An atom is to a mole as A.A dozen is to an egg B.An egg is to a dozen C.A goose is to a gaggle D.Both B and C

Answers

Answer 1

Answer: The correct option is D) Both B and C.

Explanation:

Mole is defined as the measurement of a substance that contains [tex]6.022\times 10^{23}[/tex] a number of particles (atoms, molecules, ions, etc..)

A dozen simply means that there is 12 number of articles like eggs, bananas, etc..

A gaggle is known as the collection of goose.

When an atom is compared with a mole, then an egg will be compared with a dozen, and a goose will be compared with a gaggle.

Thus, an atom is to a mole as an egg is to a dozen and a goose is to a gaggle.


Related Questions

Which pair of compounds has the same empirical formula?
1.
C2H2 and C6H6
2
C2H6 and C3H8
3.
CH3OH and C2H5OH
4.
CH3CHO and CH3COOH

Answers

Explanation:

Correct option is

B

CH

3

COOH

Empirical formula of Glucose C

6

H

12

O

6

= C

1

H

2

O

1

Now, Empirical formula of CH

3

COOH=C

1

H

2

O

1

As empirical formula is the simplest whole number ratio of number of different types of atoms present in the given molecular formula.

Answer : B

Explanation:

Which of the following is key to generating a bell curve?

Answers

I think that the answer is: sample size
The Flynn effects generating a bell curve

At STP, which gaseous sample has the same number
of molecules as 5.0 liters of O2 (g)?
A) 6.0 L of F2 (g)
B) 4.5 L of O2 (g)
C) 3.0 L of H2 (g)
D) 5.0 L of Cl2 (9)

Answers

D
I hope this helps have a great day

If the initial amount of indium-117 is 5.2 g, how much indium-117 is left in the body after 86 min

Answers

i need to go home and play on the game

Why is blood considered a suspension?

Answers

Blood is considered a suspension because it contains particles that can settle out. A (heterogeneous) suspension is defined as a mixture between a liquid and particles of a solid. ... Blood cells separate and settle from the plasma, the watery part of the blood.

Answer:

Because platelets and other things are "suspended" in the plasma.

Explanation:

When blood is put into a centrifuge it separates into its separate components (eg: Red blood cells, plasma, White blood cells, platelets, etc)

What makes our cells different from bacteria?

A. Our cells are larger.

B. Our cells are rounder.

C. Our cells contain nucleui.

Answers

Answer:

C

Explanation:

Bacteria lacks a nucleus.

C our cells produce from nucleus’s

1.20 × 104) × (2.152 × 102) = × 10^6 203/5.3=

Answers

I hoped that helped by the way I went on https://doyourmath.com/web-algebrator/#c=solve&v1=1.2%255C%2520x%255C%2520104%255C%2520x%255C%25202.152%255C%2520x%255C%2520102%253D10%255E%257B6%255C%2520%257D%255Cleft%2528%255Cfrac%257B203%257D%257B5.3%257D%255Cright%2529%255Cnl%2520&v2=solve&v3=x To get the answer.

help me plsssssssss.... im timed

Answers

Answer:

a

Explanation:

a

Answer:

B. Isotopes of the element.

Explanation:

Isotopes are basically atoms of the same element that contain the same number of protons, but a different number of neutrons.

A chemist must prepare 900.0 mL of potassium hydroxide solution with a pH of 12.20 at 25°C.
He will do this in three steps:
• Fill a 900.0 mL volumetric flask about halfway with distilled water.
• Weigh out a small amount of solid potassium hydroxide and add it to the flask.
. Fill the flask to the mark with distilled water.
Calculate the mass of potassium hydroxide that the chemist must weigh out in the second step. Round your answer to 2 significant digits and put your answer in grams (g).

Answers

Answer:

0.80 g

Explanation:

First we calculate the required pOH from the given pH value:

pOH = 14 - pHpOH = 14 - 12.20 = 1.80

Then we calculate the required concentration of OH⁻, using the pOH:

pOH = -log[OH⁻][OH⁻] = [tex]10^{-1.80}[/tex] = 0.0158 M

As the concentration of OH⁻ species is the sames as the concentration of KOH, we need to prepare 900 mL of a 0.0158 M KOH solution:

We calculate how many KOH moles are required, using the concentration and volume:

Converting 900 mL ⇒ 900 / 1000 = 0.900 Lmoles = 0.0158 M * 0.900 L = 0.01422 mol

Finally we convert 0.01422 moles of KOH to grams, using its molar mass:

0.01422 mol * 56 g/mol = 0.80 g

Francine makes several measurements of the mass of a metal block. The data set is shown in the table below.

Measurement
Mass of metal block (g)
1
20.73
2
20.76
3
20.68
4
20.75

After analyzing this data set, Francine calculates a value of 20.73 g.

Which of these characteristics has been calculated?
mean
median
mode
range

Answers

Answer:

Mean

Explanation:

The mean of a series of measurements is calculated when all the measurements are added up and then divided by the number of measurements taken, as follows:

Sum of Measurements = 20.73 + 20.76 + 20.68 + 20.75 = 82.92

As there are 4 measurements, the mean is:

Mean = 82.92 / 4 = 20.73

Answer:

A

Explanation:

Can you help ASAP? Thanks you.

Answers

Answer:

ok

Explanation:

Ok I can tutor you if you’d like

1,500 grams is equal to:
1.5 kg
1.5L
1.5 cm
all of the above

Answers

1kg is 1,000 grams plus .5 is 1.5 kg

How can we protect space shuttles or astronauts from space radiation in the absence of the atmospheric layer?
What is the role of gravity in maintaining the atmospheric layer around the earth ?
Please put your answers with clear explanation.
Thank you ! ​

Answers

Answer:Earth's protective magnetic bubble, called the magnetosphere, deflects most solar particles. ... The International Space Station cruises through low-Earth orbit, within Earth's protection, and the station's hull helps shield crew members from radiation too.

have a nice day

Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The half-life of phosphorus-32 is 14.3 days. What mass of phosphorus-32 is left from an original sample of 175 mg of Na332PO4 after 35.0 days

Answers

Answer: The mass of P-32 left from the original sample is 32.07 mg

Explanation:

All radioactive decay processes follow first-order reactions.

Calculating rate constant for first order reaction using half life:

[tex]t_{1/2}=\frac{0.693}{k}[/tex] .....(1)

[tex]t_{1/2}[/tex] = half life period = 14.3 days

k = rate constant = ?

Putting values in equation 1:

[tex]k=\frac{0.693}{14.3days}\\\\k=0.0485days^{-1}[/tex]

The integrated rate law equation for first-order kinetics:

[tex]k=\frac{2.303}{t}\log \frac{a}{a-x}[/tex] ......(2)

Given values:

a = initial concentration of reactant = 175 mg

a - x = concentration of reactant left after time 't' = ? mg

t = time period = 35.0 days

Putting values in equation 2:

[tex]0.0485days^{-1}=\frac{2.303}{35.0 days}\log (\frac{175}{a-x})\\\\\log (\frac{175}{a-x})=\frac{0.0485\times 35.0}{2.303}\\\\\log (\frac{175}{a-x})=0.737\\\\\frac{175}{a-x}=10^{0.737}\\\\a-x=\frac{175}{5.457}=32.07mg[/tex]

Hence, the mass of P-32 left from the original sample is 32.07 mg

How much energy is released when 2.25kg of water cools from 99.5°C to 4.2°C? 1000g=1kg; 1000J=1kJ; specific heat of water 4.184J/g°C. q=mc∆T

Answers

Answer:

897154.2 J

Explanation:

Applying,

q = mcΔT.............. Equation 1

Where q = amount of energy released, m = mass of water, c = specific heat capacity of water, ΔT = Change in temperature

From the question,

Given: m = 2.25 kg = 2250 g, c = 4.184 J/g°C, ΔT = (4.2-99.5) = -95.3°C

Substitute these values into equation 1

q = 2250(4.184)(-95.3)

q = -897154.2 J

q =

Hence the amount of heat released is 897154.2 J

2. Which of the following equations represents a neutralization reaction?

a. H2CO3 + H2O + CO2

b. 2H2O2 → 2H2O + O2

c. Ba(NO3)2 + K2CO3 →
BaCO3 + 2KNO3

d. HNO3 + NaOH → NaNO3 + H2O

Answers

Answer:

d. HNO3 + NaOH → NaNO3 + H2O

Explanation:

Hello there!

In this case, according to the given chemical reactions, it turns out necessary for us to recall the definition of neutralization reaction as those whereby an acid reacts with a base, that is why a, b and c are not within the aforementioned description.

In such a way, we infer the reaction is d. HNO3 + NaOH → NaNO3 + H2O since HNO3 is the acid and NaOH the base.

Regards!

When 20 grams of KCIO3, is dissolved in 100 grams of water, the solution can be
described as.............if the solubility equals 53.3g/100g H20.
a. Saturated
c. supersaturated
b. unsaturated
d. concentrated

Answers

Answer:

b. unsaturated .

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the definition of each type of solution:

- Supersaturated solution: comprises a large amount of solute at a temperature at which it will be able to crystalize upon standing.

- Unsaturated solution: is a solution in which a solvent is able to dissolve any more solute at a given temperature.

- Saturated solution can be defined as a solution in which a solvent is not capable of dissolving any more solute at a given temperature.

In such a way, since 20 grams of the solute are less than the solubility, we infer this is b. unsaturated, as 33.3 grams of solute can be further added to the 100 grams of water.

Regards!

Question 13 of 32

The pH of a sample of seawater is 8.0. What is the hydrogen ion concentration of seawater?

A. 8.0 M
B. 1 x 108 M
C. 6.0 M
D. 1 x 10-8 M​

Answers

Answer:

D

Explanation:

Mark Brainliest please

Answer is D

Explanation

We know that pH=−log[H^+]

pH=8

Thus, 8= −log[H^+]

Hence [H+]=10^−8

Thus, concentration of H^+ is 10^−8M

In which of the following molecules is hydrogen bonding likely to be the most significant component of the total intermolecular forces??

a. C6H13NH2
b. CH3OH
c. CH4
d. C5H11OH
e. CO2

Answers

Answer:

The given molecules are:

a. C6H13NH2

b. CH3OH

c. CH4

d. C5H11OH

e. CO2

Explanation:

The hydrogen bond is a weak electrostatic force of attarction that exists between covalently bonded hydrogen (of -OH or -NH2 or HF) with a highly electronegative atom like N,O and F.

Hydrogen bonding is of two types:

Intermolecular hydrogen bond (exists between two molecules)

Intramolecular hydrogen bond(exists within a molecule).

For example intermolecular hydrogen bond in water is shown below:

Among the given options,

a. C6H13NH2 has -NH2 linkage which leads to hydrogen bond formation.

b. CH3OH has -OH bond and it leads to hydrogen bond fomation.

d. C5H11OH has also -OH bond and it leads to hydrogen bond fomation.

Reamining molecules, CH4 and CO2 do not form hydrogen bond.

Hence, answer is:

options a,b,d.

What is homeostasis?
a.
production of urine.
b.
maintaining a stable internal environment.
c.
excretion of waste materials.
d.
none of the above.


Please select the best answer from the choices provided

Answers

Answer:

the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes.

Explanation:

Reactants which do not continue to completion are called reactants

Answers

There called reversible reactions

The formula weight of a compound is determined by adding up the individual weights of every _______ in that compound.

A. proton

B. molecule

C. atom

D. formula unit

Answers

Answer:

C. Atom

The formula weight is calculated by the sum( adding) of the atomic masses for every atom in the formula

What is the mass of NaCl required to make 150 grams of a 12% solution of NaCl in water? (5 points)

a
13 grams

b
18 grams

c
22 grams

d
32 grams

Answers

Answer:

18 grams

Explanation:

Mass of solution = 150 g

Percent concentration = 12%

Percent concentration = mass of solute/mass of solution × 100

Let the mass of solute be x

12= x/150 × 100

12= 100x/150

12 × 150 =100x

x= 12 × 150/100

x = 18 g

Answer:

18

Explanation:

Mass of solution = 150 g

Percent concentration = 12%

Percent concentration = mass of solute/mass of solution × 100

Let the mass of solute be x

12= x/150 × 100

12= 100x/150

12 × 150 =100x

x= 12 × 150/100

x = 18 g

Iodine-131 is administered orally in the form of NaI(aq) as a treatment for thyroid cancer. The half-life of iodine-131 is 8.04 days. If you begin with 34.7 mg of this isotope, what mass remains after 8.52 days have passed

Answers

Answer:

16.6 mg

Explanation:

Step 1: Calculate the rate constant (k) for Iodine-131 decay

We know the half-life is t1/2 = 8.04 day. We can calculate the rate constant using the following expression.

k = ln2 / t1/2 = ln2 / 8.04 day = 0.0862 day⁻¹

Step 2: Calculate the mass of iodine after 8.52 days

Iodine-131 decays following first-order kinetics. Given the initial mass (I₀ = 34.7 mg) and the time elapsed (t = 8.52 day), we can calculate the mass of iodine-131 using the following expression.

ln I = ln I₀ - k × t

ln I = ln 34.7 - 0.0862 day⁻¹ × 8.52 day

I = 16.6 mg

how many moles of H2o are equivelant to 97.3g h2o

Answers

Answer:

Number of mole in H2O = 5.4 moles

Explanation:

Given:

Mass of H2O = 97.3 gram

Find:

Number of mole in H2O

Computation:

We know that molar mass of H2O = 18 g/mole

So,

Number of mole = Given Mass / Molar mass

Number of mole in H2O = Mass of H2O / Molar mass of H2O

Number of mole in H2O = 97.3 / 18

Number of mole in H2O = 5.4055

Number of mole in H2O = 5.4 moles

What type of reaction is rusting?
O A. Decomposition
O B. Double-displacement
O C. Single-displacement
OD. Oxidation-reduction

Answers

The reaction of rusting is D Oxidation reduction

Two planets have similar masses but differ in their distances from the Sun.
Which planet experiences a greater gravitational force with the Sun?
A. The planet that is smaller in volume
B. The planet that is larger in volume
C. The planet that is farther from the Sun
D. The planet that is closer to the Sun

Answers

Answer:

D. The planet that is closer to the Sun

The maximum number of moles of compound E that may be formed in the following reaction is: ЗА + 5B + c 个 2E Initial moles: n(A)=0.20 n(B)=0.30 n(C)=0.10​

Answers

Answer:

E=1.1

Explanation:

let's consider moles of E is X

3(0.20)+5(0.30)+0.10 =2X

2.2=2X

x=1.1

Upon decomposition, a sample of sodium bicarbonate produces 0.0118 g of sodium carbonate, Na2CO3. How many grams of water does it produce

Answers

Answer:

2.00 × 10⁻³ g

Explanation:

Step 1: Write the balanced decomposition reaction

2 NaHCO₃ ⇒ Na₂CO₃ + CO₂ + H₂O

Step 2: Calculate the moles corresponding to 0.0118 g of Na₂CO₃

The molar mass of Na₂CO₃ is 105.99 g/mol.

0.0118 g × 1 mol/105.99 g = 1.11 × 10⁻⁴ mol

Step 3: Calculate the moles of H₂O produced with 1.11 × 10⁻⁴ moles of Na₂CO₃

The molar ratio of Na₂CO₃ to H₂O is 1:1. The moles of H₂O produced are 1/1 × 1.11 × 10⁻⁴ mol = 1.11 × 10⁻⁴ mol.

Step 4: Calculate the mass corresponding to 1.11 × 10⁻⁴ moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

1.11 × 10⁻⁴ mol × 18.02 g/mol =  2.00 × 10⁻³ g

the density of gold is 19.3 g/ml. if you had a cube made of pure gold that weighs 58.1 pounds what would be the lengh of a side of this cube

Answers

Answer:

11.1 cm

Explanation:

First we convert 58.1 pounds into grams:

58.1 lb * [tex]\frac{453.592g}{1lb}[/tex] = 26353.69 g

Then we calculate the volume of the gold cube, using the given density:

26353.69 g ÷ 19.3 g/mL = 1365.48 mL

1365.48 mL is equal to 1365.48 cm³.

With the volume of a cube we can calculate the side length:

Length = ∛(1365.48 cm³) = 11.1 cm
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