Answer:
14x+3=8x+3
14x+3 -3 = 8x+3 -3
Cancels out the 3
14x = 8x
14x - 8x = 8x -8x
Cancels out the 8x
14x = 0
x = 0
Step-by-step explanation:
Andre should have collected the like terms in order to have all the variables x on one side before taking the difference.
Inequality expressionGiven the inequality expression solved by andre expressed as:
14x + 3 ≤ 8x + 3
Simplify to have:
14x - 8x ≤ 3-3
6x ≤ 0
x ≤ 0
Hence andre should have collected the like terms in order to have all the variables x on one side before taking the difference.
Learn more on inequality here: https://brainly.com/question/24372553
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!find the value of x. only type the “number”
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
Please helppppppppppppp
Answer:
101
HOPE THIS HELPS
- Todo ❤️
Step-by-step explanation:
Suplemetary angles
180-79=101
solve pls brainliest
Answer:
first put 2 in the numerator for the first blank and 2/9 in the second blank
Step-by-step explanation:
1/3 equals 3/9 and 3/9-1/9=2/9
Answer:
[tex]\frac{3}{9}[/tex]
Step-by-step explanation:
Juan envasa 60 bombones en cajas iguales y otros 60 en otras cajas más pequeñas, con cinco bombones menos en cada una. ¿Cuántas cajas ha llenado, si de las pequeñas hay una más que de las grandes?
Juan llenó 3 cajas grandes y 4 cajas pequeñas.
En esta pregunta debemos derivar ecuaciones algebraicas a partir de la información dada en el enunciado:
Diferencia entre cajas grandes y cajas pequeñas
[tex]m - n = 1[/tex] (1)
Donde:
[tex]m[/tex] - Cantidad de cajas pequeñas.[tex]n[/tex] - Cantidad de cajas grandes.Diferencia entre la cantidad de bombones en una caja grande y la cantidad de bombones en una caja pequeña
[tex]x-y = 5[/tex] (2)
Donde:
[tex]x[/tex] - Cantidad de bombones en una caja grande.[tex]y[/tex] - Cantidad de bombones en una caja pequeña.Total de bombones en cajas grandes
[tex]x\cdot m = 60[/tex] (3)
Total de bombones en cajas pequeñas
[tex]y\cdot n = 60[/tex] (4)
By (3) and (4) in (2):
[tex]\frac{60}{m} - \frac{60}{n} = 5[/tex]
[tex]60\cdot n - 60\cdot m = 5\cdot m\cdot n[/tex] (5)
By (1):
[tex]m = 1 + n[/tex]
(1) in (5):
[tex]60\cdot n - 60\cdot (1+n) = 5\cdot (1+n)\cdot n[/tex]
[tex]60 = 5\cdot n +5\cdot n^{2}[/tex]
[tex]5\cdot n^{2}+5\cdot n -60 = 0[/tex]
[tex]n^{2}+n-12 = 0[/tex]
[tex](n+4)\cdot (n-3) = 0[/tex]
La única raíz que encaja con el enunciado es [tex]n = 3[/tex]. Por (1) tenemos que [tex]m = 4[/tex].
Juan llenó 3 cajas grandes y 4 cajas pequeñas.
Invitamos cordialmente a ver este problema sobre sistemas de ecuaciones: https://brainly.com/question/12149981
Solve for x x^2 + 6x + 1 = 0
Answer:
x = -.1715 ≈ - .172 or x = -5.83
Step-by-step explanation:
x² + 6x + 1 = 0
x² + 6x = -1
Complete the square Add to both sides (1/2 of the x-term, then square it.)
x² + 6x + 9 = -1 + 9
(x + 3)(x + 3) = 8
(x + 3)² = 8
[tex]\sqrt{(x + 3)^{2}[/tex] = [tex]\sqrt{8}[/tex]
x + 3 = ± [tex]\sqrt{8}[/tex]
x = -3 ± [tex]\sqrt{8}[/tex]
x = -3 + [tex]\sqrt{8}[/tex] or x = -3 - [tex]\sqrt{8}[/tex]
x = -.1715 ≈ - .172 or x = -5.83
Here is a right angled triangle:
Work out the area of the triangle.
Answer:
6
Step-by-step explanation:
Answer:
The area is 6 because i add it and the divide it
Please help xxxxxxxx
Answer:
a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]Step-by-step explanation:
a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]
[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]
[tex]=45000\times \:10^7[/tex]
b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]
[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]
[tex]\frac{10^5}{10^2} = 10^3[/tex]
[tex]\frac{7\times \:10^3}{2}[/tex]
[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]
[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]
[tex]\frac{2^3}{2}=2^2[/tex]
[tex]7\times \:2^2\times \:5^3=3500[/tex]
1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)
Answer:
a
Step-by-step explanation:
A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST
Answer:
The kinetic energy of the car is 43,200 Joules.
Step-by-step explanation:
KE = (1/2)mv^2
KE = (1/2)(600 kg)(12 m/s)^2
KE = (1/2)(600 kg)(144 m^2/s^2)
KE = 43,200 kg*m^2/s^2 = 43,200 Joules
Answer:
Step-by-step explanation:
KE= 1/2mv^2
KE = 1/2(600) 12^2
KE = 300 * 144 = 43200J
A person in car, travelling at 90 kilometers per hour, takes 2 seconds to go past the building on the side of the road. Calculate the length of the building in meters help
Step-by-step explanation:
very simple thought experiment :
he is going 90 km/h (90 kilometers per hour), so, he moving 90 km in 1 hour.
how far is he going in just 2 seconds ?
so, we get two ratios.
90km/1 hour = 90,000 meter / 1 hour
x meter / 2 seconds
we need to bring both ratios (they are fractions) to the same dimension of the denominators, so that we can then bring them to the same denominator.
the first is dealing with an hour.
the second one with (2) seconds.
so, how many seconds are in 1 hour ?
60 seconds per minute, 60 minutes in the hour.
60×60 = 3600 seconds.
so, now we know, the first ratio is also
90,000 meter / 3600 seconds
now we need the factor to to multiply numerator and denominator with to bring 3600 down to 2.
3600 × f = 2
f = 2/3600 = 1/1800
now we get
90,000 / 3600 × (1/1800) / (1/1800) =
(90000 / 1800) / (3600 / 1800) = 50 / 2
so, 90km/h is the same speed as 50 meter / 2 seconds.
and therefore we know, the building was 50 meters long.
Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =
Step-by-step explanation:
f(x) = -3x - 8
f(-3) = -3(-3) - 8
f(-3) = 9 - 8
f(-3) = 1
- Rectangle MNOP with vertices M(-7.-2).
M(-5, -1), 0(-27), and P(-4,-8):
90° counterclockwise about the origin
Answer:
M’ = (2, -7)
N’ = (1, -5)
O’ = (7, - 2)
P’ = (8,- 4)
Step-by-step explanation:
Swap the x and y coordinates and negate the y coordinate.
M(-7, -2) swap = (- - 2, -7) = (2,-7)
N(-5, - 1) swap = (- - 1, - 5) = (1, - 5)
O(-2,-7) swap = (- -7, -2) = (7, - 2)
P(-4,-8) swap = (- - 8, - 4) = (8, - 4)
The diameter of the rear tire of a bike is 34 inches. In low gear, you need to rotate the pedals 3 times to make the rear tire rotate 360° all the way around. How far will you travel in low gear each time you rotate the pedals? (Hint: find the circumference of the tire, then divide it by the number of rotations needed of the pedals.) Round the answer to the nearest hundredth. *
PLEASE DO NOT PUT INAPPROPIATE CONTENT!!!
If we convert 0.14 x10^3 to scientific notation, which direction should the
decimal move and how spaces should it move?
Answer:
Move it to the right by 3 spaces.
Step-by-step explanation:
10^3 is 1000
On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140
the perimeter of this triangle is 46cm find x
Answer:
the value of x is 12
......
HELPPP OMGGG
10, 10, 18, 18, 10, 5, 12, 13
Find the median and mean number of hours for these students.
If necessary, round your answers to the nearest tenth.
Name 2 of the same side interior angle.
Answer:
d & e
Step-by-step explanation:
I'm assuming by "same side interior angle" they mean consecutive interior angles. I'll attach a document explaining what that is.
Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)
Which best describes the error in finding the area of the parallelogram?
15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.
The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.
Question 2
Correct the error.
A=
=
m2
Answer:
104
Step-by-step explanation:
help!! !,
is it right or not
Answer:
No
Step-by-step explanation:
The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number
Yep!!! Your correct
find the value of 4x-6y when x=3 and y= -2
Answer:
here the answer is 24
Step-by-step explanation:
answerrrrrerrr issss hereeeeeee
Answer:
0
Step-by-step explanation:
4 multiply by x(3) = 12
6 multiply by y(2) = 12
12 -12 =0
write a peacewise function for the graph
please help me
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84
Answer:
4x - 12 = 84
Step-by-step explanation:
The last answer choice is correct because when you cross-multiply:
[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]you get 4x - 12 = 84.
Therefore, the last option is correct.
Answer:
D would be the answer (4x-12=84)
Step-by-step explanation:
4/7=12/x-3
=>1/7=3/x-3
=>x-3=21
Multiplying both sides by 4
4(x-3)=4x21
=>4x-12=84
Hope this helped :)
50 POINTS PLS HELP ME I'LL MARK BRAINLIEST
Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)
x = −3, 8; n = 3
Thank you so much!!
Answer:
Step-by-step explanation:
Here we need to find a 3rd degree polynomial that has only two distinct zeros: {-3, 8}.
Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:
f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)
One such polynomial is thus
f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient. This polynomial has a double zero at x = 8 and a third zero at x = -3.
Step-by-step explanation:
The polynomial has degree 3 and two zeros: - 3 and 8.
Since it has degree 3 it should have 3 zero's.
Two possible scenarios
1. -3 has multiplicity of two:
a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant2. 8 has multiplicity of two:
a(x + 3)(x - 8)² - is the factored form of the polynomialWrite 2.04 × 10 ⁴ as an ordinary number
Answer:
20400
Step-by-step explanation:
its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400
Write two Pythagorean triplets each having one of the numbers as 5.
Answer:
3, 4, 5 and 5, 12, 13
Step-by-step explanation:
The square of the largest side is equal to the sum of the squares of the other 2 sides.
5² = 3² + 4²
13² = 5² + 12²
The 2 triplets are (3, 4, 5 ) and (5, 12, 13)
What is the constant of proportionality for the data in the table?
Answer:
30
Step-by-step explanation:
1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5
Answer:
1.) x = 2
2.) x = 5
3.) x = 9
4.) x = 0
Step-by-step explanation:
1.) -3x - 8 = -14
-3x = -6
x = 2
2.) 4x - 6 = 14
4x = 20
x = 5
3.) -3 - 3x = -30
-3x = -27
x = 9
4.) -5x + 5 = 5
-5x = 0
x = 0
