Answers
Answer:
For 1: 6.68 g of nitrogen dioxide will contain [tex]8.73\times 10^{22}[/tex] number of molecules
For 2: The given amount of nitrogen dioxide molecules has a mass of 41.31 g.
Explanation:
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
For 1:We are given:
Mass of nitrogen dioxide = 6.68 g
Molar mass of nitrogen dioxide = 46 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of nitrogen dioxide}=\frac{6.68g}{46g/mol}=0.145mol[/tex]
Using above concept:
If 1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules
So, 0.145 moles of nitrogen dioxide will contain = [tex](0.145\times 6.022\times 10^{23})=8.73\times 10^{22}[/tex] number of molecules
Hence, 6.68 g of nitrogen dioxide will contain [tex]8.73\times 10^{22}[/tex] number of molecules
For 2:We are given:
Molecules of nitrogen dioxide = [tex]5.41\times 10^{22}[/tex] molecules
Using the above concept:
If [tex]6.022\times 10^{23}[/tex] number of molecules are present in 1 mole of a compound
So, [tex]5.41\times 10^{22}[/tex] number of molecules will be present in = [tex]\frac{1mol}{6.022\times 10^{23}}\times 5.41\times 10^{22}=0.898[/tex] moles of nitrogen dioxide
We know, molar mass of nitrogen dioxide = 46 g/mol
Using equation 1:
[tex]0.898mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.898mol\times 46g/mol=41.31g[/tex]
Hence, the given amount of nitrogen dioxide molecules has a mass of 41.31 g.
Related Questions
every action produces an equal and opposite -- ---------- when one object exterts a force on another object,the second object pushes back with the same amount of---------
someone knows the answer
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radical example ....
Answers
How many moles of sodium carbonate in 18.06x10 to the power 22
Answers
Answer:
[tex] moles = \frac{ number \: of \: particles}{6.02 \times {10}^{23} } [/tex]
=1.806×10^22/6.02×10^23
=0.03 moles
hope this helps :)
Explanation none
You burn a log on a fire. You use fire to warm yourself and help you see to read a book. What energy transformation is taking place?
Answers
Answer:
heat energy to keep you warm and light energy to be able to read your book
Explanation:
Put these atoms in order from most negative overall charge to least negative
overall charge.
11 Atom X: 104 protons, 102 electrons
11 Atom B: 24 protons, 18 electrons
1 Atom Q: 15 protons, 16 electrons
11. Atom P: 7 protons, 10 electrons
Answers
Answer:
3 Protons, 2 Neutrons, & 3 Electrons. Is the charge of this atom positive, negative, or neutral?
Explanation:
Put these atoms in order from most negative overall charge to least negative
overall charge.
11 Atom X: 104 protons, 102 electrons
11 Atom B: 24 protons, 18 electrons
1 Atom Q: 15 protons, 16 electrons
11. Atom P: 7 protons, 10 electrons
Hi, in some texts number of water molecules released during polymerization is 2n but in others 2n-1 , why?
Answers
Answer:
Explanation:
Because you only have one repeat unit, n=1. 2n-1 becomes 2(1)-1 which is equal to one, meaning one molecule of H2O is produced, as is shown by the top condensation polymerisation reaction.
If you had two repeat units, n=2 so 2n-1=3. Three H2O molecules are produced because you would need two molecules of each reactant so three condesation reactions would occur and three molecules of H2O would be released.
why are metal containers not used for storing acids
Answers
Metal containers are not used for storing acid because most of the time acid reacts with almost every metal and produces salts or oxides which alters the acid characteristics making it useless....
A 80°C la presion de vapor del benceno (C6H6) es de 1 atm. Calcula la cantidad de hexano (C6H14) que debemos añadir a 200g de benceno para que su presion de vapor sea de 700mm de Hg
Answers
Answer:
18,9g de hexano son necesarios
Explanation:
Basados en la ley de Raoult, la presión de vapor ejercida por una solución es:
P = P°*Xsolvente
Donde P es la presión de la solución deseada = 700mmHg, P° la presión de vapor de vapor del benceno = 1atm = 760mmHg y X es la fracción molar del solvente (Benceno).
Reemplazando:
700mm Hg = 760mmHg * X(Benceno)
0.9211 = X(Benceno)
La fracción molar de benceno se define como:
X = Moles benceno / Moles benceno + Moles hexano
Moles benceno -Masa molar: 78g/mol-
200g * (1mol/78g) = 2.5641 moles benceno
X = Moles benceno / Moles benceno + Moles hexano
0.9211 = 2.5641 moles benceno / 2.5641 moles benceno + Moles hexano
0.9211moles Hexano + 2.3618 = 2.5641
0.9211*Moles Hexano = 0.2023
Moles hexano = 0.2023/0.9211 = 0.2196 moles hexano.
Masa Hexano -Masa molar: 86g/mol-
0.2196 moles hexano * (86g/mol) =
18,9g de hexano son necesariosLa cantidad de hexano (C6H14) que se debe agregar a 200 g de benceno para permitir que la presión de vapor se convierta en 700 mm de Hg sería:
18.9 g
Usando la ley de Raoult, la presión de vapor que libera una solución se encuentra por:
P = P ° × X disolvente
Donde (P) denota la presión de la solución deseada
P ° denota la presión de vapor del benceno y
X denota la fracción molar del disolvente (benceno).
En el caso dado,
(P) = 700 mmHg,
P° = 1atm = 760mmHg
Fracción molar de benceno = 0,9211 (∵ 700/760)
La fracción molar de benceno (X) = Moles de benceno/Moles de benceno + Moles de hexano
Moles de benceno - Masa molar: 78g / mol - 200 g × (1 mol / 78 g)
= 2.5641 moles de benceno
X = Moles de benceno/Moles de benceno + Moles de hexano
0.9211 = 2.5641 moles Benceno/2.5641 moles Benceno + Moles de Hexano
⇒ 0,9211 × moles de Hexano + 2,3618 = 2,5641
⇒ 0.9211 × moles de Hexano = 0.2023
∵ Moles de Hexano = 0.2023/0.9211
[tex]= 0.2196 moles[/tex]
[tex]Hexane mass - Molar mass = 86g/mol - 0.2196 mole hexane[/tex] × [tex](86g/mole)[/tex]
[tex]= 18.9g[/tex]
Por tanto, 18,9 g es la respuesta correcta.
Learn more about "Benzene" here:
brainly.com/question/25798187
What mass of N2O5 will result from the reaction of 6.0 mol of NO2 if there is a 61.1% yield in the reaction
Answers
Answer:
2.0 × 10² g
Explanation:
Step 1: Write the balanced equation
2 NO₂ + 0.5 O₂ ⇒ N₂O₅
Step 2: Calculate the theoretical yield, in moles, of N₂O₅
The molar ratio of NO₂ to N₂O₅ is 2:1.
6.0 mol NO₂ × 1 mol N₂O₅/2 mol NO₂ = 3.0 mol N₂O₅
Step 3: Calculate the theoretical yield, in grams, of N₂O₅
The molar mass of N₂O₅ is 108.01 g/mol.
3.0 mol × 108.01 g/mol = 3.2 × 10² g
Step 4: Calculate the real yield, in grams, of N₂O₅
real yield = theoretical yield × percent yield
real yield = 3.2 × 10² g × 61.1% = 2.0 × 10² g
Explain how carbon’s bonding ability makes it unique.
Answers
[tex]\huge\fcolorbox{red}{pink}{Answer ♥}[/tex]
The carbon atom is unique among elements in its tendency to form extensive networks of covalent bonds not only with other elements but also with itself. ... Moreover, of all the elements in the second row, carbon has the maximum number of outer shell electrons (four) capable of forming covalent bonds.
Hope it helps uh ✌️✌️✌️
Gud mrng
write a short note on detection of nitrogen in the organic compound
Answers
ajdhrhahdjdjdndoxhdebdixhxb dbds ebenej
Cuál o cuáles de las siguientes características son correctas para la mayoría de los compuestos del carbono?
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos
IV) El enlace covalente es característico de los compuestos del carbono
Todas son correctas
II
I y IV
I, III y IV
Answers
Answer:
Todas son correctas
Explanation:
I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.
II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.
III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.
IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.
Todas son correctas
Suppose that you chose sodium carbonate to precipitate the chromium ions from a solution of chromium (III) chloride. Write and balance the equation of this double-displacement reaction.
If the solution has a volume of 520 mL and the concentration of chromium (III) chloride is 0.224 M, how many grams of sodium carbonate should you add to the solution to precipitate out all the chromium ions?
Answers
Answer:
18.5g Na2CO3
Explanation:
Chromium (III) chloride, CrCl3, reacts with Na2CO3 as follows:
2CrCl3 + 3Na2CO3 → Cr2(CO3)3(s) + 6NaCl
Where 2 moles of CrCl3 react with 3 moles of Na2CO3 to produce 1 mole of Cr2(CO3)3 -The precipitate-
To solve this question we need to find the moles of CrCl3 added. With the chemical equation we can find the moles of Na2CO3 and its mass as follows:
Moles CrCl3:
520mL = 0.520L * (0.224mol/L) = 0.116 moles CrCl3
Moles Na2CO3:
0.116 moles CrCl3 * (3 mol Na2CO3 / 2mol CrCl3) = 0.175 moles Na2CO3
Mass Na2CO3 -Molar mass: 105.99g/mol-
0.175 moles Na2CO3 * (105.99g/mol) = 18.5g Na2CO3
3. How many moles are present in 100 g of Ca(NO3)2?
PLEASEEE HELP ASAPP
Answers
0Answer: 0.6094
Explanation:
no of moles = mass / molar mass = 100/164.088= 0.6094 mole
Answer:
0.609 moles
Explanation:
mass in g ÷ atomic mass = moles
Ca(NO₃)₂ = 1 Ca 40.078 amu
2 N 28.0134 amu
+ 6 O 95.994 amu
____________________
164.0854 amu
100 g ÷ 164.0854 amu = 0.609 moles
three significant digits
(Please help)
What is the most common isotope for element X
Answers
Answer:
Isotope 2
Explanation:
Isotope 2 is the most abundant. Its percent abundance is 78.68% which is the largest percentage, and therefore the most common of the isotopes presented.
Good luck!
Which has more mass, 2 kg of steel or 5 kg of feather.
Answers
Answer:
5 kg of feather
Explanation:
Which best describes a swimming pool?
A.
It is a solute.
• B.
It IS
solvent.
C.
It is solution.
D.
It is a reactant.
•
E.
It is a product.
Answers
Answer:
Swimming pool is an example of solution
Explanation:
It has water (solvent) and dissolve ion (solute)
Answer:
it is a solution
Explanation:
the combining of (water and Cl and other pool chemicals) make it a solution.
Balance the equation of. _C + _O2 -- _CO
Answers
Explanation:
2C +O2 = 2CO
this will be the answer
The work function of an element is the energy required to remove an electron from the surface of the solid. The work function for palladium is 503.7 kJ/mol (that is, it takes 503.7 kJ of energy to remove 1 mole of electrons from 1 mole of Pd atoms on the surface of Pd metal). What is the maximum wavelength of light that can remove an electron from an atom in palladium metal
Answers
Answer:
λ = 2.38 × 10^(-7) m
Explanation:
We are given the work function for palladium as 503.7 kJ/mol.
Now let's convert this to KJ/electron.
We know from avogadro's number that;
1 mole of electron = 6.022 × 10^(23) electrons
Thus,
503.7 kJ/mol = 503.7 × 1/(6.022 × 10^(23)) = 8.364 × 10^(-22) KJ/electron = 8.364 × 10^(-19) J/electron
Formula for energy of a photon is;
E = hv
Where;
h is Planck's constant = 6.626 × 10^(-34) J.s
v is velocity
Now, v = c/λ
Where;
c is speed of light = 3 × 10^(8) m/s
λ is wavelength of light.
Thus;
E = hc/λ
Making λ the subject, we have;
λ = hc/E
λ = (6.626 × 10^(-34) × 3 × 10^(8))/(8.364 × 10^(-19))
λ = 2.38 × 10^(-7) m
Una muestra de S2 (g) se coloca en un recipiente rígido vacío a 800 K y ésta ejerce una presión inicial de 0,92 atm, luego se combina para formar S8 (g) mediante la reacción: S2 (g) ⇆ S8 (g) Una vez alcanzado el equilibrio, la presión parcial de S2 (g) ha disminuido a 0,18 atm. Calcule Kp para la reacción a esta temperatura
Answers
Answer:g
Explanation:
The field around a negatively charged object is symbolized by vectors pointing toward the sphere because a test charge, which is ______ by definition, would travel along such a vector if released in the field.
Positive
Negative
Answers
Answer:
Positive
Explanation:
Which expression is equal to f(x) · g(x)?
Answers
Answer:
C. x⁴ + 6·x³ - 12·x - 72
Explanation:
The given functions are;
[tex]f(x) =\sqrt{x^2 + 12 \cdot x + 36}[/tex]
g(x) = x³ -12
We have that [tex]f(x) =\sqrt{x^2 + 12 \cdot x + 36}[/tex] = [tex]f(x) =\sqrt{(x + 6)^2}[/tex] = (x + 6)
Therefore;
f(x)·g(x) = [tex]\sqrt{x^2 + 12 \cdot x + 36}[/tex] × (x³ - 12) = (x + 6) × (x³ - 12)
(x + 6) × (x³ - 12) = x⁴ - 12·x + 6·x³ - 72 = x⁴ + 6·x³ - 12·x - 72
∴ f(x)·g(x) = [tex]\sqrt{x^2 + 12 \cdot x + 36}[/tex] × (x³ - 12) = x⁴ + 6·x³ - 12·x - 72
an organic compound on analysis yielded 2.04g carbon, 0.34g hydrogen, 2.73g oxygen. calculate the empirical formula
Answers
Answer:
CH2O
Explanation:
According to this question:
C = 2.04g
H = 0.34g
O = 2.73g
First, we divide the mass value of each element by its atomic mass to convert to moles.
C = 2.04g ÷ 12 = 0.17mol
H = 0.34g ÷ 1 = 0.34mol
O = 2.73g ÷ 16 = 0.17mol
Next, we divide by the smallest mole value (0.17):
C = 0.17mol = 0.17 = 1
H = 0.34mol ÷ 0.17 = 2
O = 0.17mol ÷ 0.17 = 1
The whole number ratio of C,H,O is 1:2:1, hence, the empirical formula is CH2O.
Mike watch 100 m north then watch 30 m south after this he walks another 10 m north what is the magnitude of his total displacement during this walk in meters
Answers
Answer:
His total displacement is 80 m northwards
Explanation:
Given;
Mike's first displacement, x₁ = 100 m North
Mike's second displacement, x₂ = 30 m South
Mike's third displacement, x₃ = 10 m North
Let his Northwards direction be positive, and
his Southwards direction be negative
His total displacement = (100 m North) + ( - 30 m South) + (10 m north)
= (100 m + 10m - 30 m)
= 80 m Northwards
A mechanical wave starts when matter is disturbed by a source
of_______ I NEED ANSWER ASAP
Answers
Answer:
i believe energy is your answer here
Determine the enthalpy for the reaction A+B --> C If we know the following:
A+E --> C+D; delta H = -200 kJ
D+B --> E; delta H = -100 kJ
Answers
Explanation:
here is the answer to the question
As electrons are passed down the electron transport chain, the molecules are first ______ as they pick up electrons, and then ______ as they release the electrons.
Answers
Answer:
reduced; oxidized
Explanation:
An electron transport chain can be defined as a series of redox reactions (electron transporters or proton complexes) that are saddled with the responsibility of transferring electrons from electron donors to electron acceptors through a membrane in order to produce a protein gradient that creates energy or adenosine triphosphate (ATP).
Generally, as these electrons are transferred through the electron transport chain, the molecules are first reduced as they pick up electrons, and then oxidized as they release the electrons.
Cellular respiration can be defined as a series of metabolic reactions that typically occur in cells so as to produce energy in the form of adenosine triphosphate (ATP). During cellular respiration, high energy intermediates are created that can then be oxidized to make adenosine triphosphate (ATP). Therefore, the intermediary products are produced at the glycolysis and citric acid cycle stage.
Additionally, mitochondria provides all the energy required in the cell by transforming energy forms through series of chemical reactions; breaking down of glucose into Adenosine Triphosphate (ATP) used for providing energy for cellular activities in the body of living organisms.
Which refers to substances that are complex molecules and contain carbon atoms bonded to hydrogen atoms?
o
O organic
O inorganic
ionic
metallic
Answers
Answer:
organic
Explanation:
Organic substances are those which contains covalently linked carbon to hydrogen (C-H) bonds in their structure. In other words, organic compounds or substances are uniquely composed of carbon and hydrogen atoms covalently linked together.
These substances usually contain a long chain of these bonds, hence, making them complex. Therefore, according to this question, substanves that are complex molecules and contain carbon atoms bonded to hydrogen atoms are referred to as ORGANIC SUBSTANCES.
Answer:
A. Organic
Explanation:
What are the prefixes for molecular compounds?
Answers
Answer:
In nomenclature of simple molecular compounds, the more electropositive atom is written first and the more electronegative element is written last with an -ide suffix.
The Greek prefixes are used to dictate the number of a given element present in a molecular compound.
Prefixes can be shortened when the ending vowel of the prefix “conflicts” with a starting vowel in the compound.
Common exceptions exist for naming molecular compounds, where trivial or common names are used instead of systematic names, such as ammonia (NH3) instead of nitrogen trihydride or water (H2O) instead of dihydrogen monooxide.
Terms
nomenclatureA set of rules used for forming the names or terms in a particular field of arts or sciences.
electronegativeTending to attract electrons within a chemical bond.
electropositiveTending to not attract electrons (repel) within a chemical bond.
Chemical Nomenclature
The primary function of chemical nomenclature is to ensure that a spoken or written chemical name leaves no ambiguity concerning to what chemical compound the name refers. Each chemical name should refer to a single substance. Today, scientists often refer to chemicals by their common names: for example, water is not often called dihydrogen oxide. However, it is important to be able to recognize and name all chemicals in a standardized way. The most widely accepted format for nomenclature has been established by IUPAC.
Molecular compounds are made when two or more elements share electrons in a covalent bond to connect the elements. Typically, non-metals tend to share electrons, make covalent bonds, and thus, form molecular compounds.
Rules for Naming Molecular Compounds:
Remove the ending of the second element, and add “ide” just like in ionic compounds.
When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
If there is only one of the first element, you can drop the prefix. For example, CO is carbon monoxide, not monocarbon monoxide.
If there are two vowels in a row that sound the same once the prefix is added (they “conflict”), the extra vowel on the end of the prefix is removed. For example, one oxygen would be monooxide, but instead it’s monoxide. The extra o is dropped.
Generally, the more electropositive atom is written first, followed by the more electronegative atom with an appropriate suffix. For example, H2O (water) can be called dihydrogen monoxide (though it’s not usually). Organic molecules (molecules made of C and H along with other elements) do not follow this rule.
Here are the prefixes in naming molecular compounds:
Mono- 1
Di- 2
Tri- 3
Tetra- 4
Penta- 5
Hexa- 6
Hepta- 7
Octa- 8
Nona- 9
Deca- 10
Molecular compounds are named using a systematic approach of prefixes to indicate the number of each element present in the compound.
I hope it helps ●~●
#CarryOnLearningFor the equilibrium
2H2S(g) ⇋ 2H2(g) + S2(g) Kc = 9 .0X 10-8 at 700°C
the initial concentrations of the three gases are 0.300 M H2S, 0.300 M H2, and 0. 1 50 M S2' Determine the equilibrium concentrations of the gases.
Answers
Answer:
Equilibrium concentrations of the gases are
[tex]H_2S=0.596M[/tex]
[tex]H_2=0.004 M[/tex]
[tex]S_2=0.002 M[/tex]
Explanation:
We are given that for the equilibrium
[tex]2H_2S\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
[tex]k_c=9.0\times 10^{-8}[/tex]
Temperature, [tex]T=700^{\circ}C[/tex]
Initial concentration of
[tex]H_2S=0.30M[/tex]
[tex]H_2=0.30 M[/tex]
[tex]S_2=0.150 M[/tex]
We have to find the equilibrium concentration of gases.
After certain time
2x number of moles of reactant reduced and form product
Concentration of
[tex]H_2S=0.30+2x[/tex]
[tex]H_2=0.30-2x[/tex]
[tex]S_2=0.150-x[/tex]
At equilibrium
Equilibrium constant
[tex]K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}[/tex]
Substitute the values
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
By solving we get
[tex]x\approx 0.148[/tex]
Now, equilibrium concentration of gases
[tex]H_2S=0.30+2(0.148)=0.596M[/tex]
[tex]H_2=0.30-2(0.148)=0.004 M[/tex]
[tex]S_2=0.150-0.148=0.002 M[/tex]
