An atom's first 2 energy levels are filled and there are 2 electrons in the third energy
level. It's atomic number is:

Explanation:

the carbon would be sp3 hybridized, and it doesn't matter which carbon, since either of them have a full octet

Answer:

D. all of the above

Explanation:

A and C are verified by Keplar's laws of planetary motion.

B is verified by the equatorial and polar aces of the Planet.

Answer:

c

Explanation:

they dont have to orbit the sun specifically and are commonly more ovoid than spherical

Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

Answer: 0.085 (Ms)⁻¹

Explanation: Half life = 12 s

is the initial concentration = 0.98 M

Half life expression for second order kinetic is:

k = 0.085 (Ms)⁻¹

The rate constant for this reaction is 0.085 (Ms)⁻¹ .

Answer:

The left side equation is:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Explanation:

For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is

[tex]HCH_{3}COO + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H_{3}O[/tex]

The left side of this equilibrium constant equation will be written as shown below:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Answer:

2

Explanation:

Lead(|V) fluoride

Ammonium Nitrate

Lithium sulfide

For the rules, I don't know what you were taught. I just do it intuitively since I have done so much chemistry.

The first one the roman numerals represents the charge of the lead which much match the 4- charge from the 4 fluorides.

The second one is just two polyatomic ions which you just have to remember.

The last one is the typical ionic compound naming technique i guess.

Answer:

Solution given:

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

Answer:

I think you can make 26, hope this helped.

Explanation:

Answer:

Option A. 1:1

Explanation:

From the question given above, the following data were obtained:

Li => 1s² 2s¹

Cl => 1s² 2s²2p⁶ 3s²2p⁵

Lithium (Li) will form compound with Cl by losing 1 electron as shown below:

Li —> Li⁺ + e¯ ..... (1)

Cl on the other hand will accept 1 electron from Li to form the chloride ion, Cl¯ as shown below:

Cl + e¯ —> Cl¯ ...... (2)

Combining equation 1 and 2, we have:

Li + Cl + e¯ —> Li⁺ + Cl¯ +

Cancel e¯ from both side

Li + Cl —> Li⁺Cl¯

Thus, the ratio of metallic cation (+) to non-metallic anion (-) in the compound is 1:1

``````````````````````````````````

Answer:

Explanation:

The reaction between 2 chloro- 2 methyl pentane and sodium iodide takes place through SN2 mechanism . iodide ion is the nucleophile which attacks the substrate . The rate of such reaction depends upon concentration of both the nucleophile and the substrate .

Hence rate of reaction will be increased by 2 x 2 = 4 times.

option D ) is correct.

Explanation:

The given reaction represents the reaction between a tertiary alkyl halide that is 2-chloro-2-methylpentane and a nucleophile that is NaI.

This reaction favors SN1 mechanism which has order one.

So, the given reaction follows first-order kinetics.

For a first-order reaction, the rate law is:

rate =k [A]

That means the rate of the reaction is dependent on the concentration of reactants.

So, when the concentration of the reactant is doubled then, the rate of the reaction is also doubled.

Among the given options the correct answer is option B) It would double the rate.

Answer:

[tex]\Delta G=-541.4kJ/mol[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:

[tex]H_2+F_2\rightarrow 2HF[/tex]

Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:

[tex]\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol[/tex]

Regards!

Answer: Mendeleev predicted elements that would later be discovered.

Answer:

a

Explanation:

Beer-Lambert Law shows the relationship between the factors affecting the absorbance of a sample in relation to the concentration. These factors are:

the concentration c, path length (l), and the molar absorptivity (ε).

As a result, more radiation is assimilated as the concentration rises, and the absorbance rises as well. However, the longer the path length, the increase in the number of molecules and the higher the absorbance.

Thus, the straight-line equation for Beer-Lambert's law is:

A = εcl

From the above explanation, the option that doesn't relate to the deviations from linearity of Beer's law plot is in Option (a).

Answer:

Its atomic number is 14 and its atomic mass is 28. The most common isotope of uranium has 92 protons and 146 neutrons. Its atomic number is 92 and its atomic mass is 238 (92 + 146).

Noble gas elements are almost always found as a single atom in nature.

An inert gas is a gas that does not undergo chemical reactions under a set of given conditions. The noble gases often do not react with many substances and were historically referred to as inert gases.

All noble gases have the maximum number of electrons in their outer shell; i.e. 2 electrons for helium and 8 for the other five.

Noble gases are monoatomic, which means they exist as single atoms. This is because of their electronic stability.

Thus, noble gas elements are almost always found as a single atom in nature. Hence, option C is correct.

Learn more about the inert gas here:

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Answer:

they are the end results so they are after the yields symbol

Explanation:

Answer:

False

Explanation:

Because Elaidic acid is an isomer of oleic acid. I really hope this helps you.

Answer:

the weakest base will have a higher Kb value since it will be closer to an acid than a base

7 kb values represents the weakest base.

Kb is the base dissociation constant which is a measure of how completely a base dissociates into its component ions in water. pKb is define as the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

Ka is define as the acid dissociation constant while pKa is the -log of this constant. Kb is define as the base dissociation constant, while pKb is the -log of the constant.

The acid and base dissociation constants are usually expressed in terms of moles per liter (mol/L).

Thus, 7 kb values represents the weakest base.

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Answer:

The pH is greater than 7 at the equivalence point.

Explanation:

Equivalence point is the point where the acid reacts with the base as stipulated in the equation of the reaction.

When a weak acid and a strong base are titrated, the pH of the solution at equivalence point is actually found to be around about pH ~ 9.

Hence, for a weak acid and strong base titration, The pH is greater than 7 at the equivalence point.

A titration between a weak acid and a strong base yields a solution whose pH is greater than 7 at the equivalence point.

Weak acids are acids which only ionize partially in aqueous solutions.

When weak acids are dissolved in water, they produce only few hydrogen ions.

A strong base on the other hand ionizes completely to produce hydroxide ions in aqueous solutions.

The titration of a weak acid and a strong base gives a solution whose pH is greater than 7 at equivalence point.

Learn more about equivalence point at: https://brainly.com/question/18933025

Answer:

[tex]d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

[tex]d=\frac{m}{V}[/tex]

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

[tex]m=552.4g-464.7g=87.7g[/tex]

So that we are now able to calculate the density in g/mL first:

[tex]d=\frac{87.7g}{27.8mL}=3.15g/mL[/tex]

Now, we proceed to the conversion to lb/in³ by using the following setup:

[tex]d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Regards!

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

[tex]= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6[/tex]

Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

Answer:

Four common types of reactions involving carbonyl reactions: 1) nucleophilic addition; 2) nucleophilic acyl substitution; 3) alpha substitution; 4) carbonyl condensations. The first two were previously discussed and the second two involve the properties of the carbon directly adjacent to the carbonyls, α carbons.

Alpha-substitution reactions results in the replacement of an H attached to the alpha carbon with an electrophile.  

The nucleophile in these reactions are new and called enols and enolates.

Explanation:

The carbon in the carbonyl is the reference point and the alpha carbon is adjacent to the carbonyl carbon.  

Hydrogen atoms attached the these carbons denoted with Greek letters will have the same designation, so an alpha hydrogen is attached to an alpha carbon.  

Aldehyde hydrogens not given Greek leters.  

α hydrogens display unusual acidity, due to the resonance stabilization of the carbanion conjugate base, called an enolate.  

Tautomers are readily interconverted constitutional isomers, usually distinguished by a different location for an atom or a group, which is different than resonance.  

The tautomerization in this chapter focuses on the carbonyl group with alpha hydrogen, which undergo keto-enol tautomerism.  

Keto refers to the tautomer containing the carbonyl while enol implies a double bond and a hydroxyl group present in the tautomer.  

The keto-enol tautomerization equilibrium is dependent on stabilization factors of both the keto tautomer and the enol tautomer, though the keto form is typically favored for simple carbonyl compounds.  

The 1,3 arrangement of two carbonyl groups can work synergistically to stabilize the enol tautomer, increasing the amount present at equilibrium.

The positioning of the carbonyl groups in the 1,3 arrangement allows for the formation of a stabilizing intramolecular hydrogen bond between the hydroxyl group of the enol and the carbonyl oxygen as well as the alkene group of the enol tautomer is also conjugated with the carbonyl double bond which provides additional stabilization.

Aromaticity can also stabilize the enol tautomer over the keto tautomer.

Under neutral conditions, the tautomerization is slow, but both acid and base catalysts can be utilized to speed the reaction up.  

Biological enol forming reactions use isomerase enzymes to catalyze the shifting of a carbonyl group in sugar molecules, often converting between a ketose and an aldose in a process called carbonyl isomerization.

Answer:

Cu+(aq)--->Cu2+(aq) + e- : oxidation

reason: there is loss of electrons.

I2(s) + 2e--->2I-(aq) : reduction

reason: There is reduction of electrons.

Answer:

The correct approach is "12.25°C".

Explanation:

Given:

Mass of lead,

mc = 245 g

Initial temperature,

tc = 300°C

Mass of Aluminum,

ma = 150 g

Initial temperature,

ta = 12.0°C

Mass of water,

mw = 820 g

Initial temperature,

tw = 12.0°C

Now,

The heat received in equivalent to heat given by copper.

The quantity of heat = [tex]m\times s\times t \ J[/tex]

then,

⇒ [tex]245\times .013\times (300-T) = 150\times .9\times (T-12.0) + 820\times 4.2\times (T-12.0)[/tex]

⇒             [tex]3.185(300-T) = 135(T-12.0) + 3444(T-12.0)[/tex]

⇒             [tex]955.5-3.185T=135T-1620+3444T-41328[/tex]

⇒                         [tex]43903.5 = 3582.185 T[/tex]

⇒                                  [tex]T = 12.25^{\circ} C[/tex]

Answer:

1.27 × 10⁵ L

Explanation:

Step 1: Given data

Step 2: Convert the temperatures to the Kelvin scale

We will use the following expression.

K = °C + 273.15

K = 21 °C + 273.15 = 294 K

K = -48 °C + 273.15 = 225 K

Step 3: Calculate the final volume of the balloon

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂/ T₁ × P₂

V₂ = 745 Torr × 1.41 × 10⁴ L × 225 K/ 294 K × 63.1 Torr

V₂ = 1.27 × 10⁵ L

Answer:

no

Explanation:

Fluoride is not nucleophilic (having the tendency to donate electrons) enough to allow for the use of HF to cleave ethers in protic media(protic solvents are polar liquid compounds that have dissociable hydrogen atoms). The rate of reaction is comparably low, so that heating of the reaction mixture is required.

Answer:

See explanation

Explanation:

Isomers are molecules which have the same molecular formula but different structural formulas. Sometimes, isomers may even contain different functional groups.

The formula C2H6O may refer to an ether or an alcohol. The compound could be CH3CH2OH(ethanol) or CH3OCH3(methoxymethane).

Hence, the functional isomers of the formula C2H6O are ethanol and methoxymethane.

Answer:

[tex]V_2= 736mL[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the combined gas law:

[tex]\frac{P_2V_2}{T_2}= \frac{P_1V_1}{T_1}[/tex]

Thus, we solve for the final volume by solving for V2 as follows:

[tex]V_2= \frac{P_1V_1T_2}{T_1P_2}[/tex]

Now, we plug in the variables to obtain the result in milliliters and making sure we have both temperatures in Kelvins:

[tex]V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}\\\\V_2= \frac{1.20atm*735mL*279K}{(112+273)K*660/760atm}=736mL[/tex]

Regards!