An object travels 4 km from A to B towards north and then 3 km from B to C towards west. Find its displacement.​

Answers

Answer 1

QUËSTIONS:-

An object travels 4 km from A to B towards north and then 3 km from B to C towards west. Find its displacement.

ANSWER:- displacement

[tex] {x}^{2} = {3 }^{2} + {4}^{2} \\ {x}^{2} = 9 + 16 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5[/tex]

displacement = 5 km

Answer 2

Explanation:

We nee to use triangle law

As displacement is the shortest path travelled, we take A-C

so, D=√4^2+3^2

D=5km

An Object Travels 4 Km From A To B Towards North And Then 3 Km From B To C Towards West. Find Its Displacement.

Related Questions

A block of mass m is moved over a distance d. An applied force F is directed perpendicularly to the block’s displacement. How much work is done on the block by the force F?​

Answers

zero

Explanation:

Work W is defined as

W = Fd = Fdcos(theta)

and it is a dot product of the force and displacement and theta is angle between F and d Since the force is perpendicular to d, angle is 90° thus cos90 = 0. Hence work is zero.

What are the messing forces that would make the object be in equilibrium?

Answers

Answer:

A) 20 N, B) 20 N, & C) 8 N

Explanation:

For the object to be in equilibrium, the upward forces must be equal to the downward forces and the forward forces must be equal to the backward forces.

1. Determination of A and B.

Forward forces = Backward forces

A + 10 + B = 25 + 25

A + 10 + B = 50

Collect like terms

A + B = 50 – 10

A + B = 40

Assume A and B to be equal. Thus, A is 20 N and B is 20 N.

2. Determination of C

Upward forces = Downward forces

C + 112 = 20 + 100

C + 112 = 120

Collect like terms

C = 120 – 112

C = 8 N

Thus, for the object to be in equilibrium, A must be 20 N, B must be 20 N and C must be 8N.

A string that is under 50.0N of tension has linear density 5.0g/m. A sinusoidal wave with amplitude 3.0cm and wavelength 2.0m travels along the string. What is the maximum speed of a particle on the string

Answers

Answer:

9.42 m/s

Explanation:

Applying,

V' = Aω.............. Equation 1

Where V' = maximum speed of the string, A = Amplitude of the wave, ω = angular velocity.

But,

ω = 2πf................. Equation 2

Where f = frequency, π = pie

And,

f = v/λ................ Equation 3

Where, λ = wave length, v = velocity

Also,

v = √(T/μ)................. Equation 4

Where T = Tension, μ = linear density.

From the question,

Given: T = 50.0 N, μ = 5.0 g/m = 0.005 kg/m

Substitute into equation 4

v = √(50/0.005)

v = √(10000)

v = 100 m/s

Also Given: λ = 2.0 m

Substitute into equation 3

f = 100/2

f = 50 Hz.

Substitute the value of f into equation 2

Where π = constant = 3.14

ω = 2(3.14)(50)

ω = 314 rad/s

Finally,

Given: A = 3.0 cm = 0.03 m

Substitute into equation 1

V' = 0.03(314)

V' = 9.42 m/s

Deciding on the narrative point of views mean that an author must choose

Answers

Answer:

from which perspective the story is being told to the reader

Explanation:

i.e. first person on through third person or narrated.

Answer:

Deciding on the narrative point of views mean that an author must choose who is telling the story. 

Explanation:

A narrative point of view is when the narrator becomes the character of the story who also knows the emotions or feelings and thoughts of the character. The narrator can be the first person or can be the third person depending on the characters included in the story.

a. A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation.

1. the force of the horse pulling on the cart
2. the force of the cart pulling on the horse
3. the force of the horse pushing on the road
4. the force of the road pushing on the horse

b. Suppose that the horse and cart have started from rest; and as time goes on, their speed increases in the same direction. Which one of the following conclusions is correct concerning the magnitudes of the forces mentioned above?

1. Force 1 exceeds Force 2.
2. Force 2 is less than Force 3.
3. Force 2 exceeds Force 4.
4. Force 3 exceeds Force 4.
5. Forces 1 and 2 cannot have equal magnitudes.

Answers

Answer:

a) F₁ = F₂,  F₃ = F₄,  b)  the correct answer is 3

Explanation:

a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies

Forces 1 and 2 are action and reaction forces F₁ = F₂

Forces 3 and 4 are action and reaction forces F₃ = F₄

as it indicates that the

b) how the car increases if speed implies that force 1> force3

      F₁ > F₃

therefore the correct answer is 3

A 8.37*10^-5 F capacitor has 2.15*10^-4 C of charge on its plates. How much energy is stored on the capacitor

Answers

Answer:

2.76*10^-4

Explanation:

Trust me :)

Two thin conducting plates, each 56.0 cm on a side, are situated parallel to one another and 7.0 mm apart. If 10^-10 electrons are moved from one plate to the other, what is the electric field between the plates?

Answers

Answer:

[tex]E=576.5V/m[/tex]

Explanation:

From the question we are told that:

Length [tex]l=56.0cm=0.56m[/tex]

Distance apart [tex]d=7.0mm=0.007m[/tex]

Electron Transferred [tex]n=10^{-10}[/tex]

Therefore

Total Charge

Since Charge on each electron is

[tex]e=1.602*10^{-19}[/tex]

Therefore

[tex]T=1.602*10^{-19} *10^{10}[/tex]

[tex]T=1.602*10^{-9}[/tex]

Generally the equation for Charge density is mathematically given by

[tex]\rho=T/A[/tex]

Where

Area

[tex]A=0.56*0.56[/tex]

[tex]A=0.3136[/tex]

Therefore

[tex]\rho=1.602*10^{-9}/0.3136[/tex]

[tex]\rho=5.10*10^{-9}[/tex]

Generally the equation for Electric Field in the capacitor is mathematically given by

[tex]E=\frac{\rho}{e_0}[/tex]

[tex]E=\frac{5.10*10^{-9}}{8.85x10{-12}}[/tex]

[tex]E=576.5V/m[/tex]

how to reduce fluid friction

Answers

Answer:

By making the object sharp pointed

What is the magnitude of vector X?​

Answers

Explanation:

by using Pythagoras theorem

h²=p²+b²

z²=Y²+x²

x²=75²-21²

x=√5184

x=72cm is the magnitude of vector X

hope it helps

stay safe healthy and happy.

Which two factors affect the electric force between two particles?
A. The distance between them
B. Their charges
C. The strong nuclear force
D. Gravitational force
E. Their mass

Answers

Answer:

a the distance between the

What is energy?
Select one:

A force that must be exerted in order to accelerate an object.

A property that must be transferred to perform work.

A particle that can be absorbed to change momentum.

A system that can be rearranged in order to change its state.

Answers

Answer:

Energy is:

A property that must be transferred to perform work.

Answer:

Energy

Explanation:

A property that must be transferred to perform work .

Hope it is helpful to you Stay safe healthy and happy ☺️

A 1250-kg compact car is moving with velocity v1 =36.2i^+12.7j^m/s. It skids on a frictionless icy patch and collides with a 448-kg hay wagon moving with velocity v2=13.8i^+10.2j^m/s.

If the two stay together, what is their velocity?
Express your answer in meters per second in terms of i^ and j^. Use the 'unit vector' button to denote unit vectors in your answer.

Answers

Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:

(1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s) = ((1250 + 448) kg) v

where v is the velocity of the system. Solve for v :

v = ((1250 kg) ((36.2 i + 12.7 j ) m/s) + (448 kg) ((13.8 i + 10.2 j ) m/s)) / (1698 kg)

v ≈ (30.3 i + 12.0 j ) m/s

A giant chorus of 1000 vocalists is singing the same note. Suddenly, 999 vocalists stop,leaving one soloist. By how many decibels does the sound intensity level decrease? Explain.

Answers

Answer:

The decrease in decibels is 0.1 dB.

Explanation:

Let the intensity of one chorus is Io.

let the intensity of 1000 vocalist is dB.

The intensity of 1000 vocalist is 1000 Io.

[tex]dB = 10log\frac{1000Io}{Io}=30[/tex]..... (1)

let the intensity of 999 vocalist is dB'.

[tex]dB' = 10log\frac{999Io}{Io}=29.9[/tex]..... (2)

So, the change is

= dB - dB' = 30 - 29.9 = 0.1 dB

The cycle is a process that returns to its beginning, but it does not repeat
itself.
True
False

Answers

False. It does repeat itself

A hoop rolls with constant velocity and without sliding along level ground. Its rotational kinetic energy is:______a- half its translational kinetic energyb- the same as its translational kinetic energyc- twice its translational kinetic energyd- four times its translational kinetic energy

Answers

Answer:

The same as its translational KE.

The easy way to do this is to make up numbers and use them.

So, I'll say m=2 and r=3. I will also say v=3 .

Rot. Inertia of a hoop is mr^2. So the rot KE is: 1/2 (mr^2)(w^2)

note: (1/2*I*w^2)

Translational kinetic energy is basically normal KE, so 1/2(m)(v^2)

Now, lets plug our made up values in:

Rot Ke : 1/2 (9*2)(3/3) *note w = v/r

Tran Ke: 1/2(2)(9)

Rot Ke: 9

Tran Ke: 9

9=9, same.

A block with length of 1.5m,width 1=1m,height=0.5m and mass 300kg.what is the pressure at the bottom surface of the block

Answers

Answer:

Find The area and calculate pressure.

Explanation:

A pilot wishes to fly from Bayfield to Kitchener, a distance of 100 km on a bearing of 105°. The speed of the plane in still air is 240 km/h. A 20 km/h wind is blowing on a bearing of 210°.
Remembering that she must fly on a bearing of 105° relative to the ground (i.e. the resultant must be on that bearing), find (6 marks)
a) the heading she should take to reach her destination.
b) how long the trip will take.

Answers

Here is are by step :) hope this helps

First things first, you want the resultant to be in the direction of the bearing of 105 °. The distance required is irrelevant for question 1.

You want the addition of the wind speed and the planes velocity to equal some resultant in the direction one 105 °. Draw a parallelogram (vector addition) of the resultant (the 100km in direction 105°) and the wind speed. The diagonal that results from the vector addition will equal 240. You only know the angle between the resultant and the wind speed right now (105°).

https://www.geogebra.org/geometry/rbejhvta

What is the angle between the resultant (the direction we want to travel) and the direction the plane will actually go when wind speed is taken into accound???

Law of sines.

You said you have it, so we will continue under the assumption you got 4.617°.

now, take into account that the plane is accelerating 4.617° off of the 105° bearing in order to travel on the 105° bearing when wind speed is taken into account... what heading is the plane taking? 105° - 4.617° = 100.4°

There is part 1.

now you simply need to find the actual speed she is travelling along the bearing 105°. (she is traveling 240km/h with a 100.4° heading, find the correct speed for the resultant).

EDIT: The representation says 105.1°, it is supposed to say 105°

Using only astronomical data from the Appendix E in the textbook, calculate the speed of the planet Venus in its essentially circular orbit around the sun.
Venus = 4.87x10^24

Answers

Answer:

[tex]v=3.49\times 10^4\ m/s[/tex]

Explanation:

Given that,

Mass of Venus, [tex]M_V=4.87\times 10^{24}\ kg[/tex]

We know that,

Mass of Sun, [tex]M_s=1.98\times 10^{30}\ kg[/tex]

The distance between the center of Sun and the center of Venus is [tex]1.08\times 10^{11}\ m[/tex]

We need to find the peed of the planet Venus in its essentially circular orbit around the sun. using the formula,

[tex]v=\sqrt{\dfrac{GM_s}{r}}[/tex]

Put all the values,

[tex]v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.98\times 10^{30}}{1.08\times 10^{11}}}\\\\v=3.49\times 10^4\ m/s[/tex]

So, the speed of the planet venus is [tex]3.49\times 10^4\ m/s[/tex].

Sunsets are a deep red because A) tiny particles in the air are more efficient at scattering short wavelength light than they are at scattering long wavelength light. Hence, long wavelength light ends up coming directly towards you. B) most polluting gases and dust particles in the air are reddish in color and lend their color to that of the sky. C) air molecules absorb red light more efficiently than they do blue light because of their electron orbitals. D) air molecules absorb blue light more efficiently than they do red light because of their electron orbitals.

Answers

Answer:

i think its A

Answer:tiny particles in the air are more efficient at scattering short wavelength light than they are at scattering long

Explanation:

On page 14 of the call of the wild jack London, writes,in vague ways he remembered back to the youth of the breed ,this statement is example of

Answers

Answer:

On page 14 of the call of the wild jack London, writes,in vague ways he remembered back to the youth of the breed ,this statement is example of the racial unconscious. As a general rule, really great novels contain universal truths. 

Explanation:

Hey mate dont worry! My answer is correct!!

Answer:

racial unconscious

Explanation:

took the test and it was correct

A surfactant with a Hydrophile-
Lipophile Balance (HLB) value of 18 is expected to function as a solubilizing agent
O False
O True​

Answers

Answer:

Explanation:

True

The Best answer from the options is TRUE

A surfactant with a Hydrophile-lipophile Balance value of 18 is a solubilizing agent because a hydrophilic-lipophilic balance is used to measure the degree /level of hydrophilicness or liphophilicness of a Surfactant is at . and the

method used by the Hydrophile-lipophile balance to achieve this is by calculating the values for the different regions of the surfactant.

Hence a Surfactant with a hydrophile-lipophile Balance value of 18 is expected to function as a solubilizing agent.

Attached below is the HLB

Learn more : https://brainly.com/question/11338364

What is the equivalent resistance of a circuit that contains two 50.0 0
resistors connected in series to a 12.0V battery?

Answers

Answer:

the correct answer is A :)

Which option is the best blackbody radiator?

A.
The Sun

B.
A red laser pointer

C.
A tennis ball

D.
Boiling water

Answers

Answer:

A. The Sun

Explanation:

The Sun is to be considered a perfect black body.

Mixed powders may be categorized as​

Answers

Answer:

on  flow properties and free-flowing and cohesive.

Explanation:

the power Free flowing powders do not cling together, as cohesive powders stick to each other and form that do not disperse well during mixing

1. Convert the following length into meters
a. 123.50mm
b. 560cm
c. 100dm
d. 125.89km​

Answers

I don’t really know this either

A boy throws a ball straight up with a speed of 21.5 m/s. The ball has a mass of 0.19 kg. How much gravitational potential energy will the ball have at the top of its flight? (Assume there is no air resistance.) A. 43.9 J B. 37.5 J C. 48.5 J D. 41.2 J​

Answers

Answer:

Explanation:

The equation fo potential energy is PE = mgh, where m is the mass of the ball, g is the pull of gravity (constant at 9.8), and h is the max height of the ball. What we do not have here is that height. We need to first solve for it using one-dimensional equations. What we have to know above all else, is that the final velocity of an object at its max height is always 0. That allows us to use the equation

[tex]v_f=v_0+at[/tex] where vf is the final velocity and v0 is the initial velocity. We will find out how long it takes for the object to reach that max height first and then use that time to find out what that max height is. Baby steps here...

0 = 21.5 + (-9.8)t and

-21.5 = -9.8t so

t = 2.19 seconds (Keep in mind that if I used the rules correctly for sig fig's, the answer you SHOULD get is not one shown, so I had to adjust the sig fig's and break the rules. But you know what they say about rules...)

Now we will use that time to find out the max height of the object in the equation

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in:

Δx = [tex]21.5(2.19)+\frac{1}{2}(-9.8)(2.19)^2[/tex] which simplifies down a bit to

Δx = 47.1 - 23.5 so

Δx = 23.6 meters.

Now we can plug that in to the PE equation to find the PE of the object:

PE = (.19)(9.8)(23.6) so

PE = 43.9 J

instrument used in measurement Amount of substance

Answers

Answer:

For liquids: A measuring cylinder is used.

For solid: Over flow can is used

Answer:

i think a measuring cylinder

The image shows the right-hand rule being used for a current-carrying wire.

An illustration with a right hand with fingers curled and thumb pointed up.

Which statement describes what the hand shows?

When the current flows down the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
When the current flows down the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.
When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.

Answers

D PLS MARK ME AS BRAINLY

Answer:

The answer is (D): When the current flows up the wire, the magnetic field flows in on the left side of the wire and out on the right side of the wire.

Explanation:

A train moves with a uniform velocity of 36km/hr 10sec. calculate the distance travelled​

Answers

Given:-

Speed = 36 km/hr

converting speed into m/s

Speed = 36*5/18

Speed = 10 m/s

t = 10 sec  

By using the Formula

Distance = Speed * time

D = 10*10

D = 100 m

Hope it helps....

Which one will it be

Answers

Answer:

none

Explanation:

it's to high up to be affected by the gravity

a)Zero
that is the right answer
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