ANSWER AS FAST A POSSIBLE PLS!


156-3^2x5-8^2

Answer:

19:1

Step-by-step explanation:

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1

The ratio of defective headlights to non-defective headlights will be 19:1.

The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.

The ratio will be calculated as below:-

Ratio = 9500:500

Ratio = 19:1

Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.

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Answer:

The first one.

Step-by-step explanation:

Graph lines as if the inequalities were equal signs.

X = -3 is a vertical line at x = -3, because it's less than we shade to the left. All numbers less than -3 are to the left. The line is dashed because there is no equal to. Only less than. The line is not included in the solution set.

y = -x - 1 is a line with a y-intercept of -1 and a slope of -1. All values that are less that y are below the line. Because it's less than or equal to the line is solid.

Answer:

A

Step-by-step explanation:

The vertical line  is dotted at -3 and shaded to the left

x < -3

This gives us two choices left

A and C

The other line has a y intercept at -1 and is solid and shaded to the left

It is of the form

y ≤ mx+1  

We know the slope is negative since is goes down from left to right

The only Choice is A

Answer:

D. 50°

Step-by-step explanation:

We know that there are 3 line segments that are forming the angles. Based on that, we can safely say that each line segment is 180°. Given that, we can find the other 2 interior angles of the triangle. We know that one of the exterior angles is 90° so that interior angle also has to be 90° because both angles have to sum to 180. The 2nd exterior angle that we know is 140, so 180-140 = 40°. Since we know the other 2 angles of the triangle now and we know that all the angles of a triangle must sum to 180°, we add 90 and 40 to get 130 and then subtract that from 180 to get 50°. That would look something like this: 180-(90+40) = 180 - 130 = 50°. Hope this helps!

Answer

The measure of p is 50 degrees.

Explanation

You can see that p is located in a triangle.

The interior angles of a triangle always add up to 180 degrees.

So, to solve this problem, you can find the other interior angles, then subtract those from 180 to find p.

The exterior angles are 140 and 90 degrees. To find the measure of the interior angles, you subtract them from 180, (because the exterior angles and interior angles add up to 180).

The measure of the interior angles are 40 and 90 degrees; 180-140=40 and 180-90=90.

Now you can subtract the measure of the two interior angles from 180 to find p; 180-40-90=50.

Answer:

x= 1

Step-by-step explanation:

Work is shown in the picture

Answer:

x=6

pqs=82

sqr=59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

23x + 3= 141

23x = 136

x = 136/23 = 6

~~~~~~~~~~~~~~~

pqs = 13x + 4  = 13(6) + 4 = 78+4 = 82

sqr =  10x - 1 = 10(6)-1 = 60 - 1 = 59

Answer:

x = 6

Angle PQS is 82

Angle SQR is 59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

Group like terms : 23x + 3 = 141

Subtract 3 from both sides to get 23x = 138

Divide both sides by 23 to get x = 6

Angle PQS: Plug 6 into x  for 13x + 4 = 13 (6) + 4 = 82

Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59

Answer:

No solutions

Step-by-step explanation:

Convert both equations into y = mx + b form, where m is the slope and b is the y intercept.

8x + 4y = 12

4y = -8x + 12

y = -2x + 3

Rearrange the other equation:

3y = -6x - 15

y = -2x - 5

So, both equations have a slope of -2. But, one has a y intercept of 3 and the other has a y intercept of -5.

Because the lines have the same slope but different y intercepts, the lines are parallel.

Parallel lines have no solutions, because they will never intersect.

So, the system has no solutions.

Answer:

B.

Step-by-step explanation:

Other equations don't have any value of x.

Answer:

Because if you see.. The component of x will get canceled in each of the other 3 options.. ( 2x - 2x) which means no solution.. In option B.. 2x + 2x will give 4x..= 31-31 = 0..

-------------------------

Hope it helps...

Have a great day!!

Answer:

1

Step-by-step explanation:

The given equation of the function is y = -a·(x - h)² + 1

The positive constants of the equation = a, and h

The points the function crosses the x-axis = 2, and 4

Where the function crosses the x-axis, y = 0, and x = 2, and 4, therefore, when x = 2, we have;

y = 0 = -a·(2 - h)² + 1

When x = 4, we have;

0 = -a·(4 - h)² + 1

-a·(2 - h)² + 1 = -a·(4 - h)² + 1

-a·(2 - h)² = -a·(4 - h)²

(2 - h)² = (4 - h)²

±(2 - h) = +#±(4 - h)

When

(2 - h) is negative, and (4 - h) is positive, but the same magnitude, we have';

-(2 - h) = +(4 - h)

2·h = 4 + 2 = 6

h = 3

0 = -a·(4 - h)² + 1 = -a·(4 - 3)² + 1 = -a + 1

Therefore, a = 1

Answer:

[tex]a =-3[/tex]    [tex]b =2[/tex]

Step-by-step explanation:

Given

[tex]y = ab^x[/tex]

[tex](x_1,y_1) = (0,-3)[/tex]

Required

Find a and b

Substitute [tex](x_1,y_1) = (0,-3)[/tex] for x and y in [tex]y = ab^x[/tex]

[tex]-3 = ab^0[/tex]

[tex]-3 = a * 1[/tex]

[tex]-3 = a[/tex]

Rewrite as:

[tex]a =-3[/tex]

The above implies that (a) is correct;

Hence:

[tex]a =-3[/tex]    [tex]b =2[/tex]

So, the equation is:

[tex]y = -3(2)^x[/tex]

Answer: a=-3 b=2

Step-by-step explanation:

Answer:

(-3,-6) and (-3,2)

Step-by-step explanation:

A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3

Answer:

6x+8+4x+2=180

so!! 10x+10=180

10x=170

x=17

Answer:

[tex]x=17[/tex]

Step-by-step explanation:

The two angles labelled [tex]6x+8[/tex] and [tex]4x+2[/tex] are co-interior angles. When two parallel lines are cut by a traversal, co-interior angles are supplementary, meaning they add up to 180 degrees. Therefore, if line L is parallel to line M, [tex]6x+8[/tex] and [tex]4x+2[/tex] must be supplementary:

[tex]6x+8+4x+2=180[/tex]

Combine like terms:

[tex]10x+10=180[/tex]

Subtract 10 from both sides:

[tex]10x=170[/tex]

Divide both sides by 10:

[tex]x=\frac{170}{10}=\boxed{17}[/tex]

Answer:

3.6

Step-by-step explanation:

Hi there!

We are given this expression:

.6√36 (.6*√36)

And we want to find the value of it

.6 can be re-written as 0.6

In that case,

0.6*√36

First, simplify what's under the radical: √36, which is equal to 6 (6*6=36)

The expression then becomes:

0.6*6

Multiply those numbers together

0.6*6=3.6

Hope this helps!

Not enough information to solve..... Please make your question more clear

Answer:

(12xy-6x -12y)

12xy-18xy

6xy

Answer:

- xy - x + 2y

Step-by-step explanation:

5x - 13xy + 14y + 12xy - 6x - 12y ← collect like terms

= (- 13xy + 12xy) + (5x - 6x) + (14y - 12y)

= - xy - x + 2y

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Being able to do this requires that you understand what is being asked and that you understand domain. This is a piecewise function, made up of 4 different parts, and each part has a domain different from every other part. Now look at the solutions. We are given coordinates, x and y. So this is how this problem is done.

In a. the coordinate is (-1, 1), right? x = -1 here, so the equation that we "pick" (I'll explain that in a sec) has to have a domain where -1 will fall. The first part of this piecewise has a domain of less than or equal to -11. Is -1 less than or equal to -11? No, it is not. -1 is greater than -11, so the equation we "pick" to use will not be this one. Look at the next piece of the function and note its domain. This domain is that x is greater than -11 and less than 5. Does -1 fit in that domain? Is -1 included in that spread of numbers? Yes it is, so that is the equation we will use. By use I mean that we will plug in -1 for x and see if y = 1 (that number comes from the coordinate (-1, 1) where y = 1). The equation is y = x + 2 and plugging in -1 for x:

y = -1 + 2 so

y = 1 and this point is on the piecewise. Let's do one more example so you can see how it looks when it DOESN'T work out, ok?

Look at b. The coordinate is (-2, -10). x = -2, so the same domain, same equation: x + 2. We plug in -2 for x to find y:

y = -2 + 2 so

y = 0.  0 does not equal -10, so this point is not on that graph.

The key here is picking the equation whose domain includes your x value and evaluating the equation at that value of x to find y.

Answer:

Một trục số đi từ âm 6 đến dương 6. Các điểm ở âm 6, âm 2, 5.

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

x = 17

Step-by-step explanation:

(x-3)2 = 7

Divide both sides by two

(x-3)2 = 7

2 2

x-3= 31/2

x= 31/2-3

x= 1/2 or 0.5

Answer:

I think it's a

Step-by-step explanation:

hsjshbwibs hshhsvsu hshsbsbus

Answer:

                  Answer:bf                  

Step-by-step explanation:

Answer:

√74

Step-by-step explanation:

AB is the same as A multiplied by B. In order to get this value, we need to figure out the value of A and B.

We have two equations here:

a + 5b = 2b + 13

a = 3b - 5

The second equation already has A isolated. So, we can take that equation and plug in the value for A. Doing so will allow us to solve for B.

(3b - 5) + 5b = 2b + 13

8b - 5 = 2b + 13

6b - 5 = 13

6b = 18

b = 3

Now that we know B, we can use our equation that isolated A.

a = 3(3) - 5

a = 9 - 5

a = 4

Therefore, a = 4 and b = 3, and ab = 12.

Hope this helps!

Answer:

(x-3)^2+y^2=8

Step-by-step explanation:

I'm going to go ahead and assume the center is (3,0). The radius can be found by computing the distance from the center, (3,0), to a point on the circle, (5,-2).

The distance between two points is calculated by doing sqrt((distance between x's)^2+(distance between y's)^2).

The distance between our x's is 2.

The distance between our y's is 2.

The square of each then is 4 and 4 respectively.

So we have the distance is sqrt(4+4)=sqrt(8).

The radius is sqrt(8).

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and r is radius.

If r=sqrt(8), then r^2=8.

(h,k)=(3,0)

(x-h)^2+(y-k)^2=r^2

(x-3)^2+(y-0)^2=8

(x-3)^2+y^2=8

Answer:

1)  [tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2)  [tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3)  [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4)  [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5)  [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

Step-by-step explanation:

The rationalization of the denominator of the surds are found as follows;

1) [tex]\dfrac{2}{\sqrt{5} }[/tex]

[tex]\dfrac{2}{\sqrt{5} } \times \dfrac{\sqrt{5} }{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

[tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2) [tex]-\dfrac{5}{\sqrt{3} }[/tex]

[tex]-\dfrac{5}{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

[tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3) [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} }[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } \times \dfrac{ \sqrt{10} }{\sqrt{10} } = \dfrac{\sqrt{20} + \sqrt{50} }{10 } = \dfrac{2\cdot \sqrt{5} + 5 \cdot \sqrt{2} }{10} = \dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4) [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} }[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \dfrac{3 \cdot \sqrt{3}+\sqrt{6} }{3 } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5) [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} } = \dfrac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} } = \dfrac{\sqrt{15} -\sqrt{6} }{5 - 2} = \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

6) [tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} }[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} = \dfrac{\sqrt{21} + \sqrt{35}}{{3} + {5}} = \dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} =\dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]