Americium-241 is widely used in smoke detectors. The radiation released by this element ionizes particles that are then detected by a charged-particle collector. The half-life of 241Am is 432 years, and it decays by emitting alpha particles. How many alpha particles are emitted each second by a 5.54-g sample of 241Am

Answer:

Global Warming

Explanation:

The biggest concern for environmental scientists is Global Warming. Our Earth is getting warmer which is having drastic effects on our planet. Such effects include increased natural fires, decreased water supply, decreased farm yields, increased floodings, etc. Global Warming poses a huge threat to humanity and it is because of humanity's constant and ever growing usage of fossil fuels that Global Warming is becoming such a threat. This is what environmental scientists are mainly focused on.

Explanation:

U can use molar ratio of

Li : Li2SO3

2 : 1

so 3.33÷2=1.665 so 1.67 moles

then u can use the

moles = mass ÷ mr

= 12.33÷ 100.08

= 0.123 moles of CuSO3 then use the molar ratio

CuSO3 : Cu

1:1

so 0.123 moles of cu

hope this make sense:)

Answer:

I assume your talking about carbon when you say 12 so it'd be 12 grams if you are

Explanation:

The molar mass of any substance in grams per mole is numerically equal to the mass of that substance expressed in atomic mass units.

Hope this helps you some

Where is ur question ⁉️

Equilibrium shifts to the right.

OPTION A

Answer:

I don't no answer sorry

Explanation:

you follow me

Answer:

The solute is salt and the solvent is water

Explain:

Because salt is a component the dissolves in the solvent

Answer:

the correct answer is four decimal places

Answer: The concentration of the solution is 55.66g[tex]KNO_3[/tex]/100g[tex]H_2O[/tex]

Explanation:

A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

We are given:

Mass of [tex]KNO_3[/tex] = 2.31 g

Mass of water = 4.15 g

To calculate the concentration in g[tex]KNO_3[/tex]/100 g [tex]H_2O[/tex], we apply unitary method:

In 4.15 g of water, the mass of [tex]KNO_3[/tex] present is 2.31 g

So, in 100 g of water, the mass of [tex]KNO_3[/tex] present will be [tex]\frac{2.31}{4.15}\times 100=55.66g[/tex]

Hence, the concentration of the solution is 55.66g[tex]KNO_3[/tex]/100g[tex]H_2O[/tex]

Answer:

[tex]molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\ = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\ = 40.7 \: g[/tex]

Answer:

71.1

Explanation:

Plato

Answer:

16974J of energy are required

Explanation:

The energy required is:

* The energy to heat solid water from -15°C to 0°C using:

q = m*S*ΔT

* The energy to convert the solid water to liquid water:

q = dH*m

* The energy required to increase the temperature of liquid water from 0°C to 75°C

q = m*S*ΔT

The first energy is:

q = m*S*ΔT

m = Mass water = 25g

S is specific heat of ice = 2.03J/g°C

ΔT is change in temperature = 0°C - (-15°C) = 15°C

q = 25g*2.03J/g°C*15°C

q = 761.3J

The second energy is:

q = dH*m

m = Mass water = 25g

dH is heat of fusion of water = 80cal/g

q = 80cal/g*25g

q = 2000cal * (4.184J/1cal) = 8368J

The third energy is:

q = m*S*ΔT

m = Mass water = 25g

S is specific heat of water= 4.184J/g°C

ΔT is change in temperature = 75°C-0°C = 75°C

q = 25g*4.184J/g°C*75°C

q = 7845J

The energy is: 7845J + 8368J + 761J =

16974J of energy are required

Answer:

Volume of the reaction vessel is increased - shift to the left

The reaction is cooled down - shift to the right

H2 is added to the system - shift to the right

The pressure of the system is decreased - shift to the left

A catalyst is added to the system - no change

Water is removed from the system - shift to the right

Explanation:

When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.

When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.

Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.

Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.

Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.

A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.

Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.

Answer:

Explanation:

a

Answer:

IUPAC, which stands for International Union of Pure and Applied Chemistry, has a rules that guides the naming of aliphatic compounds these are explained below.

Explanation:

The International Union of Pure and Applied Chemistry ( IUPAC) has put forward a system of nomenclature which relates the me of the compound to its molecular structure. In this system, every name consists of:

--> A ROOT: This is generally the aliphatic hydrocarbon.

--> the SUFFIX: This is added to the root to indicate the presence of the principal substituent. For example the names of alkanes ends with '-ane'.

--> as many PREFIXES as necessary.

The systematic name of a compound is formed from the root hydrocarbon by adding a suffix and prefixes to denote the substitution of the hydrogen atoms.

Basic rules in to name aliphatic compounds include:

--> Take the longest continuous carbon chain as the root hydrocarbon and name it according to the number of carbon atoms it contains, adding the appropriate suffix to indicate the principal substituent group.

--> Number the carbon atoms in the root hydrocarbon from the end which will give the lowest number to the suffix, and then the prefixes.

--> Indicate the other substituents by prefixes preceded by numbers to show their positions on the carbon chain.

Answer:

18.45 g of C

Explanation:

This is a problem of rules of three:

1 mol of C₃H₈ contains 3 moles of C and 8 moles of H

If 8 moles of H are contained in 1 mol of propane

4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles

Now, If 1 mol of propane contains 3 moles of C

0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C

Let's convert the moles to mass:

1.5375 mol . 12 g /mol = 18.45 g

Answer:

A

Explanation:

In plant and yeast cells pyruvate is converted into carbon dioxide and a type of alcohol called ethanol . This process is called fermentation and yields only two molecules of ATP per glucose molecule broken down.

[tex]CO_2 + H_20[/tex]+ light energy → [tex]O_2[/tex] + sugar chemical equation represents a process that takes place in yeast cells. Hence, option A is correct.

A representation of a chemical reaction using symbols of the elements to indicate the amount of substance, usually in moles, of each reactant and product.

In plant and yeast cells pyruvate is converted into carbon dioxide and a type of alcohol called ethanol. This process is called fermentation and yields only two molecules of ATP per glucose molecule broken down.

Hence, option A is correct.

Learn more about chemical equations here:

https://brainly.com/question/12363199

#SPJ2

The question is incomplete, the complete question is;

1.000 atm of Oxygen gas, placed in a container having apinhole opening in its side. leaks from the container 2.14 timesfaster thatn 1.000 atm of an unknown gas placed in this sameapparatus. Which of the following species could be theunknown gas?

A. CL2

B. SF6

C. Kr

D. UF6

E. Xe

Answer:

SF6

Explanation:

From Graham's law;

Let the rate of diffusion of oxygen be R1

Let the rate of diffusion of unknown base be R2

Let the molar mass of oxygen by M1

Let the molar mass of unknown gas be M2

Hence;

R1/R2 = √M2/M1

So;

2.14/1 = √M2/32

(2.14/1)^2 = M/32

M= (2.14/1)^2 × 32

M= 146.6

This is the molar mass of SF6 hence the answer above.

Answer:

Wearing gloves

Explanation:

it helps on not touching chemicals

Answer:

all of the above

Explanation:

have a nice day :-)

Answer:

Strontium - 38 (atomic #)

Explanation:

An ion with 38 protons, 36 electrons, and 40 electrons is Strontium. Strontium's atomic number is 38.

Answer:

4

Explanation:

because it has 3 carbons  and 6 hydrogen

hope this helps :)

Answer:

2

Explanation:

You write your answer with the same number of significant figures as the number with the smallest amount of figures, in this case, that number is 2.1 so your answer should be written with 2 significant figures.

Answer:

Light can be treated like particles because it is made of chunks like things called protons.

the x y axis is tipped so the earth is flat