Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector.

Answers

Answer 1

Answer:

The assertion is true and reason is false.

Explanation:

Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.

Reason : The relation will hold even when Q is a null vector.

Now

[tex]\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree[/tex]

So, P and Q are perpendicular to each other.

So, the assertion is true.

Reason is false.


Related Questions

Unlike hard disks, which use magnetic charges to represent 1s and 0s, _____ use reflected light.

Answers

Answer:

Unlike hard disks, which use magnetic charges to represent 1s and 0s, Compact Disks, DVD's or Blue Rays use reflected light.

Explanation:

The way CD's work is that they are hit by a laser beam which is reflected on the surface of the disc. These disks have some valleys and mountains that reflect light differently so the CD player will interpret these differences in reflection as data which will then be turned into music, videos or computer files.

(e) Find the height and orbital velocity of the geostationary satellite above the earth assuming earth as a sphere of radius 6370 km. [Radius of earth, R = 6370km, Acceleration due to gravity
= 10ms) ​

Answers

Answer:

I don't really know this one trust me am not lieing

if the volume of cylinder is 1000 cm with 14cm height. Then find the radius of cylinder​

Answers

Answer:

radius=4.77cm

Explanation:

given

r=? ,h=14 , v=1000

then using the formula

[tex]r = \sqrt{ \frac{v}{\pi \: h} } [/tex]

= √1000/π•14

=4.77cm

a.in which portion of the curve,
1. is the velocity uniform.
2.is the velocity increasing.
3.is velocity decreasing.
4.is acceleration zero.

B. at which point does the body start to move and stop.
________________________


I will mark as brainlist​

Answers

Answer:

the answer is 4 acceleration is 0

Explanation:

this is because when parallel line is drawn through x axis the velocity will bw uniform

plz brainliest

Which of the following supports the theory of continental drift?
A. Mountains on different continents match up.
B. Earth's crust is all in one piece.
C. Earth has hot climates at the equator.
D. There is one continent on Earth.

Answers

Answer:

A. Mountains on different continents match up.

Explanation:

Due to the drifting/ moving apart of the continents, land masses is split therefore in case of a mountain that split, it matches the other part in another continent.

What happens to the electric force between two particles if the distance
between them is doubled?
A. It decreases to half the original force.
B. It increases to twice the original force.
C. It increases to 4 times the original force.
D. It decreases to 1/4 of the original force.

Answers

Answer:

D.

Explanation:

Force and distance are inversely related, so a greater distance results in a weaker force.

Two planets are separated by a distance of 4.5x108 m. One of the planets has a mass of 2.1x1021 kg. The force of attraction between the planets is 5x1024 N. What is the mass of the other planet? (Be careful with your algebra!)

Answers

Answer:

The mass of the other planet is 7.23*10^(30) kg

Explanation:

For two objects of masses m₁ and m₂ respectively, separated by a distance r, the gravitational force between them is given by:

F = G*(m₁*m₂)/r^2

Where G = 6.67*10^(-11) m^3/(kg*s^2)

Here, we know that:

r = 4.5*10^8m

m₁ = 2.1*10^21 kg

F = 5*10^24 N

And we want to find the mass of the other planet, first, let's isolate m₂ in the force equation:

(F*r^2)/(G*m₁) = m₂

Now we can replace all the values that we know in the left side, and solve it:

m₂ =[(5*10^24 N)*( 4.5*10^8m)^2]/[6.67*10^(-11) m^3/(kg*s^2)*2.1*10^21 kg]

m₂ = 7.23*10^(30) kg

The mass of the other planet is 7.23*10^(30) kg

asset question.....only answers otherwise u will be reported ​

Answers

Answer:

C. 24 hrs

Explanation:

it takes the earth 24 hrs to make one full revolution.

A 72 kg swimmer dives horizontally off a raft floating in a lake. The diver's speed immediately after leaving the raft is 3.8 m/s. If the time interval of the interaction between the diver and the raft is 0.25 s, what is the magnitude of the average horizontal force by diver on the raft?

Answers

Answer:

F = 1094.4 N

Explanation:

From impulse - momentum theorem, we now that ;

Impulse = momentum

Where;

Formula for impulse = force (F) × time(t)

Momentum = mass(m) × velocity(v)

Now, we are given;

Mass of swimmer; m = 72 kg

Speed; v = 3.8 m/s

Time; t = 0.25 s

Thus;

F × t = mv

F = mv/t

F = (72 × 3.8)/0.25

F = 1094.4 N

This value of force is the magnitude of the average horizontal force by diver on the raft.

A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 1.80 rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.

Answers

Answer:

[tex]K.E = 0.1905 J[/tex]

Explanation:

From the question we are told that:

Length [tex]L=1.4m[/tex]

Mass [tex]m=180g[/tex]

Angular Velocity [tex]\omega=1.80rads/s[/tex]

Generally the equation for Kinetic energy K.E is mathematically given by

 [tex]K.E =0.5 (1/3 ML^2 )w^2[/tex]

 [tex]K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2[/tex]

 [tex]K.E = 0.1905 J[/tex]

¿Cuántos electrones por segundo pasan a través de una sección de alambre que lleva una corriente de 0.70 A.?

Answers

Answer:

The number of electrons flowing per second is [tex]4.375\times 10^{18}[/tex].

Explanation:

How many electrons per second pass through a section of wire that carries a current of 0.70 A.?

Current, I = 0.7 A

time, t = 1 s

According to the definition of current, let the charge is q.

q = I t

q = 0.7 x 1 = 0.7 C

Let the number of electrons is n.

[tex]n =\frac{q}{e}\\\\n = \frac{0.7}{1.6\times 10^{-19}}\\\\n = 4.375\times 10^{18}[/tex]

4. Which of the following statement describes the particle model.
A. The average kinetic energy of the particles changes easily
B. All matter is made up of large triangular particles
C. There are no spaces between the particles
D. The average kinetic energy of all the particles remains constant

E.Other:​

Answers

I think it is A
Its not sure tho

6. An object is fired from the gound at 275 m/s at an angle of 55° N of E.
a. How far away did the object first hit the ground?
b. what is the maximum height that the object reaches? ​

Answers

there u go fella hope u understood

please help me with this question​

Answers

Answer:

(4) A = 3 A, A₂ = 11 A

(5) 7 A

Explanation:

(4)

From the diagram,

A = 3+6+2

A = 11 A

V = A₂R

A₂ = V/R₂............ Equation 1

Given: V = 12 V,  R₂ = 4 Ω

Substitute these values into equation 1

A₂ = 12/4

A₂ = 3 A

(5) Applying,

V = IR'

I = V/R'............ Equation 1

Where V = Voltage, I = cuurent, R' = total resistance.

But,

1/R' = (1/3)+(1/4)

1/R' = (3+4)/12

1/R' = 7/12

R' = 12/7 Ω

Given: V = 12 V

Substitute these values into equation 1

I = 12/(12/7)

I = 7 A

Therefore

A = 7 A

train starting from a railway station and moving with a uniform accleration attains a speed of 90km/hr in 10s .Find the accleration
Options
90m/s2
1m/s2
10m/s2
0.1m/s2

Answers

Answer:

a= 2.5m/s²

Explanation:

U=0

V=90km/hr

T= 10s

Convert 90km/hr to m/s

1km= 1000m

1hr= 3600s

(60×60)

therefore, 90km/hr = 90000/3600

90km/hr= 25m/s

From Newton First Equation,

V=U + AT

25=0+ A(10)

25= 10A

25/10 =10A/10

A= 2.5m/s²

Complete the sentence below using one of the following
words: equilibrium, flux, motion.
If supported at its center of gravity, an object will remain in ______ any position.

Answers

Answer:

equilibrium

Explanation:

acceleration will remain constant

how does a resistor affect an electrical circuit

Answers

Answer:

A resistor has the ability to reduce voltage and current when used in a circuit. The main function of a resistor is to limit current flow.

Explanation:

I this what you were looking for?

Which statement best describes an insulator​

Answers

Whichever one doesn’t let electricity pass through it

The picture below shows a person swinging a yo-yo in a circle. Which vector shows the velocity of the yo-yo at this moment?
A. B
B. A
C. C
D. D

Answers

C, at this moment it is directly 90 degrees to the right and is only travelling downwards

convert 700kg into grams

Answers

Answer:

700,000g

Explanation:

1kg = 1000 Grams (or any kg x 1000)

Answer:

700 kilograms is equal to 700,000 grams

Explanation:

One kilogram has 1000 grams, or if you want the other way around, one gram is 1/1000th of one kilogram. If you follow this logic, we want to use the 'one kilogram has 1000 grams' "rule", so we would do some math here.

700 kg x 1000 g = ______ g

700*1000 = 700,000

700 kg = 700,000 g

Please let me know if I misunderstood and I hope this helped!

show that pv=nrt has the same unit with energy​

Answers

Answer:

The unit of the equation P·V = n·R·T is the Joules which is the same as the unit of energy

Explanation:

The unit of energy is Joules, with symbol J

The given equation for an ideal gas is P·V = n·R·T

Where;

P = The pressure of the gas with units Pascals, Pa

V = The volume of the gas, with units m³

n = The number of moles with unit moles

R = The universal gas constant = 8.314 J/(mol·K)

T = The temperature, with units, Kelvin, K

Therefore, we get;

P·V has unit 1 Pa × 1 m³ = 1 N/m² × 1 m³ = 1 N·m = 1 Joule

Similarly, we get

n·R·T with units n mole × 8.314 J/(mol·K) × 1 K = 8.314·n Joules

Therefore, P·V = n·R·T, has the unit of Joules which is the same unit with energy.

_______ is an optical filter that passes light of a specific polarization and blocks waves of other polarizations.
a. Index of refraction
b. Laser
c. Polarizer

Answers

I’m not 100% sure but C. Would make sense

This filter picks out a specific polarization, so it makes a lot more sense to call it a polarizer than anything else.  (C)

This question is a lot like asking "What color is an orange ?".

A wave travels at 330m/s^-1. the wavelength is found to be 2.4m.
Calculate the period of oscillation of a article in the medium transmitting the waves.
The frequency of oscillations of the source transmitting the wave

Answers

Answer: frequency 137.5

Time period 0.01sec

Explanation:

when you order clothes, does the sweater has to be longer than your shirt to fit you just like the shirt?

Answers

Answer:

Yes.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Which forms of energy determine temperature: translational kinetic energy, rotational kinetic energy, vibrational kinetic energy, or all of these

Answers

oh this question seems to be difficult I don't think I can answer this

Which of the following best distinguishes the relationship between applied research and basic research?

A Applied research commercializes the discoveries of basic research and brings them to the general public.
B Basic research takes place in academia, and complex research takes place in industry.
C Basic research provides fundamental knowledge that can be used to conduct applied research.
D Applied research is not published for peer review, but basic research must be.

Answers

Answer:

C. Basic research provides fundamental knowledge that can be used to conduct applied research.

Explanation:

Applied research is used to solve practical and specific problems. Basic research is used to advance theories and scientific knowledge; it might not result in an invention or a solution, but can be used to gain knowledge about a specific subject.

Ali while driving to school computes the average speed for his trip to be 20km/hr on his return trip along the same route. There is less traffic and average speed is 30km/hr. What is the average speed for Ali's trip?

Answers

Answer:

25 km/hr

Explanation:

Since Ali's average speed for his trip to school is u = 20 km/hr and his average speed for the return trip to back home from school is v = 30 km/hr, thus his total average speed for the journey is thus V = (initial average speed + final average speed)/2 = (u + v)/2

Substituting the values of the variables into the equation, we have

V = (u + v)/2

V = (20  km/hr + 30 km/hr)/2

V = 50 km/hr/2

V = 25 km/hr

So, the average speed for Ali's trip is 25 km/hr

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.7 m/s . It then flies a further distance of 48500 m , and afterwards, its velocity is 44.7 m/s . Find the airplane's acceleration.

Answers

Answer:

[tex]\quad[/tex]0.0095 m/s²

Explanation:

We have,

Initial velocity (u) = 32.7 m/sFinal velocity (v) = 44.7 m/sDistance travelled (s) = 48500 m

We are asked to calculate the airplane's acceleration.

By using the third equation of motion,

- = 2as

v denotes final velocityu denotes initial velocitya denotes accelerations denotes distance

➝ (44.7)² - (32.7)² = 2 × a × 48500

➝ 1998.09 - 1069.29 = 97000 × a

➝ 928.8 = 97000a

➝ 928.8 ÷ 97000 = a

0.0095 m/s² = a

Mike is serving the volleyball for the second time in a volleyball game. If the ball leaves his hand with twice the velocity it had on the first serve, its horizontal range R would be:

Answers

Answer:

His new horizontal range is 4 times his initial range.

Explanation:

Since Mike serves the ball with velocity, u, his horizontal range is

R = u²sin2Ф/g where Ф is the angle between u and the horizontal.

Now, if on his second serve, the ball leaves his hand with twice the velocity of his initial serve, the new velocity is v = 2u.

So, the new range R' = v²sin2Ф/g

R' = (2u)²sin2Ф/g

R' = 4u²sin2Ф/g

Since R = u²sin2Ф/g,

R' = 4u²sin2Ф/g

R' = 4R

So, his new horizontal range is 4 times his initial range.

With what tension must a rope with length 3.00 mm and mass 0.105 kgkg be stretched for transverse waves of frequency 40.0 HzHz to have a wavelength of 0.790 mm

Answers

Answer:

the tension of the rope is 34.95 N

Explanation:

Given;

length of the rope, L = 3 m

mass of the rope, m = 0.105 kg

frequency of the wave, f = 40 Hz

wavelength of the wave, λ = 0.79 m

Let the tension of the rope = T

The speed of the wave is given as;

[tex]v = f\lambda = \sqrt{\frac{T}{\mu} } \\\\where;\\\\\mu \ is \ mass \ per \ unit \ length\\\\\mu = \frac{0.105}{3} = 0.035 \ kg/m\\\\v = f\lambda = 40 \times 0.79 = 31.6 \ m/s\\\\v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu\\\\T = (31.6^2)(0.035)\\\\T = 34.95 \ N[/tex]

Therefore, the tension of the rope is 34.95 N

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