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Answer:

9x³ + 27x²

Step-by-step explanation:

What the question is asking is to multiply f(x) and g(x) together:

Step 1: Write out expression

(fg)(x) = 3x²(3x + 9)

Step 2: Distribute

(fg)(x) = 9x³ + 27x²

Answer:

[tex]\huge\boxed{Option \ 3 : (fg)(x) = 9x^3+27x^2}[/tex]

Step-by-step explanation:

[tex]f(x) = 3x+9\\g(x) = 3x^2[/tex]

Multiplying both

[tex](fg)(x) = (3x+9)(3x^2)\\(fg)(x) = 9x^3+27x^2[/tex]

A(t) = 100t^2 + 500t + 625

3,025 square pixels

Answer:

A(t) equals 100t²+ 500t + 625.

The area of the square image after 3 seconds is 3,025 square pixels.

Answer:

(6, 4 )

Step-by-step explanation:

Given the 2 equations

2x - 10y = - 28 → (1)

- 10x + 10y = - 20 → (2)

Adding (1) and (2) term by term eliminates the term in y, that is

- 8x = - 48 ( divide both sides by - 8 )

x = 6

Substitute x = 6 into either of the 2 equations and evaluate for y

Substituting into (1)

2(6) - 10y = - 28

12 - 10y = - 28 ( subtract 12 from both sides )

- 10y = - 40 ( divide both sides by - 10 )

y = 4

Solution is (6, 4 )

Answer:

The z-score is [tex]z = 0.6[/tex]

The percentile is  [tex]p(Z < 0.6) = 72.57\%[/tex]

Step-by-step explanation:

From the question we are told that

   The  data value is  0.6 standard deviations above the mean i.e  [tex]x = \mu + 0.6 \sigma[/tex]

Where  [tex]\mu[/tex] is the population mean and [tex]\sigma[/tex] is the standard deviation

Generally the z-score is mathematically represented as

        [tex]z = \frac{x - \mu }{\sigma }[/tex]

=>     [tex]z = \frac{(\mu + 0.6\sigma ) - \mu }{\sigma }[/tex]

=>    [tex]z = 0.6[/tex]

The percentile is obtained from the z-table and the value is

     [tex]p(Z < 0.6) = 0.7257[/tex]

=>   [tex]p(Z < 0.6) = 72.57\%[/tex]

Answer:

$188.91

Step-by-step explanation:

$999*.09=$89.91

$89.91+$99=$188.91

Complete Question

The complete question is shown on the first uploaded image

Answer:

Yes  the test  suggest that the true average percentage of organic matter in such soil is something other than 3%

Step-by-step explanation:

From the question we are told that

  The  sample mean is  [tex]\= x = 2.482\%[/tex]

  The  standard deviation is [tex]\sigma = 1.614[/tex]

   The  standard error is [tex]SE = 0.295[/tex]

     The  sample size is [tex]n = 30[/tex]

   The  level of significance is  [tex]\alpha = 0.05[/tex]

  The  null hypothesis is [tex]H_o : \mu = 3\%[/tex]

   The  alternative hypothesis is  [tex]H_a : \mu \ne 3\%[/tex]

Now  the degree of freedom is evaluated as

       [tex]df = n - 1[/tex]

       [tex]df = 30 - 1[/tex]

       [tex]df = 29[/tex]

The test statistics is mathematically evaluated as

         [tex]t = \frac{ 2.482 - 3}{ 0.295}[/tex]

         [tex]t = -1.756[/tex]

The p-value is obtained from the the student t -distribution table , the value is  

        [tex]p-value = P( T \le t)= 2 * t_{ t, df } = t_{ -1.756 , 29 } = 2 *0.0448= 0.0896[/tex]

The reason for the 2 in the equation is because the test is a two -tailed test i.e  -1.756 and  1.756

Given that the [tex]p-value > \alpha[/tex] then we fail to reject the null hypothesis

Hence the test the suggest that the true average percentage of organic matter in such soil is something other than 3%

Answer:

Hey there!

We can write: -2+9=7.

Let me know if this helps :)

Answer:

[tex]\large \boxed{{-2+9=7}}[/tex]

Step-by-step explanation:

-2 is also 0-2

The arrow goes from 0 to -2.

-2 + 9 = 7

The arrow goes from -2 to 7.

Answer:

B: -x^2 + 4

Step-by-step explanation:

If the equation was [tex]f(x)=x^2[/tex], then the vertex would be at 0, and the "U" would be facing straight up. Here, the "U" is upside down, so that means the "x^2" would have to be a negative number ([tex]-x^2[/tex]) to get the upside-down "U". Then, we could see that the vertex is at positive 4, so that means that the parabola moved up 4 units, so the equation should end in +4.

Our answer is:

B: -x^2 + 4

Answer:

4.5cm

Step-by-step explanation:

Circumference = 2[tex]\pi[/tex]r

28.3=2[tex]\pi[/tex]r

28.3/2[tex]\pi[/tex]=r

4.456

The radius of the circle O is 4.5 cm.

A radius is a measure of distance from the center of any circular object to its outermost edge or boundary.

Given that, a circle having a circumference of approximately 28.3 cm, we need to find its radius,

So, Circumference = 2 π × radius

2 π × radius = 28.3

Radius = 28.3 / 2π

Radius = 28.3 / 6.28

Radius = 4.5

Hence, the radius of the circle O is 4.5 cm.

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Answer: see below

Step-by-step explanation:

The standard form of an exponential equation is: y = a(b)ˣ    where

Growth:

Exponential growth is where the final value (y) is greater than the initial value (a).

An example would be the spreading of a rumor:  

You tell 1 person (a = 1) who then tells 2 people each minute (b = 2).  How many people will they have spread the rumor to after 5 minutes (x = 5)?

y = 1(2)⁵

  = 32

Decay:

Exponential decay is where the final value (y) is less than the initial value (a).

An example would be the decrease of bacteria in a person:

A person has 100 bacteria (a = 1) who takes a pill that is supposed to cut in half the number of bacteria each hour (b = 1/2).  How many bacteria will the person have after 2 hours (x = 2)?

[tex]y=100\bigg(\dfrac{1}{2}\bigg)^2\\\\\\.\quad =100\bigg(\dfrac{1}{4}\bigg)\\\\\\.\quad = 25[/tex]

Answer:

The area of larger triangle is 48 ft².

Step-by-step explanation:

Assuming that the area of triangle formula is A = 1/2 × base × height. Then, you have to substitute the following values :

[tex]area = \frac{1}{2} \times b \times h[/tex]

[tex]let \: b = 12,h = 8[/tex]

[tex]area = \frac{1}{2} \times 12 \times 8[/tex]

[tex]area = \frac{1}{2} \times 96[/tex]

[tex]area = 48 \: {feet}^{2} [/tex]

Given that;

A∞bh

A=kbh. where k is a constant

For smaller triangle

A=kbh

16=8(4)k

16=32k

k=½

For bigger triangle

A=kbh

Where k=½ , b= 12 and h=8

A=½(12)8

A=48 square feet

Answer:

[tex]\boxed{x \geq 353}[/tex]

Step-by-step explanation:

Hey there!

Info Given

- Dot is solid

- Line goes to the right

- Dot is at 353

So by using the given info we can conclude that the inequality is,

x ≥ 353

Hope this helps :)

Answer:

Inequality: 100 + 50w ≥ 18000

What to put on graph: w ≥ 358

Answer & Step-by-step explanation:

The ratio of square feet to gallons of paint:

[tex]1440:6[/tex]

This can also be written as:

[tex]\frac{1440}{6}[/tex]

This fraction can be simplified by dividing the numerator and denominator by 6:

[tex]\frac{1440}{6}=\frac{240}{1}[/tex]

So, the ratio of square feet to gallons of paint is:

1 gallon for every 240 ft².

:Done

Answer:

0

Step-by-step explanation:

- 2×3= - 6

2×3=6

-6+6=0

Answer:

0

Step-by-step explanation:

first

(-2x3)+(3x2)

-6+6=0

Answer:

if x = 2

f(x) = -3x^2 + 180x -285

f(x) = -3*2*2 + 180*2 -285

f(x) = -12 + 360 -285

f (x) = 63

Step-by-step explanation:

Answer:

1256 i think

Step-by-step explanation:

Answer:

$522.49

Step-by-step explanation: 549.99*.05=27.50 (discount)

549.99-27.50=$522.49

Answer:

$522.49

Step-by-step explanation:

First, find the discount amount. You can do this by multiplying the original cost by the discount amount. A little trick for remembering to multiply instead of divide is to think "five percent of the original amount"

5% = 0.05

549.99 ⋅ 0.05 = 27.4995

That means the discount amount is $27.50

Subtract the discount amount from the original price

$549.99 - $27.50 = $522.49

Answer:

$18.37

Step-by-step explanation:

$16.70 × 1.10 = $18.37

or

$16.70 × 0.10 = $1.67

$16.70 + 1.67 = $18.37

Answer:

15/225

Step-by-step explanation:

The number of chaperones for the group of students can be represented with a ratio - 15:225 or 15/225.

Because there are 15 chaperones for the 225 students, you can state what the ratio does - for every 225 students, there are 15 chaperones.

However, 15/225 can be reduced to 1/15, so for every 15 students, there is 1 chaperone.

Answer: [tex]4x^2-21x-2[/tex] .

Step-by-step explanation:

Given: The difference of two trinomials is [tex]x^2 -10x + 2[/tex]. If one of the trinomials is [tex]3x^2 - 11x - 4[/tex].

Then, the other trinomial will be ([tex]3x^2 - 11x - 4[/tex] ) + ([tex]x^2 -10x + 2[/tex])

[tex]=3x^2-11x-4+x^2-10x+2\\\\=3x^2+x^2-11x-10x-4+2\\\\=4x^2-21x-2[/tex]

Hence, the other trinomial could be : [tex]4x^2-21x-2[/tex] .

Answer:

Slope of the tangent line (m) = 1 / 2

Step-by-step explanation:

Given:

Point A = (4,2)

Origin point = (0,0)

Find:

Slope of the tangent line (m)

Computation:

Slope of the tangent line (m) = (y2-y1) / (x2-x1)

Slope of the tangent line (m) = (2-0) / (4-0)

Slope of the tangent line (m) = 2 / 4

Slope of the tangent line (m) = 1 / 2

Answer:

2

Step-by-step explanation:

The term 3x² has 2 as an exponent, the correct option is C.

Exponents are the base raised by power, it is written in the superscript of a number.

The expression is  3x² +y-5

The term 3x² has 2 as an exponent.

Therefore, the correct option is C.

The missing options are

A.3x2

B. y

A 2

C. -5

D. None of these choices are correct.

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Answer:

The maximum rate of change of f at (0, 9) is 72 and the direction of the vector is  [tex]\mathbf{\hat i}[/tex]

Step-by-step explanation:

Given that:

F(x,y) = 8 sin (xy) at (0,9)

The maximum rate of change f(x,y) occurs in the direction of gradient of f which can be estimated as follows;

[tex]\overline V f (x,y) = \begin {bmatrix} \dfrac{\partial }{\partial x } (x,y) \hat i \ + \ \dfrac{\partial }{\partial y } (x,y) \hat j \end {bmatrix}[/tex]

[tex]\overline V f (x,y) = \begin {bmatrix} \dfrac{\partial }{\partial x } (8 \ sin (xy) \hat i \ + \ \dfrac{\partial }{\partial y } (8 \ sin (xy) \hat j \end {bmatrix}[/tex]

[tex]\overline V f (x,y) = \begin {bmatrix} (8y \ cos (xy) \hat i \ + \ (8x \ cos (xy) \hat j \end {bmatrix}[/tex]

[tex]| \overline V f (0,9) |= \begin {vmatrix} 72 \hat i + 0 \end {vmatrix}[/tex]

[tex]\mathbf{| \overline V f (0,9) |= 72}[/tex]

We can conclude that the  maximum rate of change of f at (0, 9) is 72 and the direction of the vector is  [tex]\mathbf{\hat i}[/tex]

Answer:

3/6 = 1/2 = 0.5

Step-by-step explanation:

3 / 6 = 1/2 = 0.5

Answer:

The answer is C. SSA ≅ SSA.

Step-by-step explanation:

To check for similar triangles, SSA congruence would not work because the other side can be any length. Also, there is not an SSA postulate because this theorem by itself cannot prove congruence.

The other three properties do work because they show congruence unlike the other congruent factors.

Answer:

A. 340 grams

Step-by-step explanation:

My brain

Answer:

7 pi cm^2 or  approximately 21.98 cm^2

Step-by-step explanation:

First find the area of the large circle

A = pi r^2

A = pi 3^2

A = 9 pi

Then find the area of the small unshaded circle

A = pi r^2

A = pi (1)^2

A = pi

There are two of these circles

pi+ pi = 2 pi

Subtract the unshaded circles from the large circle

9pi - 2 pi

7 pi

If we approximate pi as 3.14

7(3.14) =21.98 cm^2

Answer:

[tex]\boxed{\sf 7\pi \ cm^2 \ or \ 21.99 \ cm^2 }[/tex]

Step-by-step explanation:

[tex]\sf Find \ the \ area \ of \ the \ two \ smaller \ circles.[/tex]

[tex]\sf{Area \ of \ a \ circle:} \: \pi r^2[/tex]

[tex]\sf r=radius \ of \ circle[/tex]

[tex]\sf There \ are \ two \ circles, \ so \ multiply \ the \ value \ by \ 2.[/tex]

[tex](2) \pi (1)^2[/tex]

[tex]2\pi[/tex]

[tex]\sf Find \ the \ area \ of \ the \ larger \ circle.[/tex]

[tex]\sf{Area \ of \ a \ circle:} \: \pi r^2[/tex]

[tex]\sf r=radius \ of \ circle[/tex]

[tex]\pi (3)^2[/tex]

[tex]9\pi[/tex]

[tex]\sf Subtract \ the \ areas \ of \ the \ two \ circles \ from \ the \ area \ of \ the \ larger \ circle.[/tex]

[tex]9\pi -2\pi[/tex]

[tex]7\pi[/tex]

Answer:

Yes , it satisfies the hypothesis and  we can conclude that c = 1 is an element of [0,2]

c = 1 ∈ [0,2]

Step-by-step explanation:

Given that:

[tex]f(x) = 4x^2 -3x + 2, [0, 2][/tex]

which is read as the function of x = 4x² - 3x + 2 along the interval [0,2]

Differentiating the function with respect to x is;

f(x) = 8x - 3

Using the Mean value theorem to see if the function satisfies it, we have:

[tex]f'c = \dfrac{f(b)-f(a)}{b-a}[/tex]

[tex]8c -3 = \dfrac{f(2)-f(0)}{2-0}[/tex]

since the polynomial function is differentiated in [0,2]

[tex]8c -3 = \dfrac{(4(2)^2-3(2)+2)-(4(0)^2-3(0)+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(4(4)-3(2)+2)-(4(0)-3(0)+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(16-6+2)-(0-0+2)}{2-0}[/tex]

[tex]8c -3 = \dfrac{(12)-(2)}{2}[/tex]

[tex]8c -3 = \dfrac{10}{2}[/tex]

8c -3  = 5

8c = 5+3

8c = 8

c = 8/8

c = 1

Therefore, we can conclude that c = 1 is an element of [0,2]

c = 1 ∈ [0,2]

Answer:

x = 58

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

90  = 32+x

Subtract 32 from each side

90-32 = x

58 =x