An airplane accelerates from a speed of 33 m/s at the constant rate of 3.0 m/s2 over a distance of 500 m. What the final velocity?​

Answers

Answer 1

Answer:

Explanation:

v² = u² + 2as

v² = 33² + 2(3.0)(500)

v² = 4089

v = 63.9452...

v = 64 m/s


Related Questions

Throwing all over the place will___________the environment.​

Answers

Answer:

pollute the environment

Look up the specs on a c6 rocket engine. How many C6 engines would it take to launch Mr. Blazey (90kg)
from the elevation of Boulder to the elevation of longs peak? (3 points) What would the max power be? (3
points) The max acceleration? (3 points) For all 12 points, you'll need to account for the mass of the added
rockets (you can assume their mass declines linearly over their burn and is O after they finish burning).

Answers

Answer:

The Estes C6-0 engine is a booster stage engine designed for model rocket flight and has to be used with a standard engine. This engine is for flights in rockets weighing less than 4 ounces, including the engines. Each package includes 3 engines, 4 starters and 4 plugs.

A merry-go-round rotates from rest with an angular acceleration of 1.08 rad/s2. How long does it take to rotate through (a) the first 3.74 rev and (b) the next 3.74 rev

Answers

Answer:

Let ω1 be the initial angular speed and ω2 the final angular speed:

α = (ω2- α1) / t      

corresponding to a = (v2 - v1) / t  

S (distance corresponds to theta)

1 rev = 2 pi      and 3.74 rev = 7.48 pi = 23.5 radians

S = 1/2 a t^2 linear     or S = 1/2 α t^2    angular acceleration

23.5 = 1/2 * 1.08 t^2     and t = 6.60 sec   for first 3.84 rev

b)  ω1 = 1.08 * 6.6 = 7.13 rad/sec    initial speed for second 3.74

23.5 = 7.13 t + .54 t^2        compare to S = v1 t + 1/2 a t^2

.54 t^2 + 7.13 t - 23.5 = 0    

t^2 + 13.2 t - 43.5 = 0

t = 2.7 sec for next 3.74

Check:

7.13 * 2.7 + .54 * 2.7^2 = 23.2 rad = 3.7 rad

Two identical vertical springs S1 and S2 have masses m1 = 400 g and m2 = 800 g attached to them. If m1 causes spring S1 to stretch by 4 cm, what is the ratio of the potential energy of S1 and S2? Use g = 10 m/s^2

Select one:

a. 1:2

b. 4:1

c. 1:4

d. 1:3

e. 2:1​

Answers

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

What’s 1 + 1 many half a window

Answers

Answer:

1

+

1

is

2

Explanation:

because if you add one to a one it would end up being 2 <3

Answer: 2

Explanation: 1+1=2

This was THE hardest question I've ever decided to answer

A Vector that starts from
Origin is called what?

Answers

A vector that starts from origin is called a position vector

electric field due to on the surface of the charge sphere​

Answers

Explanation:

static electricity draws energy

A power plant running at 31 % efficiency generates 270 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant

Answers

The rate of heat energy exhausted to the river is 600.96 MW.

What is efficiency?

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Given parameters:

Efficiency of the power plant; η = 31 %

Output  electric power; O = 270 MW.

We know that, Efficiency of the power plant;

η  = (Output  electric power/ input power)× 100%

⇒ input power = (Output  electric power × 100)/η

⇒ input power = (270 × 100)/31 MW

= 870.96 MW.

So, the rate of heat energy exhausted to the river that cools the plant =  Input power- output power

= (870.96 - 270) MW

= 600.96 MW.

Hence, heat energy exhausted to the river that cools the plant  is 600.96 MW.

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Find the work done by the force field F in moving an object from A to B. F(x, y) = 6y3/2i + 9x y j A(1, 1), B(3, 4)

Answers

Answer:

138

Explanation:

(since there's a blank next to "9x y j", I'm assuming the y of F(x, y) is 9x[tex]\sqrt{y}[/tex] j)

1) find the partial derivative of each:

[tex](6y^{\frac{3}{2} })i + (9x\sqrt{y} )j[/tex]  

 [tex]f_{x} =(6y^{\frac{3}{2} })_{x} = \int\limits{6y^{\frac{3}{2} }} \, dx = 6xy^{\frac{3}{2} } +c \\\\f_{y} = (9x\sqrt{y} )_{y} = \int\limits{9xy^{\frac{1}{2} } } \, dy = 9x(\frac{2}{3} )y^{\frac{3}{2} } +c = 6xy^{\frac{3}{2} } +c[/tex]

2) use partial integrals to make gradient of f:

take whatever you got from partial integral and add them together (if they repeat, just use it once)

[tex]F =[/tex] Vf (V = gradient of)

[tex]F(x, y) = 6xy^{\frac{3}{2} }[/tex]

3) Evaluate the integrals with given points:

Integral of F dotted with dr = F(point B) - F(point A) = F(3, 4) - F(1, 1)

[tex]F(point B) = 6(3)(4)^{\frac{3}{2} }\\F(Point A) = 6(1)(1)^{\frac{3}{2}}\\F(point B) - F(pointA) = 6(3)(4)^{\frac{3}{2} }-(6(1)(1)^{\frac{3}{2}})[/tex]

= 144 - 6 = 138 units of work

Work done by the force field F in moving an object from A to B = 138 J

Given data :

Force field F(x,y) = [tex]6y^{\frac{3}{2} }i + (9x\sqrt{y} ) j[/tex]  

Step 1 : determine the partial derivatives of the vector quantity

Fx = ∫ [tex]6y^{\frac{3}{2} }i = 6xy^{\frac{3}{2} } + c[/tex]

Fy = ∫ [tex](9x \sqrt{y})_{y} = 9x(\frac{2}{3})y^{\frac{3}{2} } + c[/tex]

Equating the partial derivatives :  

[tex]9x(\frac{2}{3})y^{\frac{3}{2} } + c[/tex]  = [tex]6xy^{\frac{3}{2} } + c[/tex]

therefore the gradient of F  i.e. F = vF  = F( x,y ) = [tex]6xy^{\frac{3}{2} }[/tex]

Next step : Determine the work done

Work done ( F.dr ) = [ F(point b ) = F( 3,4 ) ]  - [ F(point A) = F( 1,1 ) ]

F(3,4 ) = 6(3)(4)[tex]^{\frac{3}{2} }[/tex]  = 144

F( 1,1 )  = 6(1)(1)[tex]^{\frac{3}{2} }[/tex]    = 6

Therefore the work done by the force field = 144 - 6 = 138 J

Hence we can conclude that the work done by the force field F is = 138 J

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Over half the global population faces a shortage of clean water. Which example is a point source water pollutant? pesticide run-off from farmers’ fields a sewer pipe draining directly into a river road oil washing into sewer drains, and eventually reaching waterways erosion from a denuded slope after a heavy rainfall

Answers

An example of a point source water pollutant is a sewer pipe draining directly into a river.

According to the United States Environmental Protection Agency, a  point source pollution is defined as;  “any single identifiable source of pollution from which pollutants are discharged, such as a pipe, ditch, ship or factory smokestack.”

Hence, an example of a point source water pollutant is a sewer pipe draining directly into a river. The pollution is coming from an easily identifiable source which is a sewer pipe connected to a river directly.

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a police finds skid marks 60m long on a highway showing where a car made an emergency stop. assuming that the acceleration was -10m/s2. how fast was the car going and did it exceed the sooed limit of 80km/h?​

Answers

the answer is 029 and 177 hours later i’m going on my grandma to

Answer:

029 and 177

simple luv:)

Explanation:

. If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration change

Answers

Answer:

a1 = -w^2 A sin w t        where w is the angular frequency

a2 =  - (2 w)^2 A sin 2 w t       where w2 = 2 w1

a2 / a1 = 4 sin 2 w t / sin  w t

Since sin 2 w t / sin w t = 2     sin w t will change twice as fast

a2 / a1 = 8      the max acceleration must change 8 tims as fast

PLEASE HELP DUE TODAY
When same vectors are in the same direction they add. When same vectors are in opposite directions, they

a, also add
b, subtract
c, multiply
d, divide

Answers

Answer:

The answer is a (also add)

what are the greenhouse gasses in the earth that are primarily responsible for the greenhouse effect on Earth

Answers

Answer:

Water Vapour, Carbon dioxide, methane,nitrous oxide,ozone.

David and Fiona want to know about how mass affects the motion of an object. David uses three objects with masses of 2 kg, 3 kg, and 8 kg, writes out his procedure, and records his observations on the force needed to move the objects. Fiona is investigating three different objects using observation. What is the difference in the way they approached this question?

A. Only Fiona gathered evidence from her investigation.
B. David used scientific articles for evidence.
C. David's observations can be replicated by repeating his procedure.
D. Fiona's observations can be replicated by observing different objects.

Answers

Answer: the answer is D if its not i'm really sorry

A magnet is located above circular current. What is the direction of the magnetic force on the magnet

Answers

The magnet is attracted to the ring since the north pole of the current loop is above the ring and the south pole is below the ring.

Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high?

Answers

Answer:

2 times more work

Explanation:

Work is a force times distance

W = Fd

The barbell does not change mass so its weight (force) is constant.

That means work is directly proportional to the distance traveled.

twice the distance means twice the work.


Carrie is driving a car. Which factors determine the kinetic energy of her car
at this point

Answers

Answer:

The two main factors that affect kinetic energy are mass and speed.

Explanation:

Kinetic energy is the energy that is caused by the motion. The kinetic energy of an object is the energy or force that the object has due to its motion. Your moving vehicle has kinetic energy; as you increase your vehicle's speed, your vehicle's kinetic energy increases.

Have a great day! :D

Question below...............

Answers

Answer:

friction force

Explanation:

force of friction is opposite to the force applied it resist the motion

A weather forecaster uses a computational model on a Monday to predict the weather on Friday. Why might that forecast change? (1 point)
A. The forecaster may have done the calculations a second time because he made a mistake in the calculation.

B. Someone may have reported the weather incorrectly before the first computation.

C. The forecaster may have had the computer model do the calculations a second time, and he found that the prediction changed.


D. An area of low pressure might move more quickly on Tuesday and Wednesday than expected.

Answers

Answer:

(d) is your answer for your question

)Suppose you have two insulated buckets containing the same amount of water at room temperature. You also happen to have two blocks of metal of the same mass, both at the same temperature, warmer than the water in the buckets. One block is made of aluminum and one is made of copper. You put the aluminum block into one bucket of water, and the copper block into the other. After waiting a while you measure the temperature of the water in both buckets. Which is warmer

Answers

The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.

The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.

At standard conditions;

the specific heat of aluminium = 0.215 cal/gm/° Cthe specific heat of copper = 0.0923  cal/gm/° C

We know that:

Heat loss by the metal block = Heat gained by the water bucket

Therefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.  

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what is democratic means in science ​

Answers

Answer:

relating to or supporting democracy or its principles.

Explanation:

A patient comes to an outpatient laboratory for a physician-ordered fasting test. The patient indicates that he forgot that the test was to be fasting and ate a candy bar 2 hours ago. The patient insists that you should draw the test because he cannot come back at another time. What should you do?

Answers

The patient eating a candy bar instead of fasting for the test should be told

that the test results will be wrong and he may receive a wrong diagnosis.

The medical practitioners told him to fast when coming for a reason and he

forgetting and eating something means the objective for the test may have

been defeated.

This is why it's best to explain to him about the consequences of his actions

which is likely getting a wrong result and diagnosis.

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The force of earth’s gravity is 10N downward. What us the acceleration of a 15kg backpack if lifted with a a 15N force?

Answers

Answer:

F-F(gr) = ma

a= {F-F(gr)}/m =

=(15-10)/15=0.33 m/s² (upward)

A block slides down a smooth ramp, starting from rest at a height h. When it reaches the bottom it's moving at speed v. It then continues to slide up a second smooth ramp. At what height is its speed equal to v/2

Answers

Answer:

3h/4

Explanation:

At speed v/2 height will be 3/4 h

What is equation of motion in kinematics?

Equation that describes the motion of point , bodies , and system of bodies without considering the force that cause them to move is called equation of motion in kinematics

When block is at top of first ramp

u=0 ( block was at rest )

a = g ( acceleration due to gravity

using equation of motion                                                                                                                                                                                                                                                                    

2as = v^2 - u^2

2gh = v^2

Then the block continued and reached a speed of v1 = v/2 on second ramp

now , final velocity = v= v1 =[tex]\sqrt{2gh}[/tex] / 2

u= [tex]\sqrt{2gh\\}[/tex]

s= h1

using equation of motion , we get

2as = v^2 - u^2

2(-g)h1 =( [tex]\sqrt{2gh}[/tex]/2)^2 - [tex]\sqrt{2gh}[/tex]

2(-g)h1 = (g h - 4 g h) / 2

h1 = 3/4 h

At speed v/2 height will be 3/4 h

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define moment of a force about a point and give the si unit of moment?​

Answers

Answer:

Moment of a force is the product of the force and the perpendicular distance of force from axis of rotation.

The SI unit of force is newton (N).

Explanation:

Hope it helps you again!

A tow truck pulls a car 5.00 km along a horizontal roadway using a cable having a tension of 850 N. (a.) How much work does the cable do on the car if it pulls horizontally? If it pulls at 35.0° above the horizontal? (b.) How much work does the cable do on the tow truck in both cases of part (a)? (c.) How much work does gravity do on the car in part (a)?

Answers

I think 1980is the answer because you add???

Identify:

In each case the forces are constant and the displacement is along a straight line, so

[tex]$$W=F s \cos \phi \text {. }$$[/tex]

Set-Up:

In part (a), when the cable pulls horizontally [tex]$\phi=0^{\circ}$[/tex] and when it pulls  [tex]$35.0^{\circ}$[/tex] above the horizontal [tex]$\phi=35.0^{\circ}$[/tex]. In part (b), if the cable pulls horizontally[tex]$\phi=180^{\circ}$[/tex]. If the cable pulls on the car  [tex]$35.0^{\circ}$[/tex] above the horizontal it pulls on the truck at below the horizontal and [tex]$\phi=145.0^{\circ}$[/tex]. For the gravity force [tex]$\phi=90^{\circ}$[/tex], since the force is vertical and the displacement is horizontal.

Execute:

(a) When the cable is horizontal, [tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 0^{\circ}=4.25 \times 10^{6} \mathrm{~J}$[/tex].

When the cable is[tex]$35.0^{\circ}$[/tex] above the horizontal,[tex]$W=(850 \mathrm{~N})\left(5.00 \times 10^{3} \mathrm{~m}\right) \cos 35.0^{\circ}=3.48 \times 10^{6} \mathrm{~J}$[/tex].

(b)[tex]$\cos 180^{\circ}=-\cos 0^{\circ}$[/tex] and [tex]$\cos 145.0^{\circ}=-\cos 35.0^{\circ}$[/tex],

So the answers are [tex]$-4.26 \times 10^{6} \mathrm{~J}$[/tex] and [tex]$-3.48 \times 10^{6} \mathrm{~J}$[/tex].

(c) Since [tex]$\cos \phi=\cos 90^{\circ}=0, W=0$[/tex] in both cases.

Evaluate: If the car and truck are taken together as the system, the tension in the cable does no net wnetwork

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A solid sphere starts from rest and rolls down a slope that is 6.4 m long. If its speed at the bottom of the slope is 5.3 m/s, what is the angle of the slope

Answers

From the relationship between acceleration a and g on an inclined plane, the angle of the slope is 13 degrees

Given that a solid sphere starts from rest and rolls down a slope that is 6.4 m long. The speed at the bottom of the slope is 5.3 m/s, the distance travelled is 6.4 m. That is,

Initial velocity U = 0 ( since it starts from rest)

Final velocity V = 5.3 m/s

distance S = 6.4 m

Let us first calculate its acceleration by using  third equation of motion.

[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2aS

[tex]5.3^{2}[/tex] = 0 + 2 x 6.4a

28.09 = 12.8a

a = 28.09 / 12.8

a = 2.2 m / [tex]s^{2}[/tex]

To calculate the angle of the slope, let us use the relationship between acceleration a and g on an inclined plane.

acceleration a = gsin∅

substitute all the relevant parameters

2.2 = 9.8 sin∅

sin∅ = 2.2/9.8

sin∅ = 0.224

∅ = [tex]Sin^{-1}[/tex](0.224)

∅ = 12.97 degrees

∅ = 13 degrees (approximately)

Therefore, the angle of the slope is 13 degrees

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Question 3 of 20 :
Select the best answer for the question.
3. Which of the following accurately describes the behavior of water when subjected to
temperature change?
A. The volume of water will decrease if heated from 6°C to 7°C.
B. The volume of water will increase if cooled from 3°C to 2°C.
O C. A mass of water will contract if cooled from 1°C to 0°C.
D. A mass of water will expand if heated from 0°C to 2°C.

Answers

As water cools the volume expands.

Answer: B. The volume of water will increase if cooled from 3°C to 2°C.

who the football games yesterday 2021

Answers

New England am I wrong I didn’t watch the game