felicitous girlie

#HaveASplendidDay

[tex]SilentNature :)[/tex]

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

Answer:

y=3

Step-by-step explanation:

y = - x +7

x=4

so y = -4 +7

y = 3

Answer:

To calculate the gradient of a straight line we choose two points on the line itself. From these two points we calculate: The difference in height (y co-ordinates) ÷ The difference in width (x co-ordinates). If the answer is a positive value then the line is uphill in direction.

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J